Update with mySQLi Prepared Statement [duplicate] - php

This question already has answers here:
PHP UPDATE prepared statement
(3 answers)
Closed 11 months ago.
I have written the code below and it is supposed to update a selected entry in the database when the user presses the update button. When I press the update button I just get a blank page. I cannot figure out what is wrong with my code. Any help would be appreciated.
<?php
//Open a new connection to the MySQL server
$mysqli = new mysqli('localhost','some directory','some password','some user ');
//Output any connection error
if ($mysqli->connect_error) {
die('Connection failed : ('. $mysqli->connect_errno .') '. $mysqli->connect_error);
}
// check if the 'id' variable is set in URL, and check that it is valid
if (isset($_GET['cd']) && is_numeric($_GET['cd']))
// get id value
$id = $_GET['cd'];
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$phonenumber = $_POST['phonenumber'];
$city = $_POST['city'];
$state = $_POST['state'];
$zipcode = $_POST['zipcode'];
$dob = $_POST['dob'];
$doi = $_POST['doi'];
$adjustername = $_POST['adjustername'];
$claimrefnumber = $_POST['claimrefnumber'];
$providernature = $_POST['providernature'];
$created = $_POST['created'];
$language = $_POST['language'];
$client = $_POST['client'];
$amountauthorized = $_POST['amountauthorized'];
$active = $_POST['active'];
$invoiceformat = $_POST['invoiceformat'];
$query = ("UPDATE tabele SET firstname, lastname, phonenumber, city, state, zipcode, dob, doi, adjustername, claimrefnumber, providernature, created,language, client, amountauthorized, active, invoiceformat, WHERE id)
VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
$statement = $mysqli->prepare($query);
$statement->bind_param('isssssssssssssssss', $id, $firstname, $lastname, $phonenumber, $city, $state, $zipcode, $dob, $doi, $adjustername, $claimrefnumber, $providernature, $created, $language, $client, $amountauthorized, $active, $invoiceformat);
if($statement->execute()){
header("some location");
}else{
die('Error : ('. $mysqli->errno .') '. $mysqli->error);
}
$statement->close();
?>

I figured it out, I finally found an example that works although I had to tweak some parts. The code below will grab the id passed from the url, do a prepared statement to update the selected id, and then redirect to a url location. The only thing missing is a Limit statement which I haven't figured out how to make work.
The code will also work to delete will be nearly identical with a few minor tweaks.
<?php
// check if the 'id' variable is set in URL, and check that it is valid
if (isset($_GET['id']) && is_numeric($_GET['id']))
// get id value
$id = $_GET['id'];
$results = $id;
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$phonenumber = $_POST['phonenumber'];
$city = $_POST['city'];
$state = $_POST['state'];
$zipcode = $_POST['zipcode'];
$dob = $_POST['dob'];
$doi = $_POST['doi'];
$adjustername = $_POST['adjustername'];
$claimrefnumber = $_POST['claimrefnumber'];
$providernature = $_POST['providernature'];
$created = $_POST['created'];
$language = $_POST['language'];
$client = $_POST['client'];
$amountauthorized = $_POST['amountauthorized'];
$active = $_POST['active'];
$invoiceformat = $_POST['invoiceformat'];
$connection = new mysqli("localhost", "some directory", "some password", "some user");
$statement = $connection->prepare("update table set firstname = ?, lastname = ?, phonenumber = ?, city = ?, state = ?, zipcode = ?, dob = ?, doi = ?, adjustername = ?, claimrefnumber = ?, providernature = ?, created = ?,language = ?, client = ?, amountauthorized = ?, active = ?, invoiceformat = ? where id = ?");
$statement->bind_param("sssssssssssssssssi", $firstname, $lastname, $phonenumber, $city, $state, $zipcode, $dob, $doi, $adjustername, $claimrefnumber, $providernature, $created, $language, $client, $amountauthorized, $active, $invoiceformat, $id);
$statement->execute();
if($statement->execute()){
header("some location");
}else{
die('Error : ('. $mysqli->errno .') '. $mysqli->error);
}
$statement->close();
?>

Related

How do i create multiple mysql table using php?

so this is my code and it only add the data to a table called 'registration' i want it to create its own table using $firstName
<?php
$firstName = $_POST['firstName'];
$lastName = $_POST['lastName'];
$gender = $_POST['gender'];
$email = $_POST['email'];
$password = $_POST['password'];
$number = $_POST['number'];
// Database connection
$conn = new mysqli('localhost','root','','test');
if($conn->connect_error){
echo "$conn->connect_error";
die("Connection Failed : ". $conn->connect_error);
} else {
$stmt = $conn->prepare("insert into registration(firstName, lastName, gender, email, password, number) values(?, ?, ?, ?, ?, ?)");
$stmt->bind_param("sssssi", $firstName, $lastName, $gender, $email, $password, $number);
$execval = $stmt->execute();
echo $execval;
echo "Registration successfully...";
$stmt->close();
$conn->close();
}
?>

Data not inserted in Database but i got message new record entered successfully [closed]

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<?php
error_reporting(E_ALL);
$username = $_POST['username'];
$email_id = $_POST['email_id'];
$phone_no = $_POST['phone_no'];
$gender = $_POST['gender'];
$country = $_POST['country'];
$courses = $_POST['courses'];
//i am checking here values***
if (!empty($username) || !empty($email_id) || !empty($phone_no) || !empty($gender) || !empty($country) || !empty($courses)) {
//db connectiion***
$host = "localhost";
$dbUsername = "root";
$dbPassword = "";
$dbname = "registartionform";
//create connection
$conn = new mysqli($host, $dbUsername, $dbPassword, $dbname);
if (mysqli_connect_error()) {
die('Connect Error('. mysqli_connect_errno().')'. mysqli_connect_error());
} else {
//check email already exists or not and insert the value in db***
$SELECT = "SELECT email_id From registration Where email_id = ? Limit 1";
$INSERT = "INSERT Into registration (username, email_id, phone_no, gender, country, courses) values($username, $email_id, $phone_no, $gender, $country, $courses)";
//Prepare statement
$stmt = $conn->prepare($SELECT);
if ($stmt !== false) {
$stmt->bind_param("s", $email_id);
$stmt->execute();
$stmt->bind_result($email_id);
$stmt->store_result();
$rnum = $stmt->num_rows;
}
if ($rnum == 0) {
$stmt->close();
$stmt = $conn->prepare($INSERT);
$stmt->bind_param("ss", $username, $email_id, $phone_no, $gender, $country, $courses);
if ($stmt !== false) {
$stmt->execute();
echo "New record inserted sucessfully";
} else {
echo "Someone already register using this email";
}
}
$stmt->close();
$conn->close();
}
} else {
echo "All field are required";
die();
}
You can't do this
INSERT Into registration (username, email_id, phone_no, gender, country, courses)
values($username, $email_id, $phone_no, $gender, $country, $courses)
and then try to bind variables
$stmt->bind_param("ss", $username, $email_id, $phone_no, $gender, $country, $courses );
You should use placeholders in your SQL query. Try with:
INSERT Into registration (username, email_id, phone_no, gender, country, courses)
values(?, ?, ?, ?, ?, ?)
Values will be provided in bind_param variables.
Also you have 7 variables in bind_param and only 6 columns in your INSERT statement. You need to mach that or SQL wont know where to put data.

I can't insert data into my database but I don't have any errors

This is my php code. Can you please help me. There's no data in my database.
<?php
require_once("dbconnect.php");
session_start();
for ($x = 0; x < $_POST['reimcounter']; $x++) {
$date = $_POST['date'];
$tin = $_POST['tin'];
$address = $_POST['address'];
$particulars = $_POST['particulars'];
$referencenumber = $_POST['refno'];
$total = floatval(preg_replace('/[^\d\.]/', '', $_POST['total' . $x]));
$nonvat = floatval(preg_replace('/[^\d\.]/', '', $_POST['nonvat' .
$x]));
Is there anything wrong with my insert code?
$sql = "INSERT INTO rtco_cms.dbo.Reimbursement VALUES (?, ?, ?, ?, ?, ?,
?, ?, ?)";
$params = array($date, $tin, $SESSION['empid'], $address,
$SESSION['clientid'], $particulars, $referencenumber, $nonvat, $total);
$stmt = sqlsrv_query($conn, $sql, $params);
}
header("location: ../reimbursement.php");
?>
Change this
$params = array($date, $tin, $SESSION['empid'], $address,
$SESSION['clientid'], $particulars, $referencenumber, $nonvat, $total);
to
$params = array($date, $tin, $_SESSION['empid'], $address,
$_SESSION['clientid'], $particulars, $referencenumber, $nonvat, $total);
Session variable calling is wrong. Hope it helps
Update your insert query for example see this query:
tsql= "INSERT INTO dbo.vF_events (
username,
Rft,
Ging,
description,
date,
trdate)
VALUES
(?, ?, ?, ?, ?, ?)";
$var = array($username, $sort, $ag, $description, $date, $trdate);
if (!sqlsrv_query($conn, $tsql, $var))
{
die('Error: ' . sqlsrv_errors());
}
echo "record added";

PHP values not going to the database

session_start();
include('dbconn.php');
if(isset($_POST['registerform']) || isset($_POST['loginform'])) {
if(isset($_POST['registerform']) && $_POST['registerform']){
//register
if(isset($_POST['username']) && !empty($_POST['username'])
&& isset($_POST['password']) && !empty($_POST['password'])
&& isset($_POST['fname']) && !empty($_POST['fname'])
&& isset($_POST['lname']) && !empty($_POST['lname'])
&& isset($_POST['email']) && !empty($_POST['email'])){
//ean einai gemata me kati ta paidia
$myName=trim($_POST['username']);
$myPass= md5(trim($_POST['password']));
$fName=trim($_POST['fname']);
$lName=trim($_POST['lname']);
$eMail=trim($_POST['email']);
if($stmt = $mysqli->prepare("INSTERT INTO users(username,password,fname,lname,email) VALUES (?, ?, ?, ?, ?)")) {
$stmt->bind_param('sssss',$name,$pass,$fname,$lname,$email);
$name = $myName;
$pass = $myPass;
$fname = $fName;
$lname = $lName;
$email = $eMail;
$stmt-> execute();
$stmt-> close();
}
}
}
}else{
echo "no form submited";
}
and this is the db connection
<?php
$host = "localhost";
$username = "root";
$password = "";
$db_name = "phpwebsite";
$mysqli = new mysqli("$host","$username","$password","$db_name");
// Check connection
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
?>
I think the problem is the insert statment because everything else seems to be working fine. When i press the signup button no errors appear . The only thing is that the values are not going to the database
The error is in your SQL query I think its a type INSTERT
if($stmt = $mysqli->prepare("INSTERT INTO users(username,password,fname,lname,email) VALUES (?, ?, ?, ?, ?)"))
Try correcting it to
if($stmt = $mysqli->prepare("INSERT INTO users(username,password,fname,lname,email) VALUES (?, ?, ?, ?, ?)"))
Edit :
For your second issue :
try { $stmt = $mysqli->prepare("INSERT INTO users(username,password,fname,lname,email) VALUES (?, ?, ?, ?, ?)")
$stmt->bind_param('sssss',$name,
$pass,$fname,
$lname,$email);
$name = $myName;
$pass = $myPass;
$fname = $fName;
$lname = $lName;
$email = $eMail;
$stmt-> execute();
$stmt-> close();
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
die("Failed to run query: " . $ex->getMessage());
}

Fatal error: Call to a member function bind_param() on a non-object in PHP

I am trying to store data into database from my form.I have try below code,but it will give me fatal error.what is the changes i have to do so that code can work fine.Here i have check my database connection all working fine but there is only one error of fatal error:Call to a member function bind_param() on a non-object.
<?php
if(isset($_POST['submit']))
{
$conn = mysqli_connect('localhost', 'root', '','tmtool');
if($conn -> connect_errno )
{
die('coudn\'t connect to the database' . mysqli_connect_error());
}
if(! get_magic_quotes_gpc() )
{
$Testcase_id = addslashes (filter_input(INPUT_POST, 'Testcase_id'));
$Testcase_title = addslashes (filter_input(INPUT_POST, 'Testcase_title'));
$Testcase_desc = addslashes(filter_input(INPUT_POST, 'Testcase_desc'));
$Product_id= addslashes(filter_input(INPUT_POST, 'Project_id'));
$Date_created= addslashes(filter_input(INPUT_POST, 'Date_created'));
$Created_by= addslashes(filter_input(INPUT_POST, 'Created_by'));
$Type= addslashes(filter_input(INPUT_POST, 'Type'));
$Priority = addslashes(filter_input(INPUT_POST, 'Priority'));
$Precondition= addslashes(filter_input(INPUT_POST, 'Precondition'));
$Test_step = addslashes(filter_input(INPUT_POST, 'Test_step'));
$Expected_result = addslashes(filter_input(INPUT_POST, 'Expected_result'));
$Request_mode = addslashes(filter_input(INPUT_POST, 'Request_mode'));
$Language = addslashes(filter_input(INPUT_POST, 'Language'));
$Category = addslashes(filter_input(INPUT_POST, 'Category'));
$Sub_category = addslashes(filter_input(INPUT_POST, 'Sub_category'));
}
else
{
$Testcase_id =(filter_input(INPUT_POST, 'Testcase_id'));
$Testcase_title =(filter_input(INPUT_POST, 'Testcase_title'));
$Testcase_desc = (filter_input(INPUT_POST, 'Testcase_desc'));
$Product_id=(filter_input(INPUT_POST, 'Project_id'));
$Date_created=(filter_input(INPUT_POST, 'Date_created'));
$Created_by=(filter_input(INPUT_POST, 'Created_by'));
$Type= (filter_input(INPUT_POST, 'Type'));
$Priority =(filter_input(INPUT_POST, 'Priority'));
$Precondition=(filter_input(INPUT_POST, 'Precondition'));
$Test_step =(filter_input(INPUT_POST, 'Test_step'));
$Expected_result =(filter_input(INPUT_POST, 'Expected_result'));
$Request_mode = (filter_input(INPUT_POST, 'Request_mode'));
$Language = (filter_input(INPUT_POST, 'Language'));
$Category = (filter_input(INPUT_POST, 'Category'));
$Sub_category = (filter_input(INPUT_POST, 'Sub_category'));
}
$sql = $conn->prepare("INSERT INTO tmtool.testcase_master ( `Testcase_id`,`Testcase_title`,`Testcase_desc`,`Product_id`,`Date_created`,`Created_by`,`Type`,`Priority`, `Precondition`, `Test_step`, `Expected_result`, `Request_mode`, `Language`, `Category`, `Sub_category`) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
$sql->bind_param('sssssssssssssss',$Testcase_id,$Testcase_title,$Testcase_desc, $Product_id, $Date_created, $Created_by, $Type , $Priority, $Precondition, $Test_step, $Expected_result, $Request_mode, $Language, $Category , $Sub_category);
if($sql->execute())
{
echo "Entered data successfully\n";
mysqli_close($conn);
}
else {
die('Could not enter data: ' . mysqli_error($conn));
}
}else{
echo "you are not able to connect to data base";
}
?>
You use mysqli_* in OOP style so you have to use the keyword new and remove the _connectpart for the connection like this:
$conn = new mysqli('localhost', 'root', '','tmtool');
//^^^ ^ '_connect' removed
//| See here
Also change your close statement from:
mysqli_close($conn);
to this:
$conn->close();
And for errors you have to use this:
$conn->error //Not mysqli_error($conn)
As suggested by #Rizier123,
When i am try to put prepare statement into if condition then it will work for me...Thanks #Rizier123
Final correction in code is:
if(($sql = $conn->prepare("INSERT INTO tmtool.testcase_master ( `Testcase_id`,`Testcase_title`,`Testcase_desc`,`Product_id`,`Date_created`,`Created_by`,`Subscriber_type`,`Priority`, `Precondition`, `Test_step`, `Expected_result`, `Activation_mode`, `Language`, `Category`, `Sub_category`) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"))== FALSE)
{
echo "false";
}
$sql->bind_param('sssssssssssssss',$Testcase_id,$Testcase_title,$Testcase_desc, $Product_id, $Date_created, $Created_by, $Subscriber_type , $Priority, $Precondition, $Test_step, $Expected_result, $Activation_mode, $Language, $Category , $Sub_category);

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