So I am working with PHP to pass a PHP array over a jQuery Ajax request to another PHP page. This is quite the task. For some reason, my json_encode is returning an array instead of a string, I am not quite sure why. Here is my PHP code:
$new_spreadsheet = nl2br($_POST['spreadsheet']);
$new_spreadsheet = explode('<br />', $new_spreadsheet);
array_shift($new_spreadsheet);
$new_spreadsheet = array_values($new_spreadsheet);
echo json_encode($new_spreadsheet);
I would show you the output, but it is really long. Basically this is outputting a PHP array which consists of each row on the spreadsheet. This is what I want to have, but the problem is that I don't want the quotes and everything in the array. I am pretty sure I need to run json_decode, but when I do that my code returns an error saying that the parameter needs to be a string. I can tell something is not right, but am not quite sure what I need to change. I would appreciate any advice.
Update: At this point, when I try to loop through the array and print each value, the first array index is equal to a double quote like so: ". There are double quotes in random values throughout the area. I am not quite sure about what is causing this.
If I echo the rows from within the json_encoded PHP array onto the console, I get the following output:
"
correct value
correct value
correct value
"
You're using JSON, which means you have to adhere to somewhat more stringent syntax rules than Javascript's. e.g.
<?php
$arr = array('This' => 'is', 'an' => 'array in php');
echo json_encode($array);
?>
output:
{"This":"is","an":"array in PHP"}
There is NO way to avoid getting quotes on the values, as they're a fundamental requirement of JSON (and Javascript). If you don't want quotes, then don't use JSON.
try only br.
$new_spreadsheet = explode("<br>", $new_spreadsheet);
It will work. and json_enode can never return an array. try var_dump and check.Also make sure before you post, use htmlspecialcharacters.
Related
So i am using this PHP code to create the json output, and I am having an issue where it’s creating an array of array with the info. I would like to get rid of one array and just display the list of API’s thats been used and number that has been used.
Looks as though the difference is you have...
"apis":[{"item_search":"0\n"},{"item_recommended":"0\n"}]
and want
"apis":{"item_search":"0\n","item_recommended":"0\n"}
If this is the case, you need to change the way you build the data from just adding new objects each time to setting the key values directly in the array...
$zone_1 = [];
foreach($zone_1_apis as $api_name ) {
$zone_1[substr($api_name, 0,-5)] = file_get_contents('keys/'.$_GET['key'].'/zone_1/'.$api_name);
}
You also need to do the same for $zone_2 as well.
It may also be good to use trim() round some of the values as they also seem to contain \n characters, so perhaps...
trim(file_get_contents('keys/'.$_GET['key'].'/zone_1/'.$api_name))
This is what I am trying to do. I am trying pass variable(s) from one form to another. I can do it in "HTML" I would like to have done in a PHP echo statement
When I call the second program from the first program I have nothing coming back in the "GET" array. I think ($v_resource_id, $v_category_id) are not being translated correctly What I am doing wrong in my syntax ? What you see here is part of the first program or calling program
echo'';
Aside from the noted html error (missing quote), you are not retrieving the correct keys, you have var and var2 but are trying to retrieve v_resource_id. You need to retrieve $_GET['var'] and $_GET['var2'].
Do print_r($_GET); to see what is being sent via $_GET. You should get:
Array (
[var] => whatever
[var2] => something else
)
Also, you may want to use the native query building function by doing http_build_query(array('var'=>'something','var2'=>'what ever')) to get a query string. Makes this easier and I think it takes care of urlencode(), you'd have to double check that.
Try this, it's about proper quoting
echo "here";
you'll use your values as $_GET['var'] and $_GET['var2']
This is so strange, i tried a bunch of combinations for the quotes but with no positive results, i just want to put the children_of_row variable to be inside a string, but it's not working as i expect, this is strange but since i know that it is me that is wrong and not php i want you guys to tell me where is my "mistake" ? (anything that helps me understand nesting php strings is appreciated).
$children_of_array is an array, $children_of_row["question_name"] is a string when i use php's gettype function, i push the value into $children_of_array, and then inside a php echo statement i implode the array (can i run php functions inside the echo statement ?), but even if i don't the results are the same, when outputted into javascript the type is not string anymore.
array_push($children_of_array,'".$children_of_row["question_name"]."');
If you want the string of $children_of_row["question_name"], you just need to put that:
array_push($children_of_array, $children_of_row["question_name"]);
As long as the variable is already a string, or a value that is allowed in an array (including arrays), it'll work.
can anyone explain the purpose of json_encode when doing a .post query.
This is what i often see in other's coding.
.post php script
...
...
echo json_encode($a);
I mean if i want to do a return from a .post script and returning an array via .post. Wouldn't i just need to do the following?
.post php script
...
...
$a = array("foo", "bar", "hallo", "world");
$string=implode(',',$a) in my php script
return $string;
javascript
$.post('$url',function(data){
data_arr=data.split(',');
//After which just get the values in the array
alert(data_arr[0]); //ALERTS 'foo'
alert(data_arr[1]); //ALERTS 'bar'
});
If anyone can just help by clearing this up for me and let me see the light for using json in this purpose, that would be great.
Perhaps its also due to my inept knowledge of JSON as well.
Would greatly appreciate it if anyone can advise me on why is it better to use JSON encode in this case and how am i suppose to use it via a .post request instead of just echoing out the string and split it later.
Thanks.
Using json_encode ensures that your data is always valid.
It doesn't really matter for simple data that you have control over, though imagine if someday you have a comma inside one of the values. With JSON encoded strings, you don't have to worry about an arbitrary separator token.
Also, with JSON you can easily encode Objects/Arrays without needing to reinvent the wheel.
First of all, in my opinion and practise, JSON syntax is fairly similar to Javascript objects and it's great when dealing with more complex data types that have to be sent/requested and parsed later on.
For example:
If you're doing a post request and you're serializing all the form fields which you validate server side (using PHP) you're most likely going to need to use key => value pairs like textbox_name => value. It's more logical to do it that way, than to select values by numeric indexes (what if the form layout changes?)
Example code using commas:
<?php
$array = array('Tom', 'Hanks', 'Football');
$string = join(',',$array);
echo $string; //it's obvious - the output is Tom,Hanks,Football
?>
The javascript that receives the string
$.post(url,{},function(data){
var values = data.split(',')
$("#name").text(values[0]);
$("#surname").text(values[1]);
$("#interests").text(values[2]);
});
So it makes sense right? But wouldn't it more sense to do this instead:
<?php
header('Content-type: application/json');
$array = array('name' => 'Tom', 'surname' => 'Hanks', 'interests' => 'Football');
echo json_encode($array);
?>
And the javascript:
$.post(url,{},function(data){
for(index in data) {
$("#"+index).text(data[index]);
}
//or
$("#name").text(data.name);
$("#surname").text(data.surname);
$("#interests").text(data.interests);
});
The same goes with parsing response data with Javascript. Having an object is more logical than having a CSV string.
Obviously it depends on the use case, but in general JSON gives you a logical structure of stringified Objects/Arrays which can be translated back into objects and arrays and looped through or manipulated in any way.
Also JSON is now a standard. Everyone uses it which means that it's not for no reason.
In other words - JSON data makes more sense.
In my form i have fields with name photoid[] so that when sent they will automatically be in an array when php accesses them.
The script has been working fine for quite some time until a couple days ago. And as far as i can remember i havent changed any php settings in the ini file and havent changed the script at all.
when i try to retrieve the array using $_POST['photoid'] it returns a string with the contents 'ARRAY', but if i access it using $_REQUEST['photoid'] it returns it correctly as an array. Is there some php setting that would make this occur? As i said i dont remember changing any php settings lately to cause this but i might be mistaken, or is there something else i am missing.
I had the same problem. When I should recieve array via $_POST, but var_dump sad: 'string(5) "Array"'. I found this happens, when you try use trim() on that array!
Double check your code, be sure you're not doing anything else with $_POST!
Raise your error_reporting level to find any potential source. It's most likely that you are just using it wrong in your code. But it's also possible that your $_POST array was mangled, but $_REQUEST left untouched.
// for example an escaping feature like this might bork it
$_POST = array_map("htmlentities", $_POST);
// your case looks like "strtoupper" even
To determine if your $_POST array really just contains a string where you expected an array, execute following at the beginning of your script:
var_dump($_POST);
And following for a comparison:
var_dump(array_diff($_REQUEST, $_POST));
Then verifiy that you are really using foreach on both arrays:
foreach ($_POST["photoid"] as $id) { print $id; }
If you use an array in a string context then you'll get "Array". Use it in an array context instead.
$arr = Array('foo', 42);
echo $arr."\n";
echo $arr[0]."\n";
Array
foo
$_POST['photoid'] is still an array. Just assign it to a variable, and then treat it like an array. ie: $array = $_POST['photoid'];
echo $array[0];