Store Value in Database With For Loop - php

Question

Here's my code: you will automatically understand what it does
<form method="post">
Enter Your Numbers
<input type="number" name="number" min="1" max="10" />
<input type="submit" name="submit" value="submit" />
</form>
<?php
if(isset($_POST['submit']))
{
$number = $_POST['number'];
for ($x=0; $x<=$number; $x++) {
echo "<input type=\"text\" name=\"tbno".$x."\">";
}
echo "<input type=\"submit\" value=\"submit\" name=\"submit1\">";
}
if(isset($_POST['submit1']))
{
$link = mysql_connect("localhost", "root", "");
$db = mysql_select_db("bookabook");
}
?>
Here's my question: I want to store the textbox values in database, but I don't know how to do this.
if(isset($_POST['submit1']))
{
$link = mysql_connect("localhost", "root", "");
$db = mysql_select_db("bookabook");
//WHAT SHOULD I WRITE HERE
}
Can anyone tell me please?

Answer 1

# HTML
echo "<input type='text' name='tbno[]' value='$x'>";
# PHP
$array = $_POST[tbno];
foreach ($array as $key => $value) {
echo "$key = $value<br/>";
}

Answer 2

Instead of using a counter $x -> name=\"tbno".$x."\", just set your inputs to an array -> name=\"tbno[]\". Then on form submit you can easily loop through them using a foreach or for loop.
<?php
if(isset($_POST['tbno']))
{
//your db connection
foreach($_POST['tbno'] as $tbno){
//INSERT INTO tbl VALUE $tbno
}
echo 'INSERTED DATA';
}
?>
<form method="post">
<?php
if(isset($_POST['number']))
{
$number = $_POST['number'];
for ($x=0; $x<$number; $x++) {
echo "<input type=\"text\" name=\"tbno[]\">";
}
}
else
{ ?>
Enter Your Numbers<input type="number" name="number" min="1" max="10" />
<?php
} ?>
<input type="submit" name="submit" value="submit" />
</form>
I condensed your 2 forms into 1, as the only thing that changes the inputs, so there is less code.

Answer 3

I think what you're looking for is an insert statement. I'm not sure I understand the code, but I understand the objective. All you need to do is create an insert(like below) statement in the for-loop that loops through the books, etc..
$number = trim($_POST['number']);
$numberOfBooks = mysqli_real_escape_string($mysqlDatabseConnectionObject,$numberOfBooks); //variable to be inserted in the database
$insertQuery = sprintf("INSERT INTO <table_name> VALUES('%s'",$numberOfBooks)); //statement to be executed
$insertResults = $mysqlDatabseConnectionObject->query($insertQuery); //execute the query
print_r($insertResults); //printing the query execution results

Answer 4

if(isset($_POST['submit1']))
{
$link = mysql_connect("localhost", "root", "");
$db = mysql_select_db("bookabook");
$values = "";
foreach($_POST as $key => $inputValue){
$values.="(".$inputValue."),";
}
$SQL_string = "INSERT INTO mitabla(micampo) VALUES $values";
mysql_query($SQL_string,$link);
}