Php how to use multiple parameters - php

there are two parameters in my app, user will fill one of them, but two parameters will get posted into php,php should select non empty field and do some action! something like this.point me right direction. i think 'isset get' should not be used three times like that right?which statement to be used 'and' or 'or' statement.?
i know it's stupid question! i appreciate ur help.
if (isset($_GET['Email']) && !empty($_GET['Fax'])) {
echo "fax is empty and Email = ".$_GET['Email'];
} elseif (isset($_GET['Fax']) && !empty($_GET['Email'])) {
echo "email is empty and Fax = ".$_GET['Fax'];
} elseif (!empty($_GET['Fax']) && !empty($_GET['Email'])) {
echo "Fax and email is empty";
} else {
echo"empty";
}

Simpler version:
$email = isset($_GET['Email']) ? $_GET['Email'] : null;
$fax = isset($_GET['Fax']) ? $_GET['Fax'] : null;
if (empty($email)) {
// email empty
}
if (empty($fax)) {
// fax empty
}

Related

Received Array From one Input Field How Can Validate it?

I want to get ten emails from user.how to check the user provide the correct email or not ? i am try multiple methods but failed to check it please help.
for($i=1;$i<=9;$i++)
{
echo "<input type='text' value='' name='email[]' class='form-control'>"."</br>";
}
// Php Code
// Step One Catch The Values
$email = $_POST['email'];
// Unset the empty values from array
foreach($email =>$key as $emails){
if($emails == ""){
unset($email[$key]);
}
}
Here I am successfully done But when i try to validate it it return me errors which i was never face.
I want to remove html special character from input field and also validate my input using filter_var for email validation. I am trying to do it with loop through method but does not work.
To achieve that look over below code. As you are receiving the array of email as an input from the end user.
if(count($_POST['email']) > 0)
{
$pattern = "/^\[?[0-9\.]+\]?$/";
foreach($_POST['email'] as $email)
{
if (preg_match($pattern, $email) === 1) {
// emailaddress is valid
}
}
}
You are writing foreach wrong way. try below code
foreach($email as $key=>$emails)
{
if($emails == "")
unset($email[$key]);
}
The easiest and safest way to check whether an email address is well-formed is to use the filter_var() function:
if(count($_POST['email']) > 0)
{
$email = $_POST['email'];
foreach($email as $key => $emails)
{
if(!filter_var($emails, FILTER_VALIDATE_EMAIL))
{
//invalid email
unset($email[$key]);
}
else
{
//valid email
}
}
}

php check if two variables are empty and merge them togheter

First thing first, i'm new to php.
I'm trying to check if two variables are both empty, and if so merge them togheter to display only one result, but if one of them is not empty, than i have to display is value.
I currently have:
$customerNotesWC = "";
$DYSPrintableOrderNotes = "test note";
Here's the code i tried so far:
function displayCustomerOrderNotes($customerNotesWC,$DYSPrintableOrderNotes){
if ($customerNotesWC == "") {
$customerNotesWC = "(none)";
}
if ($DYSPrintableOrderNotes ==""){
$DYSPrintableOrderNotes = "(none)";
}
if ($DYSPrintableOrderNotes == "(none)" && $customerNotesWC == "(none)"){
$NotesToDisplay = "(none)";
}
else {
$NotesToDisplay = $customerNotesWC . "<br/>" . $DYSPrintableOrderNotes;
}
}
Unfortunately this doesn't work, as the results is the following:
(none)
Pre-sale order note
I know that there must be a better way to achieve this, and any suggestions will be really appreciated.
Thanks a lot
In order to get your desired functionality of only printing "(none)" when both values are blank, the simplest thing to do to fix your code is remove the code that's setting either value to "(none)" and change your main if-statement to check for "":
function displayCustomerOrderNotes($customerNotesWC,$DYSPrintableOrderNotes){
if ($DYSPrintableOrderNotes == "" && $customerNotesWC == ""){
$NotesToDisplay = "(none)";
}
else {
$NotesToDisplay = $customerNotesWC . "<br/>" . $DYSPrintableOrderNotes;
}
//shouldn't there be an echo $NotesToDisplay; or return $NotesToDisplay; ? or something?
}

PHP - Check if one of two form fields is filled?

My form has Phone and Email fields.
Many people might not be wanting/able to put both,
so I thought, that the validator would require only
one of those two filled, instead of requiring the both filled.
I've tried thinking of different ways to do it but I'm pretty new to PHP,
so I couldn't come with any.
Would this be possible?
if ($_SERVER["REQUEST_METHOD"] == "POST")
{
if (empty($_POST["name"]))
{$nameErr = "Name is required";}
else
{$name = test_input($_POST["name"]);}
if (empty($_POST["email"]))
{$emailErr = "Email is required";}
else
{$email = test_input($_POST["email"]);}
if (empty($_POST["phone"]))
{$phone = "";}
else
{$website = test_input($_POST["website"]);}
if (empty($_POST["comment"]))
{$comment = "";}
else
{$comment = test_input($_POST["comment"]);}
}
Thank you.
As your title states, 1 / 2 form fields is filled in.
$i = 0; // PUT THIS BEFORE YOUR IF STATEMENTS
Inside of your statements:
if (empty($_POST["phone"])) {
$phone = "";
} else {
$i++; // PUT THIS IN ALL YOU WANT TO COUNT, IT WILL ADD 1 to $i EACH TIME YOU CALL IT
$website = test_input($_POST["website"]);
}
Now at the end, if
// YOU NEED TO CHANGE YOUR NUMBERS TO WHATEVER COUNT YOU WANT
if ($i < 2) { // IF $i IS LESS THAN 2
// YOUR CODE HERE
} else { // IF $i IS 2 OR MORE
// YOUR CODE HERE
}
Hope this is somewhat useful!
or as stated above, you can use an
if (#$A && #$B) { // REQUIRES BOTH TO BE TRUE
// YOUR CODE HERE
} elseif (#$A || #$B) { // REQUIRES ONLY ONE TO BE TRUE
// YOUR CODE HERE
} else { // NONE ARE TRUE
// YOUR CODE HERE
}
if you are wondering about the # signs above, they are simply checking if they are set, you could change the code to !empty($A) which is what you used above. Putting the ! before the empty function checks that it is false or that $A is actually set.
If i would have to check a form like you, i'd do it this way:
$res = '';
if(empty($_POST['name']))
$res .= 'The name is required.<br>';
if(empty($_POST['email']))
$res .= 'The email is required.<br>';
if(empty($_POST['phone']) && empty($_POST['email']))
$res .= 'You need to enter phone or email.<br>';
if(strlen($res) > 0) {
echo 'We have these errors:';
echo $res;
}
else {
echo 'No Errors!';
}
If you want to show only one error each time, use this code:
$res = '';
if(empty($_POST['name']))
$res = 'The name is required.<br>';
elseif(empty($_POST['email']))
$res = 'The email is required.<br>';
elseif(empty($_POST['phone']) && empty($_POST['email']))
$res = 'You need to enter phone or email.<br>';
if(strlen($res) > 0) {
echo $res;
}
else {
echo 'No Error!';
}
Even if i think it's very basic, i'll explain the mentioned part, even if you could look it up from php.net:
$res .= 'The name is required';
The ".=" operator adds the part 'The name is required' to the variable $res. If this happens the first time, the variable will be empty, because i initialized it as an empty string. With every ongoing line, another error Message will be added to the string.
if(strlen($res) > 0) {
strlen() will return the length of the string in $res. If no error occured, it would still be empty, so strlen() would return 0.

Dynamic if-statement with variables?

I'm trying to create a dynamic if-statement. The reason I want to do this, is because I need to check server-sided whether inputfields match my regex and are not empty. However, some of my inputfields can be removed in my CMS, meaning there would be more/less inputfields accordingly.
Ideally I would add variables in my if-statement but I'm not 100% sure if that's allowed, so perhaps I would need an other way to solve this problem. Here's what I tried:
if ($f_naw['streetname'] == 1)
{
$streetname= $_POST['streetname']; //Used in INSERT query
$cstreetname = " || $_POST['streetname'] == ''"; //Used to check if field is empty
$pstreetname = " || !preg_match($streetnameReg,$_POST['streetname'])"; //Used to check if it matches my regex
}
else
{
//These variables define variables if inputfields are not shown
$streetname= ''; //No streetname means it's excluded in INSERT query
$cstreetname = ''; //Not needed in check
$pstreetname = ''; //Also not needed in check
}
// more of these if/else statements
if ($_POST['firstname'] == '' || $_POST['lastname'] == '' || $_POST['email'] == '' $cstreetname $cpostalcode $chometown $ctelnr $csex $cdateofbirth)
{
echo 'One of the fields is empty.';
header('refresh:3;url=index.php');
}
else
{
//Regex check, after that more code
}
My idea was to check if a specific field is shown on the front-end and in that case I'm creating some variables that I want to paste in my if-statements.
I'm getting an error saying Server error meaning my php-code would be invalid.
Is it even possible at all to make a dynamic if-statement? If yes, at what part am I failing?
Help is much appreciated! Thanks in advance.
First of all, since it looks like you need to combine all of the conditionals with ||, you can correct your program by writing it like this:
if ($f_naw['streetname'] == 1)
{
$streetname= $_POST['streetname']; //Used in INSERT query
$cstreetname = $_POST['streetname'] == ''; //Used to check if field is empty
$pstreetname = !preg_match($streetnameReg,$_POST['streetname']); //Used to check if it matches my regex
}
else
{
//These variables define variables if inputfields are not shown
$streetname= ''; //No streetname means it's excluded in INSERT query
$cstreetname = false; //Not needed in check
$pstreetname = false; //Also not needed in check
}
if ($_POST['firstname'] == '' || $_POST['lastname'] == '' || $_POST['email'] == '' || $cstreetname || $cpostalcode || $chometown || $ctelnr || $csex || $cdateofbirth)
{
echo 'One of the fields is empty.';
header('refresh:3;url=index.php');
}
This would work, but it's unwieldy. A much better solution would be to use an array (let's name it $errors that gets dynamically populated with errors resulting from validating your fields. Like this:
$errors = array();
if ($f_naw['streetname'] == 1)
{
$streetname= $_POST['streetname']; //Used in INSERT query
if ($streetname == '') {
$errors[] = 'Streetname cannot be empty.'; // message is optional
}
if (!preg_match($streetnameReg,$streetname)) {
$errors[] = 'Streetname is invalid.'; // message is optional
}
}
And then:
if ($errors) {
echo 'There are errors with the data you submitted.';
header('refresh:3;url=index.php');
}
If you provided human-readable error messages you can also arrange for them to be displayed so that the user knows what they need to fix. And of course there are lots of variations of this technique you can use -- e.g. group the error messages by field so that you only show one error for each field.
If you want to check for empty $_POST fields you can do something like this
$error = False;
foreach($_POST as $k => $v)
{
if(empty($v))
{
$error .= "Field " . $k . " is empty\n";
}
}
if(!$error)
{
echo "We don't have any errrors, proceed with code";
}
else
{
echo "Ops we have empty fields.\n";
echo $error;
}
And after you are sure that all the fields are not empty you can do other stuff.

Multiple conditions in PHP

I know this is embarrassing easy but I cannot get this to work right now, keep getting syntax errors, I just added in a jquery code that pre-fills in a form filed and when you select the form field it will clear the default value. The result though is if a user submits the form without changing the default value, I need to see if it exist in addition to my normal string sanitations
In this snippet below of PHP I need to run 2 conditions on $fname but below will not work, can someone help please
$fname = 'first name';
if (trim($fname) == '') && ($fname != 'first name') {
$err .= "error";
}else{
$err .= "all good";
}
For karim79
this code below from your example, exactly like this gives me this error
Fatal Error: Can't use function return value in write context on line 5
<?PHP
$fname = '';
if(empty(trim($fname))) {
echo "First name is empty";
}
?>
$fname = 'first name';
if (trim($fname) == '' || $fname != 'first name') {
$err .= "error";
} else {
$err .= "all good";
}
I would prefer to use strcmp:
if (trim($fname) == '' || strcmp($fname,'first name') !== 0) {
$err .= "error";
} else {
$err .= "all good";
}
If the case of the first name is not important, you should consider using strcasecmp instead. Also note you can use empty to test for the empty string:
$fname = '';
$fname = trim($fname);
if(empty($fname)) {
echo "First name is empty";
} else {
echo "Not empty";
}
When using empty, beware the following (from the manual):
Note: empty() only checks variables as
anything else will result in a parse
error. In other words, the following
will not work: empty(trim($name)).
$fname = 'first name';
if (trim($fname) == '' || $fname == 'first name') {
$err .= "error";
}else{
$err .= "all good";
}
PS: I assumed you want to raise an error if the string is either empty or the standard value. If that's wrong let me know.
I would NOT recommend using empty() for anything. It has some tricky return patterns, including telling you that a 0 is empty, and things of that nature. This, unfortunately, is a shortcoming of PHP.
Instead, try this algorithm (The following assumes your form POSTs):
<?php
$err = array();
// this is for sticklers..with E_STRICT on, PHP
// complains about uninitialized indexes
if( isset($_POST['name']) )
{
$name = trim($_POST['name']);
}
else
{
$name = '';
}
if( strlen($name) == 0 )
{
$err[] = "First name is required.";
}
// after validation is complete....
if( count($err) > 0 )
{
echo "There are errors!";
// probably something more elaborate here, like
// outputting an ordered list to display each error
print_r($err);
}
else
{
echo "It's all good!";
}
?>

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