Assign and return select option dynamically? - php

Question

I have a form select which is generated based on results returned from a mysql query.
Q1) How do I assign a name identity (integer value) based on the teamID pull out of the database?
Q2) How could I then get the option selected and add it to a php variable which could then be used to update a table based on the users selection?
Below is the code I have so far for creating the dynamic drop down list, which get the results out of the database.
<?php
$data= mysql_query("SELECT * FROM teams
WHERE teamID NOT IN (
SELECT TeamID
FROM leagueInformation
WHERE leagueID = 1
)
") or die(mysql_query());
echo "<select name=\"team\" class=\"col-lg-12\" style=\"padding:10px; background:#e1e1e1;\">\n";
while($info = mysql_fetch_array( $data ))
{
$teamID = $info['teamID'];
echo "<option name=" . $team . " value=" . $teamID . ">" .$info['teamName'] . "</option>";
}
echo "</select>\n";
?>

Answer 1

Q1) How do I assign a name identity (integer value) based on the teamID pull out of the database?
This question is not so clear, but I think this is what you are trying to do?
<?php $data= mysql_query(
"SELECT * FROM teams WHERE teamID NOT IN (
SELECT TeamID
FROM leagueInformation
WHERE leagueID = 1)
") or die(mysql_query());
?>
<form name="teams_form" method="POST">
<select name="team" class="col-lg-12" style="...">
<?php while($info = mysql_fetch_array( $data )): ?>
<option value="<?php echo $info['teamID'] ?>">
<?php echo $info['teamName'] ?>
</option>
<?php endwhile; ?>
</select>
</form>
Q2) How could I then get the option selected and add it to a php variable which could then be used to update a table based on the users selection?
First you will need to wrap your select inside a form (like I did), then you can check the selected value like this:
if(isset($_POST['team']) && !empty['team']){
$selected_team = $_POST['team'];
mysql_query("Do what you want with the selected team");
}
Some notes about your code:
Avoid to use mysql_*, use mysqli_* or PDO, and always prevent SQL injections
<option> tags don't have name properties, and in this case $team is not defined
Embed PHP inside HTML, not HTML in PHP.

Answer 2

Your first question doesn't make sense to me yet, I'll update the answer when it does.
When the user submits the form, you can get the option selected using the $_GET or $_POST (depending your your form's method) variables.
Like this:
$teamId = $_POST['team'];

Answer 3

put everything in a <form/> with an action pointing to the page, and a method (get or post), then in the script get the variable by the <select/> name value reading $_GET or $_POST variables, and I quote the comment about the "name" in option as invalid attribute.