PHP Show results else nothing to display - php

Question

I have this script here that shows a list of results. How to do l say "No results" if no results are found. I believe it's the else statement but couldn't quiet get it to work.
<?php
$result = mysql_query("SELECT * FROM emailquotes order by id desc")
or die(mysql_error());
while($row = mysql_fetch_array( $result )) {
echo "<tr height='25px' valign='center'>";
echo '<td valign="middle"><p><img src="../../Images/Icons/table-delete.png"/></p></td>';
echo '<td><p>' . $row['ssp'] . '</p></td>';
echo '<td><p>' . $row['ssp'] . '#someonewhere.com</p></td>';
echo '<td><p>' . $row['surname'] . '</p></td>';
echo '<td><p>Car</p></td>';
echo '<td><p>Show Prices</p></td>';
echo "</tr>";
}
?>

Answer 1

You can try with mysql_num_rows function:
$count = mysql_num_rows($result);
if ($count > 0) {
// loop rows
} else {
// no result
}

Answer 2

Put your while loop in a if-statement and check if there is any results before running the loop. Then you echo "No results" in the else.

Answer 3

It should be like this:
<?php
$result = mysql_query("SELECT * FROM emailquotes order by id desc")
or die(mysql_error());
if( mysql_num_rows($result)) {
while($row = mysql_fetch_array( $result )) {
echo "<tr height='25px' valign='center'>";
echo '<td valign="middle"><p><a href="delete.php?id=' . $row['id'] . '"><img
src="../../Images/Icons/table-delete.png"/></a></p></td>';
echo '<td><p>' . $row['ssp'] . '</p></td>';
echo '<td><p>' . $row['ssp'] . '#someonewhere.com</p></td>';
echo '<td><p>' . $row['surname'] . '</p></td>';
echo '<td><p>Car</p></td>';
echo '<td><p>Show Prices</p></td>';
echo "</tr>";
}
}
else {
echo "No Result";
}
?>