How I can display all rows in php - php

Question

I wrote this code to retrieve some rows form database
session_start();
$con = mysqli_connect('localhost', 'root', '');
if(!$con)
{
die("not ok");
}
mysqli_select_db($con,"uoh");
$q = " SELECT * FROM student WHERE id = " . $_SESSION['user_id'] ." and password = " . $_SESSION['user_pass'];
$result = mysqli_query($con , $q ) ;
if($row = mysqli_fetch_array($result))
{
echo "this academic transcripts for " . $row["name"];
echo " and the id is " . $row["id"];
}
$q1 = " SELECT student_record.course,student_record.grade,student_record.term,coe_courses.crd
FROM student_record INNER JOIN coe_courses ON student_record.course_number = coe_courses.course_number
where student_record.id = ".$_SESSION['user_id'] ;
$result = mysqli_query($con , $q1 ) ;
if($row = mysqli_fetch_array($result))
{
echo "<br />";
echo "<table border=\"1\" style=\"width:500\">";
echo "<tr>";
echo "<th>coe_courses</th>";
echo "<th>terms</th>";
echo "<th>Grades</th>";
echo "<th>CRD</th>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row["course"]. "</td>";
echo "<td>" . $row["term"]. "</td>";
echo "<td>" . $row["grade"]. "</td>";
echo "<td>" . $row["crd"]. "</td>";
echo "</tr>";
echo "</table>";
}
The problem is that only shows the first row while I have three rows in phpMyAdmin.
enter image description here

Answer 1

You need to call fetch_* repeatedly to retrieve all rows from your result set; each time you call it it retrieves the next row in the result set.
In your sample code above, you would replace
if ($row = mysqli_fetch_array($result))
{
with
while ($row = mysqli_fetch_array($result))
{
This will loop until fetch_array tries to read beyond the last record in $result, at which point fetch_array returns false and the loop exits.