Is there a php function that counts the number of similar characters in a string?
I've looked at levenshtein, similar_text, and metaphone none seem to do this.
Example in/output would be:
Hello, Heil outputs 3 (h, e, l)
Use count_chars
Example
$data = "Two Ts and one F.";
foreach (count_chars($data, 1) as $i => $val) {
echo "There were $val instance(s) of \"" , chr($i) , "\" in the string.\n";
}
http://php.net/manual/en/function.count-chars.php
You can use str_split to convert the strings into arrays, then array_unique and array_intersect to get the common letters.
For example:
$str1 = "hello";
$str2 = "hola";
$chars1 = array_unique(str_split($str1));
$chars2 = array_unique(str_split($str2));
echo "Common characters: ".count(array_intersect($chars1, $chars2));
Related
I was wondering if there's a combo of functions or a direct function that can count how many numbers appears in a string, without use a long-way as str_split and check every character in a loop.
From a string like:
fdsji2092mds1039m
It returns that there's 8 numbers inside.
You can use filter_var() with the FILTER_SANITIZE_NUMBER_INT constant, then check the length of the new string. The new string will contain only numbers from that string, and all other characters are filtered away.
$string = "j3987snmj3j";
$numbers = filter_var($string , FILTER_SANITIZE_NUMBER_INT);
$length = strlen($numbers); // 5
echo "There are ".$length." numbers in that string";
Note that each number will be counted individually, so 137 would return 3, as would 1m3j7.
Live demo
Other solution:
function countNumbers(string $string) {
return preg_match_all('/\d/', $string, $m);
}
You can use regular expression
Try like this:
$myString = 'Som3 Charak1ers ar3 N0mberZ h3re ;)';
$countNumbers = strlen((string)filter_var($myString, FILTER_SANITIZE_NUMBER_INT));
echo 'Your input haz ' . $countNumbers . ' digits in it, man';
You can also make a function out of this to return only the number, if you need it.
Following code does what you intend to do:
<?php
$string = 'dsfds98fsdfsdf8sdf908f9dsf809fsd809f8s15d0d';
$splits=str_split($string);
$count=0;
foreach ($splits as $split){
if(is_numeric($split)){
$count++;
}
}
print_r($count);
Output: 17
I want to count the frequency of occurrences of all the letters in a string. Say I have
$str = "cdcdcdcdeeeef";
I can use str_split and array_count_values to achieve this.
array_count_values(str_split($str));
Wondering if there is another way to do this without converting the string to an array? Thanks
You don't have to convert that into an array() you can use substr_count() to achieve the same.
substr_count — Count the number of substring occurrences
<?php
$str = "cdcdcdcdeeeef";
echo substr_count($str, 'c');
?>
PHP Manual
substr_count() returns the number of times the needle substring occurs in the haystack string. Please note that needle is case sensitive.
EDIT:
Sorry for the misconception, you can use count_chars to have a counted value of each character in a string. An example:
<?php
$str = "cdcdcdcdeeeef";
foreach (count_chars($str, 1) as $strr => $value) {
echo chr($strr) . " occurred a number of $value times in the string." . "<br>";
}
?>
PHP Manual: count_chars
count_chars — Return information about characters used in a string
There is a php function that returns information about characters used in a string: count_chars
Well it might not be what you are looking for, because according to http://php.net/manual/en/function.count-chars.php it
Counts the number of occurrences of every byte-value (0..255) in
string and returns it in various ways
Example from same link (http://php.net/manual/en/function.count-chars.php):
<?php
$data = "Two Ts and one F.";
foreach (count_chars($data, 1) as $i => $val) {
echo "There were $val instance(s) of \"" , chr($i) , "\" in the string.\n";
}
?>
class Strings
{
public function count_of_each_letter($string){
$string_chars = array();
$length_ = mb_strlen($string,'UTF-8');
if($length_== 0){return null;}
else{
for ($i=0; $i < $length_; $i++) {
$each_letter = mb_substr($string,0,1,'UTF-8');
$string_chars[$each_letter] = mb_substr_count($string, $each_letter);
$string = str_replace($each_letter,"", $string);
$length_ = mb_strlen($string,'UTF-8');
}
$string = '';
foreach ($string_chars as $key => $value) {
$string .= $key.'-'.$value.'<br>';
}
return $string;
}
}
}
$new_counter = new Strings();
echo $new_counter::count_of_each_letter('ختواجرایآهنگبهصورتتکنفرهنمود.اوازسال۱۹۷۲تا۱۹۷۵،۴آلبوماستودیوییتک‌نفرهمنتشرکردوحتینامزدیکجایزهاسکارهمشد.درهمینسال‌هاگروهاقدامبهبرگزاریتورکنسرتدراروپاونیزیکتورجهانیکردند.جکسونفایودرسال۱۹۷۵ازشرکتنشرموسیقیموتاونرکوردزبهسی‌بی‌اسرکوردزنقلمکانکردند.گروههمچنانبهاجراهایبین‌المللیخودادامهمی‌دادواز۱۹۷۶تا۱۹۸۴(از۱۵تا۲۴سالگیمایکل)ششآلبوماستودیوییدیگرمنتشرکرد.درهمینمدت،مایکلترانه‌سرایاصلیگروهجکسونزبود.Cantional,oderGesangbuchAugsburgischerKonfessionin1627.ohannSebastianBachcomposedafour-partsetting,BWV285,whichiswithouttext.twaspublishedasNo.196inthecollectionofchoralesbyJohannPhilippKirnbergerundCarlPhilippEmanufread');
you can do it by following way as well:
$str = 'aabbbccccdddeeedfff';
$arr = str_split($str);
$result = array_count_values($arr);
$string = http_build_query($result,'','');
echo str_replace('=','',$string);
I have an array with strings like:
209#ext-local : SIP/209 State:Idle Watchers 2
208#ext-local : SIP/208 State:Unavailable Watchers 1
How can I echo the state for example Idle or Unavailable?
Thanks.
Using regex it will match any string containing letters and numbers.
$string = '209#ext-local : SIP/209 State:Idle Watchers 2';
preg_match("/State\:([A-Za-z0-9]+)/", $string, $results);
echo $results[1]; // Idle
strpos will search the string to see if it is contains the characters in that exact order.
strpos will not always work if the word idle or unavailable has the possibility to show up in any other way in the string.
You can use the php explode and parse the sting into an array of strings.
exp.
$string = "209#ext-local : SIP/209 State:Idle Watchers 2";
$string = explode(':', $string);
will give you ['209#ext-local ',' SIP/209 State','Idle Watchers 2']. Then if you explode the 3rd entry my ' ' you would get your answer.
$answer = explide(' ', $string[2]);
echo $answer[0];
Assuming your strings are all the same format, you can try splitting the string down using explode(), which returns an array of string, separated by a provided delimiter, like
foreach ($yourStrings as $s) {
$colonSplit = explode(":", $stringToSplit);
$nextStringToSplit = $colonSplit[2];
$spaceSplit = explode(" ", $nextStringToSplit);
$status = $spaceSplit[0];
echo $status;
}
May not be elegant but it should work.
Quick (and dirty) way. Assuming your array contains the full elements you listed above, the array element values do NOT contain 'idle' or 'unavailable' in any other capacity other than what you listed, and you just want to echo out the value and "is idle" or "is unavailable":
//$a being your array containing the values you listed above
foreach ($a as $status) {
if (strpos($status, "Idle") == true)
echo $status . " is idle";
elseif (strpos($status, "Unavailable") == true)
echo "$status" . " is unavailable";
}
Given two equal-length strings, is there an elegant way to get the offset of the first different character?
The obvious solution would be:
for ($offset = 0; $offset < $length; ++$offset) {
if ($str1[$offset] !== $str2[$offset]) {
return $offset;
}
}
But that doesn't look quite right, for such a simple task.
You can use a nice property of bitwise XOR (^) to achieve this: Basically, when you xor two strings together, the characters that are the same will become null bytes ("\0"). So if we xor the two strings, we just need to find the position of the first non-null byte using strspn:
$position = strspn($string1 ^ $string2, "\0");
That's all there is to it. So let's look at an example:
$string1 = 'foobarbaz';
$string2 = 'foobarbiz';
$pos = strspn($string1 ^ $string2, "\0");
printf(
'First difference at position %d: "%s" vs "%s"',
$pos, $string1[$pos], $string2[$pos]
);
That will output:
First difference at position 7: "a" vs "i"
So that should do it. It's very efficient since it's only using C functions, and requires only a single copy of memory of the string.
Edit: A MultiByte Solution Along The Same Lines:
function getCharacterOffsetOfDifference($str1, $str2, $encoding = 'UTF-8') {
return mb_strlen(
mb_strcut(
$str1,
0, strspn($str1 ^ $str2, "\0"),
$encoding
),
$encoding
);
}
First the difference at the byte level is found using the above method and then the offset is mapped to the character level. This is done using the mb_strcut function, which is basically substr but honoring multibyte character boundaries.
var_dump(getCharacterOffsetOfDifference('foo', 'foa')); // 2
var_dump(getCharacterOffsetOfDifference('©oo', 'foa')); // 0
var_dump(getCharacterOffsetOfDifference('f©o', 'fªa')); // 1
It's not as elegant as the first solution, but it's still a one-liner (and if you use the default encoding a little bit simpler):
return mb_strlen(mb_strcut($str1, 0, strspn($str1 ^ $str2, "\0")));
If you convert a string to an array of single character one byte values you can use the array comparison functions to compare the strings.
You can achieve a similar result to the XOR method with the following.
$string1 = 'foobarbaz';
$string2 = 'foobarbiz';
$array1 = str_split($string1);
$array2 = str_split($string2);
$result = array_diff_assoc($array1, $array2);
$num_diff = count($result);
$first_diff = key($result);
echo "There are " . $num_diff . " differences between the two strings. <br />";
echo "The first difference between the strings is at position " . $first_diff . ". (Zero Index) '$string1[$first_diff]' vs '$string2[$first_diff]'.";
Edit: Multibyte Solution
$string1 = 'foorbarbaz';
$string2 = 'foobarbiz';
$array1 = preg_split('((.))u', $string1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
$array2 = preg_split('((.))u', $string2, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
$result = array_diff_assoc($array1, $array2);
$num_diff = count($result);
$first_diff = key($result);
echo "There are " . $num_diff . " differences between the two strings.\n";
echo "The first difference between the strings is at position " . $first_diff . ". (Zero Index) '$string1[$first_diff]' vs '$string2[$first_diff]'.\n";
I wanted to add this as as comment to the best answer, but I do not have enough points.
$string1 = 'foobarbaz';
$string2 = 'foobarbiz';
$pos = strspn($string1 ^ $string2, "\0");
if ($pos < min(strlen($string1), strlen($string2)){
printf(
'First difference at position %d: "%s" vs "%s"',
$pos, $string1[$pos], $string2[$pos]
);
} else if ($pos < strlen($string1)) {
print 'String1 continues with' . substr($string1, $pos);
} else if ($pos < strlen($string2)) {
print 'String2 continues with' . substr($string2, $pos);
} else {
print 'String1 and String2 are equal';
}
string strpbrk ( string $haystack , string $char_list )
strpbrk() searches the haystack string for a char_list.
The return value is the substring of $haystack which begins at the first matched character.
As an API function it should be zippy. Then loop through once, looking for offset zero of the returned string to obtain your offset.
I have written the PHP code for getting some part of a given dynamic sentence, e.g. "this is a test sentence":
substr($sentence,0,12);
I get the output:
this is a te
But i need it stop as a full word instead of splitting a word:
this is a
How can I do that, remembering that $sentence isn't a fixed string (it could be anything)?
use wordwrap
If you're using PHP4, you can simply use split:
$resultArray = split($sentence, " ");
Every element of the array will be one word. Be careful with punctuation though.
explode would be the recommended method in PHP5:
$resultArray = explode(" ", $sentence);
first. use explode on space. Then, count each part + the total assembled string and if it doesn't go over the limit you concat it onto the string with a space.
Try using explode() function.
In your case:
$expl = explode(" ",$sentence);
You'll get your sentence in an array. First word will be $expl[0], second - $expl[1] and so on. To print it out on the screen use:
$n = 10 //words to print
for ($i=0;$i<=$n;$i++) {
print $expl[$i]." ";
}
Create a function that you can re-use at any time. This will look for the last space if the given string's length is greater than the amount of characters you want to trim.
function niceTrim($str, $trimLen) {
$strLen = strlen($str);
if ($strLen > $trimLen) {
$trimStr = substr($str, 0, $trimLen);
return substr($trimStr, 0, strrpos($trimStr, ' '));
}
return $str;
}
$sentence = "this is a test sentence";
echo niceTrim($sentence, 12);
This will print
this is a
as required.
Hope this is the solution you are looking for!
this is just psudo code not php,
char[] sentence="your_sentence";
string new_constructed_sentence="";
string word="";
for(i=0;i<your_limit;i++){
character=sentence[i];
if(character==' ') {new_constructed_sentence+=word;word="";continue}
word+=character;
}
new_constructed_sentence is what you want!!!