while executing the below query i'm not getting sucess value
$name=qwe;
$result = mysql_query("SELECT *FROM USER WHERE name = $name");
Instead of above query if i put the below, I can able to get the appropriate ans:
$result = mysql_query("SELECT *FROM USER WHERE name = 'qwe'");
Can anyone give a solution for my first query??
Close the variable in quote and concatenate the string into query
$name= "qwe";
$result = mysql_query("SELECT *FROM USER WHERE name = '".$name."'");
one more note
please use mysqli for security purposes. Thanks
Use the following:
$result = mysql_query("SELECT *FROM USER WHERE name = '".$name."'");
P.S. I have not tested the above code but it should work.
select * from table_name where col_name = '".$variable."'
Directly use :
$name = 'qwe';
$result = mysql_query("SELECT * FROM USER WHERE name = '$name'");
And on more advise, you should never use mysql_* functions now as they have been deprecated in newer versions of PHP and will produce the notices.
I'm trying to get data from a table column that has a corresponding ID, but when I try to get an ID it gives me a 'resource ID'. My column ID holds INTs, and I found that if I add or subtract to the resource ID i get a number so I tried adding then subtracting 1, but it still isn't working.
<?php
mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("blog") or die(mysql_error());
$strSQL = "SELECT id FROM blogtable ORDER BY id DESC";
$rs = mysql_query($strSQL);
$artID = $rs-1+1;//So if I don't do this, I get resource ID#'#'
?>
This code is on the same page, but in a separate container.
<?php
$getArticle = "SELECT title FROM blogtable Where id = '$artID'";
$selectedArticle = mysql_query($getArticle);
echo $selectedArticle;
?>
I was hoping this would get me the text from my title column, but it just gives me another resource id.
You can use
$result = mysql_fetch_object($rs);
$artID = $result->id;
...
$selectedArticle = mysql_query($getArticle);
$res = mysql_fetch_object($selectedArticle);
echo $res->title;
But i will recommende using PDO or mysqli functions since mysql_ functions will become obsolete.
mysqli examples: http://www.w3schools.com/php/php_ref_mysqli.asp
or
PDO tutorials: http://wiki.hashphp.org/PDO_Tutorial_for_MySQL_Developers
mysql_query gives you resource id. If you want to get your ID;
$id = 0;
while ($row = mysql_fetch_assoc($rs)) {
$id = $row['ID'];
}
Or
$row = mysql_fetch_array($rs);
and get id from $row array
I'm trying to display a field from my MySQL database. It's in the table tblproducts in the row with the id is set to 1. And under the column qty.
This is the code I'm using:
<?php
mysql_connect("localhost","username","password");
mysql_select_db("database_name");
$available = "SELECT qty FROM tblproducts WHERE id = 1";
$result = mysql_query($available);
echo $result;
?>
However, I keep getting this message: Resource id #2
I've done a bit of research and seen where other people are having similar problems but most of them are trying to display their data in an HTML table whereas I just need the data from 'qty' to display. And of course I'm definitely not a MySQL guru.
Can anyone help me out with this please?
Try changing this:
$result = mysql_query($available);
To this:
$result = mysql_result(mysql_query($available), 0);
Let's start from the start. (I'll assume you have the connection set)
Form the query
$query = "SELECT `qty`
FROM `tblproducts`
WHERE `id` = 1";
Execute the query
$run = mysql_query($query);
Now, put the result in an assoc array
$r = mysql_fetch_array($run);
See the contents of the array
echo $r['qty'];
It's also advised that you move up from mysql to either mysqli, or PDO. PDO is preferred as you're not bound to the MySQL database model.
Try this:
Here you need to generate associative array and then get the resulting row.
$query = "SELECT `qty` FROM `tblproducts` WHERE `id` = 1";
$run = mysql_query($query);
$r = mysql_fetch_array($run);
echo $r['qty'];
-
Thanks
For example, for some queries like SELECT MAX(field), the query result is usually only a field value, rather than returning rows to you.
Now the field of the value I wanna get is integer type.
As I'm a beginner of php, how can I get that value from the query result?
As I do the following
$query = "SELECT MAX(stringid) FROM XMLString";
$result = mysql_query($query, $link);
echo $result;
Then nothing is echoed out.
I have check the db connection made by mysqlconnect, and it's got no problem.
And I tried this query in MySQL at phpMyAdmin, then the query is what I want, too?
So why would it be like that, and any solution?
Thanks!
You will always retrieve rows back from an SQL query, even if there's only one row with one field. You can directly retrieve a specific field of a specific row using mysql_result:
$query = "SELECT MAX(stringid) FROM XMLString";
$result = mysql_query($query, $link);
echo mysql_result($result, 0, 0);
$query = "SELECT MAX(stringid) as val FROM XMLString";
$result = mysql_query($query, $link);
$rows = mysql_num_rows($result);
if($rows > 0) {
$rstAry = mysql_fetch_array($result);
echo $rstAry['val'];
}
Try This
mysql_query is not printing results. Maybe try this:
echo mysql_result($result);
You are not getting any result because mysql_query returns a database object.
You will need to process this "database object" using mysql_fetch_array. This command 'fetches' an array out of a MySQL "database object". The array you are fetching is the rows your query produced. In your case, it is just one row.
Here is the code:
This step sets your query:
$query = "SELECT MAX(stringid) as val FROM XMLString";
This step will run your query, and return the database object:
$result_database_object_whatever = mysql_query($query, $link);
This step will process the database object, and give you an array of the queried rows:
$result_array = mysql_fetch_array($query, $link);
This step will echo the first row returned by your query:
echo $result_array[1];
You can do something like this:
$query = "SELECT MAX(stringid) FROM XMLString";
$result = mysql_query($query, $link);
$fetch = mysql_fetch_assoc($result);
echo $fetch['stringid'];
The mysql_fetch_assoc() function retrieves the data in an associative array.
Would it help to give the max a name you could reference? Also ifyou think there's syntax errors you could just add the error to help clarify.
$query = "SELECT MAX(stringid) as maxNum FROM XMLString";
$result = mysql_query($query, $link) or die(mysql_error());
echo $result;
What's the best way with PHP to read a single record from a MySQL database? E.g.:
SELECT id FROM games
I was trying to find an answer in the old questions, but had no luck.
This post is marked obsolete because the content is out of date. It is not currently accepting new interactions.
$id = mysql_result(mysql_query("SELECT id FROM games LIMIT 1"),0);
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database_name', $link);
$sql = 'SELECT id FROM games LIMIT 1';
$result = mysql_query($sql, $link) or die(mysql_error());
$row = mysql_fetch_assoc($result);
print_r($row);
There were few things missing in ChrisAD answer. After connecting to mysql it's crucial to select database and also die() statement allows you to see errors if they occur.
Be carefull it works only if you have 1 record in the database, because otherwise you need to add WHERE id=xx or something similar to get only one row and not more. Also you can access your id like $row['id']
Using PDO you could do something like this:
$db = new PDO('mysql:host=hostname;dbname=dbname', 'username', 'password');
$stmt = $db->query('select id from games where ...');
$id = $stmt->fetchColumn(0);
if ($id !== false) {
echo $id;
}
You obviously should also check whether PDO::query() executes the query OK (either by checking the result or telling PDO to throw exceptions instead)
Assuming you are using an auto-incrementing primary key, which is the normal way to do things, then you can access the key value of the last row you put into the database with:
$userID = mysqli_insert_id($link);
otherwise, you'll have to know more specifics about the row you are trying to find, such as email address. Without knowing your table structure, we can't be more specific.
Either way, to limit your SELECT query, use a WHERE statement like this:
(Generic Example)
$getID = mysqli_fetch_assoc(mysqli_query($link, "SELECT userID FROM users WHERE something = 'unique'"));
$userID = $getID['userID'];
(Specific example)
Or a more specific example:
$getID = mysqli_fetch_assoc(mysqli_query($link, "SELECT userID FROM users WHERE userID = 1"));
$userID = $getID['userID'];
Warning! Your SQL isn't a good idea, because it will select all rows (no WHERE clause assumes "WHERE 1"!) and clog your application if you have a large number of rows. (What's the point of selecting 1,000 rows when 1 will do?) So instead, when selecting only one row, make sure you specify the LIMIT clause:
$sql = "SELECT id FROM games LIMIT 1"; // Select ONLY one, instead of all
$result = $db->query($sql);
$row = $result->fetch_assoc();
echo 'Game ID: '.$row['id'];
This difference requires MySQL to select only the first matching record, so ordering the table is important or you ought to use a WHERE clause. However, it's a whole lot less memory and time to find that one record, than to get every record and output row number one.
One more answer for object oriented style. Found this solution for me:
$id = $dbh->query("SELECT id FROM mytable WHERE mycolumn = 'foo'")->fetch_object()->id;
gives back just one id. Verify that your design ensures you got the right one.
First you connect to your database. Then you build the query string. Then you launch the query and store the result, and finally you fetch what rows you want from the result by using one of the fetch methods.
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database',$link);
$sql = 'SELECT id FROM games'
$result = mysql_query($sql,$link);
$singleRow = mysql_fetch_array($result)
echo $singleRow;
Edit: So sorry, forgot the database connection. Added it now
'Best way' aside some usual ways of retrieving a single record from the database with PHP go like that:
with mysqli
$sql = "SELECT id, name, producer FROM games WHERE user_id = 1";
$result = $db->query($sql);
$row = $result->fetch_row();
with Zend Framework
//Inside the table class
$select = $this->select()->where('user_id = ?', 1);
$row = $this->fetchRow($select);
The easiest way is to use mysql_result.
I copied some of the code below from other answers to save time.
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database',$link);
$sql = 'SELECT id FROM games'
$result = mysql_query($sql,$link);
$num_rows = mysql_num_rows($result);
// i is the row number and will be 0 through $num_rows-1
for ($i = 0; $i < $num_rows; $i++) {
$value = mysql_result($result, i, 'id');
echo 'Row ', i, ': ', $value, "\n";
}
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$db = new mysqli('localhost', 'tmp', 'tmp', 'your_db');
$db->set_charset('utf8mb4');
if($row = $db->query("SELECT id FROM games LIMIT 1")->fetch_row()) { //NULL or array
$id = $row[0];
}
I agree that mysql_result is the easy way to retrieve contents of one cell from a MySQL result set. Tiny code:
$r = mysql_query('SELECT id FROM table') or die(mysql_error());
if (mysql_num_rows($r) > 0) {
echo mysql_result($r); // will output first ID
echo mysql_result($r, 1); // will ouput second ID
}
Easy way to Fetch Single Record from MySQL Database by using PHP List
The SQL Query is SELECT user_name from user_table WHERE user_id = 6
The PHP Code for the above Query is
$sql_select = "";
$sql_select .= "SELECT ";
$sql_select .= " user_name ";
$sql_select .= "FROM user_table ";
$sql_select .= "WHERE user_id = 6" ;
$rs_id = mysql_query($sql_select, $link) or die(mysql_error());
list($userName) = mysql_fetch_row($rs_id);
Note: The List Concept should be applicable for Single Row Fetching not for Multiple Rows
Better if SQL will be optimized with addion of LIMIT 1 in the end:
$query = "select id from games LIMIT 1";
SO ANSWER IS (works on php 5.6.3):
If you want to get first item of first row(even if it is not ID column):
queryExec($query) -> fetch_array()[0];
If you want to get first row(single item from DB)
queryExec($query) -> fetch_assoc();
If you want to some exact column from first row
queryExec($query) -> fetch_assoc()['columnName'];
or need to fix query and use first written way :)