I'm trying to get data from a table column that has a corresponding ID, but when I try to get an ID it gives me a 'resource ID'. My column ID holds INTs, and I found that if I add or subtract to the resource ID i get a number so I tried adding then subtracting 1, but it still isn't working.
<?php
mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("blog") or die(mysql_error());
$strSQL = "SELECT id FROM blogtable ORDER BY id DESC";
$rs = mysql_query($strSQL);
$artID = $rs-1+1;//So if I don't do this, I get resource ID#'#'
?>
This code is on the same page, but in a separate container.
<?php
$getArticle = "SELECT title FROM blogtable Where id = '$artID'";
$selectedArticle = mysql_query($getArticle);
echo $selectedArticle;
?>
I was hoping this would get me the text from my title column, but it just gives me another resource id.
You can use
$result = mysql_fetch_object($rs);
$artID = $result->id;
...
$selectedArticle = mysql_query($getArticle);
$res = mysql_fetch_object($selectedArticle);
echo $res->title;
But i will recommende using PDO or mysqli functions since mysql_ functions will become obsolete.
mysqli examples: http://www.w3schools.com/php/php_ref_mysqli.asp
or
PDO tutorials: http://wiki.hashphp.org/PDO_Tutorial_for_MySQL_Developers
mysql_query gives you resource id. If you want to get your ID;
$id = 0;
while ($row = mysql_fetch_assoc($rs)) {
$id = $row['ID'];
}
Or
$row = mysql_fetch_array($rs);
and get id from $row array
Related
Right now I am selecting some data from Mysql which I want to echo out, but I don't know how..
Code
<?php
// Database connection
require_once($_SERVER["DOCUMENT_ROOT"] . "/includes/config.php");
require_once($_SERVER["DOCUMENT_ROOT"] . "/includes/opendb.php");
// News 1
$searchroutenews1 = "SELECT newsid FROM NewsHomepage WHERE id = '1'";
$handlenews1 = mysqli_query($GLOBALS["___mysqli_ston"], $searchroutenews1);
$news1 = mysqli_fetch_row($handlenews1);
$searchroutenewsimg1 = "SELECT newsimg FROM NewsHomepage WHERE id = '1'";
$handlenewsimg1 = mysqli_query($GLOBALS["___mysqli_ston"], $searchroutenewsimg1);
$NewsImg1 = mysqli_fetch_row($handlenewsimg1);
// News 2
$searchroutenews2 = "SELECT newsid FROM NewsHomepage WHERE id = '2'";
$handlenews2 = mysqli_query($GLOBALS["___mysqli_ston"], $searchroutenews2);
$news2 = mysqli_fetch_row($handlenews2);
$searchroutenewsimg2 = "SELECT newsimg FROM NewsHomepage WHERE id = '2'";
$handlenewsimg2 = mysqli_query($GLOBALS["___mysqli_ston"], $searchroutenewsimg2);
$NewsImg2 = mysqli_fetch_row($handlenewsimg2);
// News 3
$searchroutenews3 = "SELECT newsid FROM NewsHomepage WHERE id = '3'";
$handlenews3 = mysqli_query($GLOBALS["___mysqli_ston"], $searchroutenews3);
$news3 = mysqli_fetch_row($handlenews3);
$searchroutenewsimg3 = "SELECT newsimg FROM NewsHomepage WHERE id = '3'";
$handlenewsimg3 = mysqli_query($GLOBALS["___mysqli_ston"], $searchroutenewsimg3);
$NewsImg3 = mysqli_fetch_row($handlenewsimg3);
?>
After this I require_once this in an other file, and then I echo the variables $news1, $news2, $news3, $NewsImg1, $NewsImg2 and $NewsImg3. But if I echo this variables out now it says: array.
You can fetch all this information via a single query, instead of the 6 you currently are running. Then it's a matter of putting mysqli_fetch_*() as the argument of a while, as you'll then fetch all the rows, until that function returns null - at which point you've fetched all the rows returned by the query.
$result = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT newsid, newsimg FROM NewsHomepage WHERE id IN (1, 2, 3)");
while ($row = mysqli_fetch_assoc($result)) {
echo $row['newsid']." ".$row['newsimg'];
}
Change however you need it to be displayed inside the while loop, and use the two variables as they are inside.
Alternatively, you can use WHERE id BETWEEN 1 AND 3 instead, but using IN (1, 2, 3) can more easily be changed to the exact ids you need.
http://php.net/mysqli-result.fetch-assoc
First you should read http://php.net/manual/en/mysqli-result.fetch-row.php
you can find there mysqli_result::fetch_row -- mysqli_fetch_row — Get a result row as an enumerated array mysqli_fetch_row always return array so now you can't echo array thats why it gives you array.
You can try foreach loop or for loop or while loop to display your data. there are also various methods to get array value.
Below is an example you can use.
while ($news1 = mysqli_fetch_row($handlenews1)) {
echo $news1[0];
}
I am trying to retrieve the last ID from the database and increment it by one. My problem is that I am not able to retrieve it in a particular category. For instance, I have categories with a string value of A, B and C. The category with a string value of A will return only id starting from 1 as 10001, 10002 and the last ID to be retrieved is 10002 plus 1 so that the ID to be displayed is 10003.
Category "B" will return 20002 and category "C" will return 30002.
Here is my code:
<?php
$con = mysql_connect("server","username","password","db_name") or die (mysql_error());
mysql_select_db($con, 'db_name');
$sql = "Select `id` from `tbl_violation` WHERE `category` = 'A' ORDER BY `category` DESC LIMIT 1";
$result = mysql_query ($sql,$con);
while($row = mysql_fetch_array($result, $con))
{
$i = $row['id'];
$i++;
echo "DLR - " .$i;
}
?>
The error is this:
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in ...
Notice: Undefined variable: i in ...
First I must say again... Stay away from mysql_connect() and all other mysql_* functions. If you want a simple fix, just replace it with mysqli_ functions and make sure you escape ALL user provided input. A bit of reading But I would recommend to look into PDO.
That out of the way, your MYSQL problem is easy. You want to GROUP the elements so all the rows with same category column are groupped together and then select the maximum for each group. Your SQL would then be:
SELECT category, MAX(id) AS highest_id FROM tbl_violation GROUP BY category;
see this fiddle I made with a similar table.
You can then access the results you get from mysqli_query function the same way you do now...
while($row = mysqli_fetch_array($result, $con))
{
$i = $row['highest_id'];
$i++;
$category = $row['category'];
echo "$category - $i";
}
You can use SELECT MAX to get the highest id. I am assuming that id is not unique. If so, remove the WHERE statement from the query. Try the following.
<?php
$con = mysql_connect("server","username","password","db_name") or die (mysql_error());
mysql_select_db("database");
$sql = "Select MAX(`id`) from `tbl_violation` WHERE `category` = 'A";
$result = mysql_query ($sql,$con);
while($row = mysql_fetch_array($result))
{
$i = $row['id'];
echo "DLR - " .$i++;
}
?>
Also I would like to add that I agree with flynorc. Use PDO or mysqli.
Use
ORDER BY `id` DESC
Instead of
ORDER BY `category` DESC
I'm trying to display a field from my MySQL database. It's in the table tblproducts in the row with the id is set to 1. And under the column qty.
This is the code I'm using:
<?php
mysql_connect("localhost","username","password");
mysql_select_db("database_name");
$available = "SELECT qty FROM tblproducts WHERE id = 1";
$result = mysql_query($available);
echo $result;
?>
However, I keep getting this message: Resource id #2
I've done a bit of research and seen where other people are having similar problems but most of them are trying to display their data in an HTML table whereas I just need the data from 'qty' to display. And of course I'm definitely not a MySQL guru.
Can anyone help me out with this please?
Try changing this:
$result = mysql_query($available);
To this:
$result = mysql_result(mysql_query($available), 0);
Let's start from the start. (I'll assume you have the connection set)
Form the query
$query = "SELECT `qty`
FROM `tblproducts`
WHERE `id` = 1";
Execute the query
$run = mysql_query($query);
Now, put the result in an assoc array
$r = mysql_fetch_array($run);
See the contents of the array
echo $r['qty'];
It's also advised that you move up from mysql to either mysqli, or PDO. PDO is preferred as you're not bound to the MySQL database model.
Try this:
Here you need to generate associative array and then get the resulting row.
$query = "SELECT `qty` FROM `tblproducts` WHERE `id` = 1";
$run = mysql_query($query);
$r = mysql_fetch_array($run);
echo $r['qty'];
-
Thanks
What's the best way with PHP to read a single record from a MySQL database? E.g.:
SELECT id FROM games
I was trying to find an answer in the old questions, but had no luck.
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$id = mysql_result(mysql_query("SELECT id FROM games LIMIT 1"),0);
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database_name', $link);
$sql = 'SELECT id FROM games LIMIT 1';
$result = mysql_query($sql, $link) or die(mysql_error());
$row = mysql_fetch_assoc($result);
print_r($row);
There were few things missing in ChrisAD answer. After connecting to mysql it's crucial to select database and also die() statement allows you to see errors if they occur.
Be carefull it works only if you have 1 record in the database, because otherwise you need to add WHERE id=xx or something similar to get only one row and not more. Also you can access your id like $row['id']
Using PDO you could do something like this:
$db = new PDO('mysql:host=hostname;dbname=dbname', 'username', 'password');
$stmt = $db->query('select id from games where ...');
$id = $stmt->fetchColumn(0);
if ($id !== false) {
echo $id;
}
You obviously should also check whether PDO::query() executes the query OK (either by checking the result or telling PDO to throw exceptions instead)
Assuming you are using an auto-incrementing primary key, which is the normal way to do things, then you can access the key value of the last row you put into the database with:
$userID = mysqli_insert_id($link);
otherwise, you'll have to know more specifics about the row you are trying to find, such as email address. Without knowing your table structure, we can't be more specific.
Either way, to limit your SELECT query, use a WHERE statement like this:
(Generic Example)
$getID = mysqli_fetch_assoc(mysqli_query($link, "SELECT userID FROM users WHERE something = 'unique'"));
$userID = $getID['userID'];
(Specific example)
Or a more specific example:
$getID = mysqli_fetch_assoc(mysqli_query($link, "SELECT userID FROM users WHERE userID = 1"));
$userID = $getID['userID'];
Warning! Your SQL isn't a good idea, because it will select all rows (no WHERE clause assumes "WHERE 1"!) and clog your application if you have a large number of rows. (What's the point of selecting 1,000 rows when 1 will do?) So instead, when selecting only one row, make sure you specify the LIMIT clause:
$sql = "SELECT id FROM games LIMIT 1"; // Select ONLY one, instead of all
$result = $db->query($sql);
$row = $result->fetch_assoc();
echo 'Game ID: '.$row['id'];
This difference requires MySQL to select only the first matching record, so ordering the table is important or you ought to use a WHERE clause. However, it's a whole lot less memory and time to find that one record, than to get every record and output row number one.
One more answer for object oriented style. Found this solution for me:
$id = $dbh->query("SELECT id FROM mytable WHERE mycolumn = 'foo'")->fetch_object()->id;
gives back just one id. Verify that your design ensures you got the right one.
First you connect to your database. Then you build the query string. Then you launch the query and store the result, and finally you fetch what rows you want from the result by using one of the fetch methods.
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database',$link);
$sql = 'SELECT id FROM games'
$result = mysql_query($sql,$link);
$singleRow = mysql_fetch_array($result)
echo $singleRow;
Edit: So sorry, forgot the database connection. Added it now
'Best way' aside some usual ways of retrieving a single record from the database with PHP go like that:
with mysqli
$sql = "SELECT id, name, producer FROM games WHERE user_id = 1";
$result = $db->query($sql);
$row = $result->fetch_row();
with Zend Framework
//Inside the table class
$select = $this->select()->where('user_id = ?', 1);
$row = $this->fetchRow($select);
The easiest way is to use mysql_result.
I copied some of the code below from other answers to save time.
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database',$link);
$sql = 'SELECT id FROM games'
$result = mysql_query($sql,$link);
$num_rows = mysql_num_rows($result);
// i is the row number and will be 0 through $num_rows-1
for ($i = 0; $i < $num_rows; $i++) {
$value = mysql_result($result, i, 'id');
echo 'Row ', i, ': ', $value, "\n";
}
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$db = new mysqli('localhost', 'tmp', 'tmp', 'your_db');
$db->set_charset('utf8mb4');
if($row = $db->query("SELECT id FROM games LIMIT 1")->fetch_row()) { //NULL or array
$id = $row[0];
}
I agree that mysql_result is the easy way to retrieve contents of one cell from a MySQL result set. Tiny code:
$r = mysql_query('SELECT id FROM table') or die(mysql_error());
if (mysql_num_rows($r) > 0) {
echo mysql_result($r); // will output first ID
echo mysql_result($r, 1); // will ouput second ID
}
Easy way to Fetch Single Record from MySQL Database by using PHP List
The SQL Query is SELECT user_name from user_table WHERE user_id = 6
The PHP Code for the above Query is
$sql_select = "";
$sql_select .= "SELECT ";
$sql_select .= " user_name ";
$sql_select .= "FROM user_table ";
$sql_select .= "WHERE user_id = 6" ;
$rs_id = mysql_query($sql_select, $link) or die(mysql_error());
list($userName) = mysql_fetch_row($rs_id);
Note: The List Concept should be applicable for Single Row Fetching not for Multiple Rows
Better if SQL will be optimized with addion of LIMIT 1 in the end:
$query = "select id from games LIMIT 1";
SO ANSWER IS (works on php 5.6.3):
If you want to get first item of first row(even if it is not ID column):
queryExec($query) -> fetch_array()[0];
If you want to get first row(single item from DB)
queryExec($query) -> fetch_assoc();
If you want to some exact column from first row
queryExec($query) -> fetch_assoc()['columnName'];
or need to fix query and use first written way :)
I want to get the number of rows in my MySQL table and store that number in a php variable. This is the code I'm using:
$size = #mysql_query("SELECT COUNT(*) FROM News");
$size ends up being "Resource ID #7." How do I put the number of rows directly into $size?
mysql_query returns a query resource id. In order to get values from it you need to use mysql_fetch_assoc on the resource id to fetch a row into an array.
$result = mysql_query("SELECT COUNT(*) FROM News");
$row = mysql_fetch_assoc($result);
$size = $row['COUNT(*)'];
You need to call mysql_fetch_row or one of its sister functions.
<?php
// untested
$result = #mysql_query("SELECT COUNT(*) FROM News");
// error handling
$row = mysql_fetch_row($result);
$count = $row[0];
?>
try the following:
$size = #mysql_query("SELECT COUNT(*) AS `total` FROM News");
$query = mysql_fetch_array($size);
echo $query['total'];
On a related note you can use the mysql_num_rows() function to obtain the number of rows from a given query. This is handy if you need to grab the data but also know the number of rows.
<?php
$result = #mysql_query("SELECT * FROM news");
$count = #mysql_num_rows($result);
?>