PHP select arrays based on value in a multidimensional array - php

I have an array with the below structure and I need to select the greatest education level from the sub arrays that have selected=>1, the greater the [key] the greater the education level.
anyway to do this with PHP built in array functions?
Array
(
[0] => Array
(
[key] => 0
[selected] => 1
[value] => Highschool diploma
)
[1] => Array
(
[key] => 1
[selected] => 0
[value] => Vocational training
)
[2] => Array
(
[key] => 2
[selected] => 0
[value] => College degree (Outside Quebec)
)
[3] => Array
(
[key] => 3
[selected] => 1
[value] => College degree (Quebec)
)
[4] => Array
(
[key] => 4
[selected] => 1
[value] => Baccalaureate
)
[5] => Array
(
[key] => 5
[selected] => 0
[value] => Masters degree
)
[6] => Array
(
[key] => 6
[selected] => 0
[value] => Doctorate
)
)

PHP >= 5.5.0
To get all the selected keys:
$keys = array_filter(array_column($array, 'selected'));
// or if there can be values other than 0 and 1
$keys = array_keys(array_column($array, 'selected'), '1');
To get the key with the highest value:
$max = max(array_filter(array_column($array, 'selected')));
// or if there can be values other than 0 and 1
$max = max(array_keys(array_column($array, 'selected'), '1'));

array_walk($data, function($el) use(&$ret) {
// or if (empty($ret) ...
if (!isset($ret) || ($el['selected'] >= 1 && $ret['key'] < $el['key']))
$ret = $el;
});
var_dump($ret);
Just do not forget to unset or set $ret = false; //null, etc..
if you want to run this code multiple times :)

If you want to use php built-ins, array_reduce is probably the way to go. Something like this should do the trick:
$result = array_reduce($theArray, function($state, $item) {
if($item['selected'] !== 1) return $state;
if($state === null) return $item;
if($item['key'] > $state['key']) return $item;
return $state;
});
echo $result['value'];
update: I should note that the above only works in PHP 5.3 or later, because it uses anonymous functions, which weren't available in earlier versions of PHP. If you're working with an earlier version, you really should upgrade. But if you can't upgrade, then you'll have to define the function part as a normal stand-alone function, and then pass the name of your function (as a string) in the second argument to array_reduce. This approach is shown in the examples on the doc page for array_reduce.

Sure. Loop through each inner array, and check their values against the one that is currently top. For example: https://eval.in/private/5c5a2ba8015119
$final = array();
foreach($array as $education) {
if($education['selected'] != 1) {
continue;
}
if(isset($final['key']) == FALSE
OR $education['key'] > $final['key']) {
$final = $education;
}
}
echo print_r($final, true);

I've build a test function for you.
Tested and working! Cheers to Baccalaureate!
<?php
// Demo Data
$your_array = array(
array(
'key'=>0,
'selected'=>1,
'value'=>'Highschool diploma'
),
array(
'key'=>1,
'selected'=>0,
'value'=>'Vocational training'
),
array(
'key'=>2,
'selected'=>0,
'value'=>'College degree (Outside Quebec)'
),
array(
'key'=>3,
'selected'=>1,
'value'=>'College degree (Quebec)'
),
array(
'key'=>4,
'selected'=>1,
'value'=>'Baccalaureate'
),
array(
'key'=>5,
'selected'=>0,
'value'=>'Masters degree'
),
array(
'key'=>6,
'selected'=>0,
'value'=>'Doctorate'
)
);
// Actual function
$array_count = (count($your_array)-1);
$highest_education = 'Nothing found.';
for($i=$array_count;$i>0;$i--)
{
if($your_array[$i]['selected']==1)
{
$highest_education = $your_array[$i]['value'];
break;
}
}
// Testing output
echo $highest_education;
?>

Related

Average result of multidimensional array in PHP

This is a question for all the array specialists out there. I have an multi dimension array with a result as number (can be 0,1 or 2) and need the average for each grouped by parent.
In the example below the calculation would be:
subentry1_sub1 = 2 + 2 = 4 (4/2=2)
subentry1_sub2 = 1 + 1 = 2 (2/2=1)
So what I try to archive in PHP is the following result:
subentry1_sub1 average = 2
subentry1_sub2 average = 1
...
I already tried some solutions from similar questions. But with all the recursive functions I didn't managed to get it aggregated by the last child name (e.g. subentry1_sub1).
Any ideas?
EDIT:
subentry1_sub1 is 2 + 2 because its two times in the array
[entry1] => [subentry1] => [subentry1_sub1] => result
[entry2] => [subentry1] => [subentry1_sub1] => result
Array
(
[entry1] => Array
(
[subentry1] => Array
(
[subentry1_sub1] => Array
(
[value] => abc
[result] => 2
)
[subentry1_sub2] => Array
(
[value] => abc
[result] => 1
)
)
[subentry2] => Array
(
[subentry2_sub1] => Array
(
[value] => abc
[result] => 1
)
[subentry2_sub2] => Array
(
[value] => abc
[result] => 1
)
)
)
[entry2] => Array
(
[subentry1] => Array
(
[subentry1_sub1] => Array
(
[value] => abc
[result] => 2
)
[subentry1_sub2] => Array
(
[value] => abc
[result] => 1
)
)
[subentry2] => Array
(
[subentry2_sub1] => Array
(
[value] => abc
[result] => 1
)
[subentry2_sub2] => Array
(
[value] => abc
[result] => 1
)
)
)
)
Try this code. In this i have created a new array $sum which will add result value of same subentry childs with same key and another array $count which will count the number of times each key repeats
<?php
$data = array('entry1'=>array(
'subentry1'=>
array(
'subentry1_sub1'=>array('value'=>'abc','result'=>2),
'subentry1_sub2'=>array('value'=>'abc','result'=>1)
),
'subentry2'=>
array(
'subentry2_sub1'=>array('value'=>'abc','result'=>1),
'subentry2_sub2'=>array('value'=>'abc','result'=>1)
)
),
'entry2'=>array(
'subentry1'=>
array(
'subentry1_sub1'=>array('value'=>'abc','result'=>2),
'subentry1_sub2'=>array('value'=>'abc','result'=>1)
),
'subentry2'=>
array(
'subentry2_sub1'=>array('value'=>'abc','result'=>1),
'subentry2_sub2'=>array('value'=>'abc','result'=>1)
)
)
);
$sum = array();
$repeat = array();
foreach($data as $input){
foreach($input as $array){
foreach($array as $key=>$value){
if(array_key_exists($key,$sum)){
$repeat[$key] = $repeat[$key]+1;
$sum[$key] = $sum[$key] + $value['result'];
}else{
$repeat[$key] = 1;
$sum[$key] = $value['result'];
}}}}
echo "<pre>";
print_r($sum);
print_r($repeat);
foreach($sum as $key=>$value){
echo $key. ' Average = '. $value/$repeat[$key]."</br>";
}
Output
Array
(
[subentry1_sub1] => 4
[subentry1_sub2] => 2
[subentry2_sub1] => 2
[subentry2_sub2] => 2
)
Array
(
[subentry1_sub1] => 2
[subentry1_sub2] => 2
[subentry2_sub1] => 2
[subentry2_sub2] => 2
)
subentry1_sub1 Average = 2
subentry1_sub2 Average = 1
subentry2_sub1 Average = 1
subentry2_sub2 Average = 1
You can easily calculate avg now
Note : As you mentioned you are counting occurence of subentry1_sub1 etc so i did the same so it will also count whether key result exists or not
I know this is an old thread but im pretty sure there is a much easier way of doing this for anyone who is interested:
If you know the result will always be a number:
foreach($my_array as $entry_name => $entry_data)
{
foreach($entry_data as $sub_name => $sub_data)
{
$sub_results = array_column($sub_data, 'result');
$averages[$entry_name][$sub_name] = array_sum($sub_results)/count($sub_results);
}
}
If its possible the result could be NULL or empty, this will check it and return 'N/A' if there is no valid data to calculate an average from:
foreach($my_array as $entry_name => $entry_data)
{
foreach($entry_data as $sub_name => $sub_data)
{
$sub_results = array_filter(array_column($sub_data, 'result'));
$averages[$entry_name][$sub_name] = (count($sub_results) > 0 ? array_sum($sub_results)/count($sub_results) : 'N/A');
}
}
both of these solutions will give you an averages array that will output the average per subentry per entry.
Try this like,
<?php
$data=array('entry1'=>array(
'subentry1'=>
array(
'subentry1_sub1'=>array('value'=>'abc','result'=>3),
'subentry1_sub2'=>array('value'=>'abc','result'=>3)
),
'subentry2'=>
array(
'subentry2_sub1'=>array('value'=>'abc','result'=>2),
'subentry2_sub2'=>array('value'=>'abc','result'=>8)
)
),
'entry2'=>array(
'subentry1'=>
array(
'subentry1_sub1'=>array('value'=>'abc','result'=>6),
'subentry1_sub2'=>array('value'=>'abc','result'=>6)
),
'subentry2'=>
array(
'subentry2_sub1'=>array('value'=>'abc','result'=>10),
'subentry2_sub2'=>array('value'=>'abc','result'=>12)
)
)
);
foreach($data as $k=>$v){
echo "----------------$k---------------------\n";
if(is_array($v)){
foreach($v as $a=>$b){
if(is_array($b)){
echo $a.' average = ';
$c=array_keys($b);// now get *_sub*
$v1=isset($b[$c[0]]['result']) ? $b[$c[0]]['result'] : '';
$v2=isset($b[$c[1]]['result']) ? $b[$c[1]]['result'] : '';
echo ($v1+$v2)/2;
echo "\n";
}
}
}
}
Online Demo
In the meantime I found a simple working solution myself:
foreach ($data as $level2) {
foreach ($level2 as $level3) {
foreach ($level3 as $keyp => $level4) {
foreach ($level4 as $key => $value) {
if($key == 'result') $stats[$keyp] += $value;
}
}
}
}
With that you get the total for every key in an new array $stats.
But be sure to checkout the solution from user1234, too. It's working great and already includes the calculation of the average.
https://stackoverflow.com/a/39292593/2466703

2 arrays: keep only elements with different value

I have 2 arrays:
Array
(
[0] => Array
(
[id] => 1
[fieldname] => banana
[value] => yellow
)
)
Array
(
[0] => Array
(
[id] => 1
[fieldname] => rome
[value] => city
)
[1] => Array
(
[id] => 2
[fieldname] => bla
[value] => yes
)
)
I want to create a new array that contains only elements where "id" is different. In other words I want to get this output:
Array
(
[0] => Array
(
[id] => 2
[fieldname] => bla
[value] => yes
)
)
[id] => 2 was the only different [id] so I keep it.
Said that I've already managed to achieve my goal with an inefficient pile of foreach, if statements and temp variables. I really don't want to use a wall of code for this very small thing so I started to look for a native PHP function with no success. What's the easiest way to get the result? Is it possible that I strictly need to use a foreach with so many if?
You can use array_udiff with a function.
Computes the difference of arrays by using a callback function for
data comparison.
Returns an array containing all the values of the first array that are not
present in any of the other arguments.
The code:
// Setup two arrays as per your question
$array1 = array (
'0' => array (
'id' => '1',
'fieldname' => 'banana',
'value' => 'yellow',
)
);
$array2 = array (
'0' => array (
'id' => '1',
'fieldname' => 'rome',
'value' => 'city',
),
'1' => array (
'id' => '2',
'fieldname' => 'bla',
'value' => 'yes',
)
);
// Setup the callback comparison function
function arrayCompare($array2, $array1) {
return $array2['id'] - $array1['id'];
}
// Use array_udiff() with the two arrays and the callback function
$arrayDiff = array_udiff($array2, $array1, 'arrayCompare');
print_r($arrayDiff);
The above code returns the following:
Array (
[1] => Array (
[id] => 2
[fieldname] => bla
[value] => yes
)
)
This should do it. Not super short and it does use a temporary variable, so perhaps not what you were looking for. I've named the two arrays one and two.
$ids = array();
$result = array();
foreach ($one as $x) {
$ids[$x['id']] = 1; //This way, isset($x['id']) vill return true
}
foreach ($two as $x) {
if (!isset($ids[$x['id']])) {
$result[] = $x;
}
}
I would be surprised if there wasn't an even more compact way to do it.
EDIT: This is an alternative variant with nested for each. Not particularly short either.
$result = array();
foreach ($one as $x) {
foreach ($two as $y) {
if ($x['id'] == $y['id']) {
//A match, lets try the next $x
continue 2;
}
}
//No matching id in $two
$result[] = $x;
}

Comparing in an Array: If two highest value exists, then compare the other value

Suppose I have an array like:
array( [0] => array([item]=>apple [buy]=>50 [sell]=>30)
[1] => array([item]=>lemon [buy]=>50 [sell]=>60)
[2] => array([item]=>banana [buy]=>40 [sell]=>20)
[3] => array([item]=>orange [buy]=>20 [sell]=>30)
)
Currently I am using this script to check which item has the most buyer
function getMax($array, $val)
{
$max = 0;
foreach( $array as $k => $v )
{
$max = max( array( $max, $v[$val] ) );
}
return $max;
}
$highestBuy = getMax($thisArray, 'buy');
foreach($thisArray as $i=>element){
if($element['buy'] == $highestBuy){
$thisArray[$i]['highestBuy'] = 'yes';
} else {
$thisArray[$i]['highestBuy'] = 'no';
}
}
In this case, both apple and lemon will have highestBuy a yes value. But now I want to find out which item is the most popular by checking their sell if there are two or more same value of highestBuy. Which is the most simple or fastest way to make the output like:
array([0] => array([item]=>apple [buy]=>50 [sell]=>30 [mostPopular]=>no)
[1] => array([item]=>lemon [buy]=>50 [sell]=>60 [mostPopular]=>yes)
[2] => array([item]=>banana [buy]=>40 [sell]=>20 [mostPopular]=>no)
[3] => array([item]=>orange [buy]=>20 [sell]=>30 [mostPopular]=>no)
)
Thanks in advance.
EDIT:
What I want to do is:
find out the highest buy
If this value occur only once(which means there are one highest buy in the array) then push the [mostPouplar]=>yes into the array
If not(there are two or more same highest value), then find out the highest sell.
That's mean if the highest value is unique, it will stop doing further action. If not, it will keep going to find secondary highest value in an array. Is it possible to achieve this?
Sort array with your rules and take first element
$array = array( '0' => array('item'=>apple, 'buy'=>50 ,'sell'=>30),
'1' => array('item'=>lemon, 'buy'=>50, 'sell'=>60),
'2' => array('item'=>banana, 'buy'=>40, 'sell'=>20),
'3' => array('item'=>orange, 'buy'=>20 ,'sell'=>30)
);
usort($array,
function($a, $b) {
$res = $b['buy'] - $a['buy'];
if (!$res) $res = $b['sell'] - $a['sell'];
return $res; });
result:
Array (
[0] => Array ( [item] => lemon [buy] => 50 [sell] => 60 )
[1] => Array ( [item] => apple [buy] => 50 [sell] => 30 )
[2] => Array ( [item] => banana [buy] => 40 [sell] => 20 )
[3] => Array ( [item] => orange [buy] => 20 [sell] => 30 ) )
I had changed the getMax() to return the index of the most popular item
function getMax($array, $val, $val2)
{
$max_item = 0;
foreach( $array as $k => $v )
{
if($array[$max_item][$val] <= $v[$val] && $array[$max_item][$val2] <= $v[$val2])
$max_item = $k;
}
return $max_item;
}
$highestBuy = getMax($thisArray, 'buy', 'sell');
foreach($thisArray as $i => $element){
$thisArray[$i]['mostPopular'] = ($i == $highestBuy) ? 'yes' : 'no';
}

Combination of arrays

I have tried to get the below code to work for a good couple of hours, but just don't succeed.
I have this date array:
Array ( [0] => Array ( [0] => 2007 )
[1] => Array ( [0] => 2008 )
[2] => Array ( [0] => 2009 )
...
)
and this plusMinus one:
Array ( [0] => Array ( [plus] => 2 [date] => 2007 )
[1] => Array ( [minus] => 1 [date] => 2008 )
[2] => Array ( [minus] => 1 [date] => )
[3] => Array ( [plus] => 1 [date] => 2010 [minus] => 1 )
)
I have been trying to combine them into this:
Array ( [0] => Array ( [date] => 2007 [plus]=> 2)
[1] => Array ( [date] => 2008 [minus]=> 1)
[2] => Array ( [date] => 2009 [plusMinus]=> 0)
[3] => Array ( [date] => 2010 [plus] => 1 [minus]=>1 )
...
)
So basically I want to check if a value of the date array exists in the plusMinus array. If true the date and values from the plusMinus array shall replace the entry in the date array.
If false, the original date array entry is complemented by a [plusMinus] => 0 key-value pair.
The way I have tried to do it is this:
foreach ($filler as $key1 => $value1)
{
foreach ($plusMinus as $key2 => $value2)
{
if ($value1['0'] !== $value2['date'])
{
$value1['plusMinus'] = '0';
$result2[$key1][] = $value1;
}
elseif ($value1['0'] == $value2['date'])
{
if (array_key_exists('plus',$value2))
{
$value1['plus'] = $value2['plus'];
$result2[$key1][]=$value1;
}
elseif(array_key_exists('minus',$value2))
{
$value1['minus'] = $value2['minus'];
$result2[$key1][]=$value1;
}
elseif(array_key_exists('minus',$value2) &&
array_key_exists('plus',$value2))
{
}
}
}
}
$valuesComplete = array();
foreach ($result2 as $value) {
$result2 = $value['0'];
array_push($valuesIncomplete, $result2);
}
return $valuesComplete;
Instead of the desired outcome described above I get this:
Array ( [0] => Array
( [0] => 2007 [plus] => 2 )
[1] => Array ( [0] => 2008 [plusMinus => 0 )
[2] => Array ( [0] => 2009 [plusMinus] => 0 )
[3] => Array ( [0] => 2010 [plusMinus] => 0 )
[4] => Array ( [0] => 2011 [plusMinus] => 0 )
[5] => Array ( [0] => 2012 [plusMinus] => 0 )
[6] => Array ( [0] => 2013 [plusMinus] => 0 )
)
What am I missing? Thanks for any help!
Unfortunately, because of the input data format, I can't see any way to do this that doesn't involve an O(n + m + p) operation. But no matter, you gotta do what you gotta do.
Firstly I would start by filtering the useless elements from the PlusMinus array. Since it's already fairly close to the desired output format, it makes sense to use this as the base of the result.
$temp = array();
foreach ($plusMinus as $item) {
if (!empty($item['date'])) {
$temp[$item['date']] = $item;
}
}
Notice that I used the date as the index of the temporary array we're using to build the result. This is to allow you to easily ensure that the result array is in the correct order, and to quickly check whether an item needs to be added from the Filler array.
Next, we need to add any missing elements from the Filler array:
foreach ($filler as $item) {
if (!isset($temp[$item[0]])) {
$temp[$item[0]] = array(
'date' => $item[0],
'plusMinus' => 0
);
}
}
Now all the data is in the array in the correct format, we just need to sort it:
ksort($temp);
...and get convert it back to an indexed array:
return array_values($temp);
No need for the performance killing nested loops or complex flow control.
See it working
As I understood you need to add years that not in second array but in first?
In that case you can do:
foreach ($filler as $key1 => $value1)
{
$ok = false;
foreach ($plusMinus as $key2 => $value2)
{
if($value2['date']==$value1[0])
{
$ok = true;
break;
}
}
if(!$ok)
{
$plusMinus[$value1[0]]=array('date'=>$value1[0], 'plusMinus'=>0);
}
}
<?php
$a1 = array(array( 2007 ),
array( 2008 )
);
$a2 = array(array('plus'=>1, 'date'=>2007),
array('minus'=>1,'date'=>2008),
array('plus'=>1, 'minus'=>1, 'date'=>2008)
);
$r = array();
foreach($a1 as $k1=>$d1) {
$year = $d1[0];
foreach( $a2 as $k2=>$d2 ) {
if( $d2['date'] == $year ) {
$r[$year]['date'] = $year;
if(isset($d2['plus'])) {
$r[$year]['plus'] = $d2['plus'];
}
if(isset($d2['minus'])) {
$r[$year]['minus'] = $d2['minus'];
}
}
}
}
print_r($r);
and result
Array
(
[2007] => Array
(
[date] => 2007
[plus] => 1
)
[2008] => Array
(
[date] => 2008
[minus] => 1
[plus] => 1
)
)
$ar1 = array( array(2007), array(2008), array(2009), array(2010) );
$ar2 = array(
array("date"=>2007, "plus"=>2),
array("date"=>2008, "minus"=>1),
array("date"=>"", "minus"=>1),
array("date"=>2010, "plus"=>1, "minus"=>1)
);
foreach($ar2 as $key=>$val){
if(isset($ar1[$key][0]))
$val["date"] = $ar1[$key][0];
$ar2[$key] = $val;
}
I am not sure if I understand you correctly but this works fine...
It will work only if you are sure that your both arrays "date" equals one to other..
This is what I came up with:
To not create the product of both arrays (foreach inside foreach), I first index the $plusMinus array with the date. That will allow to test quickly if a year exists or not:
$years = array_combine(array_column($plusMinus, 'date'), $plusMinus);
This uses the array_column() function of PHP 5.5, if you don't have it you can easily create it your own.
After doing that it is exactly how you wrote it in your own words:
foreach($date as &$entry)
{
list($year) = $entry;
$entry = array('date' => $year);
// check if a value of the date array exists in the plusMinus array.
if (isset($years[$year])) {
// If true the date and values from the plusMinus array shall replace the entry in the date array
$entry += $years[$year];
} else {
// If false, the original date array entry is complemented by a [plusMinus] => 0 key-value pair.
$entry += array('plusMinus' => 0);
}
}
unset($entry);
See it i action.
This will work just fine.
I did not at all understand your question, but if i got it this is the way:
First make your $datearray more understandable like this:
$dateArray = array(2007,2008,2009,2010);
$plusMinus = array(
array( 'plus' => 2 ,'date' => 2007),
array( 'minus' => 1 ,'date' => 2008),
array ( 'minus' => 1 , 'date' => '' ),
array ( 'plus' => 1 , 'date' => 2010 , 'minus' => 1 )
);
You can make it multidimensional later;
After that:
foreach($dateArray as $k=>$v)
{
if(in_array($v,$plusMinus[$k]))
{
$filler[$k] = $plusMinus[$k];
}
else{
if(empty($plusMinus[$k]['date']))
{
$filler[$k]['date']= $v;
$filler[$k]['plusMinus'] = 0;
}
}
}
This is simple and clean, understandable way with very little code if your arrays will always have the structure you described, meaning the plusMinus values for 2007 are in the cell [0] and the 2007 in the dateArrays is also in the cell [0] like you have shown. I hope i could help.

Count number of different strings?

I have an array that looks like
Array
(
[1] => Array
(
[0] => Date
[1] => Action
)
[2] => Array
(
[0] => 2011-01-22 11:23:19
[1] => SHARE_TWEET
)
[3] => Array
(
[0] => 2011-01-22 11:23:19
[1] => SHARE_FACEBOOK
)
and many other different values (about 10), what I want to do is I want to count the number of times a string is in the array. I was going to use array_count_values but it doesn't count multidimensional arrays.
Any other options?
This could be done by first flattening the array, and then using array_count_values() on it:
For flattening, here is the trick:
$array = call_user_func_array('array_merge', $arrays);
And then:
$counts = array_count_values($array);
Output:
array (
'Date' => 1,
'Action' => 1,
'2011-01-22 11:23:19' => 2,
'SHARE_TWEET' => 1,
'SHARE_FACEBOOK' => 1,
)
Full code:
$array = call_user_func_array('array_merge', $arrays);
var_export(array_count_values($array));
Any time you're dealing with arrays, especially with loops in PHP I can't string enough suggest you look at the array documentation, You'd be suprised how quickly you realise most of the loops in your code is unnecessary. PHP has a built in function to achieve what you're after called array_walk_recursive. And since you're using PHP5 you can use closures rather that create_function (which can be very troublesome, especially to debug, and can't be optimised by the PHP interpreter afik)
$strings = array();
array_walk_recursive($arr, function($value, $key) use (&$strings) {
$strings[$value] = isset($strings[$value]) ? $strings[$value]+1 : 1;
});
I know, unary statements aren't always clear, but this one is simple enough, but feel free to expand out the if statement.
The result of the above is:
print_r($strings);
Array
(
[Date] => 1,
[Action] => 1,
[2011-01-22 11:23:19] => 2,
[SHARE_TWEET] => 1,
[SHARE_FACEBOOK] => 1,
)
Pseudo Code
$inputArray = // your array as in the example above
foreach ($inputArray as $key => $value) {
$result[$value[1]] = $result[$value[1]] + 1;
}
var_dump($result);
Here is a way to do the job:
$arr = Array (
1 => Array (
0 => 'Date',
1 => 'Action'
),
2 => Array (
0 => '2011-01-22 11:23:19',
1 => 'SHARE_TWEET'
),
3 => Array (
0 => '2011-01-22 11:23:19',
1 => 'SHARE_FACEBOOK'
)
);
$result = array();
function count_array($arr) {
global $result;
foreach($arr as $k => $v) {
if (is_array($v)) {
count_array($v);
} else {
if (isset($result[$v])) {
$result[$v]++;
} else {
$result[$v] = 1;
}
}
}
}
count_array($arr);
print_r($result);
output:
Array
(
[Date] => 1
[Action] => 1
[2011-01-22 11:23:19] => 2
[SHARE_TWEET] => 1
[SHARE_FACEBOOK] => 1
)

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