How to limit the number of pagination pages - PHP - php

I have this algorithm I made for pagination.
The $array variable is a result set from the query after the page number and limit has been set. It's a result from a PDO::fetchAll() function.
The $array["totalCount"] contains the count of ALL the rows in the table, not only that set but all the rows.
What I want is to limit the number of pages displayed, and make it somehow like google style pagination, I've search a lot of similar questions online, but what makes me struggle is to guess how I can implement it in my algorithm which is much different from others.
Thanks in advance.
public static function renderPaginationBar($obj, $params) {
$array = $obj->getAll($params);
$set = $params["set"];
$perSet = $params["limit"];
$pages = ceil((int)$array["totalCount"] / (int)$perSet);
if($pages > 1 && $set <= $pages) {
$query = preg_replace('/set=\d*/i', '', http_build_query($_GET));
?>
<ul class="pagination">
<?php
if($set > 1) {
?>
<li><<< Inicio</li>
<li><<</li>
<?php
}
for($i = 1; $i <= $pages; $i++) {
$class = $set == $i ? "active" : "";
?>
<li class="<?php echo $class; ?>"><?php echo $i; ?></li>
<?php
}
if($set < $pages) {
?>
<li>>></li>
<li>Último >>></li>
<?php
}
?>
</ul>
<?php
}
unset($array["totalCount"]);
return $array;
}

you can try displaying it as a dropdown between the 'next' and 'prev' button if you want.. it would be easier to display all the page numbers..
or you can first get the value of current page, add 5 and store it as '$add' and minus 5 and store it as '$minus' then insert this in the page buttons:
<input type="submit" value="<?php echo $page_num;?>" <?php if($pagenum > $add || $pagenum < $minus){ echo "style='display:none'";?>>
it will hide the buttons that are more than 5 and less than 5 the current page
replace yor 'for' with this:
$get_add = $params["set"] + 5;
$get_minus = $params["set"] - 5;
for($i = 1; $i <= $pages; $i++) {
$class = $set == $i ? "active" : "";
?>
<li class="<?php echo $class; ?>" <?php if($i > $get_add || $i < $get_minus){ echo "style='display:none;position:absolute'";?>><?php echo $i; ?></li>
<?php
}

Related

limit pages shown in pagination php script

I have 100+ records in my database so i am using pagination but it prints page number for every page like 1,2,3,5 and so on how to limit the number shown in pagination.
Here is my code:
$row_offer2=mysqli_num_rows($sql_result2);
$total=ceil($row_offer2/$num_rec);
echo "<div class='col-md-12' style='margin:0 auto;text-align:center;'><ul
class='pagination '>";
echo "<li id='1' class='pag'>".'|<'."</li>"; // Goto 1st page
for ($i=1; $i<=$total; $i++) {
echo "<li id=".$i." class='pag'>".$i."</a></li> ";
};
echo "<li id=".$total." class='pag'>".'>|'."</a></li> "; // Goto last page
echo "</ul></div>";
?>
Show pagination for current page +- x pages (x should be something like 2-3) and show the first and last page.
$currentPage = 6;
function getPages($cp, $max, $offset) {
$pages = [];
$pages[] = 1;
$min = ($cp - $offset) > 1 ? $cp - $offset : 1;
$lim = ($cp + $offset) < $max ? $cp + $offset : $max;
for ($i = $min; $i < $lim; $i++) {
$pages[] = $i;
}
$pages[] = $max;
return array_unique($pages);
}
var_dump(getPages($currentPage, 20, 3));
then you can simply loop with foreach through array you receive from this function and display your LIs
Control your loop with number you want to show. If you want to show 3 pages in pagination just do this.
for ($i=1; $i<=3; $i++) {
echo "<li id=".$i." class='pag'>".$i."</a></li> ";
};

How to set 2 different classes by if else condtion in foreach loop with predefined order?

Suppose I have 10 records, and 2 different classes namely c1, c2
<div class="c2">..content..</div>
<div class="c2">..content..</div>
<div class="c1">..content..</div>
<div class="c1">..content..</div>
<div class="c2">..content..</div>
<div class="c2">..content..</div>
<div class="c1">..content..</div>
<div class="c1">..content..</div>
<div class="c2">..content..</div>
<div class="c2">..content..</div>
i want the if else condition where class order needs to maintained like c2,c2,c1,c1,c2,c2,c1,c1,c2,c2.....so on
foreach(x as y){
if() {
<div class="<?php echo $class1;?>">..content..</div>
} else {
<div class="<?php echo $class2;?>">..content..</div>
}
class order should be c2,c2,c1,c1,c2,c2,c1,c1,c2,c2.....so on
Check the page url http://themesflat.com/html/nah/portfolio-creative.html
You can use a bitwise operator (&) here, and with 2 and this will toggle the class...
$i = 0;
foreach($x as $y){
if($i & 2) {
$class = "1";
} else {
$class = "2";
}
echo "<div class=$class>..content..</div>";
$i++;
}
I've extracted the echo out as this keeps it consistent, just have a variable for the class you want to have and put that in the if instead.
You can do it with a separate counter
$current = 'c2';
$count = 1;
for ($i = 0; $i < 10; $i++) {
echo '<div class="'. $current . '">..content..</div>';
if ($count == 2) {
$current = $current == 'c1' ? 'c2' : 'c1';
$count = 0;
}
$count++;
}
Demo: https://3v4l.org/7ftjg
This will of course work just as well in a foreach-loop.
Note: If it's only about styling the divs differently, you could do this in CSS alone. Here's a similar question and answer: nth-child: how to pick elements in groups of two
I'm pretty sure you can resolve the problem via css pseudo class :nth-of-type but if you prefered PHP you can try the following example.
<?php
$class_types = ['c2', 'c1'];
$records = array_fill(0, 10, '..content..'); // replace with your records
$records_length = count($records);
$html_output = '';
foreach ($records as $index => $item) {
$type = floor($index / $records_length * $records_length / 2) % 2;
$class = $class_types[$type];
$html_output .= sprintf('<div class="%s">%s</div>', $class, $item);
}
echo $html_output;
Try this code:
$counter = 1;
for($i=0;$i<=10; $i++){
if($counter==1 or $counter==2) {
echo '<div class="c1">..content..</div>';
} else {
echo '<div class="c2">..content..</div>';
}
if($counter==4){
$counter=0;
}
$counter++;
}
?>
How about we chunk the main array into an array or arrays of two
like
<?php
$chunked_array = array_chunk( $your_array , 2 );
// This will give us an array of 2 elements array
// now we will loop
for( $i = 1 ; $i < count( $chunked_array ); $++ ){
$contents = $chunked_array[$i];
foreach( $contents as $content ){
if ( $i%2 == 0 ){
//<div class="<?php echo $class1;?>">..content..</div>
}else{
//<div class="<?php echo $class2;?>">..content..</div>
}
}
}
using this way we have one loop and it will always be in a group of two even when your data grow or shrink

php pagination - how do i limit the number of pages show

I am having difficulties understanding how to limit the number of pages with pagination. I am trying to list my articles in my DB but I have over 500 pages! I would only like to show a max of about 15 page numbers at a time. I can't seem to understand the answers given in the other questions.
Here is my code for the Pagination:
<?php
require 'core/init.php';
$page = isset($_GET['page']) ? (int)$_GET['page'] : 1;
if(!isset($_GET['page'])){
$_GET['page'] = 1;
}
if(! (int)$_GET['page']){
$_GET['page'] = 1;
}
if($_GET['page'] < 1){
$_GET['page'] = 1;
}
$perPage = 18;
$start = ($page > 1) ? ($page * $perPage) - $perPage : 0;
$articles = DB::getInstance()->query("SELECT SQL_CALC_FOUND_ROWS * FROM articles ORDER BY added DESC LIMIT {$start}, {$perPage}");
foreach($articles->results() as $article){ ?>
<div class="article-container">
<h2><?php echo $article->title; ?></h2>
</div>
<?php
}
// pagination
$total = DB::getInstance()->query("SELECT FOUND_ROWS() as total");
$total = $total->results()[0];
foreach ($total as $total => $value) {
}
$pages = ceil($value / $perPage);
$maxpage = 15;
?>
<div class="pagination">
<?php if($_GET['page'] >= 2){
echo 'Prev';
}
for ($i=1; $i <= $pages; $i++) : ?>
<a href="?page=<?php echo $i; ?>" <?php if($page === $i) { echo 'class="pageSelected"'; } ?>><?php echo $i; ?></a>
<?php endfor;
if((int)$_GET['page'] != $i - 1 ){
echo 'Next';
}
?>
</div>
This works as expected but it only spits out the number of pages from 1 to 500. What is the best/easiest way to show something like this:
1 2 3 4 5 6 7 8 9 10 11 12 13 ... >
?
You need to change your for-cycle, the starting point and ending point
$count = 9;
$startPage = max(1, $page - $count);
$endPage = min( $pages, $page + $count);
for($i = $startPage; $i < $endPage; $i++) {
// write out the link to the page
}
then if the page is 250 it will show only 241, 242, ..., 250, ..., 257, 258

Pagination does not work perfectly

I have the following code:
$max = 4;
$page = isset($_GET['page']) ? ($_GET['page']) : '1';
$init = $page - 1;
$init= $max * $init;
$strCount = "SELECT COUNT(*) AS 'total_mytable' FROM mytable";
$varstrCount = $crud->viewdatas($strCount);
$total = 0;
if(count($varstrCount)){
foreach ($varstrCount as $row) {
$total = $row["total_mytable"];
}
}
$result = "SELECT * FROM mytable ORDER BY id_mytable LIMIT $init,$max";
$varresult = $crud->viewdatas($result);
content of page:
<?php
if(count($varresult)){
foreach ($varresult as $res) {
?>
<h5><?php echo $res['title'] ?></h5>
<?php
}
}
?>
<?php
$max_links = 10;
$previous = $page - 1;
$next = $page + 1;
$pgs = ceil($total / $max);
if($pgs > 1 ){
if($previous > 0){
echo "<li><a href='".BASE_URL."/category/$previous' aria-label='Previous'><span aria-hidden='true'>«</span></a></li>";
} else{
}
for($i=$page-$max_links; $i <= $pgs-1; $i++) {
if ($i <= 0){
}else{
if($i != $page{
if($i == $pgs){ //if end insert 3 dots
echo "<li><a href='".BASE_URL."/category/".($i)."'>".$i."</a></li> ...";
}else{
echo "<li><a href='".BASE_URL."/category/".($i)."'>".$i."</a></li>";
}
} else{
if($i == $pgs){ //if end insert 3 dots
echo "<li>".$i."</li> ...";
}else{
echo "<li>".$i."</li>";
}
}
}
}
if($next <= $pgs){
echo "<li><a href='".BASE_URL."/category/$next' aria-label='Next'><span aria-hidden='true'>»</span></a></li>";
}else{
}
}
?>
The result:
And I not understand the reason for the active number stay right off the paging menu
In the code I defined max-links for 10, but no show number 5 and if I define max links for 3 changes nothing , displays the same result as the image.
Thanks for any help
echo "<li>".$i."</li>";
on the above line add up a href, seems like you have css formatting for li>a because of which you are not getting the required formatting on only li. so for getting better formatting for all paging links current, prev, next. you need to add up a tags.
echo "<li><a>".$i."</a></li>"; //in your else part

PHP Pagination Problem

I'm having a problem with my PHP pagination for a project.
It almost works but it doesn't seem to display the numbers correctly.
I want only 6 more page numbers to display after the selected and one before;
(also if you are on page one display 7 after)
For example:
If on Page 1: 1/2/3/4/5/6/7/8
If on Page 2: 1/2/3/4/5/6/7/8
If on Page 5: 4/5/6/7/8/9/10/11
If on Page 10: 9/10/11/12/13/14/15/16
This is my code so far...
if($page == ceil($NumOfPages) && $page != 1){
for($i = 1; $i <= ceil($NumOfPages)-1; $i++){
if($i > 0){
echo "{$i}";
}
}
}
if ($page == ceil($NumOfPages) ) {
$startPage = $page;
}else{
$startPage = 1;
}
for ($i = $startPage; $i <= $page+6; $i++){
if ($i <= ceil($NumOfPages)){
if($i == $page) {
echo "<a href='/page/$i/' title='View movies page $i' id='pagelisel'>$i</a> ";
}else{
echo "<a href='/page/$i/' title='View movies page $i' id='pageli'>$i</a> ";
}
}
}
Any help would be greatly appreciated,
Thanks!
I assumed that (partly for myself... ;) ):
$page is the selected page
$startPage is the first page number you want to show
$numPages is already ceil-ed
First you need to find $startPage. Depending whether $page is the first one (ie has the value one 1, another assumption) or not. Your check is slightly off, as it check if it is equal to the last page.
if($page == 1) {
$startPage = 1;
} else {
$startPage = $page - 1;
}
Then you need to find out the last page number you want to print ($lastPage). So check if $startPage is near the end and set ~$lastPage` accordingly:
if($startPage + 7 > $numPages) {
$endPage = $numPages;
} else {
$endPage = $startPage + 7;
}
Finally, use you for-loop which seem ok, but loop from $startPage to $endPage.
Here's an alternative approach that should work for you as well:
$pageCurrent = $page;
$pagePrevious = $pageCurrent-1;
$pageClass = '';
$pageStart = 1;
$pageEnd = $pageCurrent+6;
$pageMax = ceil($NumOfPages);
if($pageCurrent==1){
echo "1";
}else{
echo "$pagePrevious";
}
for($i = $pageStart; $i <= $pageEnd; $i++){
if($i <= $pageEnd){
if($i == 1 && $pageCurrent != 1){
$pageClass = 'selected';
}else{
$pageClass = '';
}
echo "$i";
}
}

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