I have 100+ records in my database so i am using pagination but it prints page number for every page like 1,2,3,5 and so on how to limit the number shown in pagination.
Here is my code:
$row_offer2=mysqli_num_rows($sql_result2);
$total=ceil($row_offer2/$num_rec);
echo "<div class='col-md-12' style='margin:0 auto;text-align:center;'><ul
class='pagination '>";
echo "<li id='1' class='pag'>".'|<'."</li>"; // Goto 1st page
for ($i=1; $i<=$total; $i++) {
echo "<li id=".$i." class='pag'>".$i."</a></li> ";
};
echo "<li id=".$total." class='pag'>".'>|'."</a></li> "; // Goto last page
echo "</ul></div>";
?>
Show pagination for current page +- x pages (x should be something like 2-3) and show the first and last page.
$currentPage = 6;
function getPages($cp, $max, $offset) {
$pages = [];
$pages[] = 1;
$min = ($cp - $offset) > 1 ? $cp - $offset : 1;
$lim = ($cp + $offset) < $max ? $cp + $offset : $max;
for ($i = $min; $i < $lim; $i++) {
$pages[] = $i;
}
$pages[] = $max;
return array_unique($pages);
}
var_dump(getPages($currentPage, 20, 3));
then you can simply loop with foreach through array you receive from this function and display your LIs
Control your loop with number you want to show. If you want to show 3 pages in pagination just do this.
for ($i=1; $i<=3; $i++) {
echo "<li id=".$i." class='pag'>".$i."</a></li> ";
};
Related
I have the following code:
$max = 4;
$page = isset($_GET['page']) ? ($_GET['page']) : '1';
$init = $page - 1;
$init= $max * $init;
$strCount = "SELECT COUNT(*) AS 'total_mytable' FROM mytable";
$varstrCount = $crud->viewdatas($strCount);
$total = 0;
if(count($varstrCount)){
foreach ($varstrCount as $row) {
$total = $row["total_mytable"];
}
}
$result = "SELECT * FROM mytable ORDER BY id_mytable LIMIT $init,$max";
$varresult = $crud->viewdatas($result);
content of page:
<?php
if(count($varresult)){
foreach ($varresult as $res) {
?>
<h5><?php echo $res['title'] ?></h5>
<?php
}
}
?>
<?php
$max_links = 10;
$previous = $page - 1;
$next = $page + 1;
$pgs = ceil($total / $max);
if($pgs > 1 ){
if($previous > 0){
echo "<li><a href='".BASE_URL."/category/$previous' aria-label='Previous'><span aria-hidden='true'>«</span></a></li>";
} else{
}
for($i=$page-$max_links; $i <= $pgs-1; $i++) {
if ($i <= 0){
}else{
if($i != $page{
if($i == $pgs){ //if end insert 3 dots
echo "<li><a href='".BASE_URL."/category/".($i)."'>".$i."</a></li> ...";
}else{
echo "<li><a href='".BASE_URL."/category/".($i)."'>".$i."</a></li>";
}
} else{
if($i == $pgs){ //if end insert 3 dots
echo "<li>".$i."</li> ...";
}else{
echo "<li>".$i."</li>";
}
}
}
}
if($next <= $pgs){
echo "<li><a href='".BASE_URL."/category/$next' aria-label='Next'><span aria-hidden='true'>»</span></a></li>";
}else{
}
}
?>
The result:
And I not understand the reason for the active number stay right off the paging menu
In the code I defined max-links for 10, but no show number 5 and if I define max links for 3 changes nothing , displays the same result as the image.
Thanks for any help
echo "<li>".$i."</li>";
on the above line add up a href, seems like you have css formatting for li>a because of which you are not getting the required formatting on only li. so for getting better formatting for all paging links current, prev, next. you need to add up a tags.
echo "<li><a>".$i."</a></li>"; //in your else part
if( isset($_GET['page'] ) )
{
$page = $_GET['page']-1;
$offset = $recLimit * $page;$page = $_GET['page']+1;
}
else
{
$page=2;
$offset = 0;
}
$phpself = $_SERVER['PHP_SELF'];
if( $totalPages <= $noofpages )
{
echo "Pages if less than or equal 5 : ";
for($i=1; $i <= $totalPages; $i++)
{
echo "$i |";
}
}
else
{
$i=1;
for($i; $i <= $totalPages; $i++)
{
echo "$i |";
}
}
?><table border="1" cellpadding="8"><tr> <th>ID</th><th>Name</th><th>Age</th><th>E-mail ID</th><th>Verified</th>
I'm goin to make a PHP pagination but i've some problem, in this i want to show 5 pages and 4 records per page. and if we click on next button then it shows the remaining page. And there are total 7 pages.
Since I couldn't really understand your code, here is something to get you started:
$items_per_page = 4;
/* Get the total number of records */
$result = mysqli_query("select count(*) as n from ...");
$row = mysqli_fetch_assoc($result);
$total_count = $row["n"];
/* Calculate the total number of pages */
$total_pages = ceil($total_count / $items_per_page);
/* Determine the current page */
$current_page = intval(#$_GET["page"]);
if(!$current_page || $current_page < 1) { $current_page = 1; }
if($current_page > $total_pages) { $current_page = $total_pages; }
/* Get the records for the current page */
$limit = $items_per_page;
$offset = ($current_page - 1) * $items_per_page;
$result = mysqli_query("select ... limit " . $offset . ", " . $limit);
To display the pagination links, use this:
for($i = 1; $i <= $total_pages; $i++)
{
if($i > 1) { print(" | "); }
if($current_page == $i) { print($i); }
else { print('' . $i . ''; }
}
Pagination problem in search result
I am trying to paginate the search results, Here is the code that i'm using to look up for the search queries from user's form. I am getting search results paginated, but when i click 2 nd page of results it shows undefined index for those item posted...While gone through tutorials i have seen to use $_GET instead of $_POST ,after doing that chane also no improvement in results
As i am new to this php code, can you guys help or guide me in the right direction?
/////////////test.php//////////////////
mysqli_report(MYSQLI_REPORT_ERROR);
// number of results to show per page
$per_page = 2;
// figure out the total pages in the database
if ($result = $mysqli->query("SELECT * FROM bridegroom where Gender like '%$Name%' and Castest like'%$caste%' and Location like '%$location%' order by AGE"))
{
if ($result->num_rows != 0){
$total_results = $result->num_rows;
// ceil() returns the next highest integer value by rounding up value if necessary
$total_pages = ceil($total_results / $per_page);
if (isset($_GET['page']) && is_numeric($_GET['page']))
{
$show_page = $_GET['page'];
if ($show_page > 0 && $show_page <= $total_pages)
{
$start = ($show_page -1) * $per_page;
$end = $start + $per_page;
}
else
{
$start = 0;
$end = $per_page;
}
}
else
{
$start = 0;
$end = $per_page;
}
// display pagination
echo "<p> <b>View search results:</b> ";
for ($i = 1; $i <= $total_pages; $i++)
{
if (isset($_GET['page']) && $_GET['page'] == $i)
{
echo $i . " ";
}
else
{
echo "<a href='test.php?page=$i'>$i</a> ";
}
}
echo "</p>";
// display data in table
// loop through results of database query, displaying them in the table
for ($i = $start; $i < $end; $i++)
{
// make sure that PHP doesn't try to show results that don't exist
if ($i == $total_results) { break; }
// find specific row
$result->data_seek($i);
$row = $result->fetch_row();
// echo out the contents of each row into a table
echo ("Name:$row[1]<br><span class=\"old\"> Age:$row[4]</span><br><span class=\"sold\">Caste:$row[5]</span><br><span class=\"old\">Location:</span><span class=\"sold\">$row[6]</span><br><br>");
}
// close table>
}
else
{
echo "No results to display!";
}
}
// error with the query
else
{
echo "Error: " . $mysqli->error;
}
// close database connection
$mysqli->close();
// display pagination
echo "<p> <b>Your search results:</b> ";
for ($i = 1; $i <= $total_pages; $i++)
{
if (isset($_GET['page']) && $_GET['page'] == $i)
{
echo $i . " ";
}
else
{
echo "<a href='test.php?page=$i'>$i</a> ";
}
}
echo "</p>";
?>
I want to limit the number of pages displayed on my pagination php script below. This was a script made a few years back for me, and although I have read through similar problems on here, their coding is very different.
Any help with this would be really appreciated.
Here is my current script:
<?php
if ($max_pages>1) {
echo "<br>";
if ($page>0) {
echo 'Previous';
}
for ($x=0;$x<$max_pages;$x++) {
if ($page<>$x) {
echo ''.($x+1).'';
}
else {
echo '<span class="pagination">'.($x+1).'</span>';
}
}
if (($page+1<>$max_pages)) {
echo 'Next';
}
}?>
Your current script cycles $x between 0 and $max_pages.
What you can do is first replace them with $from_page and $to_page:
$from_page = 0;
$to_page = $max_pages;
...
for ($x=$from_page; $x < $to_page; $x++)
at which point the script will work just as before.
Now if you want to only display from $N pages before to $N pages after $page,
$N = 5; // display 5+5+1 = 11 pages
$from_page = $page - $N; if ($from_page < 0) $from_page = 0;
$to_page = $from_page + 2*$N+1; if ($to_page > $max_pages) $to_page = $max_pages;
$from_page = $to_page - 2*$N-1; if ($from_page < 0) $from_page = 0;
Not the most elegant way perhaps, but it will try to fit an 11-page area centered on the current page. You may want to also display a link to pages 0 and $max_pages-1.
MRE version
<?php
if ($max_pages>1)
{
$N = 5; // display 5+5+1 = 11 pages
$to_page = min($max_pages, max(0, $page - $N) + 2*$N+1);
$from_page = max($to_page - 2*$N-1, 0);
echo "<br>";
if ($page > 0)
{
echo 'Previous';
}
for ($x=$from_page; $x < $to_page; $x++) {
if ($page != $x) {
echo ''.($x+1).'';
}
else {
echo '<span class="pagination">'.($x+1).'</span>';
}
}
if (($page+1<>$max_pages)) {
echo 'Next';
}
}?>
I'm having a problem with my PHP pagination for a project.
It almost works but it doesn't seem to display the numbers correctly.
I want only 6 more page numbers to display after the selected and one before;
(also if you are on page one display 7 after)
For example:
If on Page 1: 1/2/3/4/5/6/7/8
If on Page 2: 1/2/3/4/5/6/7/8
If on Page 5: 4/5/6/7/8/9/10/11
If on Page 10: 9/10/11/12/13/14/15/16
This is my code so far...
if($page == ceil($NumOfPages) && $page != 1){
for($i = 1; $i <= ceil($NumOfPages)-1; $i++){
if($i > 0){
echo "{$i}";
}
}
}
if ($page == ceil($NumOfPages) ) {
$startPage = $page;
}else{
$startPage = 1;
}
for ($i = $startPage; $i <= $page+6; $i++){
if ($i <= ceil($NumOfPages)){
if($i == $page) {
echo "<a href='/page/$i/' title='View movies page $i' id='pagelisel'>$i</a> ";
}else{
echo "<a href='/page/$i/' title='View movies page $i' id='pageli'>$i</a> ";
}
}
}
Any help would be greatly appreciated,
Thanks!
I assumed that (partly for myself... ;) ):
$page is the selected page
$startPage is the first page number you want to show
$numPages is already ceil-ed
First you need to find $startPage. Depending whether $page is the first one (ie has the value one 1, another assumption) or not. Your check is slightly off, as it check if it is equal to the last page.
if($page == 1) {
$startPage = 1;
} else {
$startPage = $page - 1;
}
Then you need to find out the last page number you want to print ($lastPage). So check if $startPage is near the end and set ~$lastPage` accordingly:
if($startPage + 7 > $numPages) {
$endPage = $numPages;
} else {
$endPage = $startPage + 7;
}
Finally, use you for-loop which seem ok, but loop from $startPage to $endPage.
Here's an alternative approach that should work for you as well:
$pageCurrent = $page;
$pagePrevious = $pageCurrent-1;
$pageClass = '';
$pageStart = 1;
$pageEnd = $pageCurrent+6;
$pageMax = ceil($NumOfPages);
if($pageCurrent==1){
echo "1";
}else{
echo "$pagePrevious";
}
for($i = $pageStart; $i <= $pageEnd; $i++){
if($i <= $pageEnd){
if($i == 1 && $pageCurrent != 1){
$pageClass = 'selected';
}else{
$pageClass = '';
}
echo "$i";
}
}