PHP - Button to delete Item from MySQL - php

Question

I am coding some video upload script and I am with the admin panel right now.
There I have a List with all Videos. And each video has one delete button on the right side.
When I click the button then this video should be deleted from database but its not working after I click the button nothing happens.
<?php
$query = mysql_query("SELECT * FROM `videos`");
while($row = mysql_fetch_assoc($query))
{
$id = $row['id'];
$name = $row['name'];
echo "<a href='watch.php?id=$id'>$name</a><br />
<input type='submit' name='remove' value='Delete'<br />";
}
if (isset($_POST['remove']))
{
foreach ($_POST['id'] as $the_id)
{
if (!mysql_query("DELETE FROM videos WHERE id = '$the_id'"))
{
echo mysql_error();
}
}
}
?>
Of course on the header I have the mysql connect query. This is just the php code for listing all videos and try to delete.

Answer 1

Here is an example of doing this with MySQLi, including binding parameters to avoid SQL injection -
if (isset($_POST['remove'])) {
$remove = $mysqli->prepare("DELETE FROM `videos` WHERE `id` = ?");
$vid_id = $_POST['vid_id'];
$remove->bind_param('s', $vid_id);
if(!$remove->execute() === true) {
echo $mysqli->error;
}
}
$query = "SELECT * FROM `videos`";
if ($result = $mysqli->query($query)) {
while($row = $result->fetch_object()){
$id = $row->id;
$name = $row->name;
echo "<a href='watch.php?id=$id'>$name</a><br />";
echo "<form name='delete_vid' method='post'>";
echo "<input type='hidden' name='vid_id' value='$id'>";
echo "<input type='submit' name='remove' value='Delete'<br />";
echo "</form>";
}
} else {
echo mysqli_error($connection);
}
$result->close();
Of course you will have to provide a $connection` to the database, but thsi should get you started not only with MySQLi but with adding a form for each video.
More on SQL Injection

Answer 2

Maybe the problem is in the html, each delete button must be in and independent form, with a hidden input with the id too.
echo "<a href='watch.php?id=$id'>$name</a><br />
<form method='post'><input type='hidden' value='$id'><input type='submit' name='remove' value='Delete'<br /></form>";

Answer 3

<form method="post" >
<?php
$query = mysql_query("SELECT * FROM `videos`");
while($row = mysql_fetch_assoc($query))
{
$id = $row['id'];
$name = $row['name'];
echo "<a href='watch.php?id=$id'>$name</a><br />
<button name='id' value='".$id."' type='submit' >Delete</button>
<br />";
}
if (!mysql_query("DELETE FROM videos WHERE id = '".$_POST['id']."'"))
{
echo mysql_error();
} else {
echo 'successfully deleted';
}
?>
</form>