Updating database using php - php

Question

This code looks horrible and I know. I don't know how to fix it though. When I try and update the table using the edit web page, only the first row in the first column updates but the subtitle is not updating in the second column, first row. Is there a way to change this? Sorry for the terrible explanation.
Update Page
//Home Title
$homeTitleUpdate = $_POST["homeTitleChange"];
$editRow = $_POST["rowID"];
$query = " UPDATE Home SET title = '$homeTitleUpdate' WHERE homeID = '$editRow' ";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn));
if ($result) {
echo "<p> - Title updated succesfully to $homeTitleUpdate.</p>";
} else {
echo "<p> - Title did not update. Something went wrong</p>";
}
//Home Subtitle
$homeSubtitleUpdate = $_POST["homeSubtitleChange"];
$query1 = " UPDATE Home SET subtitle = '$homeSubtitleUpdate' ";
$result1 = mysqli_query($conn, $query) or die(mysqli_error($conn));
if ($result) {
echo "<p> - Subtitle updated successfully to $homeSubtitleUpdate.</p>";
} else {
echo "<p> - Subtitle did not update. Something went wrong</p>";
}
Edit Page
<?php
echo "<h2 style='color:black'>";
echo "<input type'text' name='homeTitleChange' value=$homeTitle>";
echo "<input type='hidden' name='rowID' value=$getID>";
echo "</h2>";
echo "<h4 style='color:black'>";
echo "<input type'text' name='homeSubtitleChange' value=$homeSubtitle>";
echo "<input type='hidden' name='rowID' value=$getID>";
echo "</h4>";
?>
<input type="submit" value="save" />

Answer 1

<?php
echo "<h2 style='color:black'>";
echo "<form action="change to your file" method="post">
echo "<input type'text' name='homeTitleChange' value=$homeTitle>";
echo "<input type='hidden' name='rowID' value=$getID>";
echo "</h2>";
echo "<h4 style='color:black'>";
echo "<input type'text' name='homeSubtitleChange' value=$homeSubtitle>";
echo "<input type='hidden' name='rowID' value=$getID>";
echo "</h4>";
?>
<input type="submit" name="submit" value="save" />
</form>
You did not have a form
//Home Title
if(isset($_POST['submit'])){
if
(
!empty($_POST["homeTitleChange"])
&&
!empty($_POST["homeSubtitleChange"]) &&
!empty($_POST["rowID"])
)
{
$homeTitleUpdate = $_POST["homeTitleChange"];
$homeSubtitleUpdate = $_POST["homeSubtitleChange"];
$editRow = $_POST["rowID"];
$query = "UPDATE Home SET title = '$homeTitleUpdate', subtitle ='$homeSubtitleUpdate' WHERE homeID = '$editRow' ";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn));
if ($result) {
echo "<p> - Title/Subtitle updated succesfully to $homeTitleUpdate.</p>";
} else {
echo "<p> - Title/Subtitle did not update. Something went wrong</p>";
}
}
}
You can change your php and do it all within one query

Answer 2

You need to add 'where' condition while updating subtitle as well
$query1 = " UPDATE Home SET subtitle = '$homeSubtitleUpdate' WHERE homeID = '$editRow' ";
on other hand, you can update both of them in single query, like this
$query = " UPDATE Home
SET title = '$homeTitleUpdate', subtitle = '$homeSubtitleUpdate'
WHERE homeID = '$editRow' ";
wouldn't this be better? unless you have some specific reason