I have three mysql tables subjects, examinations, examinfo
TABLE - SUBJECTS
subjectid
subjectname
subjectExamid
TABLE - EXAMINFO
examid
exam
TABLE EXAMINATIONS
fname
lname
studentid
score
subjectid
ON subject.subjectExamid = exam.examid
ON examination.subjectid = subject.subjectid
Now i would like to generate HTML table indicating scores students get per paper against subject
STRUCTURE TABLE OUTPUT
Student details against each subject score
EDIT CODE SAMPLE
<?php
$examinid = 3;
$subjects = mysqli_query(
$con,"
SELECT * FROM subjects
WHERE examid = '$examinid'
ORDER BY shortname ASC
");
$content = mysqli_query(
$con,"
SELECT DISTINCT exam.idcandidate, exam.sex, exam.fname, exam.lname
FROM examinations
AS exam
INNER JOIN examinfo
AS info
ON exam.id_subject = info.idsubject
WHERE info.idexam = '$examinid'
");
?>
<div id="table_1">
<table cellpadding="0" cellspacing="0" border="0">
<tr>
<td class="table1tr">#</td>
<td class="table1tr">Candidate</td>
<td class="table1tr">ID</td>
<td class="table1tr">Sex</td>
<?php
// output subjects
while($subRow = mysqli_fetch_array($subjects)){
$arbv = strtoupper($subRow['shortname']);
$subjectname = ucwords(strtolower($subRow['subjectname']." - ".$subRow['subjectid'].""));
?>
<td class="table1tr" title="<?php echo $subjectname; ?>">
<?php echo $arbv; ?>
</td>
<?php
}
?>
<td class="table1tr">Exam</td>
</tr>
<?php
while($stdnt = mysqli_fetch_array($content)){
$fullname = ucwords(strtolower("$stdnt[lname] $stdnt[fname]"));
$studentid = str_replace(array('/', 'M', 'W', 'S', 'F', '-'), "",$stdnt['idcandidate']);
if($sex = $stdnt['sex'] == Male){
$sex = M;
}else{ $sex = F; }
$id_subject = $stdnt['id_subject'];
$x++;
$zebra_1 = ($x%2)? 'TableZebra_1': 'TableZebra_2';
?>
<tr>
<td class="<?Php echo $zebra_1; ?>"><?php echo $count++; ?></td>
<td class="<?Php echo $zebra_1; ?>"><?Php echo $fullname; ?></td>
<td class="<?Php echo $zebra_1; ?>"><?php echo $studentid; ?></td>
<td class="<?Php echo $zebra_1; ?>"><?php echo $sex; ?></td>
<td class="<?Php echo $zebra_1; ?>">
<!-- Problem is here how to output the subject grades $grade -->
<!--
My first unsuccessful approach
SELECT score
FROM examinations AS test
INNER JOIN examinfo AS testinfo ON testinfo.idsubject = test.id_subject
WHERE testinfo.idexam
IN (
SELECT idexam
FROM examinfo
WHERE idexam = $examinid
)
AND test.id_subject = $id_subject AND test.idcandidate = '$studentid'
Then output results - But this falls it shows one student subjects in one cell
-->
</td>
<td class="<?Php echo $zebra_1; ?>">Exam</td>
</tr>
<?php
} // loop content
?>
</table>
</div>
If your solution is not concat(); you may first
follow the simple steps
1 loop $contents // to get info such as studentid
2 inside the loop of $contents loop $subjects // to get all subjects including subjectids
3 inside $subject loop, loop examinations table where studentid = '$studentid' AND subjectid = '$subjectid'
if step three return null echo empty cell otherwise echo cell with score
I have no time to test this, but you may follow the steps and it will work otherwise try google search
Related
$totDays = cal_days_in_month(CAL_GREGORIAN,$_REQUEST['month'],$_REQUEST['year']);
$attData = $commonObj->getAttendanceData($_REQUEST['month'],$_REQUEST['year']);
`
Student Name
<?php foreach($attData as $attk=>$attv){
$punchin = $commonObj->getTimeOfDate($attData[$attk]['punchin']);
$punchout = $commonObj->getTimeOfDate($attData[$attk]['punchout']);
$nam=$attv['name'];
?>
<tr>
<th class="danger">
<?php echo $nam;?>
</th>
<?php for($i=1;$i<=$totDays;$i++){?>
<?php if($commonObj->getDayOfDate($attData[$attk]['punch_time']) == $i){
echo "<td class='success' id='att_$i'>".$punchin.'-'.$punchout;?>
<table class="table table-responsive"style="display: none; position:relative;min-width:100px;max-width:200px; margin-top: -40px;" id="<?php echo "det_att_".$i;?>">
<tr>
<td>Time:</td>
<td><?php echo "p"?>
</td></tr>
<tr>
<td>UID:</td>
<td><?php echo $attData[$attk]['rfid_uid'];?></td>
</tr>
</table>
<?php
}else {echo "<td class='info'>#na";}?>
</td>
<?php }?>
</tr>
<?php }?>
</tr>
</table>`
this is the code for displaying on the web for viewing attendance ..
and here is the code for database part for getting attendance...
public function getAttendanceData($month,$year){
if(!is_numeric($month) || $month>12 || $month<1){
$this->setErrorMsg("Please Select valid month!");
header("location:viewAttendance.php");
exit;
}
$retData = array();
$fullDate = $year."-".$month;
//print_r($_SESSION);
if($_SESSION['user_type']==1){
$sql = "
SELECT t1.*
, t2.rfid_uid
, punch_time as punchin
, t2.name
FROM tbl_attendance as t1
right
join tbl_users as t2
on t1.rfid_uid = t2.rfid_uid
WHERE YEAR(punch_time) = $year
AND MONTH(punch_time) = $month
and t2.rfid_uid ='".$_SESSION['rfid_uid']."'
";
$retData = $this->getData($sql);
}else if($_SESSION['user_type'] == 2){
$sql = "SELECT t1.*,t2.rfid_uid,punch_time as punchin,t2.name FROM tbl_attendance as t1 right join tbl_users as t2 on t1.rfid_uid=t2.rfid_uid WHERE YEAR(punch_time) = $year AND MONTH(punch_time) = $month group by t2.rfid_uid";
$retData = $this->getData($sql);
}
return $retData;
}
web viewing imagedatabase table for attendanceuser
the attendance is recorded in the database but is not shown on the web..please help
I have question table and subject table and question table contain subject wise questions for online examination.
I need to fetch subject wise questions with subject name as header and show all the questions in subject wise serial number such as example: Maths: Q1, Q2, Q3
English: Q1, Q2, Q3 and so on.
How to achieve it in php and mysql. The question table and subject table are given below.
Question sample data are given below
<?php
require_once 'config.php';
//$con = mysqli_connect("localhost","root","","database_name");
$query1 = "SELECT q.q_id,q.setq_no, q.qtext_eng, s.sub_id, s.sub_name
FROM question q
INNER JOIN subject s ON s.sub_id = q.sub_id
INNER JOIN questionset qs ON qs.qset_id = q.qset_id
WHERE qs.qset_id =2 ORDER BY s.sub_id";
?>
<table class="table table-bordered">
<thead>
<tr>
<th>Q.No</th>
<th>Q Set number</th>
<th>Q text eng</th>
</tr>
<?php
$result1 = mysqli_query($link,$query1);
while($row1 = mysqli_fetch_array($result1))
{
$subID = $row1['sub_id'];
$subName = $row1['sub_name'];
?>
<h2><?php echo "$subName" ?></h2>
<?php
error_reporting(0);
$sno++;
$qSet = $row1['setq_no'];
$qEng = $row1['qtext_eng'];
?>
<tr>
<td><?php echo $sno; ?></td>
<td><?php echo $qSet; ?></td>
<td><?php echo $qEng; ?></td>
</tr>
</tbody>
</table>
<?php
}
?>
I am including some of your columns from question table here , you can add the rest same way
<?php
$con = mysqli_connect("localhost","root","","database_name");
$query1 = "SELECT q.q_id,q.setq_no, q.qtext_eng, s.sub_id, s.sub_name
FROM question q
INNER JOIN subject s ON s.sub_id = q.sub_id
INNER JOIN questionset qs ON qs.qset_id = q.qset_id
WHERE qs.qset_id =2 ORDER BY s.sub_id";
$presubID = 0;
<table class="table table-bordered">
while($row1 = mysqli_fetch_array($result1))
{
$subID = $row1['sub_id'];
if($subID != $presubID){
$subName = $row1['sub_name'];
<h2><?php echo "$subName" ?></h2>
$sno=0;
<thead>
<tr>
<th>Q.No</th>
<th>Q Set</th>
<th>Q text eng</th>
</tr>
</thead>
}
$presubID = $subID;
$sno++;
$qSet = $row1['setq_no'];
$qEng = $row1['qtext_eng'];
<tr>
<td><?php echo $sno; ?></td>
<td><?php echo $qSet; ?></td>
<td><?php echo $qEng; ?></td>
</tr>
<?php
}
?>
</table>
I have two tables one for members having fields as id , name
Second table as results with fields as rid , mid (member id foreign key), pid , score
I need to show name of member and their score where pid=$id
My query is :
$sel = mysql_query("SELECT m.name,r.score FROM member m, score r WHERE m.id=r.mid and r.pid='$id'");
<?php $i=0; while( $sql = mysql_fetch_assoc( $sel )) { ?>
<tr>
<td align="center"><?php $i++; echo $i; ?> </td>
<td align="center"><?php echo ucfirst( $sql['name'] ); ?></td>
<td align="center"><?php echo $sql['score']; ?></td>
</tr>
<?php } ?>
But no records are getting output.
There are matching records but it is not entering in while loop.
Use as:
$sel = mysql_query("SELECT m.name as name, r.score as score FROM member m, score r WHERE m.id=r.mid and r.pid='$id'");
Or so, if you do not want to use as:
<?php echo ucfirst( $sql['m.name'] ); ?>
I have a table where I need to fill an ID in a td using the value retrieved from a Mysql Table. I tried like this:
<?php
$ww = db_query("SELECT id, item1 FROM table1 WHERE table1.id = '".$record->main_data."'" );
?>
<td id="id_field1" class="<?php echo $ww->id;?>" >
<?php
foreach($ww as $ee)
{ echo $ee->item1;}
?>
</td>
I know the use of:
<td id="id_field1" class="<?php echo $ww->id;?>" >
is wrong, but I am not getting any other idea can you help me to generate an id for this td from the id retrieved from the Query?
EDIT
After the use of:
$ww = db_query("SELECT id, item1, FROM table1 WHERE table1.id = '" . $record->main_data . "'");
foreach ($ww as $row) {
?>
<td id="id_field<?php echo $row->id; ?>" class="<?php echo $row->id; ?>" >
<?php echo $row->item1; ?>
</td>
<?php
}
I am getting two issues--
1 ) Getting a warning from the DATATABLES plugin for fixedheader which says
Requesetd unknown parameter '11' for row 0
2 ) For empty td , the next <td> gets moved , instead of first <td> and I am getting the second <td> values of class and id inside the first... In this case, the table row is shifted to left with empty in the last column td
EDIT2 : this worked with no issues
I tried like this - is it ok to do like this: please comment on it-
<?php $ww = db_query("SELECT id FROM table1 WHERE table1.id = '".$record->main_data."'" );?>
<td id="id_field1" class="cart_wonid<?php foreach($ww as $ee) { echo $ee->id;}?>">
<?php
$ww = db_query("SELECT item1 FROM table1 WHERE table1.id = '".$record->main_data."'" );
foreach($ww as $ee){
echo $ee->main_data;
}
?>
</td>
EDIT
OP using drupal.
Put your td into the loop.
$ww = db_query("SELECT id, item1, FROM table1 WHERE table1.id = '" . $record->main_data . "'");
foreach ($ww as $row) {
?>
<td id="id_field<?php echo $row->id; ?>" class="<?php echo $row->id; ?>" >
<?php echo $row->item1; ?>
</td>
<?php
}
I am done with a CMS school system which i created from scratch for practice in php. My question is for example I have Accounting 101, Computer Science 101, however there must multiple times for Accounting 101. For example: Ticket 1035, 1036 are both Accounting 101 and they should appear in the same table, but in my code it shows them in different classes. Here is my code.
if(isset($_GET['id']))
{
$category = $_GET['id'];
$sql = "SELECT * FROM classes WHERE category_id = " . $category;
$query2 = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_object($query2))
{
?>
<center><h3><?php echo $row->class_name . '-' . $row->units; ?> </h3></center>
<table border ="0" wdith="100%">
<tr>
<td>
<strong>Description: </strong>
<?php echo $row->class_description; ?>
</tr>
</td>
</table>
<br/>
<table border="1" width="44%">
<tr>
<td width="60"><b>Ticket</b> </td>
<td width="123"><b>Days</b></td>
<td width="120"><b>Hours</b></td>
<td width="64"><b>Room</b></td>
<td><b>Instructor</b></td>
</tr>
<tr>
<td width="60"> <?php echo $row->ticket; ?> </td>
<td width="123"><?php echo $row->days; ?></td>
<td width="120"><?php echo $row->start_hours . $row->time_format . '-' . $row->end_hours . $row->time_format2 ; ?> </td>
<td width="64"> <?php echo $row->room_number; ?></td>
<td><?php echo $row->instructor_name; ?></td>
</tr>
}//end while
}//end if
Its showing Accounting 101 with different tickets in different tables, but it should be all in 1 table. Thanks.
You need a double loop if you're trying to get records inside of records. For example:
while ($row1 = mysql_fetch_object($query1))
{
echo $row1->ParentName;
$query2 = 'select * from `mytable` where `myForeignKey` = ' . $row1->ParentId;
while ($row2 = mysql_fetch_object($query2))
{
echo $row2->ChildName;
}
}
You could also do a left join. Let me know if you need a sample of that.
Edit:
The left join would be done like this:
$sql = "select * from `classes` as a where category_id = '{$category}' left join `tickets` as b on a.id = b.class_id"
Ref. http://www.w3schools.com/sql/sql_join_left.asp