Show error when url isnt allowed list? - php

Question

if $text isnt allowed list print error. Dont know how do do it
$allowedDomains = array('www.test1.com', 'www.test2.co.uk', 'test3.com');
$text = 'this is my url www.abcd.com/index.php?page=home';

Answer 1

try like this
$allowedDomains = array('www.test1.com', 'www.test2.co.uk', 'test3.com');
if ( !in_array('your-domain-name', $allowedDomains) {
echo 'show your error here';
} else {
echo 'do what ever you want here';
}

Answer 2

Here's another way of doing it: create a regex using the list of domains, and then use that to test your text strings.
$allowedDomains = array('www.test1.com', 'www.test2.co.uk', 'test3.com');
# concatenate the allowed domains with | and surround with brackets so the regex will
# match any of the array items
# i.e. $regex is (www.test1.com|www.test2.co.uk|test3.com)
$regex = "(" . implode("|", $allowedDomains) . ")";
# a couple of test strings
$texts = array('this is my url www.abcd.com/index.php?page=home',
'my home page is www.test3.com');
foreach ($texts as $t) {
if (preg_match("/$regex/", $t)) {
echo "Found a match! $t\n";
}
else {
echo "No match found: $t\n";
}
}
Output:
No match found: this is my url www.abcd.com/index.php?page=home
Found a match! my home page is www.test3.com

Answer 3

I've written a function for you that'll allow you to add / remove domain names and / or domain extensions as you please, taking into account that not everyone types "http(s)" and / or "www" into their domain searches and also the unpredictability of what kind of information might be behind the domain or not:
<?php
function testDomain($domain){
//Set domain names
$arrDomainNames = array("test1","test2","test3");
//Set domain extensions like .com .co .info
//Do NOT add .co.uk! .uk is taken care of in the regex
$arrDomainExt = array("com","co");
$cntDomainNames = count($arrDomainNames);
$cntDomainExt = count($arrDomainExt);
$i = 0;
$y = 0;
$DomNames = "";
$DomExt = "";
foreach($arrDomainNames as $value){
if($i == $cntDomainNames - 1){
$DomNames .= $value;
} else {
$DomNames .= $value ."|";
}
$i++;
}
unset($value);
foreach($arrDomainExt as $value){
if($y == $cntDomainExt - 1){
$DomExt .= $value;
} else {
$DomExt .= $value ."|";
}
$y++;
}
unset($value);
$pattern = "/((((http|ftp|https)+(:)+(\/{2})))?+(www\.)?(((". $DomNames .")+\.)+(". $DomExt .")+(\.uk)?(:[0-9]+)?((\/([~0-9a-zA-Z\#\+\%#\.\/_-]+))?(\?[0-9a-zA-Z\+\%#\/&\[\];=_-]+)?)?))\b/imu";
if(preg_match($pattern, $domain)){
echo "Domain match!<br />";
} else {
echo "Domain not match!<br />";
}
}
testDomain("www.test1.com"); //match
testDomain("test1.com"); //match
testDomain("http://www.test1.co.uk"); //match
testDomain("test1.com/info.php?who=you"); //match
testDomain("www.google.com"); //no match
?>

Answer 4

How to make it working with
$arrDomainNames = array("test1.com","test2.org","test3.co.uk","test3.net");
without
$arrDomainExt = array("com","co");