How to correctly check if page was included? [duplicate] - php

Question

This question already has answers here:
PHP: Check if a file is loaded directly instead of including?
(15 answers)
Closed 8 years ago.
I want to make sure that my pages are being included working index page. I would like to know what would be correct way of assuring that my page is being included instead of rendered by itself?
Right now I'm checking if there are at least 2 included files, but I'm not sure I'd it's behavior.
include('config/config.inc.php');
$cms = new cms();
if(($_SERVER['REQUEST_METHOD'] === 'GET' || $_SERVER['REQUEST_METHOD'] === 'POST') && !empty($_GET['page'])) {
include($cms->GetTheme() . "/head.php");
$cms->IncludeModule($_GET['page']); <- actual page being included
include($cms->GetTheme() . "/foot.php");
} // end (GET || POST) && GET
else { // just index.php
include($cms->GetTheme() . "/head.php");
foreach($cms->GetModuleList() as $module) {
echo " $module <br />";
}
include($cms->GetTheme() . "/foot.php");
} // end ELSE
Included page and how I check is it's included
<?php
$module_name = 'Log out user';
$module_directory = 'admin';
$this->SetTitle($module_name); // setting page title
if(count(get_required_files()) < 2) {
header('Location: index.php');
}
else {
if(isset($_SESSION['user'])) {
$this->DestroyUser();
echo "You have been logged out! Please navigate to the Login Page.";
}
else {
header('Location: index.php?page=login');
}
}
?>

Answer 1

I'm not sure if you're talking about this:
include 'test.php';
If yes, then do a simple test like this:
test.php
$testVar = '1';
index.php
include 'test.php';
echo $testVar;
I have no idea what library you're using, so i hope this simple example will allow you to understand.