Passing data between PHP files - php

Question

Here I have foo.php that runs in the background without any HTML, it's never visited by the user.
<?php
if (isset($_GET['data'])) {
$bar = $_GET['data']; // data comes from a html form on another page.
$str = strtoupper($bar);
echo $str;
}
This is just a simple example, but let's say I wan't to pass $str to another file, script.php for extra processing.
What's the best method for this? The only way I can think of doing this is by posting it into a database and then retrieving it inside of script.php ?

Answer 1

Using Session:
//On page 1
$_SESSION['varname'] = $bar;
//On page 2
$var_value = $_SESSION['varname'];
Remember to run the session_start() statement on both these pages before you try to access the $_SESSION array, and also before any output is sent to the browser.
Cookie:
//One page 1
$_COOKIE['varname'] = $bar;
//On page 2
$var_value = $_COOKIE['varname'];
As # Rizier123 mentioned "Cookies can be deleted or disabled! Wouldn't do that if the variable is very important ". So better avoid this approach.

Answer 2

Something like this is probebly a easy way to do it:
You can make a function out of the if statement
foo.php:
<?php
function fooFunction() {
if (isset($_GET['data'])) {
$bar = $_GET['data']; // data comes from a html form on another page.
$str = strtoupper($bar);
return $str;
}
}
?>
script.php:
<?php
require_once 'foo.php';
?>
OR if you already have a session you can insert it into the session array like this:
foo.php:
<?php
session_start();
if (isset($_GET['data'])) {
$bar = $_GET['data']; // data comes from a html form on another page.
$str = strtoupper($bar);
$_SESSION['str'] = $str;
}
?>
script.php:
<?php
session_start();
echo $_SESSION['str'];
?>

Answer 3

If you include (or require) a php script X into another php script Y, Y will have acces to all X datas and functions. You could also use sessions like #sanki commented.

Answer 4

Here are some links that could be useful for you:
include
require
Sessions

Answer 5

Pass data as GET parameter
<?php
if (isset($_GET['data'])) {
$bar = $_GET['data']; // data comes from a html form on another page.
$str = strtoupper($bar);
echo $str;
header("Location: script.php?data={$str}");
}
?>
But this will make script.php run immediately after current file.

Answer 6

you can do
`php script.php $str`;
to invoke script.php with your string as a command line argument.
http://php.net/manual/en/language.operators.execution.php