calling a php session variable from outer script - php

Question

i have a problem calling a session variable from another script. can anybody help me on this matter.
Below is the script that i create the session and store the time in a session variable.
<?php
session_start();
$orgtimestamp = date("Y-m-d h:i:sa");
$_SESSION['orgtimestamp'] = $orgtimestamp;
?>
Here is the script that i try to access this session variable from a function of it. till now nothing worked
<?php
include '../../mydomain/myscript.php';
class survey_Tracksciprt
{
public static function timeofclick(){
session_start();
$time_org = $_SESSION['orgtimestamp'];
echo $time_org;
}
}
this hasnt worked upto now, nothing prints...can anybody give tips to sought this out and its compulsory to have this function timeofclick

Answer 1

You're not creating your class on your second file add:
//I don't know what this does but if it already starts a session remove the session start inside the class.
include '../../mydomain/myscript.php';
$survey = new survey_Tracksciprt();
$survey::timeofclick();
class survey_Tracksciprt
{
public static function timeofclick(){
session_start();
$time_org = $_SESSION['orgtimestamp'];
echo $time_org;
}
}
I also advice putting session_start at the top of your file.

Answer 2

<?php
session_start();
include '../../mydomain/myscript.php';
class survey_Tracksciprt
{
public static function timeofclick(){
$time_org = $_SESSION['orgtimestamp'];
echo $time_org;
}
}
Always use the session_start(); at the top line of the page.

Answer 3

First, you need an init-session.php file, containing:
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
Second, you need to include this file at the start of your loader/layout (whatever you have there), so no operation will be executed before you initialize your session.
Third, you should initialize $orgtimestamp like this:
<?php
$orgtimestamp = date("Y-m-d h:i:sa");
$_SESSION['orgtimestamp'] = $orgtimestamp;
?>
Fourth, you need to call survey_Tracksciprt::timeofclick().