Change the result that shown in a table - php

Question

I have a table that has a column named result, the result is a variable that bank sent to me by post method... and the values are : 1, 2 ... so when the bank send to me 1 , I want show to the user its accepted, and if it was 2, show to the user its rejected... i need a if formulas that do the rest.
<?php
$id_get= $_POST['id_get'];
$trans_id = $_POST['trans_id'];
$servername = "localhost";
$username = "blah";
$password = "blah";
$dbname = "blah";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
?>
<?php
mysqli_query($conn, "SET NAMES 'utf8'");
$result = mysqli_query($conn,"SELECT id_get, trans_id, result FROM users");
echo "<table border='1' width='800' align='center'>
<tr>
<th>ID</th>
<th>transaction Result</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr align='center'>";
echo "<td width=10%>" . $row['id_get'] . "</td>";
echo "<td width=10%>" . $row['trans_id'] . "</td>";
echo "</tr>";
}
echo "</table>";?><br>
<div align="center">
<?php
mysqli_close($conn);
?>

Answer 1

use case in PHP
$resultname= $row['trans_get'];
switch($resultname){
case("1"):
echo "Accepted";
break;
case("2"):
echo "Rejected";
break;
default:
echo "N/A";
break;
}
So it should be something like:
while($row = mysqli_fetch_array($result))
{
$resultname= $row['trans_get'];
switch($resultname){
case("1"):
echo "Accepted";
break;
case("2"):
echo "Rejected";
break;
default:
echo "N/A";
break;
}
echo "<tr align='center'>";
echo "<td width=10%>" . $row['id_get']. "</td>";
echo "<td width=10%>" . $resultname . "</td>";
echo "</tr>";
}

Answer 2

You can check the value of $row['result'] inside the while($row = mysqli_fetch_array($result)) block and display the content of <td> accordingly
while($row = mysqli_fetch_array($result))
{
echo "<tr align='center'>";
echo "<td width=10%>" . $row['id_get'] . "</td>";
echo "<td width=10%>" . $row['trans_id'] . "</td>";
if ($row['result'] == '1') {
echo "<td width=10%>Accepted</td>";
}
else if ($row['result'] == '2') {
echo "<td width=10%>Rejected</td>";
}
else {
echo "<td width=10%>Unknown</td>";
}
echo "</tr>";
}
or alternatively you can change your query to this
$result = mysqli_query($conn,"SELECT id_get, trans_id, (CASE WHEN result = 1 THEN 'Accepted' WHEN result = 2 THEN 'Rejected' ELSE 'Unknown' END) AS result_description FROM users");
and simply display $row['result_description']
while($row = mysqli_fetch_array($result))
{
echo "<tr align='center'>";
echo "<td width=10%>" . $row['id_get'] . "</td>";
echo "<td width=10%>" . $row['trans_id'] . "</td>";
echo "<td width=10%>" . $row['result_description'] . "</td>";
echo "</tr>";
}

Answer 3

You can use a case statement:
SELECT id_get, trans_id,
(case when result = 1 then 'Accepted'
when result = 2 then 'Rejected'
else 'Unknown'
end) as ResultString
FROM users;
You can also create a reference table in the database and use a join. This is recommended for a real application, because it ensures that the same strings are used for any query.