I am trying to start using APIs, doing calls and so forth. Just barely starting to learn. Found a way to get Facebook shares on a post using the graph api.
I did this with PHP; here is the code:
$response = file_get_contents('https://graph.facebook.com/? id=mydomain.com');
echo $response;
this is the response that I get:
{"id":"http://sportsmockery.com/2014/11/hey-bears-fire-everyone/","shares":22}
What I want is to somehow get the share count (22) into a variable so I can do stuff with it…(i changed the domain that gets that share count to my domain.com);
anyway; I am not sure what is the standard way to do this, if you control what is received with how you do your call; or if you just get the full response and pull out what you want…
Been looking around and have not been able to find anything that will really help with this.
I am hoping someone can help me with this…
All the best, G
Use json_decode() which will make all of the properties easily accessible.
$parsedResponse = json_decode($response);
$count = $parsedResponse->shares;
echo $count;
This is a json response.
Parsing JSON file with PHP
http://php.net/manual/en/function.json-decode.php
Related
I used the code from http://angularjs.org/ (Wire up a Backend)
Here in project.js
angular.module('project', ['firebase']).
value('fbURL', 'https://angularjs-projects.firebaseio.com/').
factory('Projects', function(angularFireCollection, fbURL) {
return angularFireCollection(fbURL);
}).
config(function($routeProvider) {
I used this code in my web page. Instead of https://angularjs-projects.firebaseio.com/ url i want to use my url i.e http://test.com/test.php. But it didn't work.
Also i want to know in my php file in which format the out put should be?
Do you need to echo the content in php file or use the return command? Please give suggestion. I have searched a lot. I couldn't find the solution.
I think in firebase url https://angularjs-projects.firebaseio.com/ they are returning the response from their back-end service. That is why it didn't worked for you even if you changed the URL.
And answer to your second question;
If you make a call to your back-end service its better to have a json response style from your PHP and you don't have to use any return command for that. Instead you should echo your contents.
For example in your PHP file if you are getting the results as an array you can give back the response to the angular application as;
echo json_encode($result_array);
Hope it helps.
I think you should separate backend and frontend and treat them as two separated application. Both apps should communicate with each other by sending ajax request (front) and respone data in json format (backend). In my opinion it's the best way to handle this.
I got a response from the reddit API where the statistics from a link is made into a array. However, I can't figure out how to get the score-value from the response.
My current code:
http://pastebin.com/mH7udEKD
The response I get:
http://pastebin.com/N5smhxry
Should give you the score value:
$json_output['data']['children'][0]['data']['score']
it seems the only way to reach it is $json_result["data"]["children"][0]["data"]["score"].. are you sure this is the way to pull what you want from the API?
Just look at the response. Looks like this should do it:
$json_output['data']['children'][0]['data']['score']
spent a few hours trying to figure this out, but cannot for the life of me figure out what's going wrong.
All I'm trying to do is load this:
https://recruit.zoho.com/ats/EmbedResult.hr?jodigest=2cV.Sr2As6VxhLMxQGuTNij*g.Fb3J7ysduDs.AC9sU-&atslocale=en_GB&rawdata=json
which I believe is json, into either javascript/jquery or php and use the data.
I've looked into jsonp, followed some tutorials, used some demos as templates and just can't get the above data to work.
If anyone can shed some light it would be much appreciated. It really shouldn't be this complicated, but I don't know what's going wrong.
Yep, that's JSON. The site may not support JSONP, so you're gonna have to use PHP to do this.
This is untested, but should work.
<?php
$url = 'https://recruit.zoho.com/ats/EmbedResult.hr?jodigest=2cV.Sr2As6VxhLMxQGuTNij*g.Fb3J7ysduDs.AC9sU-&atslocale=en_GB&rawdata=json';
$JSON = file_get_contents($url);
// echo the JSON (you can echo this to JavaScript to use it there)
echo $JSON;
// You can decode it to process it in PHP
$data = json_decode($JSON);
var_dump($data);
?>
JSONP relies on the server to return a JSONP formatted response. Basically, to use JSONP the server needs to return a JSON string wrapped in a function invocation ({"foo":1} becomes func({"foo":1})).
As the server your using doesn't return a JSONP response, you cannot use JSONP, you can only use JSON.
This is a shame, as JSON cannot be used x-domain due to the same origin policy (SOP). Therefore, the only option you have is to use a proxy server, which retrieves the JSON from the server, and either gives it to you in JSONP (see Yahoo Pipes), or which is on the same domain as the requested page (write a simple PHP script to get the file using file_get_contents() and then echo the output), in which case it can return the JSON.
I breifly looked at the requirements and it looks like you need an API key as well as an account. I saw that the site provides services for XML and JSON only. It looks to be fairly well documented.
Hey, well I'm trying to use google images api with PHP, and I'm really not sure what to do.
This is basically what I have right now:
$jsonurl = "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=test";
$json = file_get_contents($jsonurl,0,null,null);
$json_output = json_decode($json);
Where would I go from there to retrieve the first image url?
With a minor change to the last line of your code sample, the following will output the url of the first image in the result set.
<?php
$jsrc = "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=test";
$json = file_get_contents($jsrc);
$jset = json_decode($json, true);
echo $jset["responseData"]["results"][0]["url"];
?>
For security reasons, most server configurations won't let you use file_get_contents on a remote file (different domain name). It would potentially allow a hacker to load code from anywhere on the Internet to your site, then execute it.
Even if your server configuration does allow for it, then I wouldn't recommend using it for this purpose. The standard tool for retrieving remote HTTP data is cURL, and there are plenty of good tutorials out there doing exactly what you should do in this case.
So, let's say you've successfully used cURL to retrieve the JSON array.
$json_output = json_decode($json); // Now the JSON is an associative array
foreach ($json_output['responseData']['results'] as $result)
{
echo $result['url'] . '<br />';
}
Of course, you don't have to echo the URL there; you can do whatever you need to with the value.
I have to say, this is 10 shades of awesome.. But I come with bad news (don't shoot the messenger..)
Important: The Google Image Search API has been officially deprecated as of May 26, 2011. It will continue to work as per our deprecation policy, but the number of requests you may make per day may be limited.
That is, as they same, lame.
I feel as if Google might have hired one-too-many layed-off-from-IBM-types... as they seem to be killing off all their "cool" API's.
They launch services haphazardly, promising this and that and the other thing... but then some middle-manager gets screamed at after realizing (ta-da!) that XYZ project doesn't generate income (like image results without ads, lol) and then... they axe it..
Lesson: Don't get married (aka build your software or service) around any google API you can't replace on-the-fly at a moment's notice... Now, I'm no LTS-junkie - I'm just bitter because I'd much rather get my Google results via XML or JSON than the icky HTML-soup they throw at you...
One Question #Marcel... How can I get an array, or at least multiple JSON result responses using that same "formula". I thought maybe the 1 meant "result 1", but alas, no... Is their a "trick" to generate a content stream ala a Picasa xml feed?
Are there any good, free ways to do this?
I found http://fonefinder.net, which looks okay. If that's my best best, how can I query it with a phone number and get the returned carrier? (I don't see an API).
Well, it looks like your query URL is as follows:
http://www.fonefinder.net/findome.php?npa={First Three}&nxx={Next Three}&thoublock={Last Four}
I would just get that page, use PHP's XML parser on the document. This should get you started:
<?php
$xmlDOC = simplexml_load_file(/* Your Request URL */);
print_r($xmlDOC->center->table[1]->tbody->tr[1]->td[4]->a->attributes());
?>
There is this website http://phonenumberprovider.com, for some reason it doesn't have a public API yet, but the developer told me that I can use this at the moment:
http://phonenumberprovider.com/api/json/+187605591648
Returns JSON like this:
{"result":"success","description":"Phone number provider found","operator":"JAMAICA","operatorPrefix":"1876","operatorCountry":"JM"}