I am trying to get some data from my sql. But the result for the $arra_detail[] keeps repeating ... here is my code .. please review it and let me know of the mistake I am making .. any help will be appreciated ..
//Process of getting data from table
$sql = "SELECT * FROM projects JOIN project_details ON projects.project_id=project_details.project_id";
$results = $conn->query($sql);
if($results->num_rows > 0){
while($row = $results->fetch_assoc()){
$pid = $row["project_id"];
$detailQuery = "SELECT * FROM project_details WHERE project_id = $pid";
$details = $conn->query($detailQuery);
if($details->num_rows > 0){
while ($r = $details->fetch_assoc()){
$projectDetails[] = array(
"project_detail" => $r["project_detail"],
"project_payment" => $r["project_payment"],
"project_payment_date" => $r["project_payment_date"],
"project_payment_status" => $r["project_payment_status"]
);
}
}
$data[$row["project_name"]] = array(
"project_id" => $row["project_id"],
"project_start_date" => $row["project_start_date"],
"project_due_date" => $row["project_due_date"],
"project_currency" => $row["project_currency"],
"poject_details" => $projectDetails
);
}
echo "<pre>", print_r($data) , "</pre>";
} else{
echo "No data found ";
}
use inner join query instead of two query with 2 loop
SELECT * FROM projects,project_details WHERE
projects.project_id=project_details .project_id
Related
UPDATE: a solution has been found stated below: however new issue poses i didnt want to keep creating question so updated this one when i use ajax to pass through to html i get the following error response.forEach is not a function
where the code is as below is this because there are now 2 arrays?
$.get('php/test.php', function(response) {
console.log(response);
var row;
response.forEach(function(item, index) {
console.log(item);
$(`td.${item.beacon}`).css('background-color', item.location).toggleClass('coloured');
});
});
Im Pretty naff when it comes to this type of thing but i need to try get these 2 queries added to 1 ajax I have been told i should add both queries to an outer array but im not sure how to do this and the example i got was $array = $other_array
but im not sure how to write it any help would be greatly appreaciated
$sql = "SELECT beacon,TIME_FORMAT(TIMEDIFF(max(`time`),min(`time`)), '%i.%s')
AS `delivery_avg`
FROM `test`.`test`
where date = CURDATE()
and time > now() - INTERVAL 30 MINUTE
group by beacon ";
$result = $conn->query($sql);
$sql2 = 'SELECT
*
FROM
(SELECT
beacon,location,date,
COUNT(location) AS counter
FROM `test`.`test`
WHERE `date` = CURDATE() and `time` > NOW() - interval 40 second
GROUP BY beacon) AS SubQueryTable
ORDER BY SubQueryTable.counter DESC;';
$result = $conn->query($sql2);
$result = mysqli_query($conn , $sql);
$rows = array();
while($r = mysqli_fetch_assoc($result)) {
$rows[] = $r;
}
echo json_encode($rows);
$result2 = mysqli_query($conn , $sql2);
$rows2 = array();
while($r = mysqli_fetch_assoc($result2)) {
$rows2[] = $r;
}
echo json_encode($rows2);
You already got most of it right. To get the data in one go, you can combine the arrays (see the line staring with $result) and then send it JSON formatted.
$sql1 = "SELECT ...";
// Query the database
$result1 = $conn->query($sql);
// Fetch the result
$rows1 = $result1->fetch_all(MYSQLI_ASSOC);
// Same for second query
$sql2 = 'SELECT ...';
$result2 = $conn->query($sql2);
$rows2 = $result2->fetch_all(MYSQLI_ASSOC);
$result = array(
'query1' => $rows1,
'query2' => $rows2
);
header("Content-Type: application/json");
echo json_encode($result);
Some more hints:
You only need to run the query once (you have ->query() and mysqli_query() in your code).
You don't need the loop to get all result rows. The function mysqli_fetch_all() does that for you.
When you have your 2 arrays with db results, you can do something like this :
$return = array (
$result,
$result2
);
echo json_encode($return);
$sendResponse = array (
'sql1' => $sqlResult1,
'sql2' => $sqlResult2
);
echo json_encode($sendResponse);
This would be a more suitable and convenient (from JavaScript size) way
$response = [];
$response['result_first_query'] = $rows;
$response['result_second_query'] = $rows2;
echo json_encode($response);
I was working on a post system..
So, I have to show posts by friends of the user and the groups in which user has participated..
Here is my code to show posts..
<?php
$sql = "SELECT * FROM posts WHERE uploader_id=:friend_id ORDER BY id DESC";
$query = $db->prepare($sql);
$query->execute(array(
":friend_id" => $friend_id
));
$rows = $query->fetchAll(PDO::FETCH_ASSOC);
foreach ($rows as $row) {
$name = $row['name'];
echo "POST BY $name";
}
$sql = "SELECT * FROM group_posts WHERE id=:member_group ORDER BY id DESC";
$query = $db->prepare($sql);
$query->execute(array(
":member_group" => $group_id
));
$rows = $query->fetchAll(PDO::FETCH_ASSOC);
foreach ($rows as $row) {
$name = $row['name'];
echo "POST BY $name";
}
?>
Now, I want all these posts to be shuffled in a way that all the posts of the post table and group_posts table are shown in the descending order.
UPDATE
I edited my code to this..
I figured out that first I'll have to code this before coding my post system..
<?php
$sql = "SELECT * FROM friends WHERE user_one=:me OR user_two=:me2 UNION SELECT * FROM group_members WHERE member_id=:me3";
$query = $db->prepare($sql);
$query->execute(array(
":me" => $my_id,
":me2" => $my_id,
":me3" => $my_id
));
$rows = $query->fetchAll(PDO::FETCH_ASSOC);
foreach ($rows as $row) {
$user_one = $row['user_one'];
$user_two = $row['user_two'];
$group_id = $row['group_id'];
if ($user_one == $my_id) {
$friend_id = $user_two;
} else {
$friend_id = $user_one;
}
echo $friend_id . "<BR>" . $group_id;
}
?>
Now, here's the problem..
This is successfully printing the $friend_id but, it shows an undefined index 'group_id' while printing $group_id.
I have checked all the fields are correct.
Try using just one query with UNION
SELECT *
FROM (
SELECT name, id FROM posts WHERE uploader_id=:friend_id
UNION
SELECT name, id FROM group_posts WHERE id=:member_group
) p
ORDER BY p.id DESC
Note, your inner queries must return the same number of columns in the same order (and I think with the same name/alias, too).
I want to retrieve the data from db using PHP
$device_owner_resultset=mysqli_query($con, "SELECT * FROM `device_owner_details` WHERE `deviceId` =$device_details_data_id");
$device_owner_resultset_data = mysqli_fetch_array($device_owner_resultset);
$owner_deviceid = $device_owner_resultset_data['deviceId'];
$owner_name = $device_owner_resultset_data['name'];
$name_fetch_rows = mysqli_fetch_row($device_owner_resultset);
$device_realtime_resultset=mysqli_query($con, "SELECT * FROM `device_realtime_stats` WHERE `deviceId` = $owner_deviceid LIMIT $start_from , $limit");
$rows_fetch = mysqli_fetch_row($device_realtime_resultset);
if(($total_pages<=$page) &&( $total_pages>0))
{
$device_details=array('devices'=> array());
for($i=1;$i<=20;$i++)
{
$details =array('name' => $name_fetch_rows[$i]-> name, 'latitude' => $rows_fetch[$i] -> currentLatitude, 'longitude' => $rows_fetch[$i] -> currentLongitude);
array_push($device_details['devices'],$details);
}
$response = json_encode($device_details);
echo $response;
}
Here i have an parse error, what is the mistake from my coding , i think error is in mysqli_fetch_rows and its calling array
You are not using mysqli_fetch_row($result) correctly. The function mysqli_fetch_row($result) does not return all the row data. It returns an array of a single row as an enumerated array. Try this code using this code instead:
// Now only selects name column and added LIMIT 1 to MySQL query for efficiency
$device_owner_resultset = mysqli_query($con, "SELECT name FROM `device_owner_details` WHERE `deviceId` = $device_details_data_id LIMIT 1");
// Now using mysqli_fetch_assoc($result)
// instead of mysqli_fetch_array($result) for clarity
$device_owner_resultset_data = mysqli_fetch_assoc($device_owner_resultset);
// Got rid of $owner_deviceid because it should be the same as $device_details_data_id
$owner_name = $device_owner_resultset_data['name'];
// Got rid of $name_fetch_rows because it is redundant with $device_owner_resultset_data
// Query now specifies which columns it selects for clarity and efficiency
$device_realtime_resultset = mysqli_query($con, "SELECT currentLatitude, currentLongitude FROM `device_realtime_stats` WHERE `deviceId` = $device_details_data_id LIMIT $start_from, $limit");
if ($total_pages <= $page && $total_pages > 0) {
$device_details=array('devices'=> array());
// This loops through all the rows from the query
while ($row = mysqli_fetch_assoc($device_realtime_resultset)) {
// $row is an associative array where the column name is
// mapped to the column value.
// The owner name should remain the same because there is
// only one owner.
$details = array('name' => $owner_name,
'latitude' => $row["currentLatitude"],
'longitude' => $row["currentLongitude"]
);
array_push($device_details['devices'], $details);
}
$response = json_encode($device_details);
echo $response;
}
If the columns of the device_realtime_stats table are not named currentLatitude and currentLongitude make sure they are renamed.
$mysql_all_resultset = mysqli_query($con, " SELECT dot.name, drs.currentLatitude, drs.currentLongitude FROM device_details dt, device_owner_details dot, device_realtime_stats drs WHERE dt.vendorId=$vendor_id AND dot.deviceId=dt.id AND drs.deviceId= dot.deviceId LIMIT $start_from, $limit ");
if(($total_pages<=$page) &&( $total_pages>0))
{
$device_details=array('devices'=> array());
while ($rows_fetch = mysqli_fetch_assoc($mysql_all_resultset))
{
$details =array('name' => $rows_fetch['name'], 'latitude' => $rows_fetch['currentLatitude'], 'longitude' => $rows_fetch['currentLongitude']);
array_push($device_details['devices'],$details);
}
$response = json_encode($device_details);
echo $response;
}
I have a multidimensional array where under "images" I want to loop 4 rows from my database. It means I am trying to put a loop into an array. Help me.
$sql_album = "SELECT * FROM albums";
$res_album = mysql_query($sql_album) or die(mysql_error());
$albums = array();
while ($row_album = mysql_fetch_assoc($res_album)) {
$albums[$row_album['title']] = array(
"description" => $row_album['description'],
"date" => $row_album['date'],
"images" => array(
//i want to insert a loop here shown down
)
);
}
This is the loop i want to insert where i wrote the comment in the upper script:
$sql_thumb = "SELECT * FROM photos WHERE album_id = '".$row_album['id']."' LIMIT 0, 4";
$res_thumb = mysql_query($sql_thumb) or die(mysql_error());
while ($row_thumb = mysql_fetch_assoc($res_thumb)) {
echo $row_thumb['thumb_url'];
}
Start here...
include('../path/to/mysqli/connection/statements');
$query = "
SELECT a.id
, a.title
, a.description
, a.date
, p.thumb_url
FROM albums a
LEFT
JOIN photos p
ON p.album_id = a.id
ORDER
BY a.id;
";
$result = mysqli_fetch_assoc($db,$query);
Sadly PHP does not allow this kind of usage. You could however do something like this
$sql_album = "SELECT * FROM albums";
$res_album = mysql_query($sql_album) or die(mysql_error());
$albums = array();
while ($row_album = mysql_fetch_assoc($res_album)) {
$albums[$row_album['title']] = array(
"description" => $row_album['description'],
"date" => $row_album['date'],
"images" => array()
);
$sql_thumb = "SELECT * FROM photos WHERE album_id = '".$row_album['id']."' LIMIT 0, 4";
$res_thumb = mysql_query($sql_thumb) or die(mysql_error());
while ($row_thumb = mysql_fetch_assoc($res_thumb)) {
$albums[$row_album['title']]["images"][] = row_thumb['thumb_url'];
}
}
I have this code
if(!isset($_GET['album_id'])) { die("Album Not Found!"); } else { $album_id = mysql_real_escape_string($_GET['album_id']); }
$sql = "SELECT * FROM `audio_albums` WHERE `album_id` = ".$album_id."";
$qry = mysql_query($sql);
$num = mysql_num_rows($qry);
if($num == 1) {
// Fetch Array
$arr = mysql_fetch_array($qry);
// Assign Values
$album_name = $arr['album_name'];
$album_name_seo = $arr['album_name_seo'];
$album_id = $arr['album_id'];
// Fetch Songs
$sql2 = "SELECT audio_id,album_id,title FROM `audios` WHERE `album_id` = ".$album_id." AND `public_private` = 'public' AND `approved` = 'yes' LIMIT 0, 30 ";
$qry2 = mysql_query($sql2);
$arr2 = mysql_fetch_array($qry2);
print_r($arr2);
} else {
echo "Album Not Found!";
}
and when i execute the code, it results in this
Array
(
[0] => qCpPdBZIpkXfVIg4iUle.mp3
[audio_id] => qCpPdBZIpkXfVIg4iUle.mp3
[1] => 1
[album_id] => 1
[2] => Ambitionz Az a Ridah
[title] => Ambitionz Az a Ridah
)
Actually it fetches data of only one row but there are several rows in result. Whats wrong in the code? why isn't it working?
Well, mysql_fetch_array fetches one row. You just need to do a loop to fetch all of them, as the manual shows: http://php.net/mysql_fetch_array
while ($arr2 = mysql_fetch_array($qry2)) {
print_r($arr2);
}
You really should learn some SQL ( yes , actually learn it ), and stop using the horribly outdated mysql_* functions.
$stmt = $dbh->prepare('
SELECT
audios.audio_id AS audio_id
audio_albums.album_id AS album_id
audios.title AS title
audio_albums.album_name AS album
audio_albums.album_name_seo AS seo_album
FROM audios
LEFT JOIN audio_albums USING (album_id)
WHERE
audio_albums.album_id = :id
audios.public_private = "public" AND
audios.approved = "yes"
LIMIT 0, 30
');
$stmt->bindParam( ':id', $_GET['album_id'], PDO::PARAM_INT );
if ( $stmt->execute() )
{
var_dump( $stmt->fetchAll(PDO::FETCH_ASSOC) );
}else{
echo 'empty .. try another';
}