mysql statement not working - php

Question

I have this code
if(!isset($_GET['album_id'])) { die("Album Not Found!"); } else { $album_id = mysql_real_escape_string($_GET['album_id']); }
$sql = "SELECT * FROM `audio_albums` WHERE `album_id` = ".$album_id."";
$qry = mysql_query($sql);
$num = mysql_num_rows($qry);
if($num == 1) {
// Fetch Array
$arr = mysql_fetch_array($qry);
// Assign Values
$album_name = $arr['album_name'];
$album_name_seo = $arr['album_name_seo'];
$album_id = $arr['album_id'];
// Fetch Songs
$sql2 = "SELECT audio_id,album_id,title FROM `audios` WHERE `album_id` = ".$album_id." AND `public_private` = 'public' AND `approved` = 'yes' LIMIT 0, 30 ";
$qry2 = mysql_query($sql2);
$arr2 = mysql_fetch_array($qry2);
print_r($arr2);
} else {
echo "Album Not Found!";
}
and when i execute the code, it results in this
Array
(
[0] => qCpPdBZIpkXfVIg4iUle.mp3
[audio_id] => qCpPdBZIpkXfVIg4iUle.mp3
[1] => 1
[album_id] => 1
[2] => Ambitionz Az a Ridah
[title] => Ambitionz Az a Ridah
)
Actually it fetches data of only one row but there are several rows in result. Whats wrong in the code? why isn't it working?

Answer 1

Well, mysql_fetch_array fetches one row. You just need to do a loop to fetch all of them, as the manual shows: http://php.net/mysql_fetch_array
while ($arr2 = mysql_fetch_array($qry2)) {
print_r($arr2);
}

Answer 2

You really should learn some SQL ( yes , actually learn it ), and stop using the horribly outdated mysql_* functions.
$stmt = $dbh->prepare('
SELECT
audios.audio_id AS audio_id
audio_albums.album_id AS album_id
audios.title AS title
audio_albums.album_name AS album
audio_albums.album_name_seo AS seo_album
FROM audios
LEFT JOIN audio_albums USING (album_id)
WHERE
audio_albums.album_id = :id
audios.public_private = "public" AND
audios.approved = "yes"
LIMIT 0, 30
');
$stmt->bindParam( ':id', $_GET['album_id'], PDO::PARAM_INT );
if ( $stmt->execute() )
{
var_dump( $stmt->fetchAll(PDO::FETCH_ASSOC) );
}else{
echo 'empty .. try another';
}