php check if date has passed - php

Question

I'm getting dates from a Wordpress field and I need to check if the dates have past or still to come.
$dates = ['date'=>'02/12/13','date'=>'10/12/14','date'=>'14/01/15'];
foreach ($dates as $date){
$the_date = $date['date'];
echo $the_date;
echo " ";
echo date('d/m/y');
echo " ";
if($the_date < date('d/m/y')){
echo 'gone';
}else{
echo 'to come';
}
}
The foreach echos out this.
02/12/13 22/11/14 gone
10/12/14 22/11/14 gone
14/01/15 22/11/14 gone
27/01/15 22/11/14 to come
10/02/15 22/11/14 gone
It looks like it's just checking the first day date.

Answer 1

A better option is to use the DateTime class. It allows to compare two DateTime instances using comparison operators.
$dates = ['02/12/13','10/12/14','14/01/15'];
foreach ($dates as $date) {
$the_date = \DateTime::createFromFormat('d/m/y', $date);
$now = new \DateTime();
echo $date." ".($the_date < $now ? 'gone' : 'to come')."\n";
}
The problem you see is because the dates are being compared as strings. The current date is "22/11/14" so it will be greater than any other date with a day starting with "1" or "0".
PD: Your array contains many elements using the same 'date' key. That is a problem so I've removed them in my example.

Answer 2

<?php
$dates = array('02/12/13','10/12/14','14/01/15');
$now = mktime(0,0,0);
foreach($dates as $date) {
$tmp = explode('/',$date);
$date_time = mktime(0,0,0,intval($tmp[1]),intval($tmp[0]),intval($tmp[2]));
echo $date . ' ' . ($now > $date_time?'gone':'to come') . "\n";
}

Answer 3

Use PHP's DateTime API :
$date='02/12/13';
if(\DateTime::createFromFormat('d/m/y',$date) < new \DateTime()){
//date is in the past
}else{
//date is either today or in the future
}
Offical PHP doc:
http://php.net/manual/en/class.datetime.php

Answer 4

Best way is to use timestamp: Try this:
foreach ($dates as $date){
$the_date = $date['date'];
echo $the_date;
echo " ";
echo date('d/m/y');
echo " ";
if( strtotime($the_date) < time() )
{
echo ' is gone';
}
else
{
echo ' is to come';
}
}

Answer 5

Keep her simple:
// $date is the date you need to compare to today
$date = ("2015 10 03");
// Make sure their formats are purely numeric and match
if ($date->format('m.d.y') >= date('m.d.y'))
{
your procedure...
}

Answer 6

I suggest using the capabilities of the DateTime class instead. Then you can do the check as follows:
<?php
$then = $reset_date;
$then = new DateTime($then);
$now = new DateTime(date("m-d-Y"));
$sinceThen = $then->diff($now);
$new = new DateTime($reset_date);
$old = new DateTime(date("m-d-Y"));
if ( $old->modify('+1 year') < $new) {
echo "<font color='red'>Reset now <br></font>";
echo "<font color='orange'>$sinceThen->y years <br></font>";
echo "<font color='orange'>$sinceThen->m months </font>";
echo "<font color='orange'>$sinceThen->d days have passed.<br></font>";
} else {
echo "<font color='green'> $sinceThen->y years <br>
$sinceThen->m months $sinceThen->d days till to Reset.</font>";
//Combined
}
?>