Get Year From Date string - php

Question

I want to check whether the current year is greater than a date string(D-M-Y) here is my code
$OldDate = "09-30-2011";
$OldYear = strtok($OldDate, '-');
$NewYear = date("Y");
if ($OldYear < $NewYear) {
echo "Year is less than current year"
} else {
echo "Year is greater than current year";
}

Answer 1

You can use strtotime():
$OldDate = "2011-09-30";
$oldDateUnix = strtotime($OldDate);
if(date("Y", $oldDateUnix) < date("Y")) {
echo "Year is less than current year";
} else {
echo "Year is greater than current year";
}
UPDATE
Because you're using an unconventional datestamp, you have to use different methods, eg:
$OldDate = "09-30-2011";
list($month, $day, $year) = explode("-", $OldDate);
$oldDateUnix = strtotime($year . "-" . $month . "-" . $day);
if(date("Y", $oldDateUnix) < date("Y")) {
echo "Year is less than current year";
} else {
echo "Year is greater than current year";
}
NOTE: If you want to always be sure that your date gets correctly understood by strtotime, use YYYY-MM-DD

Answer 2

use the date function to get year
$OldDate = date("Y",strtotime("09-30-2011"));
$NewYear = date("Y",strtotime("now"));
if($OldYear<$NewYear)
{
echo "Year is less than current year"
}
else
{
echo "Year is greater than current year";
}

Answer 3

You can achieve your goal by doing:
$input_date = date("09-30-2011");
$input_date_arr = explode("-", $input_date);
$currYear = date("Y");
$inputYear = $input_date_arr[2];
if ($currYear > $inputYear) {
echo "Current year is greater than given year!";
} else {
echo "Current year is not greater than given year!";
}

Answer 4

$OldDate = "09-30-2011";
$OldYear = date('Y',strtotime($OldDate));
$NewYear = date("Y");
if($OldYear<$NewYear)
{
echo "Year is less than current year"
}
else
{
echo "Year is greater than current year";
}

Answer 5

You could convert the string to a timestamp, and check it with the current timestamp
if(time($OldDate) < time()){
// do stuff
} else {
// do other stuff
}

Answer 6

do this,
$dateString = '2021-02-24';
$yr = date("Y", strtotime($dateString));
$mon = date("m", strtotime($dateString));
$date = date("d", strtotime($dateString));