How to output json data in array using curl - php

I have code here that will get json data using curl. Now I want to echo all data. This will show no output.
<?php
$json = file_get_contents('myurl');
$data = json_decode($json);
print_r($data);
?>
This is json coming from my url:
({"Response_Code":"0000","ResultMobilePrefix":["0917","0905","0906","0915","0916","0926","0927","0937","0935","0817","0936","0922","0923",
"0932","0933","0934","0942","0943","0907","0908","0909","0910","0912","0918","0919","0920","
0921","0928","0929","0930","0938","0939","0948","0949","0925","0989","0999","0947","0998","
0946","0975","0977"]});


All you need is
echo json_encode($json);


Use true to convert it into array;
$data = json_decode($json,true);
echo '<pre>';
print_r($data);


for displaying json in format use json_encode() and for proper format use JSON_PRETTY_PRINT
header('Content-type: application/json');
echo json_encode($json,JSON_PRETTY_PRINT);


you need to get rid of the bracket and semicolon on the JSON file first before you can use the json_decode();
<?php
$json = file_get_contents('myurl');
//remove the brackets
$json = str_replace("(", "", $json);
$json = str_replace(")", "", $json);
//remove the semicolon
$json = str_replace(";", "", $json);
$data = json_decode($json);
print_r($data);
?>
this is a bit ugly, but hope you get the idea, you need to remove that character first


I just want to add to what Manish has explained above. This is what PHP Docs say about the second parameter:
When TRUE, returned objects will be converted into associative arrays.
else you will simply get a stdclass object


The problem is the URL does not return a valid Json
you could simply try
var_dump($data);
this will return null because it's not a valid json see json_decode
this will work
$json = file_get_contents('myurl');
$json = preg_replace('/[ ]{2,}|[\t\n\r\(\)\;]/', '', trim($json));
$data = json_decode($json);
print_r($data);

Related

Read curl php result

I'm doing a curl and getting the JSON result as:
$data = json_decode($result, true);
var_dump($data);
$data = $data["data"];
echo $data;
However, the echo of $data is "{". If I do a var_dump before assigning again the variable I see:
string(727796) "{"data":["base64_image1", "base64_image2",... ]}"
Why am I not able to access the data list? I just want to do a foreach over this list, but I cannot.

output is json so try to json_decode() again

How to Json In PHP 'iyas'

http://simsimi.com/getRealtimeReq?uuid=VbQqwsQ3qiCw1T04VrrFQzBBlkfZibg3YFkbWz6VquZ&lc=id&ft=1&reqText=Eh+jelek&status=W
How to get value from respSentence
Im using php lang ^_^

" {"status":200,"respSentence" 11 \:"respSentence"}"` is not valid json. Use some online sites to validate your json and try like this,
$json = '{"status":200,"respSentence" :"iyas"}';
$array = json_decode($json, true);
echo $array ['respSentence'];

You can try using file_get_contents and json_decode PHP functions
$url = "http://simsimi.com/........";
$data = file_get_contents($url);
$json = json_decode($data, true);
echo $json ['respSentence'];
hope it helps

Parse Data from JSON URL

I'm trying to get data onto my website by parsing data from a JSON format. The URL is http://api.bfhstats.com/api/onlinePlayers and I'm trying to output for example the currently players online on PC.
Here's the current code I have:
<?$json = file_get_contents("http://api.bfhstats.com/api/onlinePlayers");
$data = json_decode($jsondata, true);
echo $data->pc->peak24;?>
I thought this would work, however it's not displaying anything. I am very new to parsing JSON data so if someone could explain what I'm doing wrong that would be brilliant.

change:
$data = json_decode($jsondata, true);
to
$data = json_decode($json, true);
Also, json_decode returns an array so use:
echo $data['pc']['peak24'];
to access the data.

You first call the variable $json but then use $jsondata in json_decode.

You are missing the foreach cycle to fetch the two dimensional array $data:
<?php
$json = file_get_contents("http://api.bfhstats.com/api/onlinePlayers");
$data=array();
$data = json_decode($json, true);
//print_r ($data);
foreach ($data as $pc) {
echo $pc["peak24"]."<br>";
}
?>
Check the $json and $jsondata that have different name but should be the same.

get Specific JSON Response Value

json response as below:
{"Success":true,"ErrorCode":0,"UserInformation":{"UserID":"19"}......
how do I get the UserID value by using json_decode?
I tried the below code with no luck.
$Response = json_decode($Response[2]);
echo $Response[0][0][0];

This should work:
<?php
$json = '{"Success":true, "ErrorCode":"0","UserInformation":{"UserID":"19"}}';
$response = json_decode($json, true);
echo $userId = $response["UserInformation"]["UserID"];
?>
Please check the PHP documentation of json_decode at http://php.net/json_decode
You can use object as well if you skip the second parameter of the json_decode function.

PHP json_decode brings back null

I am trying to get this to work but can't see where I'm going wrong. Can anyone assist?
<?php
$jsonurl = 'http://www.foxsports.com.au/internal-syndication/json/livescoreboard';
$json = file_get_contents($jsonurl,0,null,null);
$json_output = var_dump(json_decode($json,true));
echo $json_output
?>

Hint :
The initial JSON (stored in $json variable) does NOT validate.
Code : (FIXED)
<?php
$jsonurl='http://www.foxsports.com.au/internal-syndication/json/livescoreboard';
$json = file_get_contents($jsonurl,0,null,null);
$json = strip_tags(str_replace("jQuery.fs['scoreboard'].data =","",$json));
$json_output = var_dump(json_decode($json,true));
echo $json_output;
?>
This will work. :-)

Your JSON source is not valid. You can try this validator http://jsonlint.com/

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