How to Json In PHP 'iyas' - php

http://simsimi.com/getRealtimeReq?uuid=VbQqwsQ3qiCw1T04VrrFQzBBlkfZibg3YFkbWz6VquZ&lc=id&ft=1&reqText=Eh+jelek&status=W
How to get value from respSentence
Im using php lang ^_^


" {"status":200,"respSentence" 11 \:"respSentence"}"` is not valid json. Use some online sites to validate your json and try like this,
$json = '{"status":200,"respSentence" :"iyas"}';
$array = json_decode($json, true);
echo $array ['respSentence'];


You can try using file_get_contents and json_decode PHP functions
$url = "http://simsimi.com/........";
$data = file_get_contents($url);
$json = json_decode($data, true);
echo $json ['respSentence'];
hope it helps

Related

Parse Data from JSON URL

I'm trying to get data onto my website by parsing data from a JSON format. The URL is http://api.bfhstats.com/api/onlinePlayers and I'm trying to output for example the currently players online on PC.
Here's the current code I have:
<?$json = file_get_contents("http://api.bfhstats.com/api/onlinePlayers");
$data = json_decode($jsondata, true);
echo $data->pc->peak24;?>
I thought this would work, however it's not displaying anything. I am very new to parsing JSON data so if someone could explain what I'm doing wrong that would be brilliant.

change:
$data = json_decode($jsondata, true);
to
$data = json_decode($json, true);
Also, json_decode returns an array so use:
echo $data['pc']['peak24'];
to access the data.

You first call the variable $json but then use $jsondata in json_decode.

You are missing the foreach cycle to fetch the two dimensional array $data:
<?php
$json = file_get_contents("http://api.bfhstats.com/api/onlinePlayers");
$data=array();
$data = json_decode($json, true);
//print_r ($data);
foreach ($data as $pc) {
echo $pc["peak24"]."<br>";
}
?>
Check the $json and $jsondata that have different name but should be the same.

Decode G2A search results (json) to array

Help me to grab name of games from url
This page output json format.
I try to convert it to array, but my code not work. Please help me!
$url = 'https://search.g2a.com/items/select?json.wrf=jQuery111003403934023808688_1411464896728&q=NOT+type%3Aindividual+AND+(-type%3Agaming+AND+wholesaleQty%3A%5B1+TO+*%5D+AND+wholesaleMinPrice%3A%5B0+TO+198%5D)&wt=json&start=0&rows=10000&sort=sortOrder+DESC&_=1411464896757';
$content = file_get_contents($url);
$json = json_decode($content, true);
echo "<pre>";
print_r($json);
echo "</pre>";

You should remove the JSONP parameter json.wrf from the URL first:
https://search.g2a.com/items/select?q=NOT+type%3Aindividual+AND+(-type%3Agaming+AND+wholesaleQty%3A%5B1+TO+*%5D+AND+wholesaleMinPrice%3A%5B0+TO+198%5D)&wt=json&start=0&rows=10000&sort=sortOrder+DESC&_=1411464896757
This will return a proper JSON result.

The output from that URL (that I get currently starts with):
jQuery111003403934023808688_1411464896728({"responseHeader" ...
This isn't a pure JSON response, but rather a JSONP response.
If you're just trying to parse it in PHP, maybe something like:
$url = ...; // Your URL Here
$data = file_get_contents($url);
$pos = strpos($data, '{');
$data = substr($data, $pos, strlen($data) - $pos - 2);
$json = json_decode($data, true);
echo "<pre>";
print_r($json);
echo "</pre>";

get Specific JSON Response Value

json response as below:
{"Success":true,"ErrorCode":0,"UserInformation":{"UserID":"19"}......
how do I get the UserID value by using json_decode?
I tried the below code with no luck.
$Response = json_decode($Response[2]);
echo $Response[0][0][0];

This should work:
<?php
$json = '{"Success":true, "ErrorCode":"0","UserInformation":{"UserID":"19"}}';
$response = json_decode($json, true);
echo $userId = $response["UserInformation"]["UserID"];
?>
Please check the PHP documentation of json_decode at http://php.net/json_decode
You can use object as well if you skip the second parameter of the json_decode function.

get data from JSON file (with cURL)

I would like to trnsform some JSON data to a php array, this is my code:
<?php
$obj1=json_decode('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json', true);
$championname = $obj1[data][aatrox][name];
echo $championname;
?>
The problem is that i don't know how to get the data from http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json
How can i make this code work?

Try with file_get_contents() like this:
$json = file_get_contents('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json');
$obj1 = json_decode($json , true);
$championname = $obj1['data']['aatrox']['name'];
echo $championname;

Use file_get_contents to download a file.
$json = file_get_contents('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json');
$obj1 = json_decode($json, true);

PHP json_decode brings back null

I am trying to get this to work but can't see where I'm going wrong. Can anyone assist?
<?php
$jsonurl = 'http://www.foxsports.com.au/internal-syndication/json/livescoreboard';
$json = file_get_contents($jsonurl,0,null,null);
$json_output = var_dump(json_decode($json,true));
echo $json_output
?>

Hint :
The initial JSON (stored in $json variable) does NOT validate.
Code : (FIXED)
<?php
$jsonurl='http://www.foxsports.com.au/internal-syndication/json/livescoreboard';
$json = file_get_contents($jsonurl,0,null,null);
$json = strip_tags(str_replace("jQuery.fs['scoreboard'].data =","",$json));
$json_output = var_dump(json_decode($json,true));
echo $json_output;
?>
This will work. :-)

Your JSON source is not valid. You can try this validator http://jsonlint.com/

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