mysql only fetches single row rather than all - php

Question

Hello in my php code mysql only fetches 1 result which is in the last rather than all please help me why its doing like this here is my code
$requesthost = "SELECT * FROM tblvhost";
$reshost = mysql_query($requesthost);
while($rowhost=mysql_fetch_array($reshost)) {
$hostvid = $rowhost['vh_id'];
$hostname = $rowhost['vh_name'];
}

Answer 1

You’re overriding the data within each loop iteration:
while($rowhost=mysql_fetch_array($reshost)) {
$hostvid = $rowhost['vh_id']; // overwritten
$hostname = $rowhost['vh_name']; // overwritten
}
To collect all the data you probably want to append them to an array:
$hostvid = array();
$hostname = array();
while($rowhost=mysql_fetch_array($reshost)) {
$hostvid[] = $rowhost['vh_id']; // insert into array
$hostname[] = $rowhost['vh_name']; // insert into array
}

Answer 2

You are overwrite your variables in your loop. Store them into an array.
while ($rowhost = mysql_fetch_array($reshost)) {
$row[] = array(
'hostvid' => $rowhost['vh_id'],
'hostname' => $rowhost['vh_name']
);
}
var_dump($row);

Answer 3

this is a good question plus its a learning curve for the ones that are new that run into these types of issues
you're code
$requesthost = "SELECT * FROM tblvhost";
$reshost = mysql_query($requesthost);
while($rowhost=mysql_fetch_array($reshost)) {
$hostvid = $rowhost['vh_id'];
$hostname = $rowhost['vh_name'];
}
looks good, but what you are doing with or how are you applying hostvid? or hostname? you can just do
while($rowhost=mysql_fetch_array($reshost)) {
$rowhost['vh_id']; //do something with the var that's getting mysql field data
$rowhost['vh_name']; //same applies here. using $rowhost will continue to to provide data depending on what you have in the db. so you're OK.
}
if you want to store the data in an array for later use outside of the loop you can follow what #mudasobwa posted. good answer.