How would i go about the following problem which involves running an update query for every row in the array defined below? I hope it becomes clear...
<?php
//Some code
user = array();
while ($row = mysql_fetch_array ($auctioncheck)){
$fdt[] = $row['finish_time'];
if ($date_time >= $fdt) {
$user[] = $row['current_bidder'];
{
{
I then want to update a table which sets the value as "user[]". What is the neatest way of doing this? I presume it requires a while loop only i don't know how to do it in this context. So it would be like...
<?php
//Above while loop and then...
$update = mysql_query("UPDATE homepage SET username = '$user[]'...so on");
Basically i want the update to be performed for every user[] in the above array. I might be able to figure it out if i knew how to determine the number of rows in the the user array. Any help would be much appreciated. Cheers.
It looks like the for each will come into play. Only i am now concerned with the elements of multiple arrays being used in the update.
$user = array();
$seller = array();
while ($row = mysql_fetch_array ($auctioncheck)){
$fdt[] = $row['finish_time'];
if ($date_time >= $fdt) {
$user[] = $row['current_bidder'];
$seller[] = $row['seller'];
}
}
$update = mysql_query("UPDATE homepage SET username = '$user[]'...WHERE username = '$seller'");
Any ides anyone for the multiple elements and arrays.
It should be $user = array();
Is this what you're looking for?
<?php
//Above while loop and then...
foreach($user as $value){
$update = mysql_query("UPDATE homepage SET username = '$value'");
}
?>
This is not PHP
user = array();
You are missing the $
Besides
where is
{
{
come into play?
Related
I know this question might be very basic for someone experienced. But I'm still in the learning process so I need some help.
I want to populate a session array with data that's coming from the database. There can be multiple items in the session array. I'm trying to do it like this -
$sql = mysqli_query($con, "SELECT * FROM `purchase_info_details` WHERE `purchase_details_id` = '$pur_det_id'");
while ($row = mysqli_fetch_array($sql)) {
$data[$i]['purchase_details_id'] = $row['purchase_details_id'];
$data[$i]['cid'] = $row['id'];
$data[$i]['item_id'] = $row['item_id'];
$data[$i]['unit_id'] = $row['unit_id'];
$data[$i]['quantity'] = $row['quantity'];
$data[$i]['price'] = $row['price'];
$data[$i]['conv_rate'] = $row['conv_rate'];
$_SESSION['list1_data']['purchase_details_id'] = $data[$i];
}
FYI: purchase_details_id is the primary key. This code works partially. What I mean is I only get one row from the table in my session array but I need to get all the rows from the table that matches my SQL query.
I've been searching for a relevant example on the internet but yet to find any. I'm really stuck with it and couldn't find any solution. Please help!
Thanks!!
The problem is that your are always overwriting the same data in your session array. When your loop is finished, you will have the last row from your dataset in your session array.
To add a new row in your session array everytime you can proceed with either:
$_SESSION['list1_data'][] = $data[$i];
or if you want a specific key from your data (assuming it is unique):
$_SESSION['list1_data'][$row['purchase_details_id']] = $data[$i];
try something like this
while ($row = mysqli_fetch_array($sql)) {
$data[$i]['purchase_details_id'] = $row['purchase_details_id'];
$data[$i]['cid'] = $row['id'];
$data[$i]['item_id'] = $row['item_id'];
$data[$i]['unit_id'] = $row['unit_id'];
$data[$i]['quantity'] = $row['quantity'];
$data[$i]['price'] = $row['price'];
$data[$i]['conv_rate'] = $row['conv_rate'];
$_SESSION["db_data"][$i] = $data[$i];// or just $_SESSION[$i] = $data[$i]
}
$_SESSION['list1_data']['purchase_details_id'] = $data[$i]; always overwrite and you get only last value . use $_SESSION['list1_data'][$row['purchase_details_id']] = $data[$i];
just assign array to session when you finish your loop . like below
$_SESSION['list1_data'] = $data;
or as you say product_id is unique then why you use $i ? (use $data[$row['purchase_details_id']]['purchase_details_id'] = value , use $data[$row['purchase_details_id']]['cid'] = value etc ...)
Do this:
$_SESSION['list1_data'][$row['purchase_details_id']] = $data[$i];
This way you can directly access specific details id from the session. For example:
$row = $_SESSION['list1_data'][1]; //row for the id = 1
Pro tip: Always check if the key is set or else you will get warnings =)
make sure that you are initialize the session() method, and you can make a 2 or 3 dimensional array as you need to keep the database value as #B-and-P mention in his comments.
thanks
Okay so I am trying to create a custom function that will echo a site url inside an iframe for the end user.
The script has to check whether or not the user has already seen the site and if they have seen it don't display it any more, but take another site url from the database etc.
Here's what I have come up with so far:
function get_urls() {
require 'config.php';
global $con;
global $currentUsername;
$con = mysqli_connect($hostname, $dbusername, $dbpassword, $dbname);
$query = "SELECT site_url FROM sites WHERE site_url IS NOT NULL";
$result = mysqli_query($con, $query);
// Get all the site urls into one array
$siteUrls = array();
$index = 0;
while($row = mysqli_fetch_assoc($result)) {
$siteUrls[$index] = $row;
$index++;
}
$query2 = "SELECT site_url FROM views WHERE user = '$currentUsername' AND site_url IS NOT NULL";
$result2 = mysqli_query($con, $query2);
// Get urls the user has already seen into another array
$seenUrls = array();
$index = 0;
while($row2 = mysqli_fetch_assoc($result2)) {
$seenUrls[$index] = $row2;
$index++;
}
// Compare the two arrays and create yet another array of urls to actually show
$urlsToShow = array_diff($siteUrls, $seenUrls);
if (!empty($urlsToShow)) {
// Echo the url to show for the iframe within browse.php and add an entry to the database that the user has seen this site
foreach ($urlsToShow as $urlToShow) {
echo $urlToShow;
$query = "INSERT INTO views VALUES ('', '$currentUsername', '$urlToShow')";
mysqli_query($con, $query);
break;
}
}
// Show the allSeen file when all the ads are seen
else {echo 'includes/allSeen.php';}
mysqli_free_result($result);
mysqli_close($con);
}
I have currently found two errors with this. First the $siteUrls and $seenUrls are all okay, but when I compare the two using array_diff then it returns an empty array.
Secondly the script doesn't write the site url into the database because the $urlToShow is an array not a single url?
I think the problem is in your code is at the place where you are creating your $siteUrls, $seenUrls arrays. mysqli_fetch_assoc() function will give you a result row as an associative array. So if you want to change some of your code in the while loops.
Please chnage this
while($row = mysqli_fetch_assoc($result)) {
$siteUrls[$index] = $row;
$index++;
}
To
while($row = mysqli_fetch_assoc($result)) {
$siteUrls[$index] = $row['site_url'];
$index++;
}
And in the second while loop also. Change this
while($row2 = mysqli_fetch_assoc($result2)) {
$seenUrls[$index] = $row2;
$index++;
}
To
while($row2 = mysqli_fetch_assoc($result2)) {
$seenUrls[$index] = $row2['site_url'];
$index++;
}
and try
i would not run two queries and try to merge the result array. you can use mysql itself to just return the sites that have not been seen yet:
SELECT sites.site_url FROM sites
LEFT JOIN views ON views.site_url=sites.site_url AND views.user='$currentUsername'
WHERE sites.site_url IS NOT NULL AND views.site_url IS NULL
This will return only site_urls from sites, that have no entry in the views table. The LEFT JOIN will join the two tables and for every non-matching row there will be NULL values in the views.site_url, so that is why i am checking for IS NULL.
Your saving of $urlToShow should work, if you set to $row field content and not $row itself as suggested, but if you want to check what is in the variable, don't use echo use this:
print_r($urlToShow);
If the variable is an array, you will see it's content then.
#Azeez Kallayi - you don't need to index array manually.
$seenUrls[] = $row2['site_url'];
In addition, you can fetch all result
$rows = mysqli_fetch_all($result2,MYSQLI_ASSOC);
foreach($rows as $row){
echo $row['site_url'];
}
Iwas wondering if someone could help me?
I have a table called markers, in this table it stores multiple records each with a name etc. I would like to echo each name however the below code only shows one results. How can I show more than one. Can someone please help I am new to PDO.
$stmt = $dtb->query('SELECT * FROM markers');
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$markerName = $row['name'];
}
Use an array to hold the result, in your code, the variable $markerName is overwrote on each iteration.
$stmt = $dtb->query('SELECT * FROM markers');
$markerName = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$markerName[] = $row['name'];
}
That is because you are overwriting it each and every time , use an array instead.
Rewrite like this...
$markerName = array(); //<---- Add here
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$markerName[] = $row['name'];
}
echo implode('<br>',$markerName); //<---- Implode it up for display
Rewrite like this
$names = $dtb->query('SELECT * FROM markers')->fetchAll();
Being new to PDO, you are supposed to try tag wiki first, where you can find an answer not only to this one but to many other questions.
There is probably something dumb I am doing wrong here.
public function get_scores($id)
{
$results = array();
$sql = "SELECT * FROM scores WHERE comp_id = $id";
$rows = $this->db->query($sql)->result();
foreach($rows as $row) {
if($row->confirmed_id) {
$results[$row->uid] += $row->score;
}
}
sort($results);
return $results;
}
So basically what I am trying to do is add all of the users scores in the database and return them in order of rank. confirmed->id is just a check to make sure the score has been confirmed (and thus is addable to their total score). I am basically trying to just make an associative array where the key is the users ID, and the score of each question they have in the database is added on. The query works fine, and $row-uid and $row->score both return the correct thing for every row, but $results[] never has anything added to it. If I even change it just to something silly like $results[3] = 0 at top, and then $results[3]++ or += 1 in the for loop, it doesn't add anything to $results[3].
EDIT: Problem solved. Indeed was something dumb -- confirmed_id was set to null by my partner when he reran our database after I had previously set it all to 1. Thanks guys :)
You are adding to $results[something] before it exists. You need to create it in the first case and then only increment it once it exists.
You need to remove the "+=" operation from the code. Check with this.
public function get_scores($id)
{
$results = array();
$sql = "SELECT * FROM scores WHERE comp_id = $id";
$rows = $this->db->query($sql)->result();
foreach($rows as $row)
if($row->confirmed_id)
$results[$row->uid] = $row->score;
sort($results);
return $results;
}
Your previous operation is similar to
$results[$row->uid] = $results[$row->uid] + $row->score;
So it will not add values to your row.
tl;dr - Pushing an array (by $array[] or $array[$id] is not working in Kohana 3, it gives a blank white page.
I'm using Kohana (3), it's my first experience with MVC and it's been great so far; however, I'm working with a database and encountered a weird problem that I was hoping someone could shed some light on:
My workflow is like this, to give you an idea of my problems surrounding:
$sql = "SELECT table1.row1, max(table2.row1) as `maxAwesome` FROM table1, table2 WHERE table1.id=table2.table1id GROUP BY table1.id";
$table1Results = DB::query(Database::SELECT, $sql)->execute();
$masterArray = array();
foreach ($table1Results as $result1)
{
$sql = "SELECT * FROM table2 WHERE table2id='" . $result1['id'] . "' AND column > 21";
$table2Results = DB::query(Database::SELECT, $sql)->execute();
$subArray = array();
foreach ($table2Results as $result2)
{
$subArray[$result1['id']] = $result2;
// Even had just $subArray[] = array("whatever");
}
$masterArray[] = array("table1Data" => array(), "table2Data"=> $subArray);
}
I do a query where I run a couple max/min functions then do a query within the foreach doing another select to build a master array of data formatted the way I want it and all the SQL etc works fine and dandy; however, the problem arises when I'm pushing the array.
It seems whenever I push the array by doing either $array[] = array("data"); or by specifying the key $array[$id] = array("data"); Kohana gives me a straight blank page, no error, no output etc.
Sometimes I get a Kohana error indicating the key does not exist (duh, I'm creating it) but for the most part the output is straight white.
Why is this happening? Am I going about it wrong?
Thanks in advance.
Clarity edit:
My SQL blunders aside, the issue lies in the building of the secondary array, for example:
$queryStores = "SELECT stores.store_id, stores.title, max(product.discount) as `max_discount`, min(product.discount) as `min_discount`
FROM stores, products
WHERE products.store=stores.store_id
GROUP BY products.store";
$stores = DB::Query(Database::SELECT, $queryStores)->execute();
$formattedStores = array();
if (count($stores))
{
foreach ($stores as $store)
{
$formattedStores[$store['store_id']] = array(
"title" => $store['title'],
);
// Same result if just doing $formattedStores[] = array();
// Problem goes away should I do:
// $formattedStores = array("This works");
//
}
}
echo "<pre>";
print_r($formattedStores);
echo "</pre>";
That does not print an array, it simply gives a blank page; however, if i change it to just re-set the $formattedStores array to something I get an output. What is it about pushing the array that's causing a problem, perhaps a Kohana bug?
Thanks
Your code should be like:-
$sql = "SELECT table1.id, table1.row1, max(table2.row1) as `maxAwesome`
FROM table1, table2
WHERE table1.id = table2.table1id
GROUP BY table1.id";
$table1Results = DB::query(Database::SELECT, $sql)->execute();
$masterArray = array();
if (count($table1Results))
{
foreach ($table1Results as $result1)
{
$sqlInner = "SELECT * FROM table2
WHERE table2id = '" . $result1['id'] . "'
AND column > 21";
$table2Results = DB::query(Database::SELECT, $sqlInner)->execute();
$subArray = array();
if (count($table2Results))
{
foreach ($table2Results as $result2)
{
$subArray[$result1['id']] = $result2;
// Even had just $subArray[] = array("whatever");
}
}
$masterArray[] = array("table1Data" => array(), "table2Data"=> $subArray);
}
}
Some valuable coding standards & miss-ups:-
You have got the "id" field (w.r.t. the "table1" DB table) missing from the first SQL.
The second SQL should be better written using another variable naming, so as to keep it separate from the first one. Hence the second variable is named as "$sqlInner".
It's always better to check for any existence of array elements in an array variable, so I have used the simple checks using the "if" statement.
Hope it helps.
I've determined this to be memory related.