I have beneficiary which have multiple transactions. On home page I want to show the latest transaction created by the customer. So, latest transaction's beneficiary should come on top with amount details.
I have created query something like this. But it doesn't show the latest transaction.
$clause = "SELECT b.*, tran.transfer_amount, tran.date_added as tran_date_added
FROM beneficiary b
LEFT JOIN customer_beneficiary_mapping cbm ON b.id = cbm.ben_id
LEFT JOIN
(SELECT ben_id, transfer_amount, date_added
FROM transaction
GROUP BY ben_id
) tran
ON tran.ben_id = b.id
INNER JOIN system_country_list scl ON scl.country_id = b.ben_country
AND cbm.cus_id = '$cus_id'
ORDER BY tran.date_added DESC
";
maybe this works:
SELECT b.*, tran.transfer_amount, tran.date_added as tran_date_added
FROM beneficiary b
LEFT JOIN customer_beneficiary_mapping cbm ON b.id = cbm.ben_id
LEFT JOIN
(SELECT ben_id, transfer_amount, date_added
FROM transaction
GROUP BY ben_id
) tran
ON tran.ben_id = b.id
AND tran.date_added = (SELECT MAX(date_added) FROM transaction WHERE ben_id = b.id)
INNER JOIN system_country_list scl ON scl.country_id = b.ben_country
AND cbm.cus_id = '$cus_id'
ORDER BY tran.date_added DESC
Note that i just added a subselect in where clause: AND tran.date_added = (SELECT MAX(date_added) FROM transaction WHERE ben_id = b.id)
I found the solution. Rather than deleting the question, I am posting the answer if somebody needs.
$clause = "SELECT b.*, tran.transfer_amount, tran.date_added as tran_date_added
FROM beneficiary b
LEFT JOIN customer_beneficiary_mapping cbm ON b.id = cbm.ben_id
LEFT JOIN
(SELECT ben_id, transfer_amount, date_added
FROM transaction
GROUP BY ben_id
ORDER BY 1 DESC <----- Added this line
) tran
ON tran.ben_id = b.id
INNER JOIN system_country_list scl ON scl.country_id = b.ben_country
AND cbm.cus_id = '$cus_id'
ORDER BY tran.date_added DESC
";
I still don't know, how come it's working now. I also tried with ORDER BY date_added DESC before. But, it was not working. Anyway, It's working now. :)
Related
This is my code i am trying to left join the latest team data, not every piece of data. i have tried just using limit 1 but doesnt return anything
ORDER BY updated DESC LIMIT 1
this doesnt work
Any ideas?
$sql = "SELECT
events.id, events.time,events.status, events.home_team,events.away_team,events.league,
ht.id as home_id,ht.name as home_name,at.name as away_name,
statistics.home_goals,statistics.away_goals,statistics.time as game_time,
leagues.id as league_id,leagues.name as league_name,leagues.type as league_type,
country.name as country_name,country.logo,
hts.home_scored, ats.away_scored,
hts.home_conceeded,ats.away_conceeded,
hts.home_win,ats.away_win,
hts.home_15,ats.away_15,
hts.home_25,ats.away_25,
hts.home_btts, ats.away_btts,
hts.home_fts, ats.away_fts,
hts.home_cs, ats.away_cs,
hts.home_corners_for, ats.away_corners_for,
hts.home_corners_against, ats.away_corners_against,
hts.home_cards, ats.away_cards
FROM events
LEFT JOIN teams ht
ON ht.id = events.home_team
LEFT JOIN teams at
ON at.id = events.away_team
LEFT JOIN leagues
ON leagues.id = events.league
LEFT JOIN country
ON country.id=leagues.country
LEFT JOIN ( SELECT team,home_scored,home_conceeded,home_win,home_15,home_25,home_btts,home_fts,home_cs,home_corners_for,home_corners_against,home_cards FROM team_quick_stats ORDER BY updated DESC) hts
ON ht.id=hts.team
LEFT JOIN ( SELECT team,away_scored,away_conceeded,away_win,away_15,away_25,away_btts,away_fts,away_cs,away_corners_for,away_corners_against,away_cards FROM team_quick_stats ORDER BY updated DESC) ats
ON at.id=ats.team
LEFT JOIN statistics
ON statistics.event_id=events.id
WHERE (events.time BETWEEN $start AND $end) ORDER BY country.list_order, leagues.country ASC , leagues.id ASC, events.time ASC, home_name ASC";
Here's one way. Replace LEFT JOIN (SELECT team... etc....) ats with...
LEFT
JOIN
( SELECT x.team
, x.etc...
FROM team_quick_stats x
JOIN
( SELECT team
, MAX(updated) updated
FROM team_quick_stats
GROUP
BY team
) y
ON y.team = x.team
AND y.updated = x.updated
) ats...
I'm trying to create a leaderboard but i'm not sure how to do the mysql query.
I would like to count all the levels from a player in the skills table and get the total Level and count all the experience from a player in the experience table and get the Total Exp along with displaying the persons name from the users column.
There is 3 tables factions_mcmmo_users, factions_mcmmo_experience, factions_mcmmo_skills.
This is what i have so far but it doesn't work:
$sql = ("SELECT a.id,
(SELECT COUNT(*) FROM factions_mcmmo_experience WHERE user_id = a.id) as TotalXP,
(SELECT COUNT(*) FROM factions_mcmmo_skills WHERE user_id = a.id) as TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a LIMIT 10;");
Any help would be very appreciated
EDIT: I have it working now but i'm unsure if its the most efficient way to do things so if anyone could help me out if theres a better way, it would mean a lot.
I would also like to know if it's possible to display the total exp and level with commas if the number is in the thousands for example: total level 5,882 and total xp 582,882
EDIT 2:
I have figured out how to format the numbers but still don't know if my code is efficient
$sql = ("SELECT id, user,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_skills b WHERE b.user_id = a.id) as TotalLevel,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_experience c WHERE c.user_id = a.id) as TotalXP
FROM (SELECT id, user FROM factions_mcmmo_users) a group by id ORDER BY TotalLevel DESC, TotalXP DESC LIMIT 10;");
EDIT 3
Updated code from scaisEdge but was displaying everyones level as 1 and XP as 1, so i changed count(*) changed to sum, added an order By TotalLevel in Descending order and that seems to have worked but i can't get it to display the persons name (user column) in the user table? not sure if i was supposed to change to sum because it didn't work the other way.
$sql = ("SELECT a.id, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC
LIMIT 10;");
EDIT 4
Everything working but when i try to format the totals using "FORMAT(Sum(Columns), 0) on the inner joins, the EXP Total appears to work but the main Total Level is not displaying results that are over 1,000 and it breaks the leaderboard positioning, it should be sorting them on total level but it appears to be random, when u remove the format,0 it goes back to working
I would like it to display commas if the number number is the thousands for example: Total Level: 5,532 and Total EXP 5882,882
See live demo: http://mcbuffalo.com/playground/leaderboards/server/factions-mcmmo.php
Updated Code trying to use Format:
$sql = ("SELECT a.id, a.user, b.TotalXP, c.TotalLevel
FROM (SELECT id, user FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC;");
EDIT 5
Changed number with PHP, everything works
Original Images
you could use an couple of inner join
$sql = ("SELECT a.id, a.name, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id, name FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, COUNT(*) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, COUNT(*) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
LIMIT 10
I have this database design:
**users_tbl**
id
username
name
**posts_tbl**
id
url
users_id *FK REFERENCE to users table*
**posts_contents_tbl**
id
posts_id *FK REFERENCE to posts table
title
description
date
views
click
isDeleted
I'm using this query
SELECT a.name,a.username,c.*
FROM users_tbl a
LEFT JOIN posts_tbl b ON a.id = b.users_id
LEFT JOIN posts_contents_tbl c ON b.id = c.posts_id
ORDER BY c.id ASC
Why I try to run this query it gives me NULL results, sample output is like this
But when I try to remove the ORDER BY c.id ASC it gives me this output:
That's not my expected result.
My expected result would be it will display the posts_contents_tbl in Ascending order at the same time it won't show some null values. Some users in my database doesn't have posts data in the posts_tbl so they should not show too.
How would I do that one? Your help would be greatly appreciated and rewarded!
Thanks!
PS: I already have thousands record in my database.
In that case, you have to use INNER JOIN instead of LEFT JOIN because you only want users with posts to show. The reason why there are Null values is because the records are based on table users_tbl and you've mentioned that some of them have no post. Right?
Try this:
SELECT a.name,
a.username,
c.*
FROM users_tbl a
INNER JOIN posts_tbl b
ON a.id = b.users_id
INNER JOIN posts_contents_tbl c
ON b.id = c.posts_id
ORDER BY c.`date` DESC
I think this is what you are looking for:
SELECT a.name,a.username,c.*
FROM users_tbl a
INNER JOIN posts_tbl b
ON a.id = b.users_id
LEFT JOIN posts_contents_tbl c
ON b.id = c.posts_id
ORDER BY IFNULL(c.id, 0) ASC;
If you really needs that posts_tbl data should not display if not available.And all data of posts_contents_tbl then you need a RIGHT JOIN and INNER JOIN .
The Query like :-
SELECT a.name,a.username,c.*
FROM users_tbl a
INNER JOIN posts_tbl b ON a.id = b.users_id
RIGHT JOIN posts_contents_tbl c ON b.id = c.posts_id
ORDER BY c.id ASC;
I've got reporting of a user's score everytime it happens. Now I want to show the best score a user has had. The table set up is like this:
Player(id, name)
PlayerHasAchievement(id, playerId,
achievementId)
Achievement(id, type, amount, time)
This is what I have right now:
$query = "SELECT MAX(ach.amount) as amount, p.username, ach.time
FROM achievement as ach
INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.id
INNER JOIN player as p ON p.userId = playAch.userid
WHERE ach.type = 2
GROUP BY amount
ORDER by `amount` DESC
LIMIT $amount";
I tried to select it distinctly but it didn't work. I'm stumped, it's supposed to be so easy! Thanks for reading, I'll be grateful for any help!
The problem is the the ach.time you are getting is not the same row as the MAX(amount). Join another subquery to get the MAX(amount) first.
Note: In the table definitions you posted, playerHasAchievement has a field playerId not userId
SELECT MAX(ach.amount) as amount, p.username, MAX(ach.time) MaxTime
FROM achievement as ach
INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.id
INNER JOIN player as p ON p.userId = playAch.playerId
INNER JOIN (
SELECT playAch.playerId, MAX(ach.amount) as MaxAmount
FROM achievement as ach
INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.id
WHERE ach.type = 2
GROUP BY playAch.playerId
) g ON p.playerId = g.playerId AND ach.amount = g.MaxAmount
WHERE ach.type = 2
GROUP BY p.playerId
ORDER by `amount` DESC
LIMIT $amount";
The reason why we group the outer query, is to avoid ties - say a player had the same score twice.
In your join on line 3 don't you really want
INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.achievementId
and others are correct, you need to group by your non aggregate columns, not the aggregate one.
Assuming your db layout is as specified in the question here is the query I would use.
SELECT ach.amount, p.Name, ach.time
FROM achievement as ach
JOIN playerHasAchievement as playAch ON ach.id=playAch.achievementId
JOIN player AS p ON p.id = playAch.playerId
WHERE ach.type = 2
AND ach.amount = (SELECT MAX(ach.amount)
FROM achievement as ach
JOIN playerHasAchievement as playAch ON ach.id=playAch.achievementId
JOIN player AS p ON p.id = playAch.playerId
WHERE ach.type = 2)
GROUP BY ach.amount
ORDER by ach.time
taking the first result (in case there are multiples of the same score) will give you the high score and the lowest time.
Hope that helps!
You are not using group by appropriately, as you are only grouping by amount.
What about the user name and the time?
Please I want to add another table (Comments) to this query to count the number of comments for each article.
$query = "SELECT M.id,M.j_surname,A.j_user_id,A.id,A.jart_title, A.jart_description, A.jart_createddate, COUNT(C.artid) AS count_comments FROM jt_articles A, jt_members M, jt_article_comments C where M.id = A.j_user_id AND C.artid = A.id ORDER BY A.jart_createddate DESC
update:
something like that (you dont post the scheme of the comments table)
SELECT M.id,M.j_surname,A.j_user_id,A.id,A.jart_title, A.jart_description,
A.jart_createddate , COUNT(A.id) AS count_comments
FROM jt_articles A
left join jt_members M on M.id = A.j_user_id
left join jt_article_comments C on C.artid = A.id
group by A.id
ORDER BY A.jart_createddate DESC