This is my code i am trying to left join the latest team data, not every piece of data. i have tried just using limit 1 but doesnt return anything
ORDER BY updated DESC LIMIT 1
this doesnt work
Any ideas?
$sql = "SELECT
events.id, events.time,events.status, events.home_team,events.away_team,events.league,
ht.id as home_id,ht.name as home_name,at.name as away_name,
statistics.home_goals,statistics.away_goals,statistics.time as game_time,
leagues.id as league_id,leagues.name as league_name,leagues.type as league_type,
country.name as country_name,country.logo,
hts.home_scored, ats.away_scored,
hts.home_conceeded,ats.away_conceeded,
hts.home_win,ats.away_win,
hts.home_15,ats.away_15,
hts.home_25,ats.away_25,
hts.home_btts, ats.away_btts,
hts.home_fts, ats.away_fts,
hts.home_cs, ats.away_cs,
hts.home_corners_for, ats.away_corners_for,
hts.home_corners_against, ats.away_corners_against,
hts.home_cards, ats.away_cards
FROM events
LEFT JOIN teams ht
ON ht.id = events.home_team
LEFT JOIN teams at
ON at.id = events.away_team
LEFT JOIN leagues
ON leagues.id = events.league
LEFT JOIN country
ON country.id=leagues.country
LEFT JOIN ( SELECT team,home_scored,home_conceeded,home_win,home_15,home_25,home_btts,home_fts,home_cs,home_corners_for,home_corners_against,home_cards FROM team_quick_stats ORDER BY updated DESC) hts
ON ht.id=hts.team
LEFT JOIN ( SELECT team,away_scored,away_conceeded,away_win,away_15,away_25,away_btts,away_fts,away_cs,away_corners_for,away_corners_against,away_cards FROM team_quick_stats ORDER BY updated DESC) ats
ON at.id=ats.team
LEFT JOIN statistics
ON statistics.event_id=events.id
WHERE (events.time BETWEEN $start AND $end) ORDER BY country.list_order, leagues.country ASC , leagues.id ASC, events.time ASC, home_name ASC";
Here's one way. Replace LEFT JOIN (SELECT team... etc....) ats with...
LEFT
JOIN
( SELECT x.team
, x.etc...
FROM team_quick_stats x
JOIN
( SELECT team
, MAX(updated) updated
FROM team_quick_stats
GROUP
BY team
) y
ON y.team = x.team
AND y.updated = x.updated
) ats...
Related
I'm trying to create a leaderboard but i'm not sure how to do the mysql query.
I would like to count all the levels from a player in the skills table and get the total Level and count all the experience from a player in the experience table and get the Total Exp along with displaying the persons name from the users column.
There is 3 tables factions_mcmmo_users, factions_mcmmo_experience, factions_mcmmo_skills.
This is what i have so far but it doesn't work:
$sql = ("SELECT a.id,
(SELECT COUNT(*) FROM factions_mcmmo_experience WHERE user_id = a.id) as TotalXP,
(SELECT COUNT(*) FROM factions_mcmmo_skills WHERE user_id = a.id) as TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a LIMIT 10;");
Any help would be very appreciated
EDIT: I have it working now but i'm unsure if its the most efficient way to do things so if anyone could help me out if theres a better way, it would mean a lot.
I would also like to know if it's possible to display the total exp and level with commas if the number is in the thousands for example: total level 5,882 and total xp 582,882
EDIT 2:
I have figured out how to format the numbers but still don't know if my code is efficient
$sql = ("SELECT id, user,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_skills b WHERE b.user_id = a.id) as TotalLevel,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_experience c WHERE c.user_id = a.id) as TotalXP
FROM (SELECT id, user FROM factions_mcmmo_users) a group by id ORDER BY TotalLevel DESC, TotalXP DESC LIMIT 10;");
EDIT 3
Updated code from scaisEdge but was displaying everyones level as 1 and XP as 1, so i changed count(*) changed to sum, added an order By TotalLevel in Descending order and that seems to have worked but i can't get it to display the persons name (user column) in the user table? not sure if i was supposed to change to sum because it didn't work the other way.
$sql = ("SELECT a.id, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC
LIMIT 10;");
EDIT 4
Everything working but when i try to format the totals using "FORMAT(Sum(Columns), 0) on the inner joins, the EXP Total appears to work but the main Total Level is not displaying results that are over 1,000 and it breaks the leaderboard positioning, it should be sorting them on total level but it appears to be random, when u remove the format,0 it goes back to working
I would like it to display commas if the number number is the thousands for example: Total Level: 5,532 and Total EXP 5882,882
See live demo: http://mcbuffalo.com/playground/leaderboards/server/factions-mcmmo.php
Updated Code trying to use Format:
$sql = ("SELECT a.id, a.user, b.TotalXP, c.TotalLevel
FROM (SELECT id, user FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC;");
EDIT 5
Changed number with PHP, everything works
Original Images
you could use an couple of inner join
$sql = ("SELECT a.id, a.name, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id, name FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, COUNT(*) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, COUNT(*) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
LIMIT 10
I have beneficiary which have multiple transactions. On home page I want to show the latest transaction created by the customer. So, latest transaction's beneficiary should come on top with amount details.
I have created query something like this. But it doesn't show the latest transaction.
$clause = "SELECT b.*, tran.transfer_amount, tran.date_added as tran_date_added
FROM beneficiary b
LEFT JOIN customer_beneficiary_mapping cbm ON b.id = cbm.ben_id
LEFT JOIN
(SELECT ben_id, transfer_amount, date_added
FROM transaction
GROUP BY ben_id
) tran
ON tran.ben_id = b.id
INNER JOIN system_country_list scl ON scl.country_id = b.ben_country
AND cbm.cus_id = '$cus_id'
ORDER BY tran.date_added DESC
";
maybe this works:
SELECT b.*, tran.transfer_amount, tran.date_added as tran_date_added
FROM beneficiary b
LEFT JOIN customer_beneficiary_mapping cbm ON b.id = cbm.ben_id
LEFT JOIN
(SELECT ben_id, transfer_amount, date_added
FROM transaction
GROUP BY ben_id
) tran
ON tran.ben_id = b.id
AND tran.date_added = (SELECT MAX(date_added) FROM transaction WHERE ben_id = b.id)
INNER JOIN system_country_list scl ON scl.country_id = b.ben_country
AND cbm.cus_id = '$cus_id'
ORDER BY tran.date_added DESC
Note that i just added a subselect in where clause: AND tran.date_added = (SELECT MAX(date_added) FROM transaction WHERE ben_id = b.id)
I found the solution. Rather than deleting the question, I am posting the answer if somebody needs.
$clause = "SELECT b.*, tran.transfer_amount, tran.date_added as tran_date_added
FROM beneficiary b
LEFT JOIN customer_beneficiary_mapping cbm ON b.id = cbm.ben_id
LEFT JOIN
(SELECT ben_id, transfer_amount, date_added
FROM transaction
GROUP BY ben_id
ORDER BY 1 DESC <----- Added this line
) tran
ON tran.ben_id = b.id
INNER JOIN system_country_list scl ON scl.country_id = b.ben_country
AND cbm.cus_id = '$cus_id'
ORDER BY tran.date_added DESC
";
I still don't know, how come it's working now. I also tried with ORDER BY date_added DESC before. But, it was not working. Anyway, It's working now. :)
I am trying to grab the max date from the updates column but also return the corresponding fullname from that table, what is currently happening is that the latest updates.date is being returned but the first updates.consultant is currently being returned as well and we need the correct fullname for the MAX date.
SELECT customer.id,
customer.name,
customer.retainer_value,
customer.customer_type,
clientdetails.performance,
clientdetails.url,
members.fullname AS acc_manager,
u.maxdate,
u.fullname
FROM customer
LEFT JOIN clientdetails
ON clientdetails.id = customer.id
LEFT JOIN members
ON members.id = customer.consultant_name
LEFT JOIN (SELECT updates.clientid,
members.fullname,
Max(updates.`date`) AS MaxDate
FROM updates
LEFT JOIN members
ON members.id = updates.consultant
GROUP BY updates.clientid
ORDER BY updates.date DESC) u
ON customer.id = u.clientid
WHERE customer.switchedoff = 'N'
AND customer.companyid <> '3'
I think the easiest way in your case is to use the substring_index()/group_concat() method:
SELECT customer.id,
customer.name,
customer.retainer_value,
customer.customer_type,
clientdetails.performance,
clientdetails.url,
members.fullname AS acc_manager,
u.maxdate,
u.fullname
FROM customer
LEFT JOIN clientdetails
ON clientdetails.id = customer.id
LEFT JOIN members
ON members.id = customer.consultant_name
LEFT JOIN (SELECT updates.clientid,
substring_index(group_concat(m.fullname order by u.date desc separator '|'), '|', 1) as full_name
Max(updates.`date`) AS MaxDate
FROM updates u
LEFT JOIN members m
ON m.id = u.consultant
GROUP BY u.clientid
) u
ON customer.id = u.clientid
WHERE customer.switchedoff = 'N'
AND customer.companyid <> '3' ;
With a Left Join i have this result.
Here the screen
http://f.cl.ly/items/373Y141r1K131d0n3f1q/Schermata%202013-04-01%20alle%2016.51.18.png
i want to show only record once time, without repeat it, but with a left join all my records are different.
what i have to do for show once all my records?
the query.
SELECT * FROM login_users
LEFT JOIN login_users_seguaci
ON login_users.user_id = login_users_seguaci.following
WHERE name LIKE ""
AND user_id != '1'
ORDER BY data DESC
SELECT x.*, y.*
FROM login_users x
LEFT JOIN
(
SELECT a.*
FROM login_users_seguaci a
INNER JOIN
(
SELECT following, MAX(DATA) max_data
FROM login_users_seguaci
GROUP BY following
) b ON a.following = b.following AND
a.DATA = b.max_date
) y ON x.user_id = y.following
// WHERE ... your condition here ...
ORDER BY t.data DESC
Hello can anybody see why this query fails?
SELECT A.idAd, A.ads_in_Cat, A.title, A.currency, A.price,
A.in_dpt, A.description, A.featured FROM ads A
LEFT JOIN featured F ON F.ad = A.idAd
INNER JOIN dept D ON D.id_dept = A.in_dpt
INNER JOIN sub_cat_ad S ON S.id_sub_cat = A.ads_in_Cat
INNER JOIN cat_ad C ON C.idCat_ad = S.from_cat_ad
ORDER BY A.featured DESC LIMIT :limit, :offset
But this one works:
SELECT *FROM ads
LEFT JOIN featured ON featured.ad = ads.idAd
INNER JOIN dept ON dept.id_dept = ads.in_dpt
INNER JOIN sub_cat_ad ON id_sub_cat = ads.ads_in_Cat
INNER JOIN cat_ad ON idCat_ad = sub_cat_ad.from_cat_ad
ORDER BY featured DESC LIMIT :limit, :offset
In the first one, I don't want all columns from the table "ads", the query returns only columns till ...FROM ads A.
If you specify to only select fields from A that's what you get: Only fields from A.
If you want fields from other tables too you have to specify them as well.
SELECT
A.idAd, A.ads_in_Cat, A.title, A.currency, A.price, A.in_dpt, A.description, A.featured,
F.*,
D.*,
S.*,
C.*
FROM ads A
LEFT JOIN featured F ON F.ad = A.idAd
INNER JOIN dept D ON D.id_dept = A.in_dpt
INNER JOIN sub_cat_ad S ON S.id_sub_cat = A.ads_in_Cat
INNER JOIN cat_ad C ON C.idCat_ad = S.from_cat_ad
ORDER BY A.featured DESC LIMIT :limit, :offset