I'm trying to get only one HABTM relationship when using paginate using CakePHP 2.3.
Right now I'm getting this result:
Array
(
[0] => Array
(
[Ticket] => Array ( .....)
[User] => Array ( .....)
[Priority] => Array ( .....)
[Status] => Array(....)
[Attachment] => Array(....)
....
)
[1] => ....
[2] => ....
)
By using:
$this->Ticket->recursive = 0;
$this->paginate = array(
'limit' => 20
);
I am using $this->Ticket->recursive = 0; because I'm only interested in the belongsTo relationships with other tables, but at the same time, I would like to get only one of the HABTM relationships.
I know I could achieve it adding each of the single relationships in the contain array, like so:
$this->Ticket->recursive = 0;
$this->paginate = array(
'limit' => 20,
'contain' => array(
'Ticket`, `User`, `Priority`, `Status`, `Attachment`, `Tags`...
)
);
But I have plenty of tables and I was wondering if there's any way to do it without having to name every single table in the contain array.
I've also tried to use the recursive array inside the contains one like so:
//getting the filtered tickets
$this->paginate = array(
'limit' => 20,
'contain' => array(
'Ticket' => array('recursive' => 1),
'Tag' //this is the hasMany relationship
)
);
But it didn't work. Is there any way to achieve this without having to name all the tables to make it more simple to maintain?
Ok, as it seems there's no solution for it, I managed to do it by getting the associated models of the type belongsTo and then adding the model name of the HABTM relationship:
$associations = $this->Ticket->getAssociated('belongsTo');
$associations[] = 'Tag';
//getting the filtered tickets
$this->paginate = array(
'limit' => 20,
'contain' => $associations
);
Related
Here I want to join two table with comma separated ids
For example my data is like:
[Restaurant] => Array
(
[RST_ID] => 171
[RST_NAME] => oneone
[RST_IMAGE] =>
[RST_CAT_ID] => 2,4,6
[RST_CT_ID] => 27
[RST_IS_TOP] => 3
[RST_QR_CODE] =>
[RST_CREATED_DATE] => 1394536725
[RST_MODIFIED_DATE] => 1394536725
[RST_STATUS] => 1
)
[Category] => Array
(
[CAT_ID] => 2
[CAT_NAME] => Vegetarian
[CAT_CREATED_DATE] => 1375175962
[CAT_MODIFIED_DATE] => 1375175962
[CAT_STATUS] => 1
)
My Model Code:
var $belongsTo = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => 'RST_CAT_ID',
'conditions' => array('Category.CAT_ID IN ( Restaurant.RST_CAT_ID)')
)
);
Real Query:
SELECT
`Restaurant`.`RST_ID`, `Restaurant`.`RST_NAME`, `Restaurant`.`RST_IMAGE`,
`Restaurant`.`RST_CAT_ID`, `Restaurant`.`RST_CT_ID`, `Restaurant`.`RST_IS_TOP`,
`Restaurant`.`RST_QR_CODE`, `Restaurant`.`RST_CREATED_DATE`,
`Restaurant`.`RST_MODIFIED_DATE`, `Restaurant`.`RST_STATUS`,
`Category`.`CAT_ID`, `Category`.`CAT_NAME`, `Category`.`CAT_CREATED_DATE`,
`Category`.`CAT_MODIFIED_DATE`, `Category`.`CAT_STATUS`, `City`.`CT_ID`,
`City`.`CT_NAME`, `City`.`CT_CREATED_DATE`, `City`.`CT_MODIFIED_DATE`,
`City`.`CT_STATUS`
FROM `dailybit_dailybites`.`restaurant` AS `Restaurant`
LEFT JOIN `dailybit_dailybites`.`category` AS `Category`
ON (`Restaurant`.`RST_CAT_ID` = `Category`.`CAT_ID`
AND `Category`.`CAT_ID` IN ( `Restaurant`.`RST_CAT_ID`))
LEFT JOIN `dailybit_dailybites`.`city` AS `City`
ON (`Restaurant`.`RST_CT_ID` = `City`.`CT_ID`)
WHERE 1 = 1
So what’s the solution here?
It's giving me just one category data that for first id only.
First have a look at this question: MySQL search in comma list
As you can see the belongsTo query is just generating a join on the single id, CakePHP by default doesn't respect this special case. You will have to alter your query and pass all the ids manually, but your DB design is bad and it doesn't follow the CakePHP conventions at all.
How do you prevent duplicates (which would waste space)
How do you remove a given value (Requires custom function, leading to possibility of errors?
How do you respond to performance issues as the size of my tables increase?
Instead of changing the query you should change this awkward DB design. You want to use HABTM here and a join table: Restaurant hasAndBelongsToMany Categoryy.
restaurants <-> restaurants_categories <-> categories
If you insist on using this bad DB design you'll have to use bindModel() and set the conditions manually:
'conditions' => array('FIND_IN_SET (Category.CAT_ID, ' . $listOfIds. ')')
I haven't tested this, try it yourself, see FIND_IN_SET() vs IN()
You'll have to have another method that gets you all the ids you want here before. Like I said, this is ineffectice and bad design.
You have to set your foreign Key false and find_in_set condition
var $belongsTo = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => false,
'conditions' => array('FIND_IN_SET(Category.CAT_ID,Restaurant.RST_CAT_ID)')
)
);
// you can pass an array at the place of 'Restaurant.RST_CAT_ID'
I have a table called items and a table called item_pics.
item_pics has an item_id, file_name and a rank field (among others).
What I'm looking for is for each item my index page's $items array to contain the file_name from the item_pics matching the item's item_id with the lowest rank. So I can access like (or something like) this in my Items/index.ctp:
foreach ($items as $item):
$img = $item['Item']['ItemPic']['file_name'];
...
I'm pretty new to CakePHP, this is my first project. I thought that this within the Item model would cause item_pics data to be pulled (although I figured all related item_pics for each item would get pulled rather than just the one with the lowest rank):
public $hasMany = array(
'ItemPic' => array(
'className' => 'ItemPic',
'foreignKey' => 'item_id',
'dependent' => false
)
}
but I can see that no item_pics data is loaded (at the bottom of items/index):
SELECT `Item`.`id`, `Item`.`title`, `Item`.`description`, `Item`.`created`, `Item`.`modified`, `Item`.`type`, `Project`.`id`, `Project`.`item_id`, `Project`.`title`, `Project`.`description`, `Project`.`rank`, `Project`.`created`, `Project`.`modified`
FROM `laurensabc`.`items` AS `Item`
LEFT JOIN `laurensabc`.`projects`
AS `Project`
ON (`Project`.`item_id` = `Item`.`id`)
WHERE `Item`.`type` IN (1, 2)
LIMIT 20
also, while I would like projects to be joined in the view pages, I don't really need them in the index page.
I've done some searching and haven't been able to find exactly what I'm looking for. I suppose I could do a query within the index view item loop, but I'm trying to make sure I do things the right way... the CakePHP way. I assume I need to change something about my model relationships but I haven't had any luck.
CakePHP - Associations - HasMany, this makes it seem like I could order by rank and limit 1. But this didn't work... and even if it did, I wouldn't want that to affect the view pages but rather just the index page.
My Controller looks like this:
public function index($type = null) {
$this->Item->recursive = 0;
$conditions = array();
if ($type == "sale") {
$conditions = array(
"Item.type" => array(self::FOR_SALE, self::FOR_SALE_OR_RENT)
);
} else if ($type == "rent" ) {
$conditions = array(
"Item.type" => array(self::FOR_RENT, self::FOR_SALE_OR_RENT)
);
} else {
$conditions = array("Item.type !=" => self::HIDDEN);
}
$paginated = $this->Paginator->paginate($conditions);
debug($paginated);
$this->set('items', $paginated);
$this->set('title', ($type == null ? "Items for Sale or Rent" : "Items for " . ucwords($type)));
}
I have also tried this on my controller, but it doesn't seem to do anything either:
$this->paginate = array(
'conditions' => $conditions,
'joins' => array(
array(
'alias' => 'ItemPic',
'table' => 'item_pics',
'type' => 'left',
'conditions' => array('ItemPic.item_id' => 'Item.id'),
'order' => array('ItemPic.rank' => 'asc'),
'limit' => 1
)
)
);
$paginated = $this->paginate($this->Item);
First, set containable behavior in AppModel (or if you don't want it on each model, put it on Item model):
public $actsAs = array('Containable');
Then, on your find query:
$items = $this->Item->find('all', array(
'contain' => array(
'ItemPic' => array(
'fields' => array('file_name'),
'order' => 'rank',
'limit' => 1
)
)
));
Then the result array you can access it like:
foreach ($items as $item):
$img = $item['ItemPic']['file_name'];
Edit: Then you should put it on the paginate query:
$this->paginate = array(
'conditions' => $conditions,
'contain' => array(
'ItemPic' => array(
'fields' => array('file_name'),
'order' => 'rank',
'limit' => 1
)
)
);
In this case, I would probably order by rank and limit 1 as you said, and make that a dynamic association just for the index page (See http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#creating-and-destroying-associations-on-the-fly). So use $this->Item->bindModel(array('hasMany' => array('ItemPic' => $options))); (which I believe should replace your current settings for HasMany ItemPic, but you may have to unbindmodel first)
Associations created through bindModel will go through for the next query only, then it'll revert to your normal settings, unless you specifically set an option to keep using the new association.
As for why it's not getting ItemPics with Items, or why trying to order by rank and limit 1 didn't work for you, I can't really say without seeing more of your code.
OK, another cake question from me.
I have rather a complex table structure with quite a few joins. Here's the jist of it:
So, in summary:
RiskCategory $hasMany Client [Client $belongsTo RiskCategory]
Client $hasMany Account [Account $belongsTo Client]
Account $hasMany Holding [Holding $belongsTo Account]
In my RiskCategory model I want to run a query that basically returns the sum of the holdings in each riskCategory id, grouped by date. There's a few other conditions but here is what I've put together:
$findParams = array(
'recursive' => 4,
'fields' => array(
'Holding.holding_date',
'SUM(Holding.value) AS risk_category_value'
),
'group' => array('Holding.holding_date'),
'order' => 'Holding.holding_date ASC'
);
$findParams['conditions'] = array(
'Client.active' => true,
'Client.model' => true,
'Client.currency' => 'GBP',
'OR' => array(
'Holding.holding_date' => $this->end_date,
array(
'Holding.holding_date = LAST_DAY(Holding.holding_date)',
'MONTH(Holding.holding_date)' => array(3,6,9,12)
)
)
);
$valuations = $this->Client->Account->Holding->find( 'all', $findParams );
When I run the above cake is giving me an error saying various fields are not present in the query. The raw query created is as follows:
SELECT `Holding`.`holding_date`,
Sum(`Holding`.`value`) AS risk_category_value
FROM `ips_client_db`.`holdings` AS `Holding`
LEFT JOIN `ips_client_db`.`accounts` AS `Account`
ON ( `Holding`.`account_id` = `Account`.`id` )
LEFT JOIN `ips_client_db`.`sedols` AS `Sedol`
ON ( `Holding`.`sedols_id` = `Sedol`.`id` )
WHERE `client`.`active` = '1'
AND `client`.`model` = '1'
AND `client`.`currency` = 'GBP'
AND ( ( `Holding`.`holding_date` = '2013-10-01' )
OR (( ( `Holding`.`holding_date` = Last_day(
`Holding`.`holding_date`) )
AND ( Month(`Holding`.`holding_date`) IN ( 3, 6, 9, 12 ) ) )
) )
GROUP BY `Holding`.`holding_date`
ORDER BY `Holding`.`holding_date` ASC
It looks as though cake is not doing all the joins. It is only joining Account to Holding and then Holding to Sedol (which is another joined table in the database but is not needed for this query so I've omitted it from the diagram)
Why are the joins not being made properly and how to acheive this? I'd like to avoid writing a raw statement if possible.
EDIT: The joins should be as follows:
...
FROM risk_categories
LEFT JOIN ((clients
LEFT JOIN accounts
ON clients.id = accounts.client_id)
LEFT JOIN holdings
ON accounts.id = holdings.account_id)
ON risk_categories.id = clients.risk_category_id
...
CakePHP does not perform deep joins for associations that are more than 1 level deep. That is why you're getting an error for references to the Client table in the conditions.
For these types of problems it's easier to use the Containable behavior. I usually add this behavior to my AppModel as the default handler for associations.
Containable allows you to define the associations (only those already defined) with their fields and conditions as part of the find operation. This is done by adding a new contain key in the find parameters. Below I've taking a guess at what you might need.
$findParams = array(
'fields' => array(
'Holding.holding_date',
'SUM(Holding.value) AS risk_category_value'
),
'conditions'=>array(
'OR' => array(
'Holding.holding_date' => $this->end_date,
array(
'Holding.holding_date = LAST_DAY(Holding.holding_date)',
'MONTH(Holding.holding_date)' => array(3,6,9,12)
)
)
),
'group' => array('Holding.holding_date'),
'order' => 'Holding.holding_date ASC',
'contain'=>array(
'Account'=>array(
'Client'=>array(
'RiskCategory',
'conditions'=>array(
'Client.active' => true,
'Client.model' => true,
'Client.currency' => 'GBP',
)
)
)
)
);
$valuations = $this->Client->Account->Holding->find( 'all', $findParams );
I apologize for the horrible title, I couldn't think of how to explain my problem.
In my database I have the following tables, articles, tags, and articles_tags. An article can have many tags.
Currently I am able to grab all the articles, with all the tags, but I want to be able to find articles based upon it's tags.
My select is simple:
$articles = $this->Article->find('all', array(
// extra condition to check for tag, maybe?
'conditions' => array('Article.status' => 'active'),
'limit' => $this->articles_per_page,
'offset' => ($page_num-1)*$this->articles_per_page
));
My return from the database is as follows:
Array
(
[0] => Array
(
[Article] => Array
(
[id] => 1
)
[Tag] => Array
(
[0] => Array
(
[id] => 1
[name] => Ruby
[slug] => ruby
[uses] => 1
[ArticlesTag] => Array
(
[id] => 1
[article_id] => 1
[tag_id] => 1
)
)
)
)
What do I do if I only want to return the articles with a Ruby tag?
Try this
// In your Article model
function getArticleByTagSql($tag)
{
$dbo = $this->getDataSource();
$subQuery = $dbo->buildStatement(
array(
'fields' => array('DISTINCT(ArticlesTag.article_id)'),
'table' => "articles_tags",
'joins' => array(
array('table' => 'tags',
'alias' => 'Tag',
'type' => 'INNER',
'conditions' => array('ArticlesTag.tag_id = Tag.id')
)
),
'alias'=>"ArticlesTag",
'conditions' => array("Tag.name"=>Sanitize::clean($tag_words)),
'order' => null,
'group' => "ArticlesTag.article_id"
),
$this
);
$subQuery = ' Article.id IN (' . $subQuery . ')';
return $dbo->expression($subQuery);
}
// In your Articles Controller
$this->paginate['conditions'][] = $this->Article->getArticleByTagSql($tag_name);
$this->paginate['conditions'][] = array('Article.status' => 'active');
$this->paginate['limit'] = $this->articles_per_page;
// or as per your example
$articles = $this->Article->find('all', array(
// extra condition to check for tag, maybe?
'conditions' => array('Article.status' => 'active',$this->Article->getArticleByTagSql($tag_name)),
'limit' => $this->articles_per_page,
'offset' => ($page_num-1)*$this->articles_per_page
));
For conditions like this you can use the LinkableBehavior. It's designed for exact your wanted result. In case you don't want to use it, you have to do a query on the tag controller:
$this->Tag->find('all', array('conditions' => array('Tag.name' => 'ruby')));
Not possible directly.
The easiest way is to make the query through the tag controller
I'm updating this question with an answer for CakePHP 3.x.
You can find all articles for a given tag using an INNER JOIN. The benefit of this join is that it keeps articles as the primary table in the query. Making this an easy solution when you're paginating results by a HABTM join.
$tag_id = 3; // the ID of the tag
$query = $this->Articles->find('all')
->innerJoin('articles_tags', [
'Articles.id = articles_tags.article_id',
'articles_tags.tag_id' => $tag_id
]);
The first join condition has to be the array key. If you use a => array assignment then CakePHP will pass the articles_tags.article_id as a string argument to the join condition. Which won't work.
You can also stack innerJoin for multiple HABTM conditions. For example; find all articles for a tag and also for a category. You can also use the in query expression to match multiple tags.
You can also use the above in pagination like this $articles = $this->paginate($query);
I'm sure this information is out on the web, but this question was the top of google's results. So maybe this will help others.
I've got a series of Post models that hasAndBelongsToMany Media models. In certain function calls inside of the Post model, I don't need to retrieve the entire list of Media models. However, when I use the following code:
$this->unbindModel( array('hasAndBelongsToMany' => array('Media')) );
// Rebind to get only the fields we need:
$this->bindModel(
array('hasAndBelongsToMany' => array(
'Media' => array(
'className' => 'Media',
'joinTable' => 'media_posts',
'foreignKey' => 'post_id',
'associationForeignKey' => 'media_id',
'limit' => 1,
'fields' => array('Media.type', 'Media.path', 'Media.title')
)
)
)
);
$this->find('all', $params);
This limit only works on one of the first retrieved Post model and all following Post models have no associated Media:
Array
(
[0] => Array
(
[Profile] => Array
(
)
[Media] => Array
(
[0] => Array
(
[type] => photo
[path] => ''
[title] => ''
)
)
)
[1] => Array
(
[Profile] => Array
(
)
[Media] => Array
(
)
)
)
Any suggestions would be great. Thanks!
why not use the containable behaviour
// you would probably want the next line in the app_model ot be able to use it with all models
$this->Post->actsAs = array('Containable')
$params['conditions'] = array(
);
$params['contain'] = array(
'Media' => array(
'fields' => array(
'type', 'path', 'title'
),
'limit' => 1
)
);
$this->Post->find('all', $params);
EDIT:
Just tried that and got this sql (Module <-> Tag):
SELECT `Module`.`id` FROM `modules` AS `Module` WHERE 1 = 1
and
SELECT `Tag`.`id`, `ModulesTag`.`module_id`, `ModulesTag`.`tag_id`
FROM `tags` AS `Tag`
JOIN `modules_tags` AS `ModulesTag`
ON (`ModulesTag`.`module_id` IN (1, 2, 3, 4) AND `ModulesTag`.`tag_id` = `Tag`.`id`)
WHERE `Tag`.`belongs_to` = 'Module'
ORDER BY `Tag`.`name` ASC
LIMIT 1
obviously that cannot return the wanted result, as you would have to do a query for each Module result (which then again would result in way too many queries).
As a conclusion I would return all Tags (in my example) as the overhead in too many result rows is better than the overhead of too many queries..
Cake fetches all the Habtm-related records in one batch query and then assembles them into the results array afterwards. Any additional conditions you specify in the association will be used as is in the query, so it'll look something like this:
SELECT … FROM Media WHERE Media.id in (1, 2, 3, …) LIMIT 1
So it'll only retrieve a single HABTM model.
There's no apparently easy solution for this. Maybe you could think about the original premise again and why the "first" (LIMIT 1) record is supposedly the right one, maybe you can find a different condition to query on.
Failing that, you could rebind your models so Media has a hasMany relationship to medias_posts, the pivot table. For hasMany and belongsTo queries, Cake automatically does JOIN queries. You could use a GROUP BY clause then, which would give you the desired result:
SELECT … FROM Media JOIN medias_posts … GROUP BY medias_posts.post_id
You might also want to experiment with passing the 'join' parameter with the query, to achieve that effect without extensive rebinding.
$this->Media->find('all', array('join' => array(…), …));
Try this:
$this->yourModel->hasAndBelongsToMany['Media'] = false; // or null
And then set your HABTM association manually
$this->yourModel->hasAndBelongsToMany['Media'] = array(........);
Or simply modify the association without nulling it:
$this->yourModel->HABTM['Media']['fields'] = array(....)
CakePHP has a very powerful tool for this containable behaviour