CakePHP not joining the correct tables in find query - php

OK, another cake question from me.
I have rather a complex table structure with quite a few joins. Here's the jist of it:
So, in summary:
RiskCategory $hasMany Client [Client $belongsTo RiskCategory]
Client $hasMany Account [Account $belongsTo Client]
Account $hasMany Holding [Holding $belongsTo Account]
In my RiskCategory model I want to run a query that basically returns the sum of the holdings in each riskCategory id, grouped by date. There's a few other conditions but here is what I've put together:
$findParams = array(
'recursive' => 4,
'fields' => array(
'Holding.holding_date',
'SUM(Holding.value) AS risk_category_value'
),
'group' => array('Holding.holding_date'),
'order' => 'Holding.holding_date ASC'
);
$findParams['conditions'] = array(
'Client.active' => true,
'Client.model' => true,
'Client.currency' => 'GBP',
'OR' => array(
'Holding.holding_date' => $this->end_date,
array(
'Holding.holding_date = LAST_DAY(Holding.holding_date)',
'MONTH(Holding.holding_date)' => array(3,6,9,12)
)
)
);
$valuations = $this->Client->Account->Holding->find( 'all', $findParams );
When I run the above cake is giving me an error saying various fields are not present in the query. The raw query created is as follows:
SELECT `Holding`.`holding_date`,
Sum(`Holding`.`value`) AS risk_category_value
FROM `ips_client_db`.`holdings` AS `Holding`
LEFT JOIN `ips_client_db`.`accounts` AS `Account`
ON ( `Holding`.`account_id` = `Account`.`id` )
LEFT JOIN `ips_client_db`.`sedols` AS `Sedol`
ON ( `Holding`.`sedols_id` = `Sedol`.`id` )
WHERE `client`.`active` = '1'
AND `client`.`model` = '1'
AND `client`.`currency` = 'GBP'
AND ( ( `Holding`.`holding_date` = '2013-10-01' )
OR (( ( `Holding`.`holding_date` = Last_day(
`Holding`.`holding_date`) )
AND ( Month(`Holding`.`holding_date`) IN ( 3, 6, 9, 12 ) ) )
) )
GROUP BY `Holding`.`holding_date`
ORDER BY `Holding`.`holding_date` ASC
It looks as though cake is not doing all the joins. It is only joining Account to Holding and then Holding to Sedol (which is another joined table in the database but is not needed for this query so I've omitted it from the diagram)
Why are the joins not being made properly and how to acheive this? I'd like to avoid writing a raw statement if possible.
EDIT: The joins should be as follows:
...
FROM risk_categories
LEFT JOIN ((clients
LEFT JOIN accounts
ON clients.id = accounts.client_id)
LEFT JOIN holdings
ON accounts.id = holdings.account_id)
ON risk_categories.id = clients.risk_category_id
...

CakePHP does not perform deep joins for associations that are more than 1 level deep. That is why you're getting an error for references to the Client table in the conditions.
For these types of problems it's easier to use the Containable behavior. I usually add this behavior to my AppModel as the default handler for associations.
Containable allows you to define the associations (only those already defined) with their fields and conditions as part of the find operation. This is done by adding a new contain key in the find parameters. Below I've taking a guess at what you might need.
$findParams = array(
'fields' => array(
'Holding.holding_date',
'SUM(Holding.value) AS risk_category_value'
),
'conditions'=>array(
'OR' => array(
'Holding.holding_date' => $this->end_date,
array(
'Holding.holding_date = LAST_DAY(Holding.holding_date)',
'MONTH(Holding.holding_date)' => array(3,6,9,12)
)
)
),
'group' => array('Holding.holding_date'),
'order' => 'Holding.holding_date ASC',
'contain'=>array(
'Account'=>array(
'Client'=>array(
'RiskCategory',
'conditions'=>array(
'Client.active' => true,
'Client.model' => true,
'Client.currency' => 'GBP',
)
)
)
)
);
$valuations = $this->Client->Account->Holding->find( 'all', $findParams );

Related

CakePHP - MySQL Order by CAST to INT not working

With CakePHP 2.x and MySQL 5.6.40 i'm creating the following pagination:
$options = array(
'contain' => array(
'Category',
'ProductImage'
),
'limit' => 10,
'order' => array(
'Product.year' => 'DESC',
'Product.month' => 'DESC'
)
);
But i forgot my products.month column is varchar so i have to do a cast to convert the Product.month to integer:
$options = array(
'contain' => array(
'Category',
'ProductImage'
),
'limit' => 10,
'order' => array(
'Product.year' => 'DESC',
'CAST(Product.month as INT)' => 'DESC'
)
);
But on the Query output, it removes the Order By CAST as INT
SELECT
...
FROM
`web_quality`.`products` AS `Product`
LEFT JOIN `web_quality`.`categories` AS `Category` ON (
`Product`.`category_id` = `Category`.`id`
)
WHERE
`Product`.`category_id` IN (
SELECT
id
FROM
categories
WHERE
tag = 'revistas'
AND company_id IN (
SELECT
id
FROM
companies
WHERE
tag = 'dr'
)
)
AND NOT (
(
(`Product`.`year` = '2022')
AND (`Product`.`month` = '2')
)
)
AND `Product`.`enabled` = '1'
ORDER BY
`Product`.`year` DESC,
LIMIT 10
Also it doesn't generate any kind of error, if i try manually the query with the CAST as INT it works, but i have to do it using the CakePHP Model, what could be wrong ?
Thank you so much !
From what I remember you should use a virtual field for that, as the paginator checks whether the given field exists on the model, and whitelisting an SQL snippet doesn't seem like an overly good idea.
So in your model you'd do something like:
public $virtualFields = array(
'month_number' => 'CAST(Product.month as INT)',
);
and then you order by Product.month_number.
See also
Cookbook > Models > Virtual fields
Cookbook > Core Libraries > Components > Pagination > Control which fields used for ordering

CakePHP join with comma separated ids

Here I want to join two table with comma separated ids
For example my data is like:
[Restaurant] => Array
(
[RST_ID] => 171
[RST_NAME] => oneone
[RST_IMAGE] =>
[RST_CAT_ID] => 2,4,6
[RST_CT_ID] => 27
[RST_IS_TOP] => 3
[RST_QR_CODE] =>
[RST_CREATED_DATE] => 1394536725
[RST_MODIFIED_DATE] => 1394536725
[RST_STATUS] => 1
)
[Category] => Array
(
[CAT_ID] => 2
[CAT_NAME] => Vegetarian
[CAT_CREATED_DATE] => 1375175962
[CAT_MODIFIED_DATE] => 1375175962
[CAT_STATUS] => 1
)
My Model Code:
var $belongsTo = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => 'RST_CAT_ID',
'conditions' => array('Category.CAT_ID IN ( Restaurant.RST_CAT_ID)')
)
);
Real Query:
SELECT
`Restaurant`.`RST_ID`, `Restaurant`.`RST_NAME`, `Restaurant`.`RST_IMAGE`,
`Restaurant`.`RST_CAT_ID`, `Restaurant`.`RST_CT_ID`, `Restaurant`.`RST_IS_TOP`,
`Restaurant`.`RST_QR_CODE`, `Restaurant`.`RST_CREATED_DATE`,
`Restaurant`.`RST_MODIFIED_DATE`, `Restaurant`.`RST_STATUS`,
`Category`.`CAT_ID`, `Category`.`CAT_NAME`, `Category`.`CAT_CREATED_DATE`,
`Category`.`CAT_MODIFIED_DATE`, `Category`.`CAT_STATUS`, `City`.`CT_ID`,
`City`.`CT_NAME`, `City`.`CT_CREATED_DATE`, `City`.`CT_MODIFIED_DATE`,
`City`.`CT_STATUS`
FROM `dailybit_dailybites`.`restaurant` AS `Restaurant`
LEFT JOIN `dailybit_dailybites`.`category` AS `Category`
ON (`Restaurant`.`RST_CAT_ID` = `Category`.`CAT_ID`
AND `Category`.`CAT_ID` IN ( `Restaurant`.`RST_CAT_ID`))
LEFT JOIN `dailybit_dailybites`.`city` AS `City`
ON (`Restaurant`.`RST_CT_ID` = `City`.`CT_ID`)
WHERE 1 = 1
So what’s the solution here?
It's giving me just one category data that for first id only.
First have a look at this question: MySQL search in comma list
As you can see the belongsTo query is just generating a join on the single id, CakePHP by default doesn't respect this special case. You will have to alter your query and pass all the ids manually, but your DB design is bad and it doesn't follow the CakePHP conventions at all.
How do you prevent duplicates (which would waste space)
How do you remove a given value (Requires custom function, leading to possibility of errors?
How do you respond to performance issues as the size of my tables increase?
Instead of changing the query you should change this awkward DB design. You want to use HABTM here and a join table: Restaurant hasAndBelongsToMany Categoryy.
restaurants <-> restaurants_categories <-> categories
If you insist on using this bad DB design you'll have to use bindModel() and set the conditions manually:
'conditions' => array('FIND_IN_SET (Category.CAT_ID, ' . $listOfIds. ')')
I haven't tested this, try it yourself, see FIND_IN_SET() vs IN()
You'll have to have another method that gets you all the ids you want here before. Like I said, this is ineffectice and bad design.
You have to set your foreign Key false and find_in_set condition
var $belongsTo = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => false,
'conditions' => array('FIND_IN_SET(Category.CAT_ID,Restaurant.RST_CAT_ID)')
)
);
// you can pass an array at the place of 'Restaurant.RST_CAT_ID'

Yii Framework : Help to translate relational Sql query

I encountered a problem to write this query in a Yii model oriented style.
I have a 3 main tables : questions, categories, countries
and relational tables : questions_has_categories, questions_has_countries.
Now i try to search questions that belongs to country, category.
With normal SQL statement i write :
SELECT q.id, q.question, c.name, co.name
FROM questions AS q,
categories AS c,
countries AS co,
questions_has_countries AS ta,
questions_has_categories AS qhc
WHERE
q.id = qhc.questions_id
AND c.id = qhc.categories_id
AND q.id = ta.questions_id
AND co.id = ta.countries_id
AND c.id = 1
AND co.id = 2
This works fine.
Now with Yii Active Record i try to search like this :
$model = Questions::model()->with(
array( 'categories' => array (
'select' => 'name',
'condition' => 'categories.id=:cat_id',
'params' => array (':cat_id' => $_POST["Questions"]["categories"])
)
),
array( 'countries' => array (
'select' => 'name',
'condition' => 'countries.id=:cou_id',
'params' => array (':cou_id' => $_POST["Questions"]["countries"])
)
)
)->findAll(array ('select' => 'question'));
This code respects only the categories, not countries ( returns for all countries, doesnt filter, narrow down ).
What am i doing wrong ?
My Question Model relations function looks like this :
public function relations()
{
return array('categories' => array(self::MANY_MANY, 'Categories', 'questions_has_categories(questions_id, categories_id)'),
'countries' => array(self::MANY_MANY, 'Countries', 'questions_has_countries(questions_id, countries_id)'),
);
}
Pls help :)
Thanks
try this
$model = Questions::model()->with(
array( 'categories' => array (
'select' => 'name',
'condition' => 'categories.id=:cat_id',
'params' => array (':cat_id' => $_POST["Questions"]["categories"])
),
'countries' => array (
'select' => 'name',
'condition' => 'countries.id=:cou_id',
'params' => array (':cou_id' => $_POST["Questions"]["countries"])
)
)
)->findAll(array ('select' => 'question'));

Zend subquery arguments

The query below represents what I am trying to do, I need to pull in a list of blog_posts and also join with a users table.
What it is also doing is pulling in a random 'picture_filename' from blog_updates_pictures. It needs blog_updates as a join to reference the blog_update_id.
What I'd like to do now is also COUNT the number of blog_updates for each blog_post. I think this is a subquery but every implementation fails. It would also be good to have the count accept arguments (ie. blog_updates where date = ?). Also, there may be no updates or pictures to a blog_post.
$select = $db->select ();
$select->from ( array ('b' => 'blog_posts' ), array('headline', 'date_created'));
$select->join ( array ('u' => 'users' ), 'u.user_id = b.user_id', array ( 'email' ) );
$select->joinLeft ( array ('bu' => 'blog_updates' ), 'bu.blog_id = b.blog_id', array () );
$select->joinLeft ( array ('bup' => 'blog_updates_pictures' ), 'bu.blog_update_id = bup.blog_update_id', array ('picture_filename' ) );
Can someone show me the way?
Thanks
What I'd like to do now is also COUNT the number of blog_updates for each blog_post.
You can achieve that using aggregation - use GROUP BY bu.blog_id, and as additional column COUNT(bu.blog_id) AS blog_updates_count. It should work.
Create subselects as:
$subselect = $db->select()
->from(
array ('bu' => 'blog_updates' ),
array(
'blog_id',
'updates' => 'count(*)'
)
)
->group("bu.blog_id");
And then join the $subselect with your main $select as:
$select->join(
array( 't' => $subselect),
"t.blog_id = b.blog_id",
array( 'updates' )
);
If we had the table structure you might get a more complete answer

Cakephp joining tables via find option not working

I'm trying to join a Users table to my curent hasMany Through table which has Interest and User model id's.
Below is the find query with options:
$params = array(
'fields' => array('*', 'COUNT(DISTINCT(InterestsUser.interest_id)) as interest_count'),
'limit' => 15,
'recursive' => -1,
'offset' => $offset,
'conditions' => array('InterestsUser.interest_id' => $conditions),
'group' => array('InterestsUser.user_id'),
'order' => array('interest_count DESC', 'InterestsUser.user_id ASC', 'InterestsUser.interest_id ASC'),
'joins' => array(
array('table' => 'users',
'alias' => 'User',
'type' => 'LEFT',
'conditions' => array(
'User.id' => 'InterestsUser.user_id',
)
)
)
);
$results = $this->InterestsUser->find('all', $params);
This returns InterestsUser table fine but does not return any values for Users table. It only returns field names.
What could be wrong?
UPDATE:
OK, above is generating below SQL which I got from Cake's datasources sql log:
SELECT *, COUNT(DISTINCT(InterestsUser.interest_id)) as interest_count
FROM `interests_users` AS `InterestsUser`
LEFT JOIN users AS `User` ON (`User`.`id` = 'InterestsUser.user_id')
WHERE `InterestsUser`.`interest_id` IN (3, 2, 1)
GROUP BY `InterestsUser`.`user_id`
ORDER BY `interest_count` DESC, `InterestsUser`.`user_id` ASC, `InterestsUser`.`interest_id` ASC
LIMIT 15
Why is users table values returning NULL only for all fields?
UPDATE:
OK I tried below but this is working fine...What am I missing here!!??
SELECT * , COUNT( DISTINCT (
interests_users.interest_id
) ) AS interest_count
FROM interests_users
LEFT JOIN users ON ( users.id = interests_users.user_id )
WHERE interests_users.interest_id
IN ( 1, 2, 3 )
GROUP BY interests_users.user_id
ORDER BY interest_count DESC
LIMIT 15
The array syntax for join conditions should be like the following
array('User.id = InterestsUser.user_id')
as opposed to array('User.id' => 'InterestsUser.user_id'). For more, see http://book.cakephp.org/view/1047/Joining-tables.

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