MySQL Query Into Array for preg_replace - php

Question

ORIGINAL CODE
$sentance="are you hungry too?";
function newLanguage($text) {
$sql = "SELECT in,out FROM words";
$res = mysql_query($sql) or die();
$in_array = array();
$out_array = array();
while ($row = mysql_fetch_array($res)){
$in_array[] = $row['in']; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
return preg_replace($in_array,$out_array,$text);
}
$newwords = newLanguage($sentance);
echo $newwords;
AMENDED CODE:
ini_set("display_errors", "1");
error_reporting(E_ALL);
function newLanguage($text) {
$sql = "SELECT in,out FROM words";
$res = mysql_query($sql) or die();
$in_array = array();
$out_array = array();
while ($row = mysql_fetch_array($res)){
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
/* VERSION 2 - STATIC, FOR DEBUGGING
$in_array = array('~\you~s','~\to~s','~\too~s');
$out_array = array('noa','nie','niee');*/
return preg_replace($in_array,$out_array,$text);
}
$sentance="are you hungry too?";
$newwords = newLanguage($sentance);
var_dump($in_array);
echo $sentance;
CURRENT CODE
ini_set("display_errors", "1");
error_reporting(E_ALL);
$sentance="are you hungry too?";
function newLanguage($text) {
$sql = "SELECT * FROM words";
$res = mysql_query($sql) or die();
while ($row = mysql_fetch_array($res)){
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
return preg_replace($in_array,$out_array,$text);
}
$newwords = newLanguage($sentance);
var_dump($in_array);
echo $newwords;
I'm having Problems with my code, for the life of me I cannot get it to work, I have worked with preg_replace before in using a word filter. Though creating a dynamic array using query results totally throws me off. I have looked at a few tutorials but none have really helped me understand where I am going wrong.
Any help would be grateful :)
GOAL:
Creating a New Language translation. Database holds a row with 'in' & 'out' which is both the new language and local language.
PROBLEM:
I'm unsure if my Arrays are being successfully populated since my preg_replace isn't working.
----UPDATE----
Here is what my database looks like;
id in out
1 you noa
2 to nie
3 too niee
They are stored as VARCHARS

Answer 1

Try this:
while ($row = mysql_fetch_array($res)){
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
This turns the in worods into regular expressions, adding \b to match word boundaries.
My whole test code is:
<?php
$sentance="are you hungry too?";
function newLanguage($text) {
$in_array = array();
$out_array = array();
$rows = array(array('in' => 'you', 'out' => 'noa'),
array('in' => 'to', 'out' => 'nie'),
array('in' => 'too', 'out' => 'niee'));
foreach ($rows as $row) {
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
return preg_replace($in_array,$out_array,$text);
}
$newwords = newLanguage($sentance);
echo $newwords;
The $rows array replaces the database query, but the rest is essentially the same.

Answer 2

BIG thank you to Barmar for his dedicated help and patience in helping me solve my question!
I have made his answer correct since he helped me so much but if you wish to use my final code that is commented please feel free.
My Goal was to IMPORT database rows and insert them into an Array which will be used with preg_replace.
My Final Code was:
//this is the base text that will be modified using database information
$sentance="are you hungry too?";
function newLanguage($text) {
$sql = "SELECT * FROM words";
$res = mysql_query($sql) or die();
$in_array = array();
$out_array = array();
while ($row = mysql_fetch_array($res)){
// inserts the column row 'in' into an array called in_array
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/';
// inserts the column row 'out' into an array called out_array
$out_array[] = $row['out'];
}
//replaced any matching words from 'sentance' with 'in_array' and replaces with 'out_array'
return preg_replace($in_array,$out_array,$text);
}
//this makes a new variable and used a function to replace the text with matches in the variable
$newwords = newLanguage($sentance);
echo $newwords;