How to find a database row that matches a string? - php

I have a databse table with 100K rows and an array of 100 items. And I need to find if an array item is found in my Users table username row.
My database table Users
| id | username | fullname |
1 John John Smith
2 Elliot Jim Elliot
3 Max Max Richard
My array looks like this
[
{
string: 'Hello, this is Elliot from downtown Las Vegas!'
},
{
string: 'Hey how are you?'
}
]
My idea was to do a foreach loop through every row in my Users table (100k records) and find if it matches in my array, but it is so slow.
foreach ($MyArray as $Array) {
foreach ($dbrows as $dbrow) {
if (strpos($Array['string'], $dbrow['username']) !== false) {
echo 'found it!';
break;
}
}
}

It will be a bit hit and miss as you may find users with all sorts of weird names that match normal words, this approach splits the input into words and then uses them to form an in clause to search the database. So it only looks at records that match rather than all records...
$search = 'Hello, this is Elliot from downtown Las a1 Vegas!';
$words = str_word_count($search, 1);
$bind = str_repeat("?,", count($words));
$bind = trim($bind, ",");
$query = $conn->prepare("select * from users where username in ($bind)" );
$types = str_repeat("s", count($words));
$query->bind_param($types, ...$words);
$query->execute();
$res = $query->get_result();
while($row = $res->fetch_assoc()) {
// Process result
}
It also uses prepared statements, which is where all of the $bind and $types processing comes in. If you look at $query you will see how it's built up.

I think the better way was to separate your search arrays into words, and use it in the query, like:
<?php
// Assuming your search array is $search...
$words = array ();
foreach ( $search as $text)
{
$words = array_merge ( $words, explode ( " ", trim ( preg_replace ( "/[^0-9a-z]+/i", " ", $text))));
}
$words = array_unique ( $words);
$in = "";
foreach ( $words as $text)
{
$in .= ",'" . $mysqli->real_escape_string ( $text) . "'";
}
if ( ! $result = $mysqli->query ( "SELECT * FROM `Users` WHERE `username` IN (" . substr ( $in, 1) . ")"))
{
echo "MySQL error!";
}
// Results at $result
?>

You can use regular expressions:
<?php
$query_string = "bla bla bla...";
$qry = $mysqli_query($conn, "SELECT *FROM table WHERE username REGEXP '$query_string'");
?>
Regular expression matches data individually from table.

Related

MySQL Query Into Array for preg_replace

ORIGINAL CODE
$sentance="are you hungry too?";
function newLanguage($text) {
$sql = "SELECT in,out FROM words";
$res = mysql_query($sql) or die();
$in_array = array();
$out_array = array();
while ($row = mysql_fetch_array($res)){
$in_array[] = $row['in']; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
return preg_replace($in_array,$out_array,$text);
}
$newwords = newLanguage($sentance);
echo $newwords;
AMENDED CODE:
ini_set("display_errors", "1");
error_reporting(E_ALL);
function newLanguage($text) {
$sql = "SELECT in,out FROM words";
$res = mysql_query($sql) or die();
$in_array = array();
$out_array = array();
while ($row = mysql_fetch_array($res)){
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
/* VERSION 2 - STATIC, FOR DEBUGGING
$in_array = array('~\you~s','~\to~s','~\too~s');
$out_array = array('noa','nie','niee');*/
return preg_replace($in_array,$out_array,$text);
}
$sentance="are you hungry too?";
$newwords = newLanguage($sentance);
var_dump($in_array);
echo $sentance;
CURRENT CODE
ini_set("display_errors", "1");
error_reporting(E_ALL);
$sentance="are you hungry too?";
function newLanguage($text) {
$sql = "SELECT * FROM words";
$res = mysql_query($sql) or die();
while ($row = mysql_fetch_array($res)){
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
return preg_replace($in_array,$out_array,$text);
}
$newwords = newLanguage($sentance);
var_dump($in_array);
echo $newwords;
I'm having Problems with my code, for the life of me I cannot get it to work, I have worked with preg_replace before in using a word filter. Though creating a dynamic array using query results totally throws me off. I have looked at a few tutorials but none have really helped me understand where I am going wrong.
Any help would be grateful :)
GOAL:
Creating a New Language translation. Database holds a row with 'in' & 'out' which is both the new language and local language.
PROBLEM:
I'm unsure if my Arrays are being successfully populated since my preg_replace isn't working.
----UPDATE----
Here is what my database looks like;
id in out
1 you noa
2 to nie
3 too niee
They are stored as VARCHARS
Try this:
while ($row = mysql_fetch_array($res)){
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
This turns the in worods into regular expressions, adding \b to match word boundaries.
My whole test code is:
<?php
$sentance="are you hungry too?";
function newLanguage($text) {
$in_array = array();
$out_array = array();
$rows = array(array('in' => 'you', 'out' => 'noa'),
array('in' => 'to', 'out' => 'nie'),
array('in' => 'too', 'out' => 'niee'));
foreach ($rows as $row) {
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/'; // table in, NEW words
$out_array[] = $row['out']; //table out, ENG words
}
return preg_replace($in_array,$out_array,$text);
}
$newwords = newLanguage($sentance);
echo $newwords;
The $rows array replaces the database query, but the rest is essentially the same.
BIG thank you to Barmar for his dedicated help and patience in helping me solve my question!
I have made his answer correct since he helped me so much but if you wish to use my final code that is commented please feel free.
My Goal was to IMPORT database rows and insert them into an Array which will be used with preg_replace.
My Final Code was:
//this is the base text that will be modified using database information
$sentance="are you hungry too?";
function newLanguage($text) {
$sql = "SELECT * FROM words";
$res = mysql_query($sql) or die();
$in_array = array();
$out_array = array();
while ($row = mysql_fetch_array($res)){
// inserts the column row 'in' into an array called in_array
$in_array[] = '/\b' . preg_quote($row['in']) . '\b/';
// inserts the column row 'out' into an array called out_array
$out_array[] = $row['out'];
}
//replaced any matching words from 'sentance' with 'in_array' and replaces with 'out_array'
return preg_replace($in_array,$out_array,$text);
}
//this makes a new variable and used a function to replace the text with matches in the variable
$newwords = newLanguage($sentance);
echo $newwords;

search array of words in database

I have text :
$a = I wanna eat apple , and banana .
I wanna get every words and punctuation of that sentence :
$b = explode(' ', strtolower(trim($a)));
the result of explode is array.
I have a words table on db that has fields : id, word and typewords all in lowercase. but for punctuation there are no exist in db.
I wanna search every words in db to take the type of words, so the final result that i want to get is :
words/typeofwords = I/n wanna/v eat/v apple/n ,/, and/p banana/n ./.
here's the code :
function getWord ($word){
$i = 0 ;
$query = mysql_query("SELECT typewords FROM words WHERE word = '$word' ");
while ($row = mysql_fetch_array($query)) {
$word[$i] = $row['typewords'];
$i++;
}
return $word;
}
echo $b.'/'.getWord($b);
but it doesn't work, please help me, thanks !
Try with this:
function getWord($words){
$association = array();
foreach($words as $word)
{
$query = mysql_query("SELECT typewords FROM words WHERE word = '$word' ");
if($row = mysql_fetch_array($query))
$association[$word] = $row['typewords'];
elseif(preg_match('/[\.\,\:\;\?\!]/',$word)==1)
$association[$word] = $word;
}
return $association;
}
$typewords = getWord($b);
foreach($b as $w)
echo $w.'/'.$typewords[$w];
function getWord($word){
// concat the word your searching for with the result
// http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_concat
$query = mysql_query("SELECT CONCAT(word,'/',typewords) as this_result FROM words WHERE word = '$word' ");
$row = mysql_fetch_array($query);
return $row['this_result']." "; // added a space at the end.
}
// loop through the $b array and send each to the function
foreach($b as $searchword) {
echo getWord($searchword);
}
You assume the function parameter to be an array, but it is a string.
Edit: In your function you treat $word as an array as well as a string. Decide what you want and recode your function.

PHP Array to string conversion, mysql_fetch_assoc() expects parameter [duplicate]

This question already has answers here:
mysql_fetch_array()/mysql_fetch_assoc()/mysql_fetch_row()/mysql_num_rows etc... expects parameter 1 to be resource
(31 answers)
Closed 8 years ago.
Can someone please help me with my code, I can't get it to work.
I have an html input form where I type for example "This is a sample".
(data is saved in $_POST['Begriff'])
I want to achive a simple translation, so that the table "drinks" in column "English" is checked for existence of every single word from my input sample sentence and output if found every entry from the corresponding row in one line.
Right now I have two problems:
As soon as I add " where English in $wert" to the select statement I get:
Notice: Array to string conversion in nachlesen.php on line 34
Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given
Second Problem: How to I put the sentence together again from the returned results?
(Right now I get the output for every found word below each other, instead of one line)
Here is my code:
if ( $_POST['Begriff'] <> "")
{
$wert = explode(' ',$_POST['Begriff']);
$select = mysql_query ("SELECT * FROM drinks where English in $wert");
while ( $row = mysql_fetch_assoc($select))
{
echo ("$row[German] <br>");
echo ("$row[English]<br>");
}
}
Thanks in Advance, Daniel
<?php
// premise: the user input in $_POST['Begriff'] is a string like 'This is a sample'
//first split it into single words
// preg_split: \s+ -> one or more whitespaces , PREG_SPLIT_NO_EMPTY -> no "empty" words
// e.g. " Mary had a little lamb" -> array('Mary','had','a','little','lamb')
$words = preg_split('!\s+!', $_POST['Begriff'], -1, PREG_SPLIT_NO_EMPTY);
// now encode each string so that it can be used
// safely as a string-literal within your sql query
// see: sql injection
// this should be:
// $words = array_map(function($e) use($mysql) { return mysql_real_escape_string($e, $mysql); }, $words);
// but apparently you're not storing the resource that is returned by mysql_connect
// mysql_real_escape_string() is applied to each single element in $words
// e.g. array("it's", "been") -> array("it\\'s", "been")
$words = array_map('mysql_real_escape_string', $words);
// now put the string literals into your query
// format: ... IN ('x','y','z')
// join(",", $words) gives you x,y,z
// join("','", $words) gives you x','y','z
// i.e. the first and the last ' has to be added "manually"
// keep in mind that for an empty array $words this will produce WHERE ... IN ('')
// better test that before even trying to build the query
$query = sprintf("
SELECT
German,English
FROM
drinks
WHERE
English IN ('%s')
", join("','", $words));
// send the query to the MySQL server
// should be: $result = mysql_query($query, $mysql);
$result = mysql_query($query);
// database query -> failure is always an option
if ( !$result ) {
// add error handling here
}
else {
// in case there is not a single match in the database
// your script would print ...nothing
// I don't like that - but that debatable
// anway: wrapped in a fieldset
echo '<fieldset><legend>results:</legends>';
while( false!==($row=mysql_fetch_array($result, MYSQL_FETCH_ASSOC)) ) {
printf('%s<br />%s<br />',
// just like on the input-side you had to worry about
// sql injections
// on the output side you want to avoid
// that characters from the database can break your html structure
htmlentities($row['German']),
htmlentities($row['English'])
);
}
echo '</fieldset>';
}
(script is untested)
why don't you try implode() and convert your array to string??
if ( $_POST['Begriff'] <> "")
{
//you'l have to replace all "spaces with ',' "
$pattern = '/\s*,\s*/';
$replace = "','";
$wert = preg_replace($pattern, $replace, $_POST['Begriff']);
$select = mysql_query ("SELECT * FROM drinks where English in ('$wert')");
while ( $row = mysql_fetch_assoc($select))
{
echo ("$row[German] <br>");
echo ("$row[English]<br>");
}
}
ANOTHER SOLUTION (TO PREVENT SQL INJECTION)
if ( $_POST['Begriff'] <> "")
{
//replace multiple spaces
$str1 = preg_replace( "/\s+/", " ", $_POST['Begriff'] );
//convert to array, separated by space
$arr=explode(" ",$str1);
$safe_params=array();
foreach($arr as $param){
$safe_params[]=mysql_real_escape_string($param);
}
$wert=implode("','",$safe_params);
$select = mysql_query ("SELECT * FROM drinks where English in ('$wert')");
while ( $row = mysql_fetch_assoc($select))
{
echo ("$row[German] <br>");
echo ("$row[English]<br>");
}
}
EDIT
Processing query output according to language
$german_words=array();
while ( $row = mysql_fetch_assoc($select))
{
$german_words[$row['English']]=$row['Gernam'];
}
//$str1 is having english string
echo "English: ".$str1."<br/>";
echo "German : ";
//$arr is having array of words of $str1
foreach($arr as $eng_word){
echo $german_words[$eng_word]." ";
}
"SELECT * FROM drinks where English in ('". implode("','", $wert) . "')"
EDIT: SQL Injection safe query:
$dsn = 'mysql:dbname=' . $settings['dbname'] . ';host=' . $settings['dbhost'];
$pdo = new PDO($dsn, $settings['dbuser'], $settings['dbpass'], array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"));
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$pdo->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
if ( $_POST['Begriff'] <> "")
{
$wert = explode(' ',$_POST['Begriff']);
$placeholders = implode(',', array_fill(0, count($wert), '?'));
$sth = $pdo->prepare("SELECT * FROM drinks WHERE English in ({$placeholders})");
$sth->execute($wert);
$rows = $sth->fetchAll();
foreach($rows as $row) {
print_r( $row );
}
}

PHP compare two arrays from different locations

I am wanting to compare two different arrays. Basically I have a database with phrases in and on my website I have a search function where the user types in a phrase.
When they click search I have a PHP page which 'explodes' the string typed in by the user and its put into an array.
Then I pull all the phrases from my database where I have also used the 'explode' function and split all the words into an array.
I now want to compare all the arrays to find close matches with 3 or more words matching each phrase.
How do I do this?
Well what I've tried totally failed, but here is what I have
$search_term = filter_var($_GET["s"], FILTER_SANITIZE_STRING); //user entered data
$search_term = str_replace ("?", "", $search_term); //removes question marks
$array = explode(" ", $search_term); //breaks apart user entered data
foreach ($array as $key=>$word) {
$array[$key] = " title LIKE '%".$word."%' "; //creates condition for MySQL query
}
$q = "SELECT * FROM posts WHERE " . implode(' OR ', $array) . " LIMIT 0,10";
$r = mysql_query($q);
while($row = mysql_fetch_assoc($r)){
$thetitle = $row['title'];
$thetitle = str_replace ("?", "", $thetitle);
$title_array[] = $thetitle;
$newarray = explode(" ", $search_term);
foreach ($newarray as $key=>$newword) {
foreach($title_array as $key => $value) {
$thenewarray = explode(" ", $value);
$contacts = array_diff_key($thenewarray, array_flip($newarray));
foreach($contacts as $key => $value) {
echo $newword."<br />";
echo $value."<br /><hr />";
}
}
}
But basically all I want is to display suggested phrases which are similar to what the user has already typed into the search box.
So If I searched "How do I compare two arrays that have the same values?", I would see 10 suggestions that are worded similar, so like "How to compare multiple arrays?" or "can I compare two arrays" etc...
So basically like when I first posted this question on this site, I got other questions that may help, thats basically what I want. This code im using was origionally to match just one word or an exact matching string, im editing it to find matching words and only show phrases with 3 or more matching words.
I don't think that this is the best solution for your search script. But I'll try to give you the answer:
<?php
$string1 = "This is my first string";
$string2 = "And here is my second string";
$array1 = explode(" ", $string1);
$array2 = explode(" ", $string2);
$num = 0;
foreach($array1 as $arr) {
if(in_array($arr, $array2))
$num++;
}
$match = $num >= 3 ? true : false;
?>
use array_intersect function
$firstArray = "This is a test only";
$secondArray = "This is test";
$array1 = explode(" ", $firstArray);
$array2 = explode(" ", $secondArray);
$result = array_intersect($array1, $array2);
$noOfWordMatch = count($result);
$check = $noOfWordMatch >= 3 ? true : false; ;

How would I sort this array [duplicate]

This question already has an answer here:
Closed 10 years ago.
Possible Duplicate:
How to sort the results of this code?
Im making a search feature which allows a user to search a question and it will show the top 5 best matching results by counting the number of matching words in the question.
Basically I want the order to show the best match first which would be the question with the highest amount of matching words.
Here is the code I have.
<?php
include("config.php");
$search_term = filter_var($_GET["s"], FILTER_SANITIZE_STRING); //User enetered data
$search_term = str_replace ("?", "", $search_term); //remove any question marks from string
$search_count = str_word_count($search_term); //count words of string entered by user
$array = explode(" ", $search_term); //Seperate user enterd data
foreach ($array as $key=>$word) {
$array[$key] = " title LIKE '%".$word."%' "; //creates condition for MySQL query
}
$q = "SELECT * FROM posts WHERE " . implode(' OR ', $array); //Query to select data with word matches
$r = mysql_query($q);
$count = 0; //counter to limit results shown
while($row = mysql_fetch_assoc($r)){
$thetitle = $row['title']; //result from query
$thetitle = str_replace ("?", "", $thetitle); //remove any question marks from string
$title_array[] = $thetitle; //creating array for query results
$newarray = explode(" ", $search_term); //Seperate user enterd data again
foreach($title_array as $key => $value) {
$thenewarray = explode(" ", $value); //Seperate each result from query
$wordmatch = array_diff_key($thenewarray, array_flip($newarray));
$result = array_intersect($newarray, $wordmatch);
$matchingwords = count($result); //Count the number of matching words from
//user entered data and the database query
}
if(mysql_num_rows($r)==0)//no result found
{
echo "<div id='search-status'>No result found!</div>";
}
else //result found
{
echo "<ul>";
$title = $row['title'];
$percentage = '.5'; //percentage to take of search word count
$percent = $search_count - ($search_count * $percentage); //take percentage off word count
if ($matchingwords >= $percent){
$finalarray = array($title => $matchingwords);
foreach( $finalarray as $thetitle=>$countmatch ){
?>
<li><?php echo $thetitle ?><i> <br />No. of matching words: <?php echo $countmatch; ?></i></li>
<?php
}
$count++;
if ($count == 5) {break;
}
}else{
}
}
echo "</ul>";
}
?>
When you search something it will show something like this.
Iv put the number of matching words under each of the questions however they are not in order. It just shows the first 5 questions from the database that have a 50% word match. I want it to show the top 5 with the most amount of matching words.
What code would I need to add and where would I put it in order to do this?
Thanks
Here's my take on your problem. A lot of things have been changed:
mysql_ functions replaced with PDO
usage of anonymous functions means PHP 5.3 is required
main logic has been restructured (it's really hard to follow your result processing, so I might be missing something you need, for example the point of that $percentage)
I realize this might look complicated, but I think that the sooner you learn modern practices (PDO, anonymous functions), the better off you will be.
<?php
/**
* #param string $search_term word or space-separated list of words to search for
* #param int $count
* #return stdClass[] array of matching row objects
*/
function find_matches($search_term, $count = 5) {
$search_term = str_replace("?", "", $search_term);
$search_term = trim($search_term);
if(!strlen($search_term)) {
return array();
}
$search_terms = explode(" ", $search_term);
// build query with bind variables to avoid sql injection
$params = array();
$clauses = array();
foreach ($search_terms as $key => $word) {
$ident = ":choice" . intval($key);
$clause = "`title` LIKE {$ident}";
$clauses []= $clause;
$params [$ident] = '%' . $word . '%';
}
// execute query
$pdo = new PDO('connection_string');
$q = "SELECT * FROM `posts` WHERE " . implode(' OR ', $clauses);
$query = $pdo->prepare($q);
$query->execute($params);
$rows = $query->fetchAll(PDO::FETCH_OBJ);
// for each row, count matches
foreach($rows as $row) {
$the_title = $row->title;
$the_title = str_replace("?", "", $the_title);
$title_terms = explode(" ", $the_title);
$result = array_intersect($search_terms, $title_terms);
$row->matchcount = count($result);
}
// sort all rows by match count descending, rows with more matches come first
usort($rows, function($row1, $row2) {
return - ($row1->matchcount - $row2->matchcount);
});
return array_slice($rows, 0, $count);
}
?>
<?php
$search_term = filter_var($_GET["s"], FILTER_SANITIZE_STRING);
$best_matches = find_matches($search_term, 5);
?>
<?php if(count($best_matches)): ?>
<ul>
<?php foreach($best_matches as $match): ?>
<li><?php echo htmlspecialchars($match->title); ?><i> <br/>No. of matching words: <?php echo $match->matchcount; ?></i></li>
<?php endforeach; ?>
</ul>
<?php else: ?>
<div id="search-status">No result found!</div>
<?php endif; ?>
Try adding asort($finalarray); after your $finalarray = array($title => $matchingwords); declaration:
...
if ($matchingwords >= $percent){
$finalarray = array($title => $matchingwords);
asort($finalarray);
....
It should sort your array Ascending by the Values

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