SQL format don't work - php

i have a problem with my sql request probably a synthax problem, can u watch it? see the line:
$stmt = $this->pdo->prepare("SELECT " . $fields . "FROM" . $table . "WHERE link = " . $requestUrl);
i think "FROM" and "WHERE..." is not good, what is the exact synthax?

$requestUrl must have been wrapped with single quotes and leave proper spaces in query
$sql = "SELECT " . $fields . " FROM " . $table . " WHERE link = '" . $requestUrl ."'";
$stmt = $this->pdo->prepare($sql);

Related

Convert "INSERT" MySQL query to Postgresql query

I`m stuck for some time to fix this trouble. I followed this article https://www.sitepoint.com/creating-a-scrud-system-using-jquery-json-and-datatables/
to create SCRUD System. But I stuck when I need to add a new record to PostgreSQL.
The working MySQL part of the code is:
$db_server = 'localhost';
$db_username = 'root';
$db_password = '123456';
$db_name = 'test';
$db_connection = mysqli_connect($db_server, $db_username, $db_password, $db_name);
$query = "INSERT INTO it_companies SET ";
if (isset($_GET['rank'])) { $query .= "rank = '" . mysqli_real_escape_string($db_connection, $_GET['rank']) . "', "; }
if (isset($_GET['company_name'])) { $query .= "company_name = '" . mysqli_real_escape_string($db_connection, $_GET['company_name']) . "', "; }
if (isset($_GET['industries'])) { $query .= "industries = '" . mysqli_real_escape_string($db_connection, $_GET['industries']) . "', "; }
if (isset($_GET['revenue'])) { $query .= "revenue = '" . mysqli_real_escape_string($db_connection, $_GET['revenue']) . "', "; }
if (isset($_GET['fiscal_year'])) { $query .= "fiscal_year = '" . mysqli_real_escape_string($db_connection, $_GET['fiscal_year']) . "', "; }
if (isset($_GET['employees'])) { $query .= "employees = '" . mysqli_real_escape_string($db_connection, $_GET['employees']) . "', "; }
if (isset($_GET['market_cap'])) { $query .= "market_cap = '" . mysqli_real_escape_string($db_connection, $_GET['market_cap']) . "', "; }
if (isset($_GET['headquarters'])) { $query .= "headquarters = '" . mysqli_real_escape_string($db_connection, $_GET['headquarters']) . "'"; }
$query = mysqli_query($db_connection, $query);
I managed to write this and it fails to work for PostgreSQL:
$conn_string = "dbname=test user=postgres password=123456";
$query = "INSERT INTO it_companies VALUES ";
if (isset($_GET['rank'])) { $query .= "('" . pg_escape_string($db_connection, $_GET['rank']) . "', "; }
if (isset($_GET['company_name'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['company_name']) . "', "; }
if (isset($_GET['industries'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['industries']) . "', "; }
if (isset($_GET['revenue'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['revenue']) . "', "; }
if (isset($_GET['fiscal_year'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['fiscal_year']) . "', "; }
if (isset($_GET['employees'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['employees']) . "', "; }
if (isset($_GET['market_cap'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['market_cap']) . "', "; }
if (isset($_GET['headquarters'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['headquarters']) . "');"; }
$query = pg_query($db_connection, $query);
The message I gets from the system is: "Add request failed: parsererror"
The Edit and remove functions are working well.
I follow to build this clause from the PGSQL site example:
INSERT INTO films VALUES
('UA502', 'Bananas', 105, '1971-07-13', 'Comedy', '82 minutes');
Any what I`m doing wrong? Thanks!
UPDATE
The echo of the query and the error was the id column. In Mysql code there was no problem with the ID colum. Why when i use pgsql it does?:
INSERT INTO it_companies (rank,company_name,industries,revenue,fiscal_year,employees,market_cap,headquarters)
VALUES ('1', 'asd', 'asd', '1', '2000', '2', '3', 'asdf');
Warning: pg_query(): Query failed: ERROR: duplicate key value violates unique constraint "it_companies_pkey" DETAIL: Key (company_id)=(2) already exists. in C:\WEB\Apache24\htdocs\datatableeditor\data.php on line 121
{"result":"error","message":"query error"
,"data":[]}
UPDATE2
The working code with one bug:
$query = "INSERT INTO it_companies (rank,company_name,industries,revenue,fiscal_year,employees,market_cap,headquarters) VALUES ";
if (isset($_GET['rank'])) { $query .= "('" . $_GET['rank'] . "', "; }
if (isset($_GET['company_name'])) { $query .= "'" . $_GET['company_name'] . "', "; }
if (isset($_GET['industries'])) { $query .= "'" . $_GET['industries'] . "', "; }
if (isset($_GET['revenue'])) { $query .= "'" . $_GET['revenue'] . "', "; }
if (isset($_GET['fiscal_year'])) { $query .= "'" . $_GET['fiscal_year'] . "', "; }
if (isset($_GET['employees'])) { $query .= "'" . $_GET['employees'] . "', "; }
if (isset($_GET['market_cap'])) { $query .= "'" . $_GET['market_cap'] . "', "; }
if (isset($_GET['headquarters'])) { $query .= "'" . $_GET['headquarters'] . "') RETURNING company_id;"; }
echo $query;
After this query, the message "Add request failed: parsererror" is still there. But after a manual refresh of the page, the new data is saved. Any idea why this message apears and not loading the data automatically?
UPDATE 3 - Success
I forgot to remove echo $query; from the code causing the error message.
All works now. Thanks for the help to all! :)
You need a little more work in your query string building.
You only add the open parenthesis ( if rank is present
You only add the closing parenthesis ) if headquarters is present.
Also you need specify what field column get which value, otherwise you end with headquarter name into the fiscal_year field. If columns are not specified the values are add it on the same order as define on the table.
INSERT INTO TABLE_NAME (column1, column2, column3,...columnN)
VALUES (value1, value2, value3,...valueN);
And as other have comment check the $query to see what you have.

Could not find what's wrong in sql set values

I have the following SQL.
$sql_shells = "UPDATE `shells` SET `situation` = 'sold' WHERE `id` = '" . $id . "'";
$conn->query($sql_shells);
I updated the rows with column named buytime and another one called buyer so it would be like this:
$sql_shells = "UPDATE `shells` SET `buyer`= " . $buyer . ", `buytime`= " . $trn_date . " , `situation` = 'sold' WHERE `id` = '" . $id . "'";
$conn->query($sql_shells);
It's not updating.
`$trn_date = $trn_date = date("Y-m-d H:i:s");
and
$buyer = $_SESSION['username'];
Error log is empty.
Another SQL update doesn't have constant values and works fine
$sql_users = "UPDATE `users` SET `amount`= " . $newAmount . ", `gain`= " . $newgain . " WHERE `username` = '" . $buyer . "'";
I tried echoing the SQL query that's not working, this is what I get when I run it.
try to remove ` caracter and i think buytime and buyer should add ' caracter and remove it from id if is int type:
$sql_shells = "UPDATE shells SET buyer= '" . $buyer . "', buytime= '" . $trn_date . "' , situation = 'sold' WHERE id = " . $id ;
$conn->query($sql_shells);

Escape String in SQL Server using PHP

Whenever I implement this code, I no longer get an error while using a single quote, but the hexstring get's written to the database instead of being converted back to the original characters.
function mssql_escape($data) {
if(is_numeric($data))
return $data;
$unpacked = unpack('H*hex', $data);
return '0x' . $unpacked['hex'];
}
mssql_query('
INSERT INTO sometable (somecolumn)
VALUES (' . mssql_escape($somevalue) . ')
');
This is what I'm trying to do. $suggestTest is the variable I'm using the escape function on.
$nomDept = $_POST['nomDept'];
$subSupervisor = $_POST['subSupervisor'];
$suggestion = $_POST['suggestion'];
$suggestTest = mssql_escape($suggestion);
if ($subSupervisor == "Yes") {
$query = "INSERT INTO dbo.emp_recog (nomDept, nomSuggestion, subSupervisor) VALUES (";
$query .= "'" . $nomDept . "', ";
$query .= "'" . $suggestTest . "', ";
$query .= "'" . $subSupervisor . "');";
$res = mssql_query($query);
}
I've also tried omitting the single quotes around the variable like so
if ($subSupervisor == "Yes") {
$query = "INSERT INTO dbo.emp_recog (nomDept, nomSuggestion, subSupervisor) VALUES (";
$query .= "'" . $nomDept . "', ";
$query .= $suggestTest ", ";
$query .= "'" . $subSupervisor . "');";
$res = mssql_query($query);
}
If you use prepare to build your SQL statement, you do not need to escape the variables.

Mutliple querystring parameters to mysql query

I originally had this working:
url: http://server/blah.php?FacilityCode=FT
$facilitycode = mysql_real_escape_string($_GET["FacilityCode"]);
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
"AND ('" . $facilitycode . "' = '' OR Facility.FacilityCode = '". $facilitycode . "')";
$result = mysql_query($sql);
But I want to change this so that people can submit multiple values in the query strying somehow, ie: http://server/blah.php?FacilityCode=FT,CC,DD,EE
I tried changing the query to an "IN" clause instead of an "equals" but I'm not sure how to get the ' marks around each element.
Use implode() function for IN (...).
$a = array('AB', 'CD', 'EF', 'ZE');
echo "field IN ('" . implode("', '", $a) . "')";
... will output:
field IN ('AB', 'CD', 'EF', 'ZE')
+escape every option you get.
$facilitycode = mysql_real_escape_string($_GET["FacilityCode"]);
$array=explode(',',$facilitycode);
foreach ($array as $a){$output.="'$a',";}
$clause=substr($output,0,-1);
If your trying to create a string which looks like this: 'AB', 'CD', 'EF', 'ZE'
Try this before its placed inside the query:
$facilitycode = preg_replace('/([^,]+)/', '\'$1\'', $facilitycode);
I wrote this based on your query, but still I dont get this part of query "AND ('" . $facilitycode . "' = ''", anyway you need to check if $_GET data have "," and if does explode that variable by "," so that you can add an OR clausule for everything that was separated by "," in $_GET data.
After that just form your query by doing a foreach for every element in exploded array like I done below:
<?php
$facilitycode = $_GET["FacilityCode"];
$facility_number_chk = strpos($facilitycode, ",");
if ($facility_number_chk > -1) {
$facilitycode = explode(",", $facilitycode);
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
"AND ('" . $facilitycode . "' = ''";
foreach($facilitycode as $facode) {
$facode = mysql_real_escape_string($facode);
$sql .= " OR Facility.FacilityCode = '". $facode . "'";
}
$sql .= "')";
}
else {
$facilitycode = mysql_real_escape_string($facilitycode);
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
"AND ('" . $facilitycode . "' = '' OR Facility.FacilityCode = '". $facilitycode . "')";
}
$result = mysql_query($sql);
And if there is only one element in $_GET data just do an else like I done with your regular query.
I ended up using a combination of a few of the answers. Basically I exploded on the ",", then did a foreach to add the ' marks and call escape_string, and then imploded it back.
$facilitycodes = $_GET["FacilityCode"];
if ($facilitycodes == '') {
$additionalfilter = '';
}
else {
$facilitycodearray = explode(",", $facilitycodes);
foreach($facilitycodearray as &$facilitycode) {
$facilitycode = "'" . mysql_real_escape_string($facilitycode) . "'";
}
$facilitycodesformatted = implode(",", $facilitycodearray);
$additionalfilter = " AND Facility.FacilityCode IN (" . $facilitycodesformatted . ")";
}
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
$additionalfilter;

PHP script not updating mysql table

this script is simply not working... can anyone tell me what I'm doing wrong?
$id = $_POST['id'];
$name = $_POST['name'];
$date = $_POST['date'];
$shortdesc = $_POST['shortdesc'];
$link = $_POST['link'];
$target = $_POST['target'];
$sort = $_POST['sort'];
$html = $_POST['html'];
include('appvars.php');
$query = "UPDATE insight SET name='".$name."' AND SET date='". $date . "' AND SET html='" . $html . "' AND SET shortdesc='" . $shortdesc . "' AND SET link='" . $link . "' AND SET target='" . $target . "' AND SET sort='" . $sort . "' WHERE id='" . $id . "'";
mysqli_query($dbc, $query);
You aren't escaping your values so you are vulnerable to SQL injection and also construction of invalid statements. For example, if any of your input strings contain an apostrophe then it could cause your code to fail.
Have a look at prepared statements that will make it much easier to construct your queries with parameters.
In your query you will also need to use commas instead of AND SET.
$query = "UPDATE insight SET name='foo', date='2012-12-10' WHERE id=42";
The syntax for UPDATE is described in the MySQL documentation:
UPDATE syntax
Use it like this,
$query = "UPDATE insight SET name='".$name."' ,date='". $date . "' ,html='" . $html . "' ,shortdesc='" . $shortdesc . "' ,link='" . $link . "' ,target='" . $target . "' ,sort='" . $sort . "' WHERE id='" . $id . "'";
Its working ... check now
$id = $_POST['id'];
$name = $_POST['name'];
$date = $_POST['date'];
$shortdesc = $_POST['shortdesc'];
$link = $_POST['link'];
$target = $_POST['target'];
$sort = $_POST['sort'];
$html = $_POST['html'];
include('appvars.php');
$query = "UPDATE insight SET name='".$name."' ,date='". $date . "' ,html='" . $html . "' ,shortdesc='" . $shortdesc . "' ,link='" . $link . "' ,target='" . $target . "' ,sort='" . $sort . "' WHERE id='" . $id . "'";
mysqli_query($dbc, $query);
I aint a pro at mysql, but a try.
I guess id is an integer. So, dont quote it.
Try this,
$query = "UPDATE insight SET name='".$name."' , date='". $date . "' , html='" . $html . "' , shortdesc='" . $shortdesc . "' , link='" . $link . "' , target='" . $target . "' , sort='" . $sort . "' WHERE id=". $id ;
I think the SQL syntax is not correct, you can use it like this: UPDATE tablename SET rowname = value , ....

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