Escape String in SQL Server using PHP - php

Whenever I implement this code, I no longer get an error while using a single quote, but the hexstring get's written to the database instead of being converted back to the original characters.
function mssql_escape($data) {
if(is_numeric($data))
return $data;
$unpacked = unpack('H*hex', $data);
return '0x' . $unpacked['hex'];
}
mssql_query('
INSERT INTO sometable (somecolumn)
VALUES (' . mssql_escape($somevalue) . ')
');
This is what I'm trying to do. $suggestTest is the variable I'm using the escape function on.
$nomDept = $_POST['nomDept'];
$subSupervisor = $_POST['subSupervisor'];
$suggestion = $_POST['suggestion'];
$suggestTest = mssql_escape($suggestion);
if ($subSupervisor == "Yes") {
$query = "INSERT INTO dbo.emp_recog (nomDept, nomSuggestion, subSupervisor) VALUES (";
$query .= "'" . $nomDept . "', ";
$query .= "'" . $suggestTest . "', ";
$query .= "'" . $subSupervisor . "');";
$res = mssql_query($query);
}
I've also tried omitting the single quotes around the variable like so
if ($subSupervisor == "Yes") {
$query = "INSERT INTO dbo.emp_recog (nomDept, nomSuggestion, subSupervisor) VALUES (";
$query .= "'" . $nomDept . "', ";
$query .= $suggestTest ", ";
$query .= "'" . $subSupervisor . "');";
$res = mssql_query($query);
}

If you use prepare to build your SQL statement, you do not need to escape the variables.

Related

How to fix syntax error in PHP when statement works fine in MySQL?

I'm using PHP/MySQL to store data collected from a web page. I'm getting
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO narrative_photos VALUES (`filename`, `narrative_id`) VALUES ('ash_02
When I take the statement produced by PHP and paste it into the MySQL console, the statement works fine.
Here's the PHP code:
foreach ($files['pictures']['final_name'] as $key => $final_name) {
$sql .= "INSERT INTO narrative_photos ";
$sql .= "(`filename`, `narrative_id`) ";
$sql .= "VALUES (";
$sql .= "'" . db_escape($db, $final_name) . "', ";
$sql .= "'LAST_INSERT_ID()'); ";
}
It produces something that looks like this:
INSERT INTO narrative_photos VALUES (`filename`, `narrative_id`) VALUES ('ash_020819-140257.png', 3);
If I paste that into MySQL it works. But if I comment out the PHP code and substitute:
$sql .= "INSERT INTO narrative_photos VALUES (`filename`, `narrative_id`) VALUES ('ash_020819-140257.png', 3);";
it continues to throw the MySQL error.
I've been playing with this for a couple of hours and I can't figure out where my mistake is. I would appreciate a second set of eyes. Thanks!
EDIT: Here's the entire function for context.
function insert_narrative($narrative, $files) {
global $db;
$sql = "INSERT INTO narratives ";
$sql .= "(date, positive_thing, what_you_did, goals, plan, entered_by, library_id) ";
$sql .= "VALUES (";
$sql .= "'" . db_escape($db, $narrative['sqldate']) . "', ";
$sql .= "'" . db_escape($db, $narrative['positive_thing']) . "', ";
$sql .= "'" . db_escape($db, $narrative['what_you_did']) . "', ";
$sql .= "'" . db_escape($db, $narrative['goals']) . "', ";
$sql .= "'" . db_escape($db, $narrative['plan']) . "', ";
$sql .= "'" . db_escape($db, $narrative['entered_by']) . "', ";
$sql .= "'" . db_escape($db, $_SESSION['library_id']) . "'";
$sql .= "); ";
if (!empty($files['pictures']['final_name'])) {
foreach ($files['pictures']['final_name'] as $key => $final_name) {
$sql .= "INSERT INTO narrative_photos ";
$sql .= "(`filename`, `narrative_id`) ";
$sql .= "VALUES (";
$sql .= "'" . db_escape($db, $final_name) . "', ";
$sql .= "LAST_INSERT_ID()); ";
}
}
$result = mysqli_query($db, $sql);
if ($result) {
return true;
} else {
echo mysqli_error($db);
db_disconnect($db);
exit;
}
}
EDIT #2:
I just realized that independent of the syntax error my approach isn't going to work because that LAST_INSERT_ID is probably going to pick up the ids for each of those inserts instead of just using the id from the main table. I've modified the function but I'm still getting a syntax error at SET #narrative_id. Here's the code.
$sql = "INSERT INTO narratives ";
$sql .= "(date, positive_thing, what_you_did, goals, plan, entered_by, library_id) ";
$sql .= "VALUES (";
$sql .= "'" . db_escape($db, $narrative['sqldate']) . "', ";
$sql .= "'" . db_escape($db, $narrative['positive_thing']) . "', ";
$sql .= "'" . db_escape($db, $narrative['what_you_did']) . "', ";
$sql .= "'" . db_escape($db, $narrative['goals']) . "', ";
$sql .= "'" . db_escape($db, $narrative['plan']) . "', ";
$sql .= "'" . db_escape($db, $narrative['entered_by']) . "', ";
$sql .= "'" . db_escape($db, $_SESSION['library_id']) . "'";
$sql .= "); ";
$sql .= "SET #narrative_id = LAST_INSERT_ID()";
if (!empty($files['pictures']['final_name'])) {
foreach ($files['pictures']['final_name'] as $key => $final_name) {
$sql .= "INSERT INTO narrative_photos ";
$sql .= "(`filename`, `narrative_id`) ";
$sql .= "VALUES (";
$sql .= "'" . db_escape($db, $final_name) . "', ";
$sql .= "#narrative_id); ";
}
}
If you're trying to make one query to insert all the values, you need to not include the INSERT part of the query each time, just adding a new set of values instead. You could use something like this. Note that LAST_INSERT_ID() should not be enclosed in quotes, as that will insert the literal string "LAST_INSERT_ID()" instead of the value.
$sql = "INSERT INTO narrative_photos (`filename`, `narrative_id`) VALUES ";
$values = array();
foreach ($files['pictures']['final_name'] as $final_name) {
$values[] = "('" . db_escape($db, $final_name) . "', LAST_INSERT_ID())";
}
$sql .= implode(', ', $values);
Notes
I'm assuming that you actually want all of these filenames to end up with the same value in narrative_id, which is going to link back to another table.
Although from the look of it these values have been filtered already (I presume they are actual system filenames), the code is still potentially vulnerable to SQL injection. This question and this question offer some good advice as to how you can use prepared statements with arrays of parameters.
I don't understand why you concatenating each line to a variable instead of just doing an entire statement. Also, in your examples you have used VALUES twice which is incorrect. I can't understand why you are creating the SQL statement inside a loop but you never execute it, which you need to. I don't know what API you are using but here's an example.
if (isset($files['pictures']['final_name'])) {
foreach ($files['pictures']['final_name'] as $key => $final_name) {
$sql = "INSERT INTO narrative_photos (`filename`, `narrative_id`)
VALUES ('".db_escape($db, $final_name)."', LAST_INSERT_ID())";
if (!$mysqli->query($sql)) {
echo "SQL failed: (".$mysqli->errno.") ".$mysqli->error;
}
}
} else {
echo "final name does not exist";
}

Convert "INSERT" MySQL query to Postgresql query

I`m stuck for some time to fix this trouble. I followed this article https://www.sitepoint.com/creating-a-scrud-system-using-jquery-json-and-datatables/
to create SCRUD System. But I stuck when I need to add a new record to PostgreSQL.
The working MySQL part of the code is:
$db_server = 'localhost';
$db_username = 'root';
$db_password = '123456';
$db_name = 'test';
$db_connection = mysqli_connect($db_server, $db_username, $db_password, $db_name);
$query = "INSERT INTO it_companies SET ";
if (isset($_GET['rank'])) { $query .= "rank = '" . mysqli_real_escape_string($db_connection, $_GET['rank']) . "', "; }
if (isset($_GET['company_name'])) { $query .= "company_name = '" . mysqli_real_escape_string($db_connection, $_GET['company_name']) . "', "; }
if (isset($_GET['industries'])) { $query .= "industries = '" . mysqli_real_escape_string($db_connection, $_GET['industries']) . "', "; }
if (isset($_GET['revenue'])) { $query .= "revenue = '" . mysqli_real_escape_string($db_connection, $_GET['revenue']) . "', "; }
if (isset($_GET['fiscal_year'])) { $query .= "fiscal_year = '" . mysqli_real_escape_string($db_connection, $_GET['fiscal_year']) . "', "; }
if (isset($_GET['employees'])) { $query .= "employees = '" . mysqli_real_escape_string($db_connection, $_GET['employees']) . "', "; }
if (isset($_GET['market_cap'])) { $query .= "market_cap = '" . mysqli_real_escape_string($db_connection, $_GET['market_cap']) . "', "; }
if (isset($_GET['headquarters'])) { $query .= "headquarters = '" . mysqli_real_escape_string($db_connection, $_GET['headquarters']) . "'"; }
$query = mysqli_query($db_connection, $query);
I managed to write this and it fails to work for PostgreSQL:
$conn_string = "dbname=test user=postgres password=123456";
$query = "INSERT INTO it_companies VALUES ";
if (isset($_GET['rank'])) { $query .= "('" . pg_escape_string($db_connection, $_GET['rank']) . "', "; }
if (isset($_GET['company_name'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['company_name']) . "', "; }
if (isset($_GET['industries'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['industries']) . "', "; }
if (isset($_GET['revenue'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['revenue']) . "', "; }
if (isset($_GET['fiscal_year'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['fiscal_year']) . "', "; }
if (isset($_GET['employees'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['employees']) . "', "; }
if (isset($_GET['market_cap'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['market_cap']) . "', "; }
if (isset($_GET['headquarters'])) { $query .= "'" . pg_escape_string($db_connection, $_GET['headquarters']) . "');"; }
$query = pg_query($db_connection, $query);
The message I gets from the system is: "Add request failed: parsererror"
The Edit and remove functions are working well.
I follow to build this clause from the PGSQL site example:
INSERT INTO films VALUES
('UA502', 'Bananas', 105, '1971-07-13', 'Comedy', '82 minutes');
Any what I`m doing wrong? Thanks!
UPDATE
The echo of the query and the error was the id column. In Mysql code there was no problem with the ID colum. Why when i use pgsql it does?:
INSERT INTO it_companies (rank,company_name,industries,revenue,fiscal_year,employees,market_cap,headquarters)
VALUES ('1', 'asd', 'asd', '1', '2000', '2', '3', 'asdf');
Warning: pg_query(): Query failed: ERROR: duplicate key value violates unique constraint "it_companies_pkey" DETAIL: Key (company_id)=(2) already exists. in C:\WEB\Apache24\htdocs\datatableeditor\data.php on line 121
{"result":"error","message":"query error"
,"data":[]}
UPDATE2
The working code with one bug:
$query = "INSERT INTO it_companies (rank,company_name,industries,revenue,fiscal_year,employees,market_cap,headquarters) VALUES ";
if (isset($_GET['rank'])) { $query .= "('" . $_GET['rank'] . "', "; }
if (isset($_GET['company_name'])) { $query .= "'" . $_GET['company_name'] . "', "; }
if (isset($_GET['industries'])) { $query .= "'" . $_GET['industries'] . "', "; }
if (isset($_GET['revenue'])) { $query .= "'" . $_GET['revenue'] . "', "; }
if (isset($_GET['fiscal_year'])) { $query .= "'" . $_GET['fiscal_year'] . "', "; }
if (isset($_GET['employees'])) { $query .= "'" . $_GET['employees'] . "', "; }
if (isset($_GET['market_cap'])) { $query .= "'" . $_GET['market_cap'] . "', "; }
if (isset($_GET['headquarters'])) { $query .= "'" . $_GET['headquarters'] . "') RETURNING company_id;"; }
echo $query;
After this query, the message "Add request failed: parsererror" is still there. But after a manual refresh of the page, the new data is saved. Any idea why this message apears and not loading the data automatically?
UPDATE 3 - Success
I forgot to remove echo $query; from the code causing the error message.
All works now. Thanks for the help to all! :)
You need a little more work in your query string building.
You only add the open parenthesis ( if rank is present
You only add the closing parenthesis ) if headquarters is present.
Also you need specify what field column get which value, otherwise you end with headquarter name into the fiscal_year field. If columns are not specified the values are add it on the same order as define on the table.
INSERT INTO TABLE_NAME (column1, column2, column3,...columnN)
VALUES (value1, value2, value3,...valueN);
And as other have comment check the $query to see what you have.

does binding param strip out underscores?

I used the following function:
function update_value($table, $field, $value, $type, $where1, $value1, $where2=NULL, $value2=NULL, $where3=NULL, $value3=NULL) {
$rows = array();
global $conn;
connect();
$value1 = "'" . $value1 . "'";
$sql = "UPDATE $table SET $field =? WHERE $where1 = $value1";
$bind1 = "'" . "$type" . "'";
if ($where2 != NULL) {
$value2 = "'" . $value2 . "'";
$sql .= " AND $where2 = $value2";
}
if ($where3 != NULL) {
$value3 = "'" . $value3 . "'";
$sql .= " AND $where3 = $value3";
}
$stmt = $conn->prepare($sql);
$stmt->bind_param($type, $value);
$stmt->execute();
$stmt->close();
$conn->close();
}
...to update the username field of a table (making sure it's a string before updating via the above function). I tried updating with a string followed by an underscore but when it showed up in the table the underscore had disappeared.
I'm new to binding parameters, is there certain things it strips out? If so I'd like to know exactly what so I can use preg_match to catch them before it updates and alert the users.
The way you manipulate with data is very dangerous.
But just to fix some potential issues keeping your logic you should surround all potential table and column names with backticks and prepare values with mysqli_real_escape_string():
$val1 = "'" . mysqli_real_escape_string($value1) . "'";
$sql = "UPDATE `$table` SET `$field` = ? WHERE `$where1` = $val1";
if (!empty($where2)) {
$value2 = "'" . mysqli_real_escape_string($value2) . "'";
$sql .= " AND `$where2` = $value2";
}
if (!empty($where3)) {
$value3 = "'" . mysqli_real_escape_string($value3) . "'";
$sql .= " AND `$where3` = $value3";
}

Mutliple querystring parameters to mysql query

I originally had this working:
url: http://server/blah.php?FacilityCode=FT
$facilitycode = mysql_real_escape_string($_GET["FacilityCode"]);
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
"AND ('" . $facilitycode . "' = '' OR Facility.FacilityCode = '". $facilitycode . "')";
$result = mysql_query($sql);
But I want to change this so that people can submit multiple values in the query strying somehow, ie: http://server/blah.php?FacilityCode=FT,CC,DD,EE
I tried changing the query to an "IN" clause instead of an "equals" but I'm not sure how to get the ' marks around each element.
Use implode() function for IN (...).
$a = array('AB', 'CD', 'EF', 'ZE');
echo "field IN ('" . implode("', '", $a) . "')";
... will output:
field IN ('AB', 'CD', 'EF', 'ZE')
+escape every option you get.
$facilitycode = mysql_real_escape_string($_GET["FacilityCode"]);
$array=explode(',',$facilitycode);
foreach ($array as $a){$output.="'$a',";}
$clause=substr($output,0,-1);
If your trying to create a string which looks like this: 'AB', 'CD', 'EF', 'ZE'
Try this before its placed inside the query:
$facilitycode = preg_replace('/([^,]+)/', '\'$1\'', $facilitycode);
I wrote this based on your query, but still I dont get this part of query "AND ('" . $facilitycode . "' = ''", anyway you need to check if $_GET data have "," and if does explode that variable by "," so that you can add an OR clausule for everything that was separated by "," in $_GET data.
After that just form your query by doing a foreach for every element in exploded array like I done below:
<?php
$facilitycode = $_GET["FacilityCode"];
$facility_number_chk = strpos($facilitycode, ",");
if ($facility_number_chk > -1) {
$facilitycode = explode(",", $facilitycode);
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
"AND ('" . $facilitycode . "' = ''";
foreach($facilitycode as $facode) {
$facode = mysql_real_escape_string($facode);
$sql .= " OR Facility.FacilityCode = '". $facode . "'";
}
$sql .= "')";
}
else {
$facilitycode = mysql_real_escape_string($facilitycode);
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
"AND ('" . $facilitycode . "' = '' OR Facility.FacilityCode = '". $facilitycode . "')";
}
$result = mysql_query($sql);
And if there is only one element in $_GET data just do an else like I done with your regular query.
I ended up using a combination of a few of the answers. Basically I exploded on the ",", then did a foreach to add the ' marks and call escape_string, and then imploded it back.
$facilitycodes = $_GET["FacilityCode"];
if ($facilitycodes == '') {
$additionalfilter = '';
}
else {
$facilitycodearray = explode(",", $facilitycodes);
foreach($facilitycodearray as &$facilitycode) {
$facilitycode = "'" . mysql_real_escape_string($facilitycode) . "'";
}
$facilitycodesformatted = implode(",", $facilitycodearray);
$additionalfilter = " AND Facility.FacilityCode IN (" . $facilitycodesformatted . ")";
}
$sql = "SELECT ..." .
"FROM ..." .
"WHERE ..." .
$additionalfilter;

how to assign and concat using multiple delimiters in an array?

i apologize if the question is wrong. i am a still a newbie and a learner however i would appreciate if someone correct me if i am somewhere wrong.
here in the Class method i am using for Inserting the data into the database
public function insert($table,$col,$value)
{
if(is_array($col) && is_array($value))
{
$query = "INSERT INTO ".$table."(" . implode(",",$col) . ") VALUES(" . implode(",",$value) . ")";
}
else
{
$query = "INSERT INTO " . $table . "(" . $col . ") VALUES(". $value . ")";
}
}
now here i am determining if the $col and $value is an array if yes then process it.
however i have a problem here since the VALUES in the Insert statement needs to be represnted in the single or double quote format it will not process the query and hence print the error
for example the below code would print the error
$query = "INSERT INTO users(username,email) VALUES(test,test#test.com)";
and the correct format will be
$query = "INSERT INTO users(username,email) VALUES('test','test#test.com')";
now in the col value i would like to add the single quotes to every value in the array for example the $value array which is like this.
$value = array('test','test#test.com');
should give back the value
'test','test#test.com'
instead of
test,test#test.com
how do i achieve it?
$query = "INSERT INTO $table ('" . implode("','",$col) . "')
VALUES ('" . implode("','",$value) . "')";
Make sure that neither $col nor $value is empty.
Right code:
public function insert($table,$col,$value)
{
if(is_array($col) && is_array($value))
{
$query = "INSERT INTO ".$table."(" . implode(",",$col) . ") VALUES('" . implode("','",$value) . "')";
}
else
{
$query = "INSERT INTO " . $table . "(" . $col . ") VALUES('". $value . "')";
}
}
CHANGE:
VALUES(" . implode(",",$value) . ")
TO
VALUES('" . implode("','",$value) . "')
(Your output:)
VALUES(demo,demo2)
(New Output:)
VALUES('demo','demo2')
you could do this?
$value = array("'test'","'test#test.com'");
You can use array_map() method:
function addQuotes($str)
{
return "'".$str."'";
}
$value = array_map("addQuotes", $value);
or follow a Oswald's answer recommendations.

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