Transform array associative recursive - php

We have an array with the following values:
$a = array("a", "a.b", "a.b.c", "X", "X.Y", "X.Y.Z");
And the goal is, to make modify the first array into the following structure:
$a = array(
"a" => array(
"b" => array(
"c" => array(),
),
),
"X" => array(
"Y" => array(
"Z" => array(),
),
),
);
Why i am asking? On of my customer has a table for shop categories. And these categories are in one column (simplified!):
+-----------------------+
|id | name |
+---|-------------------+
| 4 | A |
| 5 | A.B |
| 6 | A.B.C |
| 7 | X |
| 8 | X.Y |
| 9 | X.Y.Z |
+-----------------------+
How can i do this with PHP?
EDIT:
My current "solution / trys"
<?php
$arr = array(
"a",
"a.b",
"a.b.c",
"x",
"x.y",
"x.y.z",
);
$container = array();
$updateMe = array();
foreach($arr as $key => $value) {
$cleanName = explode(".", $value);
foreach($cleanName as $keyArray => $valueArray) {
for($c = 0;$c<$keyArray+1;$c++) {
$updateMe[$cleanName[$c]] = array();
}
}
$container[$cleanName[0]] = $updateMe;
unset($updateMe);
}
echo "<pre>";
var_dump($container);
echo "===\r\n";
My output:
array(2) {
["a"]=>
array(3) {
["a"]=>
array(0) {
}
["b"]=>
array(0) {
}
["c"]=>
array(0) {
}
}
["x"]=>
array(3) {
["x"]=>
array(0) {
}
["y"]=>
array(0) {
}
["z"]=>
array(0) {
}
}
}
===
SOLUTION
<?php
$arr = array(
"a",
"a.b",
"a.b.c",
"x",
"x.y",
"x.y.z",
);
$array = array();
$test = array();
foreach($arr as $key => $text) {
$array = array();
foreach(array_reverse(explode('.', $text)) as $key) $array = array($key => $array);
$test[] = $array;
}
echo "<pre>";
var_dump($test);
echo "===\r\n";

I like using references in PHP. This might not be the best solution, but it seems to work.
<?php
$arr = array(
"a",
"a.b",
"a.b.c",
"x",
"x.y",
"x.y.z",
);
$output = array();
foreach($arr as $path){
// Create a reference to the array
// As we go deeper into the path we will move this reference down
$setArray =& $output;
foreach(explode('.', $path) as $key){
// If this key does not exist, create it
if(!isset($setArray[$key])){
$setArray[$key] = array();
}
// Move the reference down one level,
// so that the next iteration will create
// the key at the right level
$setArray =& $setArray[$key];
}
}
// Destroy the reference, so that we don't accidently write to it later
unset($setArray);
var_dump($output);

You can use the accepted answer from this question, or this answer from the same question to get a good starting point (I'll use the second answer because it's shorter in this example).
$out = array();
foreach ($a as $string) {
$array = array();
foreach(array_reverse(explode('.', $string)) as $key) {
$array = array($key => $array);
}
$out[] = $array;
}
This will give you a numeric key based array, so then you can shift off the first level of the array using an answer from this question:
$out = call_user_func_array('array_merge', $out);
And your result:
Array
(
[a] => Array
(
[b] => Array
(
[c] => Array
(
)
)
)
[X] => Array
(
[Y] => Array
(
[Z] => Array
(
)
)
)
)

This should work for you:
<?php
$a = array("a", "a.b", "a.b.c", "1", "1.2", "1.2.3");
$results = array();
function stringToArray($path) {
$pos = strpos($path, ".");
if ($pos === false)
return array($path => "");
$key = substr($path, 0, $pos);
$path = substr($path, $pos + 1);
return array(
$key => stringToArray($path)
);
}
foreach($a as $k => $v) {
if(substr_count(implode(", ", $a), $v) == 1)
$results[] = stringToArray($v);
}
$results = call_user_func_array('array_merge', $results);
print_R($results);
?>
Output:
Array ( [a] => Array ( [b] => Array ( [c] => ) ) [0] => Array ( [2] => Array ( [3] => ) ) )

just tricky one
$a = array("a", "a.b", "a.b.c", "X", "X.Y", "X.Y.Z");
$res = array();
foreach ($a as $str) {
$str = str_replace('.','"]["',$str);
$tricky = '$res["'.$str.'"]';
eval ($tricky.' = array();');
};

Related

Reverse array elements with specific value

I have an array like this
$array = array( [0] => 'red1', [1] => 'blue1', [2] => 'red2', [3] => 'red3', [4] => 'blue2' );
A want to reverse order of elements with red value only so it looks like this:
$array = array( [0] => 'red3', [1] => 'blue1', [2] => 'red2', [3] => 'red1', [4] => 'blue2' );
I think a possible solution might be to:
Get all the values from the $array that you are looking for and
store them in an array $found
Reverse the values in $found keeping the keys
Replace the values in $array with the values from $found using
the key
For example:
$array = array(0 => 'red1', 1 => 'blue1', 2 => 'red2', 3 => 'red3', 4 => 'blue2');
// First get all the values with 'red' and store them in an array
$found = preg_grep('/red\d+/', $array);
// Reverse the values, keeping the keys
$found = array_combine(
array_keys($found),
array_reverse(
array_values($found)
)
);
// Then replace the values of $array with values having the same keys in $found
$array = array_replace($array, $found);
var_dump($array);
Will result in:
array(5) {
[0]=>
string(4) "red3"
[1]=>
string(5) "blue1"
[2]=>
string(4) "red2"
[3]=>
string(4) "red1"
[4]=>
string(5) "blue2"
}
You can catch red's quote to a new array and sort them.
<?php
$arr = array(
'red1',
'blue1',
'red2',
'red3',
'blue2'
);
$sortArr = array();
for ($i=0; $i < sizeof($arr); $i++) {
if(strstr($arr[$i], "red")){
$sortArr[] = &$arr[$i];
}
}
?>
I think you can do using searching specific words by strpos and sorting array by ksort (sort associative arrays in ascending order, according to the key)
foreach ($array as $key => $value) {
if(strpos($value,"red") !== false){
($key === 0) ? $index = 3 : (($key === 3) ? $index = 0 : $index = 2);
$temp[$index] = $value;
}
else {
$temp[$key] = $value;
}
}
ksort($temp);
var_dump($temp);
[But It will not work in larger array than this]

combine arrays and concat value?

Little complex to explain , so here is simple concrete exemple :
array 1 :
Array
(
[4] => bim
[5] => pow
[6] => foo
)
array 2 :
Array
(
[n] => Array
(
[0] => 1
)
[m] => Array
(
[0] => 1
[1] => 2
)
[l] => Array
(
[0] => 1
[1] => 4
[2] => 64
)
And i need to output an array 3 ,
array expected :
Array
(
[bim] => n-1
[pow] => Array
(
[0] => m-1
[1] => m-2
)
[foo] => Array
(
[0] => l-1
[1] => l-4
[2] => l-64
)
Final echoing OUTPUT expected:
bim n-1 , pow m-1 m-2 ,foo l-1 l-4 l-64 ,
I tried this but seems pity:
foreach($array2 as $k1 =>$v1){
foreach($array2[$k1] as $k => $v){
$k[] = $k1.'_'.$v);
}
foreach($array1 as $res =>$val){
$val = $array2;
}
Thanks for helps,
Jess
CHALLENGE ACCEPTED
<?php
$a = array(
4 => 'bim',
5 => 'pow',
6 => 'foo',
);
$b = array(
'n' => array(1),
'm' => array(1, 2),
'l' => array(1, 4, 64),
);
$len = count($a);
$result = array();
$aVals = array_values($a);
$bKeys = array_keys($b);
$bVals = array_values($b);
for ($i = 0; $i < $len; $i++) {
$combined = array();
$key = $aVals[$i];
$prefix = $bKeys[$i];
$items = $bVals[$i];
foreach ($items as $item) {
$combined[] = sprintf('%s-%d', $prefix, $item);
};
if (count($combined) === 1) {
$combined = $combined[0];
}
$result[$key] = $combined;
}
var_dump($result);
?>
Your code may be very easy. For example, assuming arrays:
$one = Array
(
4 => 'bim',
5 => 'pow',
6 => 'foo'
);
$two = Array
(
'n' => Array
(
0 => 1
),
'm' => Array
(
0 => 1,
1 => 2
),
'l' => Array
(
0 => 1,
1 => 4,
2 => 64
)
);
You may get your result with:
$result = [];
while((list($oneKey, $oneValue) = each($one)) &&
(list($twoKey, $twoValue) = each($two)))
{
$result[$oneValue] = array_map(function($item) use ($twoKey)
{
return $twoKey.'-'.$item;
}, $twoValue);
};
-check this demo Note, that code above will not make single-element array as single element. If that is needed, just add:
$result = array_map(function($item)
{
return count($item)>1?$item:array_shift($item);
}, $result);
Version of this solution for PHP4>=4.3, PHP5>=5.0 you can find here
Update: if you need only string, then use this (cross-version):
$result = array();
while((list($oneKey, $oneValue) = each($one)) &&
(list($twoKey, $twoValue) = each($two)))
{
$temp = array();
foreach($twoValue as $item)
{
$temp[] = $twoKey.'-'.$item;
}
$result[] = $oneValue.' '.join(' ', $temp);
};
$result = join(' ', $result);
As a solution to your problem please try executing following code snippet
<?php
$a=array(4=>'bim',5=>'pow',6=>'foo');
$b=array('n'=>array(1),'m'=>array(1,2),'l'=>array(1,4,64));
$keys=array_values($a);
$values=array();
foreach($b as $key=>$value)
{
if(is_array($value) && !empty($value))
{
foreach($value as $k=>$val)
{
if($key=='n')
{
$values[$key]=$key.'-'.$val;
}
else
{
$values[$key][]=$key.'-'.$val;
}
}
}
}
$result=array_combine($keys,$values);
echo '<pre>';
print_r($result);
?>
The logic behind should be clear by reading the code comments.
Here's a demo # PHPFiddle.
//omitted array declarations
$output = array();
//variables to shorten things in the loop
$val1 = array_values($array1);
$keys2 = array_keys($array2);
$vals2 = array_values($array2);
//iterating over each element of the first array
for($i = 0; $i < count($array1); $i++) {
//if the second array has multiple values at the same index
//as the first array things will be handled differently
if(count($vals2[$i]) > 1) {
$tempArr = array();
//iterating over each element of the second array
//at the specified index
foreach($vals2[$i] as $val) {
//we push each element into the temporary array
//(in the form of "keyOfArray2-value"
array_push($tempArr, $keys2[$i] . "-" . $val);
}
//finally assign it to our output array
$output[$val1[$i]] = $tempArr;
} else {
//when there is only one sub-element in array2
//we can assign the output directly, as you don't want an array in this case
$output[$val1[$i]] = $keys2[$i] . "-" . $vals2[$i][0];
}
}
var_dump($output);
Output:
Array (
["bim"]=> "n-1"
["pow"]=> Array (
[0]=> "m-1"
[1]=> "m-2"
)
["foo"]=> Array (
[0]=> "l-1"
[1]=> "l-4"
[2]=> "l-64"
)
)
Concerning your final output you may do something like
$final = "";
//$output can be obtained by any method of the other answers,
//not just with the method i posted above
foreach($output as $key=>$value) {
$final .= $key . " ";
if(count($value) > 1) {
$final .= implode($value, " ") .", ";
} else {
$final .= $value . ", ";
}
}
$final = rtrim($final, ", ");
This will echo bim n-1, pow m-1 m-2, foo l-1 l-4 l-64.

Making values unique in multidimensional array

I have some Problems reducing a multidimensional array into a normal one.
I have an input array like this:
Array
(
[0] => Array (
[0] => 17
[1] => 99
)
[1] => Array (
[0] => 17
[1] => 121
)
[2] => Array (
[0] => 99
[1] => 77
)
[3] => Array (
[0] => 45
[1] => 51
)
[4] => Array (
[0] => 45
[1] => 131
)
So I have a multidimensional array with some overlaps in the values (eg 17,99 and 17,121)
Now I want to have an output like this:
Array
(
[0] => Array (
[0] => 17
[1] => 99
[2] => 121
[3] => 77
)
[2] => Array (
[0] => 45
[1] => 51
[3] => 131
)
I want to save, which articles are the same in my database this way. The output array shpuld still be a multidimesional array, but every number on the second level should be unique in the array.
I'm trying to solve this for more than a week now, but I dont get it to work. I know it should be easy...but anyway - I dont get it :D
This is what i got so far:
$parity_sorted = array();
foreach($arr as $key => $a){
if(count($parity_sorted) > 0){
foreach($parity_sorted as $key2 => $arr_new){
if(in_array($a[0], $arr_new) || in_array($a[1], $arr_new)){
if(!in_array($a[0], $arr_new)){array_push($parity_sorted[$key2], $a[0]);}
if(!in_array($a[1], $arr_new)){array_push($parity_sorted[$key2], $a[1]);}
} else {
array_push($parity_sorted, array($a[0],$a[1]));
}
}
} else {
array_push($parity_sorted, array($a[0],$a[1]));
}
}
Did you maybe already solve problem like this or is there a much easier way? Maybe I just think too complicated (It's not my first try, but this code was the last try)
Any help would be appreciated. Thanks a lot
Here is my revised code given your comment and a DEMO of it working as expected. ( http://codepad.org/CiukXctS )
<?php
$tmp = array();
foreach($array as $value)
{
// just for claraty, let's set the variables
$val1 = $value[0];
$val2 = $value[1];
$found = false;
foreach($tmp as &$v)
{
// check all existing tmp for one that matches
if(in_array($val1, $v) OR in_array($val2, $v))
{
// this one found a match, add and stop
$v[] = $val1;
$v[] = $val2;
// set the flag
$found = true;
break;
}
}
unset($v);
// check if this set was found
if( ! $found)
{
// this variable is new, set both
$tmp[] = array(
$val1,
$val2,
);
}
}
// go trough it all again to ensure uniqueness
$array = array();
foreach($tmp as $value)
{
$array[] = array_unique($value); // this will eliminate the duplicates from $val2
}
ORIGIN ANSWER
The question is badly asked, but I'll attempt to answer what I believe the question is.
You want to gather all the pairs of arrays that have the same first value in the pair correct?
$tmp = array();
for($array as $value)
{
// just for claraty, let's set the variables
$val1 = $value[0];
$val2 = $value[1];
if(isset($tmp[$val1])) // we already found it
{
$tmp[$val1][] = $val2; // only set the second one
}
else
{
// this variable is new, set both
$tmp[$val1] = array(
$val1,
$val2,
);
}
}
// go trough it all again to change the index to being 0-1-2-3-4....
$array = array();
foreach($tmp as $value)
{
$array[] = array_unique($value); // this will eliminate the duplicates from $val2
}
Here is solution for common task.
$data = array(array(17,99), array(17,121), array(99,77), array(45,51), array(45,131));
$result = array();
foreach ($data as $innner_array) {
$intersect_array = array();
foreach ($result as $key => $result_inner_array) {
$intersect_array = array_intersect($innner_array, $result_inner_array);
}
if (empty($intersect_array)) {
$result[] = $innner_array;
} else {
$result[$key] = array_unique(array_merge($innner_array, $result_inner_array));
}
}
var_dump($result);
Try:
$arr = array(array(17,99),
array(17,121),
array(99,77),
array(45, 51),
array(45, 131)
);
foreach($arr as $v)
foreach($v as $m)
$new_arr[] = $m;
$array = array_chunk(array_unique($new_arr), 4);
var_dump($array);
Demo
It uses array_unique and array_chunk.
Output:
array(2) { [0]=>array(4) { [0]=> int(17) [1]=>int(99)
[2]=>int(121) [3]=> int(77) }
[1]=> array(3) { [0]=> int(45) [1]=>int(51)
[2]=>int(131) }
}
I think I get your problem. Let me have a crack at it.
$firstElems = array();
$secondElems = array();
foreach ( $arr as $v ) {
$firstElems[ $v[0] ] = array( $v[0] );
}
foreach ( $arr as $v ) {
$secondElems[ $v[1] ] = $v[0];
}
foreach ( $arr as $v ) {
if ( isset( $secondElems[ $v[0] ] ) ) {
array_push( $firstElems[ $secondElems[ $v[0] ] ], $v[1] );
}
else {
array_push( $firstElems[ $v[0] ], $v[1] );
}
}
foreach ( $firstElems as $k => $v ) {
if ( isset( $secondElems[ $k ] ) ) {
unset( $firstElems[ $k ] );
}
}
Output:
Array
(
[17] => Array
(
[0] => 17
[1] => 99
[2] => 121
[3] => 77
)
[45] => Array
(
[0] => 45
[1] => 51
[2] => 131
)
)
(Code examples: http://codepad.org/rJNNq5Vd)
I truly believe I understand you and if this is the case here is what you're looking for:
function arrangeArray($array) {
$newArray = array(array_shift($array));
for ($x = 0; $x < count($newArray); $x++) {
if (!is_array($newArray[$x])) {
unset($newArray[$x]);
return $newArray;
}
for ($i = 0; $i < count($newArray[$x]); $i++) {
foreach ($array as $key => $inArray) {
if (in_array($newArray[$x][$i], $inArray)) {
$newArray[$x] = array_unique(array_merge($newArray[$x], $inArray));
unset($array[$key]);
}
}
}
$newArray[] = array_shift($array);
}
}
Which will return:
array(2) {
[0]=>
array(4) {
[0]=>
int(17)
[1]=>
int(99)
[2]=>
int(121)
[4]=>
int(77)
}
[1]=>
array(3) {
[0]=>
int(45)
[1]=>
int(51)
[3]=>
int(131)
}
}
For:
var_dump(arrangeArray(array(
array(17,99),
array(17,121),
array(99,77),
array(45, 51),
array(45, 131),
)));
And:
array(1) {
[0]=>
array(6) {
[0]=>
int(17)
[1]=>
int(99)
[2]=>
int(121)
[3]=>
int(45)
[4]=>
int(77)
[6]=>
int(51)
}
}
For:
var_dump(arrangeArray(array(
array(17,99),
array(17,121),
array(99,77),
array(45, 51),
array(45, 17),
)));

PHP group repeated elements in array

How can the array be separated into groups of identical elements (concatenated chars).
For example, I have this array:
Array(
[0] => 1
[1] => 1
[2] => 1
[3] => 2
[4] => 2
[5] => 1
)
and want to group all identical numbers in only one element, bringing the together with concatenation to get something like this:
Array(
[0] => 111
[1] => 22
[2] => 1
)
To group all identical elements by concatenating them together (will not work for concatenating just the neighboring identical elements)
$arr = array (1,1,1,2,2,1);
$sum = array_count_values($arr);
array_walk($sum, function(&$count, $value) {
$count = str_repeat($value, $count);
});
print_r($sum);
Output
Array (
[1] => 1111
[2] => 22 )
Or for concatenating just the neighboring identical elements
$prev=null;
$key=0;
foreach ( $arr as $value ) {
if ($prev == $value){
$res[$key] .= $value;
} else {
$key++;
$res[$key] = $value;
$prev=$value;
}
}
print_r($res);
Output
Array (
[1] => 111
[2] => 22
[3] => 1 )
Here two functions
1 will return
Array
(
[1] => Array
(
[0] => 1
[1] => 1
[2] => 1
[3] => 1
)
[2] => Array
(
[0] => 2
[1] => 2
)
)
as output and second one will return
Array
(
[1] => 1111
[2] => 22
)
as output
$array = array(
1,1,1,2,2,1
);
print_r(groupArray($array));
print_r(groupSame($array));
function groupArray($array){
$temp = array();
foreach($array as $value){
if(!isset($temp[$value])){
$temp[$value] = array();
}
array_push($temp[$value],$value);
}
return $temp;
}
function groupSame($array){
$temp = array();
foreach($array as $value){
if(!isset($temp[$value])){
$temp[$value] = "";
}
$temp[$value] .= $value;
}
return $temp;
}
<?php
$i=0;
foreach($Arrays as $key=>$val) {
if (!isset($array[$i]))
$array[$i]=$val;
else if (!isset($mem) || $val==$mem)
$array[$i]=10*$array[$i]+$mem;
else
$i++;
$mem=$val;
}
?>
$array = array(1,1,1,2,2,1);
$start = "";
$new_array = array();
foreach($array as $v){
$v = (string)$v;
if($start==$v){
$count = count($new_array) - 1;
$val = $new_array[$count].$v;
$new_array[$count] = $val;
} else{
$new_array[] = $v;
}
$start = $v;
}
var_dump($new_array);
Tested and its working..
Output > array(3) { [0]=> string(3) "111" [1]=> string(2) "22" [2]=> string(1) "1" }
$newarray = array_unique($oldarray);
$count = array_count_values($oldarray);
foreach($newarray as &$val){
$val = str_repeat($val,$count[$val]);
}
http://codepad.org/FUf0n8sz

php - sort by value of last key in array?

I'm trying to figure out how to sort an array by the value of the last key, when the number of keys are unknown?
So, if I have arrays that look like this:
Array(
[0] => Array(
[0] => Bob
[1] => A
[2] => Parker
)
[1] => Array(
[0] => John
[1] => Smith-Doe
)
[2] => Array(
[0] => Giuseppe
[1] => Gonzalez
[2] => Octavio
[3] => Hernandez
)
)
I want to sort it by the last value in the array:
Giuseppe Gonzalez Octavio Hernandez
Bob A. Parker
John Smith-Doe
$arr = array(
array('Bob', 'A', 'Parker'),
array('John', 'Smith-Doe'),
array('Giuseppe', 'Gonzalez', 'Octavio', 'Hernandez')
);
usort($arr, 'sort_by_last_item');
var_dump($arr);
function sort_by_last_item($a, $b)
{
return end($a) > end($b);
}
or if you're using php 5.3:
$arr = array(
array('Bob', 'A', 'Parker'),
array('John', 'Smith-Doe'),
array('Giuseppe', 'Gonzalez', 'Octavio', 'Hernandez')
);
usort($arr, function($a, $b) { return end($a) > end($b); });
var_dump($arr);
$data = array( /* your data */ );
$output = array();
foreach ( $data as $v ) {
$output[ end($v) ] = $v;
}
ksort($output);
var_dump($output);
alternatively:
$data = array( /* your data */ );
$output = array();
foreach ( $data as $v ) {
$key = implode(' ', array_reverse($v));
$output[ $key ] = $v;
}
ksort($output);
var_dump($output);
Second method allow you to have many records with the same last element and sorts by last elements, and if they are equals - sort by first before last and so on...
This works:
function array_last_item_sort($array){
$return = array();
$sort = array();
foreach($array as $i => $item){
$sort[$i] = $item[count($item) - 1];
}
asort($sort);
foreach($sort as $i => $value){
$return[] = $array[$i];
}
return $return;
}

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