'where' like querying an array or object - php

[{"id":1,"username":"example","email":"example#gmail.com","password":"example123","created_at":"2015-01-13 11:39:24","updated_at":"2015-01-13 11:39:24"},
{"id":2,"username":"ex2","email":"ex#ex.com","password":"example","created_at":"2015-01-13 11:39:02","updated_at":"2015-01-13 11:39:02"}]
I got an object like above. The thing I want to is select the object that's id is 1 for example. Like
select * from object where id=1
with SQL
How to do it?

I hope i got your question right.
Try the following
<?php
$array = json_decode('[{"id":1,"username":"example","email":"example#gmail.com","password":"example123","created_at":"2015-01-13 11:39:24","updated_at":"2015-01-13 11:39:24"},
{"id":2,"username":"ex2","email":"ex#ex.com","password":"example","created_at":"2015-01-13 11:39:02","updated_at":"2015-01-13 11:39:02"}]');
foreach( $array as $v ) {
if( $v["id"] == 1 ) {
echo "I am ID 1";
break;
}
}

Decode your object (http://php.net/manual/it/function.json-decode.php) and then traverse your array with a foreach checking the id value inside of it with an if statement.
$obj_to_array = json_decode($json_object);
$target = '';
foreach($obj_to_array as $row){
if($row['id'] == 1)
$target = $row;
}
// $target holds your row with id = 1

$data = '[{"id":1,"username":"example","email":"example#gmail.com","password":"example123","created_at":"2015-01-13 11:39:24","updated_at":"2015-01-13 11:39:24"},
{"id":2,"username":"ex2","email":"ex#ex.com","password":"example","created_at":"2015-01-13 11:39:02","updated_at":"2015-01-13 11:39:02"}]';
$data = json_decode($data);
$id = 1;
$key = 'id';
$data = array_filter(
$data,
function($value) use ($key, $id) {
return ($value->$key == $id);
}
);
var_dump($data);

Decode the object using json_decode. Use the code below
<?php
$json='[{"id":1,"username":"example","email":"example#gmail.com","password":"example123","created_at":"2015-01-13 11:39:24","updated_at":"2015-01-13 11:39:24"},
{"id":2,"username":"ex2","email":"ex#ex.com","password":"example","created_at":"2015-01-13 11:39:02","updated_at":"2015-01-13 11:39:02"}]';
$p = json_decode($json,true);
$l=count($p);
for($i=0;$i<=$l;$i++){
$id=$p[$i]["id"];
if($id==1){
print_r($p[$i]); // WIll print the id if 1
}
}
Hope this helps you

Related

How to get data from database that result as an array in model codeigniter

I want to make a query that results like this in codeigniter MODEL:
$caldata = array (
15 => 'yes',
17 => 'no'
);
Is that possible to do?
Take NOTE: The 15,17 and yes,no are in the same database table.
There is no core helper function to achieve what you want in CI. But you can create your own helper function:
function pluck($arr = [], $val = '', $key = '')
{
// val - label for value in array
// key - label for key in array
$result = [];
foreach ($arr as $value) {
if(!empty($key)){
$result[$value[$key]] = $value[$val];
}else{
$result[] = $value[$val];
}
}
return $result;
}
you can use result_array() function so you can have something like:
$query = $this->db->select('id,answer')->from('users')->get();
$result = $query->result_array();
print_r($result);
After that you have your array and you can make the $key => $value relation of the fields
After a long search i found an answer. Sample way to do this:
$query = $this->db->select('start_date, class')->from('event')->like('start_date', "$year-$month", 'after')->get();
$datavariable = $query->result();
$caldata = array();
foreach($datavariable as $row){
$caldata[substr($row->start_date,8,2)] = $row->class;
}

How to extract data from JSON - Laravel & JSON

This is how my json looks like ["Chicken",{"quantity":"1"},"Froggies",{"quantity":"2"},"Fryies",{"quantity":"3"}].
Is there a way that i can get the data out the results like
Chicken : 1, Froggies:2, Fryies:3
I tried to use implode to get this done but i get an error saying array to string conversion,
Below is my code
foreach($request->get('item_id') as $key => $id)
{
$selected_item = Item::all()->where('id',$id);
foreach($selected_food as $select)
{
$food_selected[]= $select->name ;
$food_selected[] = ['quantity' => $request->get('quantity')[$key]];
}
}
$query ="Your items are ".implode(',',$food_selected)."";
Maybe array of objects would be more useful in that situation, which you could get this way:
$arr = [];
foreach ( $request->get('item_id') as $key => $id ) {
$selected_item = Item::all()->where('id', $id);
foreach ( $selected_item as $select ) {// $selected_item or $selected_food here
/*
$obj = new stdClass;
$obj->{$select->name} = $request->get('quantity')[$key];
$arr[] = $obj;*/
$arr[$select->name] = (int) $request->get('quantity')[$key];
}
}
$query = '';
foreach ( $arr as $k => $v ) {
$query .= ' '.$k.': '.$v.',';
}
$query = rtrim($query, ',');
$query = ltrim($query);
$query = "Your items are ".$query;
I assume that the ID is unique key for an Item and your Item::all()->where('id',$id) will return only one record. If this is true, the second loop is unnecessary.
Based on this assumption, I come to this code:
$result = collect($request->get('item_id'))
->map(function($itemId, $itemKey) use ($request) {
$item = Item::find($itemId);
return $item->name . ' : ' . $request->get('quantity')[$itemKey];
})->implode(',');
// $result contains the string: "Chicken : 2, Fries : 1"
For explanation:
Cast the array into a collection
Use map to loop over it
Find the Item by its ID
Return the name and the quantity (this returns a collection)
Implode the collection

PHP check variable if exists in array of json

Array : [{"ID":1},{"ID":2}]
$id=1;
I want to check if $id exists in the array.
Thank you!
You may try Laravel's Collection::contains method, for example:
$collection = collect(json_decode($jsonString, true));
if ($collection->contains(1) {
// Exists...
}
Also, you may use key/value pair like this:
if ($collection->contains('ID', 1) {
//...
}
Also, if you want to get that item from the collection then you may try where like this:
$id = $collection->where('ID', 1)->first(); // ['ID' => 1]
You have a json formatted array and you need to decode it using json_decode first. After that loop the array to check for the id that you want.
So the code should look like this:
$json = '[{"ID":1},{"ID":2}]';
$id = 1;
$data = json_decode($json, true);
foreach($data as $item){
if($item['id'] == $id) {
echo 'it exists';
}
}
Iterate the array using for loop and use the value as a param to json_decode.
$id = 1;
$arr = array('{"ID":1}', '{"ID":2}');
foreach($arr as $val) {
if (in_array($id, json_decode($val, TRUE))) {
echo "id present";
}
}
Try this, if value is exist it will give key of array
$jsondata = '[{"ID":1},{"ID":2}]';
$array = json_decode($jsondata,true);
$key = array_search(1, array_column($array, 'ID'));
Just check if the string is in the json array, with little computation.
I think it's the more efficient way. Check the result here.
<?php
$id = 1;
$array = ['{"ID":1}', '{"ID":2}'];
echo in_array(json_encode(["ID" => $id]), $array) ? 'Yes' : 'No';

How to remove an object from JSON array in PHP

I have a JSON array. I want to delete the entry that have number 4 and return the left over array
$filters = '{"1":1,"2":2,"3":4}';
$fobj = json_decode($filters, TRUE);
foreach($fobj as $key => $value)
{
if (in_array(4, $fobj)) {
unset($fobj[4]);
}
}
echo $filters = json_encode($fobj );
But this echo does not give me what I want. I want it to return something like this:
{"1":1,"2":2}
You're removing the fourth value of the array, not the value. Use array_search instead
$filters = '{"1":1,"2":2,"3":4}';
$fobj = json_decode($filters, TRUE);
$search = array_search(4, $fobj);
if($search !== false) unset($fobj[$search]);
echo $filters = json_encode($fobj );
$index = array_search("4", $array);
unset($array[$index]);
http://php.net/manual/de/function.array-search.php
http://php.net/manual/de/function.unset.php
That's all. Hope it helps!

array to string php

Hy every one I have this problem with an array I start like this...
$name = array($_POST['names']);
$nameId = array();
$query = mysql_query("SELECT id FROM types WHERE find_in_set (name, '$name')");
while($row = mysql_fetch_assoc($query)){
$nameId[] = array('ids' => $row['id'] );
}
which gives me arrays like this..
$name:
array('0'=>'name1,name2,name3')
$names:
array('0'=>array('ids'=>'61'), '1'=>array('ids'=>'6'), '2'=>array('ids'=>'1'))
how can I bring this in an string/form like this..
array('0'=>'61,6,1')
The idea is to save the ids to the Database.
Or is the a better more efficent way to get names from a form compare them with a database and get the ids back to save them to the Database?
many thanks in advance.
Change your assignment to this:
$nameId[] = $row['id'];
$name = array(name1,name2,name3);
$nameId = array();
$query = mysql_query("SELECT id FROM types WHERE find_in_set (name, '$name')");
while($row = mysql_fetch_assoc($query)){
//below line changed
$nameId[] = $row['id'] ;
}
$string = implode(',',$nameId);
Try this :
$array = array(0=>array(0=>'61'),1=>array(0=>'6'),2=>array(0=>'1'));
$result = implode(",",call_user_func_array('array_merge', $array));
Please note : Here all are numeric keys, so change your code to :
$nameId[] = array($row['id'] ); , remove key 'ids' from here
Output :
61,6,1
Thats what I think
$nameId[] = $row['id'];
$stringId = implode(',',$name);
Use following function that will loop through array and find ids key and merge it into other array and after that when you calling this function it will impload it.
function CustomFindJoinArray( $needly, $array )
{
$results = array();
foreach ( $array as $key => $value )
{
if ( is_array( $value ) )
{
$results = array_merge($results, foo( $needly, $value ));
}
else if ( $key == $needly )
{
$results[] = $value;
}
}
return $results;
}
echo implode( ",", CustomFindJoinArray( "ids", $your_array ) );
where $your_array will be array('0'=>array('ids'=>'61'), '1'=>array('ids'=>'6'), '2'=>array('ids'=>'1'))
OR More simple
foreach ($your_array as $key => $ids) {
$newArray[] = $array[$key]["ids"];
}
$string = implode(',', $newArray);
$ids = array();
foreach($nameId as $curr) {
$ids[] = $curr['ids'];
}
$str = "(".implode(",",$ids).")";

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