PHP check variable if exists in array of json - php

Question

Array : [{"ID":1},{"ID":2}]
$id=1;
I want to check if $id exists in the array.
Thank you!

Answer 1

You may try Laravel's Collection::contains method, for example:
$collection = collect(json_decode($jsonString, true));
if ($collection->contains(1) {
// Exists...
}
Also, you may use key/value pair like this:
if ($collection->contains('ID', 1) {
//...
}
Also, if you want to get that item from the collection then you may try where like this:
$id = $collection->where('ID', 1)->first(); // ['ID' => 1]

Answer 2

You have a json formatted array and you need to decode it using json_decode first. After that loop the array to check for the id that you want.
So the code should look like this:
$json = '[{"ID":1},{"ID":2}]';
$id = 1;
$data = json_decode($json, true);
foreach($data as $item){
if($item['id'] == $id) {
echo 'it exists';
}
}

Answer 3

Iterate the array using for loop and use the value as a param to json_decode.
$id = 1;
$arr = array('{"ID":1}', '{"ID":2}');
foreach($arr as $val) {
if (in_array($id, json_decode($val, TRUE))) {
echo "id present";
}
}

Answer 4

Try this, if value is exist it will give key of array
$jsondata = '[{"ID":1},{"ID":2}]';
$array = json_decode($jsondata,true);
$key = array_search(1, array_column($array, 'ID'));

Answer 5

Just check if the string is in the json array, with little computation.
I think it's the more efficient way. Check the result here.
<?php
$id = 1;
$array = ['{"ID":1}', '{"ID":2}'];
echo in_array(json_encode(["ID" => $id]), $array) ? 'Yes' : 'No';