Join table without any reference - php

Question

in the result of sql query, I will check with php which column has record.
example:
if ($column_1) {echo $column_1}
if ($column_2) {echo $column_2}
if ($column_3) {echo $column_3}
I don't use else if there because I need it to continue in checking the record from the sql query.
However with the php code above, I can't union table in order to get another record of column from that table too. First, because the column count doesn't match. Then even though I manipulate the column, it will give me a duplicate row.
What I have been trying so far to achieve this is to use sub query. But before I know the result, it has come with an error.
Well, this is my full code. Have a look, please.
$sql = "SELECT op.reference_no, op.eight_percent, op.ten_percent,
op.date, op.claim, op.orders_history_id,
oh.one_product_price, oh.quantity,
(
SELECT it.type
FROM infimoney_transfer it
),
(
SELECT it.receiveable
FROM infimoney_transfer it
),
(
SELECT oh.id AS ohid
FROM infimoney_transfer it
)
FROM order_promotion op
LEFT JOIN orders_history oh
ON oh.id = op.orders_history_id
WHERE oh.customer_id = $member_id";
$saldo = $mysqli->query($sql);
if(!$saldo){ printf("Errormessage: %s\n", $mysqli->error); die(); }
if ($saldo->num_rows > 0) {
while($objek = $saldo->fetch_object()) {
if ($objek->eight_percent)
{
$sourceCash = $objek->quantity % 10 > 4 ? 1 : 0;
echo "<tr>
<td>".$objek->reference_no . "</td>
<td>Cashback 8%</td>
<td>".$objek->date."</td>
<td>".$sourceCash * 5 * $objek->one_product_price."</td>
<td>".$objek->eight_percent."</td>
<td> - </td>
<td> Not Yet </td>
</tr>";
}
if ($objek->ten_percent)
{
$sourceCash = (int)($objek->quantity / 10);
echo "<tr>
<td>".$objek->reference_no . $objek->orders_history_id."</td>
<td>Cashback 10%</td>
<td>".$objek->date."</td>
<td>".$sourceCash * 10 * $objek->one_product_price."</td>
<td>".$objek->ten_percent."</td>
<td> - </td>
<td> Not </td>
</tr>";
}
if ($objek->claim)
{
$sourceCash = (int)($objek->quantity / 10);
echo "<tr>
<td>".$objek->reference_no . $objek->orders_history_id."</td>
<td>Claimed</td>
<td>".$objek->date."</td>
<td>".$objek->claim."</td>
<td> - </td>
<td>".$objek->claim."</td>
<td> Not </td>
</tr>";
}
Please Help. Thanks in Advance.

Answer 1

If you join your tables all in the same select query, it will not give you duplicate rows:
$sql = "SELECT op.reference_no, op.eight_percent, op.ten_percent,
op.date, op.claim, op.orders_history_id,
oh.id, oh.one_product_price, oh.quantity,
it.type, it.receiveable,
FROM order_promotion op
LEFT JOIN orders_history oh ON oh.id = op.orders_history_id
LEFT JOIN infimoney_transfer it ON it.orders_list_id=oh.order_list_id
WHERE oh.customer_id = $member_id";