PHP OOP NOT ADDING - php

Im trying to create a to-do list following a tutorial from phpacademy. Iv managed to get everything to work, accept for submitting the user input into the database. This is my code so far.
<?php
require 'init.php';
if(isset($_POST['submit'])){
$name = trim($_POST['name']);
if(!empty($name)) {
$query = $db->prepare("
INERT INTO items (name,done) VALUES (:name,0)
");
$query->execute([
'name' => $name
]);
}
}
else {
echo ' not submitted';
} ?>

Try this way to fix your typo INSERT and :name
<?php
require 'init.php';
if(isset($_POST['submit']))
{
$name = trim($_POST['name']);
if(!empty($name))
{
$query = $db->prepare("
INSERT INTO items (name,done) VALUES (:name,0)
");
$query->execute([
':name' => $name
]);
echo "Successfully Inserted";
}
}
else{
echo ' not submitted';
}
?>

Related

Can you figure out why this PHP model doesn't insert the data in a MySQL database?

I'm trying to insert some data with PHP, but I have this problem with the following model not inserting the data into the SQL database. The controller sends the data correctly, I checked and is also received in the model(also checked), but the query is not working, the data is not inserted in the database. Can you help me?
This is the controller:
<?php
try {
$name = "Frank";
$lname = "Casttle";
$email = "frankcastle#email.com";
$mobile = "3136556195";
// $name = htmlspecialchars($_POST['name']);
// $lname = htmlspecialchars($_POST['lname']);
// $email = htmlspecialchars(trim($_POST['mail']));
// $mobile = htmlspecialchars(trim($_POST['phone']));
require_once ("../model/connection.php");
require_once ("../model/handle_data_model.php");
$connection = Connect::connection();
$handleUser = new Handle_users($connection);
$insertUser = new Users_obj();
if(empty($name) || empty($lname) || empty($email) || empty($mobile)) {
echo "<b class='text-danger'>¡You must complet all required fields!<b>";
} else {
$insertUser->set_name(mb_strtolower($name));
$insertUser->set_lname(mb_strtolower($lname));
$insertUser->set_email(mb_strtolower($email));
$insertUser->set_userMobile($mobile);
// echo "<b class='text-danger'>¡Data Sent!<b>";
$handleUser->set_basicUser($insertUser);
}
} catch(exception $e) {
// die ("Error: " . $e->getMessage());
die ();
echo "<b class='text-danger'>1. ".$e->getMessage()."<b>)";
}
?>
This is the model:
<?php
public function set_basicUser(Users_obj $setUser) {
$name = $setUser->get_name();
$lname = $setUser->get_lname();
$email = $setUser->get_email();
$mobile = $setUser->get_userMobile();
echo $name." ".$lname." ".$email." ".$mobile ; // Data is arriving correctly
$this->connection->beginTransaction();
try {
$insert_persona = "INSERT INTO usuario (name, lname, mail, phone) VALUES
('".$name."', '".$lname."', '".$email."', '".$mobile."')";
$this->connection->exec($insert_persona);
echo "<b class='text-primary'>2. ¡User Inserted!<b>";
} catch (PDOexception $e) {
$this->connection->rollback();
echo "<b class='text-danger'>3. ".$e->getMessage()."<b>)";
}
$this->connection = null;
}
?>
At the end, the code enters in the try and execute the code, the transaction is succesful, even it didn't throw error, but the model is not inserting the data into the database. Can you help me? Maybe I'm missing something. Thank you!

Trouble adding data from one table to another

I've been trying to make a payment page where after adding sufficient information, the order is taken with the items in the cart. for some reason, my code isn't responding and is showing a blank screen. I am relatively new to PHP. could anyone help me out? Here is the code below:-
<?php
require_once('../connection.php');
require_once('../product.php');
session_start();
$name = $_POST['name'];
$email = $_POST['email'];
$address = $_POST['address'];
if(isset($_POST['payment-made'])){
if(empty($name) || empty($email) || empty($address)){
echo "<script>alert('Please enter the complete information!');
window.location = 'orders.inc.php';</script>";
} else {
if(isset($_SESSION['Uid'])){
if(isset($_SESSION['cart'])){
$product_id = array_column($_SESSION['cart'], 'product_id');
$result = mysqli_query($conn,"SELECT * FROM `products`");
while($row = mysqli_fetch_assoc($result)){
foreach($product_id as $id){
if($row['product_id']==$id){
$ordername = $row['item_name'];
$nooforder = 1;
$sql1 = "INSERT INTO orders(order_name, no_order, cust_name, del_add)
VALUES ('$ordername', '$nooforder', '$name', '$email', '$address');";
$done = mysqli_query($conn, $sql1);
if($done){
echo "successful";
}
else{
ini_set('display_errors', '1');
ini_set('display_startup_errors', '1');
error_reporting(E_ALL);
}
}
}
}
}
}
}
}
?>
I have doubts the problem lies within the $ordername variable. Could anyone clarify what's causing the problem and how to solve it?
Your INSERT query names four columns, but provides five variables to insert.

Error adding data in mysql table using PHP

I'm making a simple CURD operation using PHP and MYSQL. However I'm not able to insert/add data in the created table.
I think it might be a syntax error itself, but I can't figure out which one. The rest of the code works fine.
operation.php:
require_once("../CRUD/php/db.php");
$conn = createDB();
if(isset($_POST['create']))
{
createData();
}
function createData()
{
$name = textboxValue("name_type");
$age = textboxValue("age_type");
$gender = textboxValue("gender_type");
$email = textboxValue("email_type");
$contact = textboxValue("contact_type");
$dept = textboxValue("dept_type");
$sql = "INSERT INTO details(name,age,gender,email,contact,department)
VALUES('$name', '$age', '$gender', $email', '$contact', '$dept');";
if(mysqli_query($GLOBALS['conn'],$sql))
{
echo "Data added";
}
else
{
echo "Error adding data";
}
}
function textboxValue($value)
{
$textbox = mysqli_real_escape_string($GLOBALS['conn'], trim($_POST[$value]));
if(empty($textbox))
{
return false;
}
else
{
return $textbox;
}
}
"Error adding data" gets echoed. I can share the html code as well if needed.
$sql = "INSERT INTO details(name,age,gender,email,contact,department)
VALUES(\"$name\", \"$age\", \"$gender\", \"$email\", \"$contact\", \"$dept\");";
and so? By the way one quote you forgot near $email

Not able to insert the data from url to database in php

final.php
Here I am trying to get the data from the url using GET method and trying to insert into the database. I was able to insert the data for first few rows after that the data is not inserted. Can anyone help me regarding this?
when I try to run the url: www.myii.com/app/final.php?name=123&glucose=3232...
the data is not inserting.
<?php
include("query_connect.php");
$name = $_GET['name'];
$glucose = $_GET['glucose'];
$temp = $_GET['temp'];
$battery = $_GET['battery'];
$tgs_a = $_GET['tgs_a'];
$tgs_g = $_GET['tgs_g'];
$heartrate = $_GET['heartrate'];
$spo2 = $_GET['spo2'];
$rr = $_GET['rr'];
$hb = $_GET['hb'];
$ina22 = $_GET['ina22'];
$accucheck = $_GET['accucheck'];
$isactive = $_GET['isactive'];
$address = $_GET['address'];
$deviceno = $_GET['deviceno'];
$sql_insert = "insert into query (name,glucose,temp,battery,tgs_a,tgs_g,heartrate,spo2,rr,hb,ina22,accucheck,isactive,address,deviceno) values ('$name','$glucose','$temp',$battery','$tgs_a','$tgs_g','$heartrate','$spo2','$rr','$hb','$ina22','$accucheck','$isactive','$address','$deviceno')";
mysqli_query($sql_insert);
if($sql_insert)
{
echo "Saving succeed";
//echo $date_time;
}
else{
echo "Error occured";
}
?>
Query_connect.php
This is my database config php file.
<?php
$user = "m33root";
$password = "me3i434";
$host = "localhost";
$connection = mysqli_connect($host,$user,$password);
$select = mysqli_select_db('miiyy',$connection);
if($connection)
{
echo "connection succesfull<br>";
}
else {
echo "Error";
}
?>
Make sure that all columns can contain NULL so that not filled fields will stay NULL instead of throwing an error.
Try below to see mysql error:
mysql_query($sql_insert);
echo mysql_error()
Try these
In SQL
Change the table name of query to some other name. Because "query" is reserved in SQL
In code
if (!mysqli_query($con,$sql_insert ))
{
echo("Error description: " . mysqli_error($con));
}
else
{
echo "Success";
}
Use mysqli_error() function

Cannot execute sql INSERT query (mysql_query) in php script. PHP/MySQL -- Time Sensitive

UPDATE: NOW RESOLVED - Thanks everyone!
Fix: I had a column named "referred_by" and in my code it's called "referred_by_id" - so it was trying to INSERT to a column that didn't exist -- once I fixed this, it decided to work!
I have limited time left to work on this project. The clock is ticking.
I'm trying to INSERT $php_variables into a TABLE called "clients".
I've been trying for hours to get this script to work, and I got it to work once, but then I realized I forgot a field, so I had to add another column to the TABLE and when I updated the script it stopped working. I reverted by but now it's still not working and I'm just frustrating myself too much.
<?php
error_reporting(E_ALL);
ini_set("display_errors", 1);
if (!isset($_COOKIE["user"]))
{
header ("Location: ./login.php");
}
else
{
include ("./source.php");
echo $doctype;
}
$birthday = $birth_year . "-" . $birth_month . "-" . $birth_day;
$join_date = date("Y-m-d");
$error_type = 0;
$link = mysql_connect("SERVER", "USERNAME", "PASSWORD");
if (!$link)
{
$error = "Cannot connect to MySQL.";
$error_type = 1;
}
$select_db = mysql_select_db("DATABASE", $link);
if (!$select_db)
{
$error = "Cannot connect to Database.";
$error_type = 2;
}
if ($referred_by != "")
{
$result = mysql_query("
SELECT id FROM clients WHERE referral_code = $referred_by
");
if (!$result)
{
$error = "Cannot find referral.";
$error_type = 3;
}
while ($row = mysql_fetch_array($result))
{
$referred_by_id = $row['id'];
}
}
else
{
$referred_by_id = 0;
}
$first_name = mysql_real_escape_string($_POST['first_name']);
$last_name = mysql_real_escape_string($_POST['last_name']);
$birth_month = mysql_real_escape_string($_POST['birth_month']);
$birth_day = mysql_real_escape_string($_POST['birth_day']);
$birth_year = mysql_real_escape_string($_POST['birth_year']);
$email = mysql_real_escape_string($_POST['email']);
$address = mysql_real_escape_string($_POST['address']);
$city = mysql_real_escape_string($_POST['city']);
$state = mysql_real_escape_string($_POST['state']);
$zip_code = mysql_real_escape_string($_POST['zip_code']);
$phone_home = mysql_real_escape_string($_POST['phone_home']);
$phone_cell = mysql_real_escape_string($_POST['phone_cell']);
$referral_code = mysql_real_escape_string($_POST['referral_code']);
$referred_by = mysql_real_escape_string($_POST['referred_by']);
$organization = mysql_real_escape_string($_POST['organization']);
$gov_type = mysql_real_escape_string($_POST['gov_type']);
$gov_code = mysql_real_escape_string($_POST['gov_code']);
$test_query = mysql_query
("
INSERT INTO clients (first_name, last_name, birthday, join_date, email, address, city, state, zip_code,
phone_home, phone_cell, referral_code, referred_by_id, organization, gov_type, gov_code)
VALUES ('".$first_name."', '".$last_name."', '".$birthday."', '".$join_date."', '".$email."', '".$address."', '".$city."', '".$state."', '".$zip_code."',
'".$phone_home."', '".$phone_cell."', '".$referral_code."', '".$referred_by_id."', '".$organization."', '".$gov_type."', '".$gov_code."')
");
if (!$test_query)
{
die(mysql_error($link));
}
if ($error_type > 0)
{
$title_name = "Error";
}
if ($error_type == 0)
{
$title_name = "Success";
}
?>
<html>
<head>
<title><?php echo $title . " - " . $title_name; ?></title>
<?php echo $meta; ?>
<?php echo $style; ?>
</head>
<body>
<?php echo $logo; ?>
<?php echo $sublogo; ?>
<?php echo $nav; ?>
<div id="content">
<div id="main">
<span class="event_title"><?php echo $title_name; ?></span><br><br>
<?php
if ($error_type == 0)
{
echo "Client was added to the database successfully.";
}
else
{
echo $error;
}
?>
</div>
<?php echo $copyright ?>
</div>
</body>
</html>
Definitely not working as is. Looks you have a 500 error, since you have an else with a missing if:
else
{
$referred_by_id = 0;
}
Otherwise, you'll need to post your DB schema.
Also, note that you're really taking the long way around with this code, which makes it difficult to read & maintain. You're also missing any sort of checks for SQL injection... you really need to pass things through mysql_real_escape_string (and really, you should use mysqli, since the mysql interface was basically deprecated years ago).
$keys = array('first_name',
'last_name',
'birthday',
'join_date',
'email',
'address',
'city',
'state',
'zip_code',
'phone_home',
'phone_cell',
'referral_code',
'referred_by_id',
'organization',
'gov_type',
'gov_code');
$_REQUEST['birthdate'] = $_REQUEST['birth_year'].'-'.$_REQUEST['birth_month'].'-'.$_REQUEST['birth_day'];
$_REQUEST['join_date'] = date('Y-m-d',time());
$params = array();
foreach ($keys as $key)
{
$params[] = mysql_real_escape_string($request[$key]);
}
$sql = 'INSERT INTO clients ('.implode(',', $keys).') ';
$sql .= ' VALUES (\''.implode('\',\'', $params).'\') ';
You've an error on line 81:
else
{
$referred_by_id = 0;
}
I don't see an IF construct before that, make the appropriate correction and run the script again.
Without looking at the table structure to make sure all the fields are there, I'm going to assume it's something with the data.
Any quotes in the data will lead to problems (including SQL injection security holes). You should wrap each $_POST[] with mysql_real_escape_string(), such as:
$first_name = mysql_real_escape_string($_POST['first_name']);
EDIT: Further debugging...
As someone suggested (sorry, can't find the comment), try:
$sql = "
INSERT INTO clients (first_name, last_name, birthday, join_date, email, address, city, state, zip_code,
phone_home, phone_cell, referral_code, referred_by_id, organization, gov_type, gov_code)
VALUES ('".$first_name."', '".$last_name."', '".$birthday."', '".$join_date."', '".$email."', '".$address."', '".$city."', '".$state."', '".$zip_code."',
'".$phone_home."', '".$phone_cell."', '".$referral_code."', '".$referred_by_id."', '".$organization."', '".$gov_type."', '".$gov_code."'
)";
// Debug:
print "<pre>". $sql ."</pre>";
mysql_query($sql);
The SQL statement should be printed out when submitting the form. Take that SQL statement and try to execute it directly in MySQL to see if it works, or if it generates an error.

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