Trouble adding data from one table to another - php

Question

I've been trying to make a payment page where after adding sufficient information, the order is taken with the items in the cart. for some reason, my code isn't responding and is showing a blank screen. I am relatively new to PHP. could anyone help me out? Here is the code below:-
<?php
require_once('../connection.php');
require_once('../product.php');
session_start();
$name = $_POST['name'];
$email = $_POST['email'];
$address = $_POST['address'];
if(isset($_POST['payment-made'])){
if(empty($name) || empty($email) || empty($address)){
echo "<script>alert('Please enter the complete information!');
window.location = 'orders.inc.php';</script>";
} else {
if(isset($_SESSION['Uid'])){
if(isset($_SESSION['cart'])){
$product_id = array_column($_SESSION['cart'], 'product_id');
$result = mysqli_query($conn,"SELECT * FROM `products`");
while($row = mysqli_fetch_assoc($result)){
foreach($product_id as $id){
if($row['product_id']==$id){
$ordername = $row['item_name'];
$nooforder = 1;
$sql1 = "INSERT INTO orders(order_name, no_order, cust_name, del_add)
VALUES ('$ordername', '$nooforder', '$name', '$email', '$address');";
$done = mysqli_query($conn, $sql1);
if($done){
echo "successful";
}
else{
ini_set('display_errors', '1');
ini_set('display_startup_errors', '1');
error_reporting(E_ALL);
}
}
}
}
}
}
}
}
?>
I have doubts the problem lies within the $ordername variable. Could anyone clarify what's causing the problem and how to solve it?

Answer 1

Your INSERT query names four columns, but provides five variables to insert.