I am creating a website where it sends values from a JavaScript object into a MySQL database via PHP
Here is the code:
<!DOCTYPE html>
<html>
<body>
<p>Creating a JavaScript Object.</p>
<p id="demo"></p>
<script>
var person = {
firstName : "John",
lastName : "Doe",
age : 50,
eyeColor : "blue"
};
</script>
</body>
</html>
Overall, my question is how to send the objects data to the MySQL using PHP?
<?php
$servername = "localhost";
$username = "username";
$password = "password";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
If I type the code in before it prints out:
connect_error) {die("Connection failed: " . $conn->connect_error);} echo "Connected successfully";?>
It sounds to me like you are trying to jump from not knowing how to work with PHP and MySQL to also adding JavaScript.
First let me give you an example of how to work with all of those things.
Here is the repo with all of these files: https://github.com/Goddard/simplelogin-example.
This is what connects you to the database:
<?php
error_reporting(E_ALL);
ini_set('display_errors',1);
define("__DB_NAME__", 'job');
define("__DB_DSN__", 'mysql:dbname=' . __DB_NAME__ . ';host=127.0.0.1');
define("__DB_USERNAME__", 'root');
define("__DB_PASSWORD__", '');
if(session_id() == '') {
session_start();
}
if(!isset($_SESSION['username']))
{
$_SESSION['username'] = NULL;
}
//database setup
try {
$db = new PDO ( __DB_DSN__, __DB_USERNAME__, __DB_PASSWORD__ );
$db->query ( "use " . __DB_NAME__);
}
catch ( PDOException $e ) {
echo 'Could not connect : ' . $e->getMessage ();
}
?>
This is what works with the database information:
<?php
include("db.php");
if(trim(htmlentities(addslashes(filter_input(INPUT_GET, 'type')), ENT_QUOTES)) === "loginUser")
{
try {
$username = trim(filter_input(INPUT_GET, 'username'));
$password = trim(filter_input(INPUT_GET, 'password'));
$fetch = $db->prepare("SELECT * FROM `users` WHERE user_name = :username");
$fetch->bindParam(':username', $username, PDO::PARAM_STR);
$fetch->execute();
$result = $fetch->fetch(PDO::FETCH_OBJ);
if($result)
{
if(password_verify($password, $result->password_hash))
{
$currentDateTime = date('Y-m-d H:i:s');
$update = $db->prepare("UPDATE `users` SET `last_login` = :lastlogin WHERE `client_id` = :clientid");
$update->bindParam(':lastlogin', $currentDateTime);
$update->bindParam(':clientid', $result->client_id);
$loginUpdate = $update->execute();
$resultArray['error'] = 0;
$resultArray['errorMessage'] = "None";
$resultArray['userName'] = $result->user_name;
$_SESSION['username'] = $result->user_name;
echo json_encode($resultArray);
}
else
{
$resultArray['error'] = 1;
$resultArray['errorMessage'] = "Incorrect Password";
echo json_encode($resultArray);
}
}
else
{
$resultArray['error'] = 1;
$resultArray['errorMessage'] = "Incorrect Username";
echo json_encode($resultArray);
}
} catch (PDOException $e) {
$resultArray['error'] = 1;
$resultArray['errorMessage'] = $e->getMessage();
echo json_encode($resultArray);
}
}
Related
Im trying to do if else using Camp data in table testing_data. did i do this correctly in retrieve the data and calling it in if else..i really newbies in php ..hope you can help me..tq
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "brindley";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM testing_data";
$result = $conn->query($sql);
$user = mysqli_fetch_array($result);
if($user["t_month"] === 'Q1')
{
if($user['t_bbq'] === 'Kambing Golek')
{
if($user['t_participant'] =='>=21 to <=40')
{
if($user['t_outdoor'] == 'Tiada')
{
if($user['t_packages']== 'Pakej 4')
{
echo "YES, People prefer choose packages like this";
}
else
{
echo "NO";
}
}
}
}
?>
I am trying to send a data from android studio, but I am getting lines under the table instead of assigning data.
Dont know where I am gone wrong.Plz help me.Thanks in advance.
This is my PHP code
add_employee
<?php
include('connection.php');
if (isset($_POST["name"])){
$emp_name = $_POST["name"];
echo $emp_name;
echo "is your name";
}
else{
$emp_name = NULL;
echo "POST filename is not assigned";
}
$success = 0;
$status = "Active";
$sqli = "INSERT INTO `employee` (`emp_name`) VALUES ('$emp_name')";
if(mysqli_query($conn,$sqli)){
$success=1;
}
$response["success"]=$success;
die(json_encode($response));
mysqli_close($conn);
?>
Connection.php
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass);
if(!$conn) {
die('Could not connect: ' . mysqli_error());
}
mysqli_select_db($conn,'student');
?>
You have so many errors in your code. no db name, no proper query definition. you can use this simple code:
Connection.php
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "slim";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
?>
Inserting employee code:
<?php
if (isset($_POST["name"])){
$emp_name=$_POST["name"];
echo $emp_name;
echo "is your name";
}
else{
$emp_name = null;
echo "POST filename is not assigned";
}
$success=0;
$status="Active";
$sql = "INSERT INTO employee (name)
VALUES ('$emp_name')";
if ($conn->query($sql) === TRUE) {
$success=1;
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
It's working and easy to understand for you.
I refer the below links http://www.discorganized.com/php/a-complete-nusoap-and-flex-example-part-1-the-nusoap-server/
Code:
$client = new nusoap_client("http://localhost/jenny_flowers/online-shopping/webservice/index.php?wsdl",array('trace' => 1));
$in_contact=array ('first_name'=>'sona','last_name' => 'sdsdsd','email' => 'ssdsd','phone_number' => 'sdsd');
$result = $client->call('insertContact', $in_contact);
if ($result){ echo "OK";
} else { echo "Error";
}
But it displays
Array to string conversion in C:\wamp\www\jenny_flowers\online-shopping\webservice\lib\nusoap.php on line 7266
What is the actual issue? help.
First have connect file
connect.php
<?php
$mysql_db_hostname = "localhost";
$mysql_db_user = "root";
$mysql_db_password = "";
$mysql_db_database = "your database";
$con = #mysqli_connect($mysql_db_hostname, $mysql_db_user, $mysql_db_password,
$mysql_db_database);
if (!$con) {
trigger_error('Could not connect to MySQL: ' . mysqli_connect_error());
}
?>
insert.php
<?php
include_once('connect.php');
error_reporting( error_reporting() & ~E_NOTICE );
//$first_name= $_GET['first_name'];
$last_name= $_GET['last_name'];
$email= $_GET['email'];
$phone_number= $_GET['phone_number'];
{
$insert="INSERT INTO //your_table_name(first_name,last_name,email,phone_number)values
('$first_name','$last_name','$email','$phone_number')";
$result = mysqli_query($con, $insert);
if(!$result)
{
print("invalid query");
}
else
{
$output['success']=1;
$output['message']="Insert records successfully";
print(json_encode($output));
}
}
?>
Have JSON Viwer in your browser to view the json output
otherwise you can used echo in it
I am getting issue in update code.I am able to inserted data in database.I am passing null values in table. I want to update that null values.I am getting the sccessfully message but data is not updating. Please help me....
//Insert code
<?php
// Start the session
session_start();
?>
<?php
// Start the session
session_start();
?>
<?php
try{
$product=$_POST['product'];
/*
$product2=$_POST['product2'];
$product3=$_POST['product3'];
*/
// form data
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$conn=mysql_connect($servername, $username, $password) or die('Connection failed: ' . mysql_error());
#mysql_select_db($database, $conn) or die("Could not select your database".mysql_error());
$insertQuery = "Insert into contactus(Id,Product) values('null','$product')";
$result = mysql_query($insertQuery);
if($result){
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../index.html';</script>";
}
else
{
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../index.html';</script>";
}
mysql_close($conn);
header('Location: /newstore/contact.html');
}
catch(Exception $e) {
echo ("<script>alert('Something went terribly wrong. Please try again later.');location.href = ''../index.html';</script>");
return false;
}
?>
//Update code
<?php
// Start the session
session_start();
?>
<?php
try{
// form data
$name=$_POST['name'];
$email=$_POST['email'];
$mobile=$_POST['mobile'];
$product=isset($_POST['product']);
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$conn=mysql_connect($servername, $username, $password) or die('Connection failed: ' . mysql_error());
#mysql_select_db($database, $conn) or die("Could not select your database".mysql_error());
;if ((strlen($name) < 3) or (strlen($email) < 3) or(strlen($mobile) < 3))
{
echo ("<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>");
}else
{
$UpdateQuery = "update contactus set Name='$name',Email='$email',Mobile='$mobile' where Id='(select count(*) from contactus)' ";
$result = mysql_query($UpdateQuery);
if($result){
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../newstore/index.html';</script>";
}
else
{
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>";
}
}
mysql_close($conn);
}
catch(Exception $e) {
echo ("<script>alert('Something went terribly wrong. Please try again later.');location.href = ''../newstore/index.html';</script>");
return false;
}
?>
I see no point in doing an Insert and then doing an Update. You already have all the data, so just Insert it all at once.
EDIT AFTER COMMENTS
First Handler:
<?php
start_session();
if(isset($_POST['product'])){
$product=$_POST['product'];
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$mysqli = new mysqli($servername, $username, $password, $database);
/* check connection */
if (mysqli_connect_errno()) {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again. (" . mysqli_connect_error() . ")');location.href = '../newstore/index.html'</script>");
exit();
}
if ($result = $mysqli->query("INSERT INTO contactus (Id,Product) VALUES ('null','$product')")) {
// Grab new ID when INSERT is successfull, add it to Session
$_SESSION['contact_id'] = $mysqli->insert_id;
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../index.html';</script>";
} else {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../index.html';</script>";
$mysqli->close();
exit();
}
$mysqli->close();
}
header('Location: /newstore/contact.html');
?>
Second Handler:
<?php
start_session();
// form data
$name=isset($_POST['name'])?$_POST['name']:"";
$email=isset($_POST['email'])?$_POST['email']:"";
$mobile=$_POST['mobile'];
if ((strlen($name) < 3) || (strlen($email) < 3) || (strlen($mobile) < 3)){
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>";
exit();
}
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$mysqli = new mysqli($servername, $username, $password, $database);
/* check connection */
if (mysqli_connect_errno()) {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again. (" . mysqli_connect_error() . ")');location.href = '../newstore/index.html'</script>");
exit();
}
if ($stmt = $mysqli->prepare("UPDATE contactus SET `Name`=?, `Email`=?, `Mobile`=?) WHERE `ID`=?")){
/* bind parameters for markers */
$stmt->bind_param("sssi", $name, $email, $mobile, $_SESSION['contact_id']);
/* execute query */
$stmt->execute();
$result = $stmt->get_result();
if($result){
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../newstore/index.html';</script>";
} else {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>";
}
$stmt->close();
}
$mysqli->close();
?>
I just want to test db connection from my browser. But i get empty page. I am not getting Error message.
<?php
$con = mysqli_connect('http://ec2-54-67-69-153.us-west-1.compute.amazonaws.com/', 'root', 'root') or die(mysqli_error($con));
if ($con) {
echo "success";
} else {
echo "fail";
}
mysqli_close($con);
?>
**Here is a handy function that connects you to a Database, using *Object Oriented* style:**
function MySQLi_quickConnect()
{
$host = 'somewebsite.db.120327161.hostedresource.com'; //or 'http://localhost'
$username = '<YOUR USERNAME>';
$password = '<YOUR PASSWORD>';
$database = '<YOUR DATABASES NAME>';
$db = new MySQLi($host,$username,$password,$database);
$error_message = $db->connect_error;
if($error_message != NULL){die("Error:" . $error_message . "<br>" . "Occured in function
MySQLi_quickConnect");}
return $db;
}
**A simple example on how you would query the Database:**
$db = MySQLi_quickConnect(); //this is your new Database object
$sql = "<YOUR SQL STATEMENT>";
$stmt = $db->query($sql);
if(!$stmt){die('MyError : ('. $db->errno .') '. $db->error);} //kill script, show errors