Data already Inserted I want to update the data - php

Question

I am getting issue in update code.I am able to inserted data in database.I am passing null values in table. I want to update that null values.I am getting the sccessfully message but data is not updating. Please help me....
//Insert code
<?php
// Start the session
session_start();
?>
<?php
// Start the session
session_start();
?>
<?php
try{
$product=$_POST['product'];
/*
$product2=$_POST['product2'];
$product3=$_POST['product3'];
*/
// form data
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$conn=mysql_connect($servername, $username, $password) or die('Connection failed: ' . mysql_error());
#mysql_select_db($database, $conn) or die("Could not select your database".mysql_error());
$insertQuery = "Insert into contactus(Id,Product) values('null','$product')";
$result = mysql_query($insertQuery);
if($result){
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../index.html';</script>";
}
else
{
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../index.html';</script>";
}
mysql_close($conn);
header('Location: /newstore/contact.html');
}
catch(Exception $e) {
echo ("<script>alert('Something went terribly wrong. Please try again later.');location.href = ''../index.html';</script>");
return false;
}
?>
//Update code
<?php
// Start the session
session_start();
?>
<?php
try{
// form data
$name=$_POST['name'];
$email=$_POST['email'];
$mobile=$_POST['mobile'];
$product=isset($_POST['product']);
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$conn=mysql_connect($servername, $username, $password) or die('Connection failed: ' . mysql_error());
#mysql_select_db($database, $conn) or die("Could not select your database".mysql_error());
;if ((strlen($name) < 3) or (strlen($email) < 3) or(strlen($mobile) < 3))
{
echo ("<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>");
}else
{
$UpdateQuery = "update contactus set Name='$name',Email='$email',Mobile='$mobile' where Id='(select count(*) from contactus)' ";
$result = mysql_query($UpdateQuery);
if($result){
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../newstore/index.html';</script>";
}
else
{
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>";
}
}
mysql_close($conn);
}
catch(Exception $e) {
echo ("<script>alert('Something went terribly wrong. Please try again later.');location.href = ''../newstore/index.html';</script>");
return false;
}
?>

Answer 1

I see no point in doing an Insert and then doing an Update. You already have all the data, so just Insert it all at once.
EDIT AFTER COMMENTS
First Handler:
<?php
start_session();
if(isset($_POST['product'])){
$product=$_POST['product'];
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$mysqli = new mysqli($servername, $username, $password, $database);
/* check connection */
if (mysqli_connect_errno()) {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again. (" . mysqli_connect_error() . ")');location.href = '../newstore/index.html'</script>");
exit();
}
if ($result = $mysqli->query("INSERT INTO contactus (Id,Product) VALUES ('null','$product')")) {
// Grab new ID when INSERT is successfull, add it to Session
$_SESSION['contact_id'] = $mysqli->insert_id;
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../index.html';</script>";
} else {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../index.html';</script>";
$mysqli->close();
exit();
}
$mysqli->close();
}
header('Location: /newstore/contact.html');
?>
Second Handler:
<?php
start_session();
// form data
$name=isset($_POST['name'])?$_POST['name']:"";
$email=isset($_POST['email'])?$_POST['email']:"";
$mobile=$_POST['mobile'];
if ((strlen($name) < 3) || (strlen($email) < 3) || (strlen($mobile) < 3)){
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>";
exit();
}
//database Connection details
$servername = "localhost";
$username = "root";
$password = "";
$database="store";
$error = "";
$mysqli = new mysqli($servername, $username, $password, $database);
/* check connection */
if (mysqli_connect_errno()) {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again. (" . mysqli_connect_error() . ")');location.href = '../newstore/index.html'</script>");
exit();
}
if ($stmt = $mysqli->prepare("UPDATE contactus SET `Name`=?, `Email`=?, `Mobile`=?) WHERE `ID`=?")){
/* bind parameters for markers */
$stmt->bind_param("sssi", $name, $email, $mobile, $_SESSION['contact_id']);
/* execute query */
$stmt->execute();
$result = $stmt->get_result();
if($result){
echo "<script>alert('Thank You. Your Data Received Succefully.');location.href = '../newstore/index.html';</script>";
} else {
echo "<script>alert('Something went wrong with your data inserted. Please fill the form again.');location.href = '../newstore/index.html';</script>";
}
$stmt->close();
}
$mysqli->close();
?>