Php count cannot work for my notification - php

Question

When I echo ''.$count.'' its display 11101101. But I want to total count like 8 or 7 etc. What is my wrong here in my code please.
I used to try $count = mysqli_num_rows($u); also but result was same.
my code:
$g = mysqli_query($dbh,"SELECT id FROM update WHERE from_id`='".$b."' OR `to_id`='".$session->id."'") or die(mysqli_error($dbh));
while ($rows = mysqli_fetch_assoc($g)) {
$ids[]= $rows['id'];
}
foreach ( $ids as $id ){
$u = mysqli_query($dbh,"SELECT id FROM updateside WHERE `id`='".$id."' AND `view` = '0'") or die(mysqli_error($dbh));
$count = mysqli_affected_rows($dbh);
while ($rows = mysqli_fetch_assoc($u)) {
$nid= $rows['id'];
}
echo ''.$count.'';
}

Answer 1

Assign total count to a variable something like this:
Assumes mysqli_num_rows needs query result $u as argument.
$total = 0;
foreach ( $ids as $id ){
$u = mysqli_query($dbh,"SELECT id FROM updateside WHERE `id`='".$id."' AND `view` = '0'") or die(mysqli_error($dbh));
$count = mysqli_num_rows($u);
$count = ($count == "") ? 0 : $count;
$total = $total + $count;
while ($rows = mysqli_fetch_assoc($u)) {
$nid= $rows['id'];
}
}
echo $total;

Answer 2

You will need to change your code a bit like this
foreach ( $ids as $id ){
$u = mysqli_query($dbh,"SELECT id FROM updateside WHERE `id`='".$id."' AND `view` = '0'") or die(mysqli_error($dbh));
while ($rows = mysqli_fetch_assoc($u)) {
$nid= $rows['id'];
}
echo mysqli_num_rows($u);
}
If you need to echo after all foreach statements use this
$count=0;
foreach ( $ids as $id ){
$u = mysqli_query($dbh,"SELECT id FROM updateside WHERE `id`='".$id."' AND `view` = '0'") or die(mysqli_error($dbh));
while ($rows = mysqli_fetch_assoc($u)) {
$nid= $rows['id'];
}
$count = $count + mysqli_num_rows($u);
}
echo $count;

Answer 3

I think your issue is simply formatting bug. Why use the '' here?
Try simply write:
echo $count;

Answer 4

you can simply use
$count=$u->num_rows;
echo $count;