editing an html form with php using ajax - php

I'm trying to create an update form where the user selects an ID and the rest of the form gets automatically filled with the corresponding data to that ID which would make updating really simple, obviously i'd have to use AJAX but do i really have to write a whole form code inside the PHP and return it in a single statement and then assigning it in a single innerHTML?
Is it possible to run whatever returns from the php file as a javascript, such that i would be able to write a mini scripts to set the innerHTML of each element by itself and without having to reload the whole form's HTML code, just the values inside form elements?
<?php
$myname = "test";
$myage = 22;
echo
'<script>
document.getElementById("name").innerHTML = "$myname";
document.getElementById("age").innerHTML = "$myage";
</script>';
?>
PS i have no experience of AJAX and i can only find the xmlhttp.responseText for returning the output of a PHP script.

It would be better if you return the data structured in some form (e.g.: JSON), then process it with JavaScript.
For example, instead of what you are returning, do something like this:
<?php
$to_return = array(
"name" => "test",
"age" => 22
);
echo json_enconde($to_return);
Then on your page, parse your response, and process it:
data = JSON.parse(response);
document.getElementById("name") = data.name;
document.getElementById("age") = data.age;
If you want to standardize it a little bit more, you could return something like this:
[
{
"target": "name",
"value": "test"
},
{
"target": "age",
"value": 22
}
]
and create a function like this:
function populateForm(data) {
for (var x = 0; x < data.length; x++) {
document.getElementById(data[x].target).innerHTML = data[x].value;
}
}
Then call that function with the JSON response from your PHP.

I would recommand to return an Array in the server side (the php that handles the ajax request). and in the browser side after you get the the respone from the server then you set
document.getElementById("name").innerHTML = $myname;
document.getElementById("age").innerHTML = $myage;

Related

JavaScript PHP HighChart transform a PHP array to a javascript array

I saw other posts but it doesn't work. I am a bit confused here on how I implement an array into JS from PHP...
In the PHP file (test.php) I have :
$table = array();
while($row = mysqli_fetch_assoc($result) )
{
$value=$row['value'];
$date=$row['date'];
$table[$value]=$date;
}
And in JavaScript I have :
<?php include 'test.php'; ?>
...
data: (function() {
// generate an array of random data
var data = [],
time = (new Date()).getTime(),
i;
for (i = -19; i <= 0; i++) {
data.push({
x: time + i * 1000,
y: Math.random()
});
}
return data;
So what I look for is to put $value=$row['value']; in the y : and $date=$row['date']; in the x : OR perhaps putting the entire table $table in the var data will work also .
I'm new to JavaScript, so thanks in advance..!
So in your php file....
Add a line at the bottom that converts the table to json data.
And give it a variable...
$table = array();
while($row = mysqli_fetch_assoc($result) )
{
$value=$row['value'];
$date=$row['date'];
$table[$value]=$date;
}
$jsondata = json_encode($table);
Then in your other file....
echo that variable into your data object, in the javascript.
Remember to remove that whole random number generating function...(its just an example)
Echoing PHP into javascript is definitely not considered good practice though.
And it would be better to actually do an ajax call to your php file, and insert like that....I'll also show you how to do ajax.
<?php include 'test.php'; ?>
...
data: [<?php echo $jsondata;?>], //remove that function that was here..
// it was just to generate random numbers for the demo
....
}
EDIT / UPDATE For ajax...
So for ajax...instead of assigning a variable to $jsondata.
Just return it like so...(in your PHP file)
return json_encode($table);
Then for this way....you dont include('test.php') like you did before.
Instead you just have this script inside your $(document).ready(function(){....
$.getJSON('test.php', function(myJSON) {
//and inside this function you put your highcharts stuff...
//remove that function() that generates random data
// And you will put the 'myJSON' return object inside the 'data':[] array...
// Provided you have structured your data correctly for highcharts, it should work...
// If not.... it'll be a start, and you're well on your way to debugging it
}

MySQL Query not returning newest results on setInterval

I am having a problem with setInterval in the $(document).ready(function(){}
What I am doing is setting the interval to do is call a PHP script that runs some MySQL queries to check the condition of 4 switches and then updating the screen with the values are in the database like so:
$(document).ready(function(){
setInterval(function(){
<?php require('fetchSwitchStatuses.php'); ?>
$("#switch1").css('background', 'rgb(<?php echo $switchColor1 ?>)');
$("#switch1").html('<?php echo $switchState1 ?>');
$("#switch2").css('background', 'rgb(<?php echo $switchColor2 ?>)');
$("#switch2").html('<?php echo $switchState2 ?>');
$("#switch3").css('background', 'rgb(<?php echo $switchColor3 ?>)');
$("#switch3").html('<?php echo $switchState3 ?>');
$("#switch4").css('background', 'rgb(<?php echo $switchColor4 ?>)');
$("#switch4").html('<?php echo $switchState4 ?>');
},1000);
});
Here is the code for fetchSwitchStatuses.php:
$connect = mysqli_connect("localhost", "root", "root");
mysqli_select_db($connect, "db_name");
$fetch1 = mysqli_query($connect,
"SELECT SwitchStatus FROM Switches WHERE PinNumber = '3'"
);
$fetch2 = mysqli_query($connect,
"SELECT SwitchStatus FROM Switches WHERE PinNumber = '5'"
);
$fetch3 = mysqli_query($connect,
"SELECT SwitchStatus FROM Switches WHERE PinNumber = '6'"
);
$fetch4 = mysqli_query($connect,
"SELECT SwitchStatus FROM Switches WHERE PinNumber = '9'"
);
$i = 1;
while($row = mysqli_fetch_array(${'fetch'.$i}))
{
if($row['SwitchStatus'] == 0)
{
${'switchColor'.$i} = "255, 0, 0";
${'switchState'.$i} = "OFF";
}
else if ($row['SwitchStatus'] == 1){
${'switchColor'.$i} = "0, 255, 0";
${'switchState'.$i} = "ON";
}
else {
${'switchColor'.$i} = "100, 100, 100";
${'switchState'.$i} = "ERROR";
}
$i++;
}
mysqli_close($connect);
When the page is loaded the information is correct, whatever is in the database is what is reflected by the colors on the screen.
When I click on the object to change the value, all of the necessary changes are made and the database is updated. However, the problem arises when the Interval is repeated. The values are switched back to whatever the original values were when the page was loaded. So, although the information is correctly changed in the database, for some reason the colors of the buttons is always reset to the first value read by the queries.
How can I fix this so that the information that is reflected on the screen is accurate?
With AJAX technology you can:
Send a request and get results from server by requesting a page (a .txt .js .html or even php).
So with AJAX you can get result of a page save something to database, get something from data base, you can work with sessions and anything you can do with a php file.
When you send an AJAX request to a see a page(i.e /userData.php?userId=5) the page /userData.php?userId=5 will be executed and its output will be returned.(HTML or just a word ‘yes’ or ‘no’ or ‘you can’t access to this user’s information’).
You can send data to file with POST or GET. But the question is how you can get data from page. Because the result AJAX will give you is what the requested page echoed to page like this
<html>
….
</html>
Or
‘Yes’
Or
<?php echo ‘something’; ?>
So what about getting a row of Date or lots of data? Because the only thing you are getting is a text or maybe a long text.
For that you can use JSON which Is something like nested arrays.
[
{
"term": "BACCHUS",
"part": "n.",
"definition": "A convenient deity invented by the...",
"quote": [
"Is public worship, then, a sin,",
"That for devotions paid to Bacchus",
"The lictors dare to run us in,",
"And resolutely thump and whack us?"
],
"author": "Jorace"
},
…
And this is a string too. But you can get Data in it with $.getJSON in jQuery and you can generate JSON data in server side like this.
<?php
$arr=array(
‘data’=>’ffff’,
‘anotherData’=>array(‘rrrrr’,’sssss’);
);
Echo json_encode($arr);
?>
Json_encode() in PHP gets an array and returns json string of it. And we echo it.
Now we can use jQuery to get Data which will be retrieved from server.
This section if from
Learning jQuery 1.3
Better Interaction Design and Web Development with Simple JavaScript Techniques
Jonathan Chaffer
Karl Swedberg
Global jQuery functions
To this point, all jQuery methods that we've used have been attached to a jQuery object that we've built with the $() factory function. The selectors have allowed us to specify a set of DOM nodes to work with, and the methods have operated on them in some way. This $.getJSON() function, however, is different. There is no logical DOM element to which it could apply; the resulting object has to be provided to the script, not injected into the page. For this reason, getJSON() is defined as a method of the global jQuery object (a single object called jQuery or $ defined once by the jQuery library), rather than of an individual jQuery object instance (the objects we create with the $() function).
If JavaScript had classes like other object-oriented languages, we'd call $.getJSON() a class method. For our purposes, we'll refer to this type of method as a global function; in effect, they are functions that use the jQuery namespace so as not to conflict with other function names.
To use this function, we pass it the file name as before:
$(document).ready(function() {
$('#letter-b a').click(function() {
$.getJSON('b.json');
return false;
});
});
This code has no apparent effect when we click the link. The function call loads the file, but we have not told JavaScript what to do with the resulting data. For this, we need to use a callback function.
The $.getJSON() function takes a second argument, which is a function to be called when the load is complete. As mentioned before, AJAX calls are asynchronous, and the callback provides a way to wait for the data to be transmitted rather than executing code right away. The callback function also takes an argument, which is filled with the resulting data. So, we can write:
$(document).ready(function() {
$('#letter-b a').click(function() {
$.getJSON('b.json', function(data) {
});
return false;
});
});
Here we are using an anonymous function as our callback, as has been common in our jQuery code for brevity. A named function could equally be provided as the callback.
Inside this function, we can use the data variable to traverse the data structure as necessary. We'll need to iterate over the top-level array, building the HTML for each item. We could do this with a standard for loop, but instead we'll introduce another of jQuery's useful global functions, $.each(). We saw its counterpart, the .each() method, in Chapter 5. Instead of operating on a jQuery object, this function takes an array or map as its first parameter and a callback function as its second. Each time through the loop, the current iteration index and the current item in the array or map are passed as two parameters to the callback function.
$(document).ready(function() {
$('#letter-b a').click(function() {
$.getJSON('b.json', function(data) {
$('#dictionary').empty();
$.each(data, function(entryIndex, entry) {
var html = '<div class="entry">';
html += '<h3 class="term">' + entry['term'] + '</h3>';
html += '<div class="part">' + entry['part'] + '</div>';
html += '<div class="definition">';
html += entry['definition'];
html += '</div>';
html += '</div>';
$('#dictionary').append(html);
});
});
return false;
});
});
Before the loop, we empty out so that we can fill it with our newly-constructed HTML. Then we use $.each() to examine each item in turn, building an HTML structure using the contents of the entry map. Finally, we turn this HTML into a DOM tree by appending it to the .
This approach presumes that the data is safe for HTML consumption; it should not contain any stray < characters, for example.

calling php and javascript functions with one button

This is what I'm trying to achieve, but my Googling hasn't helped:
I have a button that adds a new row to a table dynamically. I also add a select component to a cell with the same action all in javascript. I'd like for that select component to populate with values from a sql select statement. Of course I don't want to define the connection to the DB in the JavaScript. So I was wondering if there was a way I could call a PHP function to retrieve the values then store it in variable within JavaScript.
PS I understand that PHP is server side as opposed to JS. But surely this is possible.
here's a simple implementation of such a thing using jQuery's ajax and php.
html
<select data-source-url="/category/list"></select>
javascript using jQuery
$("select[data-source-url]").each(function(){
var url = $(this).attr("data-source-url");
var el = $(this);
$.get(url, function(data){
for (i=0;i<data.length;i++){
el.append("<option>" + data[i] + "</option>");
}
},"json");
});
category/list endpoint (a php script)
$list = array();
$list[0] = "category 1";
$list[1] = "category 2";
$list[2] = "category 3";
$list[3] = "category 4";
$list[4] = "category 5";
echo json_encode($list);
a little explanation: what happens is a request being made via the JavaScript client to a php script, which returns an array of values in JSON (which is basically a javascript data-structure), those values are added to the select box dynamically.
Please note that on initial load of the page, the select box will be empty.
yes ofcourse you can. for storing s php variable in a js ariable you can do like this.
before storing it into js variable store the required value in your php variable
var value = '<?php echo $value;?>';
Javascript cannot connect directly to a database.
You want AJAX. A basic flow for this functionality looks like this.
Create a PHP script that connects to the database and gets the options for your select element (let's call it options.php). This script should fetch the options from the database and output them as a JSON array.
In your javascript, you would create an ajax request to options.php. With the JSON data returned from that script, you would loop over each element and create and append a corresponding option element to the dom inside of your select element.
Also consider using jQuery. It greatly simplifies ajax and provides a cross-browser solution.
Option 1
Pass a php array with all possible values to the client side using something like this on the client side:
var opt_values = [<?php echo $php_values; ?>]; //javascript array
or
var opt_values = <?php echo json_encode($php_values); ?>; //json object
Option 2
Another way is making an ajax request. Write a php function that return a JSON object and then you can manipulate the result using jQuery ajax method:
PHP function:
$json = array();
$result = mysqli_query ($connection, $query);
while($row = mysqli_fetch_array ($result))
{
$bus = array(
'id' => $row['id'],
'text' => $row['name']
);
array_push($json, $bus);
}
return = json_encode($json)
Jquery
$('#button-id').click(function(){
//adds a new row to a table dynamically
$.ajax({
type: "get",
dataType: "json",
url: "/get_values.php",
success: function (response) {
var $el = $("#myselect"); //get the select
$el.empty(); // remove old options
//Append the new values
$.each(response, function(key, value) {
$el.append($("<option></option>")
.attr("value", value.id).text(value.text));
});
}
});
});
Just thought i'd put it out there since w3schools is my friend and i kinda follow what they're saying in this post.
W3Schools PHP & AJAX communication

Pass Arrays from PHP file to JS file

I would like to pass an array I have in my PHP file to another file that is written in java script.
This is my array:
$pictures = array(
"1" => array("caption" => "1920x1200px", "tag" => "wallpaper", "link" => "#"),
);
And in my java script file this is the place where I want to call the array:
(At the place where they shall be in the code I wrote TAG, LINK and CAPTION.
Sry if this is a stupid question, but as you see, I have no idea about PHP and java script)
F.helpers.title = {
beforeShow: function (opts) {
var text = F.current.title,
type = opts.type,
title,
target;
if (!isString(text) || $.trim(text) === '') {
return;
}
title = $('<div class="fancybox-title fancybox-title-' + type + '-wrap"><h1>' + text + '</h1><p>CAPTION</p></div><div class="fancybox-title fancydownload" ><img src="../../../slider/img/download.png" alt=""/></div><div class="fancybox-title fancytag"><h2>TAG</h2></div>');
switch (type) {
case 'inside':
target = F.skin;
break;
case 'outside':
target = F.wrap;
break;
case 'over':
target = F.inner;
break;
default: // 'float'
target = F.skin;
title
.appendTo('body')
.width(title.width()) //This helps for some browsers
.wrapInner('<span class="child"></span>');
//Increase bottom margin so this title will also fit into viewport
F.current.margin[2] += Math.abs( getScalar(title.css('margin-bottom')) );
break;
}
if (opts.position === 'top') {
title.prependTo(target);
} else {
title.appendTo(target);
}
}
};
Try it using JSON. There are quite a few JSON parsers available
Encode it as JSON to convert it into a JavaScript literal, then access the resultant value as normal.
var data = <?php echo json_encode(array('foo' => 'bar')); ?>;
console.log(data['foo']);
The lifecycle of your PHP script (on the server side) is different from that of JS (on the client side). If you want to pass some information from PHP to client side, you can do one of the following:
You should print this information into the HTML file on the server side itself using your template engine.
You should return this information through another API by converting it into JSON format that is easy to browse through on the javascript side, and call your API using AJAX.
use an ajax call, something like $.post to get the array as a json array,
add an echo json_encode($picture) at the end of your PHP script.
PHP just generates files which then you send to the client. JavaScript is executed on the client side. So you should generate in php something like
var pictures = {'1': {caption: '1920x1200px', tag: 'wallpaper', link: '#'}};
and place it in html in script tag for example.
As a variant you may do it this way:
var pictures = <?= json_encode($pictures); ?>;

Unable to retrieve data using jQuery.post

I'm trying to use jQuery.post() function to retrieve some data. But
i get no output.
I have a HTML that displays a table. Clicking this table should trigger a jQuery.post event.
My scriptfile looks like this:
jQuery(document).ready(function() {
jQuery('#storeListTable tr').click(function() {
var storeID = this.cells[0].innerHTML; //This gets me the rowID for the DB call.
jQuery.post("../functions.php", { storeID: "storeID" },
function(data){
alert(data.name); // To test if I get any output
}, "json");
});
});
My PHP file looks like this:
<?php
inlcude_once('dal.php');
//Get store data, and ouput it as JSON.
function getStoreInformation($storeID)
{
$storeID = "9";//$_GET["storeID"];
$sl = new storeLocator();
$result = $sl->getStoreData($storeID);
while ($row = mysql_fetch_assoc($result)) {
{
$arr[] = $row;
}
$storeData = json_encode($arr);
echo $storeData; //Output JSON data
}
?>
I have tested the PHP file, and it outputs the data in JSON format. My only problem now is to return this data to my javascript.
since the javascript is located in the /js/ folder, is it correct to call the php file by using '../'?
I don't think I'm passing the storeID parameter correctly. What is the right way?
How can I call the getStoreInformation($storeID) function and pass on the parameter? The jQuery example on jQuery.com has the following line: $.post("test.php", { func: "getNameAndTime" }
Is the getNameAndTime the name of the function in test.php ?
I have gotten one step further.
I have moved the code from inside the function(), to outside. So now the php code is run when the file is executed.
My js script now looks like this:
jQuery('#storeListTable tr').click(function() {
var storeID = this.cells[0].innerHTML;
jQuery.post("get_storeData.php", { sID: storeID },
function(data){
alert(data);
}, "text");
});
This results in an alert window which ouputs the store data as string in JSON format.
(because I have changed "json" to "text").
The JSON string looks like this:
[{"id":"9","name":"Brandstad Byporten","street1":"Jernbanetorget","street2":null,"zipcode":"0154","city":"Oslo","phone":"23362011","fax":"22178889","www":"http:\/\/www.brandstad.no","email":"bs.byporten#brandstad.no","opening_hours":"Man-Fre 10-21, L","active":"pending"}]
Now, what I really want, is to ouput the data from JSON.
So I would change "text" to "json" and "alert(data)" to "alert(data.name)".
So now my js script will look like this:
jQuery('#storeListTable tr').click(function() {
var storeID = this.cells[0].innerHTML;
jQuery.post("get_storeData.php", { sID: storeID },
function(data){
alert(data.name);
}, "json");
});
Unfortunately, the only output I get, is "Undefined".
And if I change "alert(data.name);" to "alert(data);", the output is "[object Object]".
So how do I output the name of teh store?
In the PHP file, I've tried setting $storeID = $_GET["sID"]; But I don't et the value. How can I get the value that is passed as paramter in jQuery.post ?
(currently I have hardcoded the storeID, for testing)
Lose the quotes around "storeID":
Wrong:
jQuery.post("../functions.php", { storeID: "storeID" }
Right:
jQuery.post("../functions.php", { storeID: storeID }
bartclaeys is correct. As it is right now, you are literally passing the string "storeID" as the store ID.
However, a couple more notes:
It might seem weird that you will be setting storeID: storeID - why is only the second one being evaluated? When I first started I had to triple check everytime that I wasn't sending "1:1" or something. However, keys aren't evaluated when you are using object notation like that, so only the second one will be the actual variable value.
No, it is not correct that you are calling the PHP file as ../ thinking of the JS file's location. You have to call it in respect of whatever page has this javascript loaded. So if the page is actually in the same directory as the PHP file you are calling, you might want to fix that to point to the right place.
Kind of tied to the previous points, you really want to get your hands on Firebug. This will allow you to see AJAX requests when they are sent, if they successfully make it, what data is being sent to them, and what data is being sent back. It is, put simply, the consensus tool of choice to debug your Javascript/AJAX application, and you should have it, use it, and cherish it if you don't want to waste another 6 days debugging a silly mistake. :)
EDIT As far as your reply, if you break down what you are returning:
[
{
"id":"9",
"name":"Brandstad Byporten",
"street1":"Jernbanetorget",
"street2":null,
"zipcode":"0154",
"city":"Oslo",
"phone":"23362011",
"fax":"22178889",
"www":"http:\\/www.brandstad.no",
"email":"bs.byporten#brandstad.no",
"opening_hours":"Man-Fre 10-21, L",
"active":"pending"
}
]
This is actually an array (the square brackets) containing a single object (the curly braces).
So when you try doing:
alert(data.name);
This is not correct because the object resides as the first element of the array.
alert(data[0].name);
Should work as you expect.
Your JSON is returned as a javascript array... with [] wrapping the curly bits [{}]
so this would work.
wrong: alert(data.name);
right: alert(data[0].name);
Hope that helps.
D
Ok, thanks to Darryl, I found the answer.
So here is the functional code for anyone who is wondering about this:
javascript file
jQuery(document).ready(function() {
jQuery('#storeListTable tr').click(function() {
jQuery.post("get_storeData.php", { storeID: this.cells[0].innerHTML }, // this.cells[0].innerHTML is the content ofthe first cell in selected table row
function(data){
alert(data[0].name);
}, "json");
});
});
get_storeData.php
<?php
include_once('dal.php');
$storeID = $_POST['storeID']; //Get storeID from jQuery.post parameter
$sl = new storeLocator();
$result = $sl->getStoreData($storeID); //returns dataset from MySQL (SELECT * from MyTale)
while ($row = mysql_fetch_array($result))
{
$data[] = array(
"id"=>($row['id']) ,
"name"=>($row['name']));
}
$storeData = json_encode($data);
echo $storeData;
?>
Thanks for all your help guys!

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