I saw other posts but it doesn't work. I am a bit confused here on how I implement an array into JS from PHP...
In the PHP file (test.php) I have :
$table = array();
while($row = mysqli_fetch_assoc($result) )
{
$value=$row['value'];
$date=$row['date'];
$table[$value]=$date;
}
And in JavaScript I have :
<?php include 'test.php'; ?>
...
data: (function() {
// generate an array of random data
var data = [],
time = (new Date()).getTime(),
i;
for (i = -19; i <= 0; i++) {
data.push({
x: time + i * 1000,
y: Math.random()
});
}
return data;
So what I look for is to put $value=$row['value']; in the y : and $date=$row['date']; in the x : OR perhaps putting the entire table $table in the var data will work also .
I'm new to JavaScript, so thanks in advance..!
So in your php file....
Add a line at the bottom that converts the table to json data.
And give it a variable...
$table = array();
while($row = mysqli_fetch_assoc($result) )
{
$value=$row['value'];
$date=$row['date'];
$table[$value]=$date;
}
$jsondata = json_encode($table);
Then in your other file....
echo that variable into your data object, in the javascript.
Remember to remove that whole random number generating function...(its just an example)
Echoing PHP into javascript is definitely not considered good practice though.
And it would be better to actually do an ajax call to your php file, and insert like that....I'll also show you how to do ajax.
<?php include 'test.php'; ?>
...
data: [<?php echo $jsondata;?>], //remove that function that was here..
// it was just to generate random numbers for the demo
....
}
EDIT / UPDATE For ajax...
So for ajax...instead of assigning a variable to $jsondata.
Just return it like so...(in your PHP file)
return json_encode($table);
Then for this way....you dont include('test.php') like you did before.
Instead you just have this script inside your $(document).ready(function(){....
$.getJSON('test.php', function(myJSON) {
//and inside this function you put your highcharts stuff...
//remove that function() that generates random data
// And you will put the 'myJSON' return object inside the 'data':[] array...
// Provided you have structured your data correctly for highcharts, it should work...
// If not.... it'll be a start, and you're well on your way to debugging it
}
Related
I've created a tag input for my user in my site, for that purpose I coded a tag function with dropdown help. So my problem is that, I want to fetch data from data base in JavaScript file.
Js
var FormSamples = function () {
return {
//main function to initiate the module
init: function () {
// use select2 dropdown instead of chosen as select2 works fine with bootstrap on responsive layouts.
$('.select2_category').select2({
placeholder: "Select an option",
allowClear: true
});
$('.select2_sample1').select2({
placeholder: "Select a State",
allowClear: true
});
$(".select2_sample2").select2({
placeholder: "Type to select an option",
allowClear: true,
minimumInputLength: 1,
query: function (query) {
var data = {
results: []
}, i, j, s;
for (i = 1; i < 5; i++) {
s = "";
for (j = 0; j < i; j++) {
s = s + query.term;
}
data.results.push({
id: query.term + i,
text: s
});
}
query.callback(data);
}
});
function format(item) {
opt = $(item.element);
sel = opt.text();
og = opt.closest('optgroup').attr('label');
return og+' | '+item.text;
}
$("select").select2({
formatSelection: format,
escapeMarkup: function(m) { return m; }
});
$(".select2_sample3").select2({
tags: ['Karachi','Lahore']
});
}
};
}();
In the end of JS file you'll see:
$(".select2_sample3").select2({
tags: ['Karachi','Lahore']
});
Instead of "Karachi","Lahore" I want to fetch tags from data base.
I am fetching data like this:
$conn = mysqli_connect($servername, $username, $password, $dbname);
$sql = "SELECT * FROM tags";
$result = mysqli_query($conn, $sql);
mysqli_query ($conn,"set character_set_results='utf8'");
$row = mysqli_fetch_assoc($result);
Any body please help me that how can I fetch data in JS by PHP.
You can use json_encode in php:
$ar = array('Karachi','Lahore');
echo json_encode($ar);
and in javascript:
<script type="text/javascript">
// pass PHP variable declared above to JavaScript variable
var ar = <?php echo json_encode($ar) ?>;
</script>
output:
['Karachi','Lahore']
You are almost there. Now you can access the relevant data members of $row by selecting based on column name. For example you can look at the value of ˚$row["id"]. Also fetch_assoc type functions work row by row, so you will have to run it for each row, not each column, when you have multiple results. You can store the results in a php array but you will have to output them to the javascript portion of your file, or store them in a file javascript can access, before ending the php portion of your script. Below I write a little about each of your options.
Save data obtained form php data query to csv file, from which javascript can read.
Take a look at this SO post to learn how you can read data from csv. So in this example, your php script could read data from a database and then generate, via php, a csv file. Your javascript could then read from the csv file.
Alternately you can write from php directly to the javascript encoded in the same page assuming you can use your script in the same web page and not as a .js include. In that case, you can use json_encode to print your php arrays to javascript arrays as described in this SO post.
For example, to create two arrays accessible in Javascript of cities and countries I would do this:
<?php
...
$city = array();
$country = array();
while($row = mysqli_fetch_assoc($result)){
array_push($city, $row['city']);
array_push($country, $row['country']);
}
...?>
<script>
var city = <?php echo json_encode($city); ?>;
var country = <?php echo json_encode($country); ?>;
...
</script>
Here I am assuming you stored the data in a database with column names 'city' and 'country'
You should also consider using PDO objects for safer SQL manipulation.
I have an SQL database (I know for sure it includes remote access, if that's necessary to access a database through php). It definitely has at least one record in it, and I need to get each record and create a corresponding button that links to a php file, taking the first field for that record as a/n argument, variable, parameter, or whatever you call the whatever.php?variable=value.
For some reason, this code just gives me a blank page. Why?
<?php
$connection=mysqli_connect("myhost","myusername","mypassword","mydatabase");
$result=mysqli_query($connection, "SELECT * FROM myTable");
$resultArray=array();
while ($row = mysqli_fetch_array($result)) {
array_push($resultArray, $row['ID']);
}
$resultArrayImplode = implode(",", $resultArray);
?>
<script>
var resultArray = <?php echo $resultArrayImplode; ?>
arrayEntries = new Array();
arrayEntries = resultArray.split(",");
function CreateButtons(element, index, array) {
var button = document.createElement("input");
button.type = "button";
button.value = element;
button.onclick = function() {
document.location.href = "ButtonClicked.php?id=" + element;
}
document.body.appendChild(button);
}
arrayEntries.forEach(CreateButtons);
</script>
Thanks!
Your javascript assignment to resultArray is probably not syntactically correct due to quote characters, etc. Luckily, PHP's JSON functions automagically create good javascript for you.
Try this for the javascript output:
var arrayEntries = <?php echo json_encode($resultArray)?>;
Your problem is $resultArrayImplode; is a string, so
var resultArray = <?php echo $resultArrayImplode; ?>
renders as:
var resultArray = 1,2,3,4,5
Which is a syntax error.
What you can do is use JSON. JSON syntax is JavaScript syntax, so all you need to do is:
var arrayEntries = <?php echo json_encode($resultArray); ?>;
This should render as something like:
var arrayEntries = [1,2,3,4,5];
Which is perfect JavaScript syntax. Then the rest of your code should work.
I just don't see why do you need to use javascript for this, cant you just do the following :
<?PHP
foreach($resultArray as $result)
{
?>
Im a button click me</div>
<?PHP
}
?>
in my opinion, i see no real need for you to use javascript for this.
Hello i me and a friend have a maffia game. I have a countdown timer code but it only works when i use one timer. But i need to use it in a loop to get more timers in a table. I searched on google but nothing really helped. I saw that i had to use different id's but that didn't work for me. I have little knowledge of javascript.
This are my codes:
While loop:
while($info = mysql_fetch_object($dbres))
{
$j = 0;
$bieding = mysql_fetch_object(mysql_query("SELECT `bedrag` FROM `biedingen` WHERE `veilingid`='{$info->id}' ORDER BY `bedrag` DESC LIMIT 1"));
$tijd = ($info->tijd + $info->duur * 60 * 60 - $time);
echo '<tr>
<td>'.veilingnaam($info->id,1,1).'</td>
<td>'.usernaam($info->veiler,1,1).'</td>
<td>€'.getal($bieding->bedrag).'</td>
<td><div id="teller'.$j.'"></div></td>
</tr>';
}
Javascript part:
<script type="text/javascript">
var seconds = <?= ($tijd+1) ?>;
var countdown = document.all? document.all["teller<?= $j?>"] : document.getElementById? document.getElementById("teller<?= $j?>") : "";
var woord = "seconden";
function display()
{
seconds=seconds-1;
if(seconds==1){ woord="seconde"; }
if(seconds==0){ woord="seconden"; }
if(seconds<0)
{
self.location.replace(self.location);
}
else
{
if (countdown)
{
countdown.innerHTML=seconds+" "+woord;
setTimeout('display()',1000);
}
}
}
display();
</script>
Your while loop goes through table rows in a DB, but your JavaScript code is not part of that loop. That means you generate a HTML table for each row, but then you create <script>...</script> which includes $tijd/$j only for the last row (assuming that your while executes before the script is added to the page.
Possible workarounds:
Add a jQuery's selector, something like $("div.teller").each(function(){...}); and in that function create a timer and/or any other JavaScript code you need associated with that div.Note that this requires your div to get a CSS class "teller".
Create all JavaScript code that is needed for each DB's table row inside the PHP's while loop, but this would probably get really messy.
Also, I advise you to take a look at JavaScript's setInterval(), since it is more appropriate than setTimeout() for what you want to do.
Another thing to consider: all your timers would have a one second tick. It seems to me that it is better to have a single timer and just keep numbers of seconds (whatever that might be) in a JavaScript array (this one is easily created in PHP's while loop).
Edit: Here is one way to do this:
$data = array();
while($info = mysql_fetch_object($dbres))
{
... /* your current code */
$data[] = "{ id: 'teller$j', seconds: $tijd }";
}
$data = "[ ".implode(", ", $data)." ]";
Now, create your JavaScript code outside of the loop:
<script type="text/javascript">
var data = <?php echo $data; ?>; // It is not advisable to use <?= ... ?>
// Get references to divs via saved ids (seconds are already saved
for (i = 0; i < data.length; i++)
data.div = document.getElementById(data.id); // No need for document.all; IE supports getElementById since version 5.5
...
</script>
Now, adapt display() to work with the elements of your data array.
I have this JavaScript code that creates a table, and puts in the rows and columns.
I want to call this function, based upon some data in a database. So the amount of rows is based upon the amount of data in the database.
My data in my database is a markscheme, I want the the table to fill depending upon the amount of questions are in the database
I have tried and here is my code:
hasLoaded = true;//page loaded set to true
<?php
$query = "SELECT maxMark, criteria FROM mark ";
$result = mysql_query($query);
while ($result != null)
{
addRow();//add row with everything in
}
The correct answer is json_encode your data from PHP and store it in a JavaScript variable like this.
<?php
// populate the php rows array
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows = array_push($rows, $row);
}
?>
<script>
// populate the javascript rows array
var rows = <?php echo json_encode($rows); ?>;
for (var = 0; i < rows.length; i++) {
addRow(rows[i]);
}
</script>
I would not recommend Jamund's solution, as it would require either inline javascript, or parsing your javascript files through PHP. I would recommend using an Ajax post in your javascript function to fetch the data from your server, and then populating from there.
$(document).ready(function(){
$.ajax({
type: "POST",
url: "yourscript.php",
data:{param1: 'yourParam'},
success: PopulateTable
});
});
functionPopulateTable(data, status)
{
// Build Table with data
}
http://api.jquery.com/jQuery.ajax/ is a good place to start if you are using jQuery on your page.
I hope this problem is very simple, I can't figure out the solution myself it seems. Been trying and googling for hours, driving me nuts :) Ok, so I have a drag'n'drop + sortable (using scriptaculous and prototype for your information) on my index.php. I use this code to send the items dropped in a div using this code:
<script type="text/javascript">
//<![CDATA[
document.observe('dom:loaded', function() {
var changeEffect;
Sortable.create("selectedSetupTop", {containment: ['listStr', 'selectedSetupTop'], tag:'img', overlap:'vertical', constraint:false, dropOnEmpty: true,
onChange: function(item) {
var list = Sortable.options(item).element;
$('changeNotification').update(Sortable.serialize(list).escapeHTML());
if(changeEffect) changeEffect.cancel();
changeEffect = new Effect.Highlight('changeNotification', {restoreColor:"transparent" });
},
onUpdate: function(list) {
new Ajax.Request("script.php", {
method: "post",
parameters: { data: Sortable.serialize(list), container: list.id }
onLoading: function(){$('activityIndicator').show(), $('activityIndicator2').hide()},
onLoaded: function(){$('activityIndicator').hide(), $('activityIndicator2').show()},
});
}
});
});
// ]]>
</script>
I've been using this code before so I "kind of know" it will send me data to my script.php page. selectedSetupTop is my div containing the elements. Don't mind about the notification and the activityIndicator thingy. My script.php page looks like this for the moment:
parse_str($_POST['data']);
for ($i = 0; $i < count($selectedSetupTop); $i++) {
$test .= $selectedSetupTop[$i];
}
echo "<script>alert('$test');</script>";
I can't seem to get any output in the alert message, it's just blank. The purpose of the script.php is to update a row in a database and it will look kind of like this:
$sql = mysql_query("UPDATE table SET row = '$arrayInStringFormat' WHERE id = '1'") or die(mysql_error());
where the $arrayInStringFormat is a conversion of the array $selectedSetupTop to the format (1, 2, 3, 4). I guess I'll solve that using implode or something, but the problem is parsing the array $selectedSetupTop. I'm not it passes between the pages at all, really appreciate help! Tell me if I need to explain further.
Thanks in advance!
''''''
EDIT 1
If it will help, I used this code before that I know will send me the data and use it. Notice I don't wanna do my task like the way I do below:
$querySetup = $_GET["s"];
parse_str($_POST['data']);
for ($i = 0; $i < count($selectedSetupTop); $i++) {
$sql = mysql_query("UPDATE " . $querySetup . " SET orderId = $i, hero_selected = 'n' WHERE imageId = $selectedSetupTop[$i]") or die(mysql_error());
}
''''''
EDIT 2
So it does parse, but I still have the problem I can't print it. I wanna implode the array somehow.
Not sure how AJAX works in Scriptalicious/Prototype, but you don't seem to be getting the data from the AJAX call. In jQuery it would be something like this where the data you receive from the script is returned as the argument of the function.
onLoaded: function(msg){
$('activityIndicator').hide(),
$('activityIndicator2').show(),
alert(msg)
}
Secondly, you can't echo a PHP array, you have to encode it to JSON:
echo json_encode($test);