Time ago function php - php

Question

I'm trying to do a time ago function only going back 24 hours. So the values returned will be random like;
7 mins ago;
2 hours 39 mins ago;
5 hours ago;
I'm trying to amend this function but don't know how to limit how to limit only going back 24 hours.
function timeAgo($time_ago){
$cur_time = time();
$time_elapsed = $cur_time - $time_ago;
$seconds = $time_elapsed ;
$minutes = round($time_elapsed / 60 );
$hours = round($time_elapsed / 3600);
// Seconds
if($seconds <= 60){
echo "$seconds seconds ago";
}
//Minutes
else if($minutes <=60){
if($minutes==1){
echo "one minute ago";
}
else{
echo "$minutes minutes ago";
}
}
//Hours
else if($hours <=24){
if($hours==1){
echo "an hour ago";
}else{
echo "$hours hours ago";
}
}
}
How do i solve this?

Answer 1

You do not need such complex things.
This is enough:
$hours = rand(0, 3);
$mins = rand(0, 59);
$secs = rand(0, 59);
$text = '';
if ($hours) $text = $hours . ' hours';
if ($mins) $text .= $mins . ' mins';
if ($secs) $text .= $secs . ' secs';
// The following is almost impossible to happen, but anyway...
if (!$hours && !$mins && !$secs) $text = rand(1, 59) . ' mins';
$text .= 'ago';

Answer 2

After the line $hours = round($time_elapsed / 3600);, add if($hours > 24) return;, then you can limit the hours fewer than 24.

Answer 3

Use DateTime.diff and use the properties for DateInterval
function timeAgo(DateTime $time_ago){
$cur_time = new DateTime();
$time_elapsed = $cur_time.diff($time_ago);
$seconds = $time_elapsed.s;
$minutes = $time_elapsed.i;
$hours = $time_elapsed.h;
$days = $time_elapsed.d;
//days
if($days > 1){
if($days==1){
echo "one day ago";
}else{
echo "$days days ago";
}
}
//Hours
else if($hours > 1){
if($hours==1){
echo "an hour ago";
}else{
echo "$hours hours ago";
}
}
//Minutes
else if($minutes > 0){
if($minutes==1){
echo "one minute ago";
}
else{
echo "$minutes minutes ago";
}
}
// Seconds
else if($seconds> 0){
echo "$seconds seconds ago";
}
}